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- Question
A plasmid
Options- A. is a circular DNA molecule
- B. always contains an origin of replication
- C. usually contains one or more restriction sites
- D. all of the above
- Correct Answer
- all of the above
- 1. Which of the following is not true of small inbreeding populations?
Options- A. They tend to loose genetic diversity
- B. There is an increased incidence of recessive diseases
- C. Alleles may become fixed
- D. Mutation is increased Discuss
- 2. Restriction enzymes
Options- A. protect bacteria from viral infection
- B. cut DNA in a staggered fashion
- C. cut DNAs producing a blunt end
- D. all of the above Discuss
- 3. What enzyme forms covalent bonds between restriction fragments?
Options- A. DNA primase
- B. DNA helicase
- C. DNA polymerase
- D. DNA ligase Discuss
- 4. When populations are small, gene frequencies can change from generation to generation and some alleles may become fixed in a population. This is called __________ .
Options- A. assortative mating
- B. inbreeding
- C. heterosis
- D. genetic drift Discuss
- 5. Under which of the following conditions would population gene frequencies remain the same?
Options- A. Selection for homozygotes
- B. Small population size
- C. Active migration between groups
- D. Random mating Discuss
- 6. Knockout mice are created by
Options- A. mutagenizing a mouse and selecting for mutant offspring
- B. creating a chimera by fusing cells from two different cell lines
- C. infecting the mouse with a retrovirus
- D. transfecting embryonic stem cells with an altered gene sequence Discuss
- 7. Which of these restriction enzymes produce blunt ends?
Options- A. SaII
- B. EcoRV
- C. XhoI
- D. HindIII Discuss
- 8. A human cDNA library
Options- A. contains DNA for specific human proteins
- B. contains DNA for virtually all of the human proteins in vectors
- C. cannot be used to obtain human genes because it would be radioactive
- D. none of the above Discuss
- 9. Gluconeogenesis uses
Options- A. 3 ATPs and 2 GTPs per glucose
- B. 2 ATPs and 1 GTPs per glucose
- C. 3 ATPs and 3 GTPs per glucose
- D. 4 ATPs and 2 GTPs per glucose Discuss
- 10. Citric acid accumulation would
Options- A. stimulate phosphofructokinase activity
- B. stimulate fructose 1,6 diphosphatase activity
- C. inhibit phosphofructokinase activity
- D. both (b) and (c) Discuss
Recombinant DNA Technology problems
Search Results
Correct Answer: Mutation is increased
Correct Answer: all of the above
Correct Answer: DNA ligase
Correct Answer: genetic drift
Correct Answer: Random mating
Correct Answer: transfecting embryonic stem cells with an altered gene sequence
Correct Answer: EcoRV
Correct Answer: contains DNA for virtually all of the human proteins in vectors
Correct Answer: 4 ATPs and 2 GTPs per glucose
Correct Answer: both (b) and (c)
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