Question 1

Arrange the following words in the order in which they would appear in a standard English dictionary. Use the numbers given with each word to indicate the correct sequence: 1. Feeble 2. From 3. Floor 4. Foam 5. Fluorescent.

Accepted Answer

Introduction / Context: This question tests your understanding of dictionary order, also known as lexical or alphabetical order. You are given five English words with associated numbers and asked to determine the order in which they would appear in a typical English dictionary. Once you know the correct order, you must choose the matching numerical sequence from the given options. Such questions are common in verbal reasoning sections to check attention to spelling and alphabetical comparison of letters beyond the first character. Given Data / Assumptions: Words and codes: 1. Feeble, 2. From, 3. Floor, 4. Foam, 5. Fluorescent. We assume standard English dictionary ordering. Letter comparison is case insensitive; we compare letters from left to right. We must output the correct sequence as a string of digits, such as 13542. Concept / Approach: To arrange words in dictionary order, compare them letter by letter from left to right. First compare the first letters. If they are the same, compare the second letters, and so on, until a difference is found. The word whose differing letter is alphabetically smaller comes first. When one word is a prefix of another, the shorter word comes first. Here, all words start with the letter F, so we must examine subsequent letters carefully to determine the exact ordering. Step-by-Step Solution: Step 1: All words begin with F, so we compare the second letters: Feeble (e), From (r), Floor (l), Foam (o), Fluorescent (l). Step 2: Alphabetically, e comes before l, o, and r, so Feeble (1) must come first. Step 3: Now compare words starting with Fl: Floor (Flo...) and Fluorescent (Flu...). Between 'o' and 'u', the letter o comes before u, so Floor (3) comes before Fluorescent (5). Step 4: Next, compare the remaining Fo... and Fr... words: Foam (Fo...) and From (Fr...). Since 'o' comes before 'r', Foam (4) comes before From (2), so From will be last. Step 5: The final dictionary order is: Feeble (1), Floor (3), Fluorescent (5), Foam (4), From (2), giving the code 13542. Verification / Alternative check: As a quick verification, you can imagine looking these words up in a physical dictionary. You would first scan for FE, then FL, then FO and FR words. Among FL words, you would see FLOOR before FLUORESCENT. Among FO and FR, you would reach FOAM before FROM. Writing them out and checking the second and third letters again confirms that 1, 3, 5, 4, 2 is the only sequence consistent with dictionary order. Why Other Options Are Wrong: Option 15342 places Foam (4) before Fluorescent (5), which is incorrect because all FL words must precede all FO words. Option 13524 swaps the last two words, suggesting Foam before Fluorescent, which again violates the FL versus FO ordering. Option 15324 and other incorrect codes similarly ignore the correct alphabetical relationships between Floor, Fluorescent, Foam and From. Only 13542 respects the exact dictionary sequence. Common Pitfalls: Students sometimes compare only the first two letters and overlook tie breaking using the third or later letters. Another error is to focus on the length of words rather than actual alphabetical order; dictionary order is based on sequence of letters, not the number of letters. To avoid mistakes, always write the initial three or four letters of each word in a column and compare them systematically until you find a difference. Final Answer: The correct dictionary order corresponds to the sequence 13542, so option 13542 is the right answer.

Question 2

In the following question, consider the base word REPRESENTATION. From the alternative words given below, select the word which cannot be formed using the letters of REPRESENTATION, assuming no letter is used more times than it occurs in the base wo…

Accepted Answer

Introduction / Context: This is another word formation question designed to test attention to detail and ability to track letter counts. You are given the longer base word REPRESENTATION and asked to find which option cannot be formed from its letters. Good performance requires you to check that every letter of an option is present in the base word and that no option demands a letter that does not exist or that occurs too many times. Given Data / Assumptions: Base word: REPRESENTATION. Letters available, counting frequency: R (2), E (3), P (1), S (1), N (2), T (2), A (1), I (1), O (1). Options: Paint, Senator, Trees, Strict. Each letter in the base word can be used at most as many times as it appears there. Concept / Approach: We follow a systematic letter-counting approach. First, list the letters and frequencies in the base word. Then, for each option word, check every letter against this pool. If an option contains any letter that is missing from the base word, that word is impossible to form. If all letters appear within allowed frequencies, that option is possible. Only one option should fail this check and that will be our answer. Step-by-Step Solution: Step 1: Confirm letters in REPRESENTATION: R, E, P, R, E, S, E, N, T, A, T, I, O, N. Step 2: Check Paint: P, A, I, N, T are all available within the base word's letter pool, so Paint can be formed. Step 3: Check Senator: S, E, N, A, T, O, R all occur in the base word and none exceed their allowed frequency, so Senator can be formed. Step 4: Check Trees: T, R, E, E, S appear in the base word and enough copies of E, R and T are available, so Trees can be formed. Step 5: Check Strict: S, T, R, I, C, T require the letter C, which does not appear anywhere in REPRESENTATION. Therefore Strict cannot be formed. Verification / Alternative check: A quick visual verification is to write the alphabet and tick off which letters appear in the base word. You will see that C never appears in REPRESENTATION. Scanning the options, only Strict uses the letter C, so this immediately identifies it as impossible. All other options use only the letters P, A, I, N, T, S, E, N, O, R, which are clearly present in the base word, confirming our conclusion that Strict is the odd one out. Why Other Options Are Wrong: Paint uses P, A, I, N and T, all safely drawn from the base word. Senator uses S, E, N, A, T, O and R, each of which is available. Trees uses T, R, E and S, and the base word has enough instances of E, R and T to support this. Since all of these can be formed, none of them satisfies the requirement of being impossible, so they are not correct answers. Common Pitfalls: Candidates sometimes ignore letter frequency and only check presence, but in this question the key trap is the completely absent letter C. Another issue is mental fatigue from longer base words, leading to misreading. Writing out the base letters once and reusing that list avoids mistakes. In time-pressured tests, it helps to first look for obviously absent letters in options (such as C, L, V, etc.) to quickly identify the impossible word before doing detailed counts. Final Answer: The only option that cannot be formed from the letters of REPRESENTATION is Strict, so Strict is the correct answer.

Question 3

Arrange the following words in the order in which they appear in a standard English dictionary. Use the numerical codes for the words: 1. Counter 2. Crop 3. Create 4. Carnation 5. Creator.

Accepted Answer

Introduction / Context: This question again tests dictionary order, requiring precise comparison of alphabetic sequences. You are given five words together with numbers used as codes. Your role is to determine the correct dictionary order of the words and then select the matching numeric pattern. Such questions train you to pay very close attention to the sequence of letters beyond the first one or two positions, which is important in many reasoning and clerical tasks. Given Data / Assumptions: Words: 1. Counter, 2. Crop, 3. Create, 4. Carnation, 5. Creator. We apply standard English dictionary rules. Each word starts with the letter C, so later letters will decide the order. We must output the correct ordering as a sequence of codes like 41352. Concept / Approach: When words share the same starting letter, we look at the second, third, and successive letters to break ties. Alphabetical order is decided by the first position at which the letters differ. If one word is a prefix of another, the shorter word is considered earlier in the dictionary. Here, all words begin with C, so we start our comparison from the second letter and move step by step until a clear sequence emerges. Step-by-Step Solution: Step 1: Examine the second letters: Counter (o), Crop (r), Create (r), Carnation (a), Creator (r). Step 2: The smallest second letter is 'a', so Carnation (4) must come first in dictionary order. Step 3: Between Counter (co...) and the group of 'cr...' words, 'o' comes before 'r', so Counter (1) comes immediately after Carnation. Step 4: Now compare the three 'cr...' words: Crop (cro...), Create (cre...), Creator (cre...). Since 'e' comes before 'o', the two Cre... words appear before Crop. Step 5: Among Create and Creator, they match up to 'creat'. Create ends earlier, so it comes before Creator. Therefore the order is Create (3), Creator (5), and then Crop (2). Step 6: Combining all, the final dictionary order is 4 (Carnation), 1 (Counter), 3 (Create), 5 (Creator), 2 (Crop), which gives 41352. Verification / Alternative check: You can quickly verify by writing the words in full and underlining their first three letters: Ca..., Co..., Cr.... All Ca words come first, then Co, then Cr. Within Cr, compare Cre with Cro to see that Cre words come first. Finally, Create precedes Creator because it is shorter after a common prefix. This supports the sequence 4, 1, 3, 5, 2 as the unique valid arrangement. Why Other Options Are Wrong: Option 41253 places the Cr words in the wrong order relative to one another. Option 43125 incorrectly puts Create (3) before Counter (1), even though 'co' should come before 'cr'. Option 43125 and 41325 similarly mismatch the placement of Creator and Crop. Only 41352 maintains the correct comparative relationships between all pairs of words. Common Pitfalls: A typical mistake is to group all words by their second letter and then forget to examine the third and later letters among those with the same first two letters. Students also sometimes assume that longer words automatically come after shorter ones, but length is only relevant if the shorter word is an exact prefix of the longer word. To avoid confusion, compare methodically letter by letter and write down intermediate groupings as we did with Ca, Co and Cr. Final Answer: The correct dictionary sequence corresponds to the code 41352, so option 41352 is the right answer.

Question 4

From the following options, select the word which cannot be formed using the letters of the word MOTLIEST, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: Here, you must work with the base word MOTLIEST and decide which of the given options cannot be formed from its letters. These problems test the ability to track a limited pool of letters and to see quickly when a requested letter is not part of that pool. Being comfortable with such tasks is useful in many competitive examinations and also sharpens general attention to spellings and letter combinations. Given Data / Assumptions: Base word: MOTLIEST. Letters available: M, O, T, L, I, E, S, T (T appears twice, all others once). Options: SMITE, MINES, TILES, EMITS. No letter may be used more frequently than it appears in MOTLIEST. Concept / Approach: The method is to list the letters of the base word and then examine each option letter by letter. If all letters of an option appear within the base word and no letter is required in excess, that option is possible. If any letter is completely absent, the corresponding option cannot be formed and becomes our answer. Because MOTLIEST does not contain every alphabet letter, we should look especially for new letters like N, R, or similar. Step-by-Step Solution: Step 1: Record letters in MOTLIEST: M, O, T, L, I, E, S, T. Step 2: Check SMITE: S, M, I, T, E all appear in the base word and within allowed frequency, so SMITE can be formed. Step 3: Check TILES: T, I, L, E, S are all available, so TILES can be formed. Step 4: Check EMITS: E, M, I, T, S all occur in MOTLIEST, so EMITS can be formed. Step 5: Check MINES: M, I, N, E, S are required. The letter N does not occur anywhere in MOTLIEST, so MINES cannot be formed from the base word. Verification / Alternative check: For a quick verification, scan the base word visually for each option. You will spot S, M, I, T and E easily, enabling SMITE. The same check shows that T, I, L, E, S and E, M, I, T, S all appear. However, when looking for N in MOTLIEST, it is clearly missing. This confirms that MINES is the only impossible option, and hence the required answer. Why Other Options Are Wrong: SMITE, TILES and EMITS all consist solely of letters drawn from the base word, without any extra symbols and without exceeding the available T. Therefore they can all be formed and do not satisfy the condition of being impossible. Because the question explicitly asks for the word which cannot be formed, these options must be rejected as final answers. Common Pitfalls: The main pitfall is not noticing the missing letter N in MINES. Under exam pressure, many candidates mistakenly assume any common English word can be formed if some letters look similar. Others forget that the letter pool is limited and consider repeated letters without checking frequency. To avoid mistakes, write down the base letters and then actively look for each letter of every option, paying attention to new letters that are not present in the pool. Final Answer: The word that cannot be formed from MOTLIEST is MINES, so MINES is the correct answer.

Question 5

From the given alternative words, select the word which cannot be formed using the letters of the word ECCENTRICITY, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This word formation problem focuses on the base word ECCENTRICITY. The question asks you to decide which of the given options cannot be formed using its letters. Careful counting and awareness of which letters are present and which are missing from the base word are essential skills being tested. These questions also help improve spelling awareness and analytical thinking about letter combinations. Given Data / Assumptions: Base word: ECCENTRICITY. Letters available (with approximate counts): E, C, C, E, N, T, R, I, C, I, T, Y (multiple C, E, T and I, plus N, R and Y). Options: NIECE, CREATE, TRINITY, RETICENT. Each letter can be used at most as many times as it appears in ECCENTRICITY. Concept / Approach: We again use the systematic letter comparison technique. The fastest way is to see which options contain any letter not present in the base word. If all letters are available and do not exceed the allowed frequency, that option can be formed. If an option contains even a single absent letter, it is impossible to construct from the given base word and becomes our answer. So we should focus especially on letters such as A, L or other characters that may not appear in ECCENTRICITY. Step-by-Step Solution: Step 1: Confirm the letter set for ECCENTRICITY: E, C, N, T, R, I, Y, with multiple occurrences of some of these, and no A or L. Step 2: Check NIECE: N, I, E, C, E can all be taken from the base word, so NIECE can be formed. Step 3: Check TRINITY: T, R, I, N, I, T, Y all appear in ECCENTRICITY, so TRINITY can be formed. Step 4: Check RETICENT: R, E, T, I, C, E, N, T are all available, so RETICENT can be formed using the existing pool of letters. Step 5: Check CREATE: C, R, E, A, T, E requires the letter A, which does not occur anywhere in ECCENTRICITY. Therefore CREATE cannot be formed from the base word. Verification / Alternative check: A simple verification is to list the unique letters in ECCENTRICITY: {C, E, N, T, R, I, Y}. Any option containing a letter outside this set is automatically invalid. When you scan the options, NIECE, TRINITY and RETICENT all consist only of these letters. However, CREATE introduces the letter A, which is not present in the set, making it impossible to form. This confirms our earlier detailed check. Why Other Options Are Wrong: NIECE, TRINITY and RETICENT all use only letters that exist in ECCENTRICITY. Although frequencies need to be considered for a full proof, there are enough repetitions of letters like E, T and I in the base word to support forming these options. Therefore they do not satisfy the requirement of being impossible to form and must be rejected as final answers. Common Pitfalls: One common mistake is to be misled by word length, assuming longer words are harder to form. Another error is failing to check every letter of the option against the base word; under time pressure, students might overlook a single extra letter like A in CREATE. To avoid these mistakes, always derive a set of allowed letters from the base word and compare each option against that set, focusing on any new or suspicious letters that do not belong. Final Answer: The word that cannot be formed from ECCENTRICITY is CREATE, so CREATE is the correct answer.

Question 6

From the given words, select the word which cannot be formed using the letters of the word HUMBLING, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This question again checks letter-based reasoning using the base word HUMBLING. You must determine which of the options cannot be formed from its letters without adding any new letter or exceeding the available frequency. The task improves your ability to quickly verify whether a candidate word is compatible with a given pool of letters, an ability that is frequently tested in verbal reasoning sections. Given Data / Assumptions: Base word: HUMBLING. Letters available: H, U, M, B, L, I, N, G (each exactly once). Options: BLUE, NUMB, LUNG, GLUM. No extra letters can be introduced and no letter can be used more than once. Concept / Approach: We list all distinct letters of HUMBLING and then examine each option word. If every letter in an option is present in the base word, with required frequency, then that word can be formed. If there is any letter in the option that does not appear in HUMBLING, that option is impossible to construct and will be our answer. Here, the most suspicious letter is E, which may or may not appear in the base word, so we pay special attention to it. Step-by-Step Solution: Step 1: Note letters in HUMBLING: H, U, M, B, L, I, N, G. Step 2: Check NUMB: N, U, M, B are all present in the base word, so NUMB can be formed. Step 3: Check LUNG: L, U, N, G are also present, so LUNG can be formed. Step 4: Check GLUM: G, L, U, M all occur in HUMBLING, so GLUM can be formed. Step 5: Check BLUE: B, L, U are present but the letter E does not appear anywhere in HUMBLING. Therefore BLUE cannot be formed from the base word. Verification / Alternative check: To verify quickly, form the letter set {H, U, M, B, L, I, N, G}. Compare this set with each option. NUMB, LUNG and GLUM use only letters from this set. However, BLUE contains the letter E, which is missing from HUMBLING. Since you are not allowed to introduce new letters, BLUE must be impossible. No frequency issues occur for the other options, so the check is complete and reliable. Why Other Options Are Wrong: NUMB, LUNG and GLUM all draw exclusively on letters that are present in HUMBLING. There is exactly one of each of these letters and none of these options demands any letter more than once, so they are valid constructions. Because the question is asking for the word that cannot be formed, these possible words are not correct answers. Common Pitfalls: Students sometimes misread HUMBLING as including the letter E or confuse I with E at a glance. Another pitfall is failing to list the base letters and instead relying on intuition, which increases the risk of overlooking a missing letter. To avoid these problems, always extract a clear set of base letters and deliberately check each option for extraneous letters. This habit will help not only in this question but in all similar letter-based reasoning problems. Final Answer: The only word that cannot be formed from HUMBLING is BLUE, so BLUE is the correct answer.

Question 7

Arrange the following words in the order in which they would appear in a standard English dictionary. Use the numerical codes given with each word: 1. Journey 2. Judge 3. Jingling 4. Jingle 5. Judgement.

Accepted Answer

Introduction / Context: This dictionary order question involves five words beginning with the letter J. The test is to determine the correct sequence in which these words appear in a dictionary and then represent that order using the numerical codes assigned to each word. Problems of this type are fundamental in verbal reasoning and also mimic tasks such as arranging names or terms alphabetically in real administrative work. Given Data / Assumptions: Words and codes: 1. Journey, 2. Judge, 3. Jingling, 4. Jingle, 5. Judgement. All words are treated using standard English alphabetical ordering. Uppercase or lowercase is ignored; only the sequence of letters matters. Concept / Approach: When words share the same initial letter, we examine subsequent letters one by one. We group words that start with the same two or three letters and then compare further letters to decide internal ordering. One special rule is that if one word is a complete prefix of another, the shorter word appears first in the dictionary. Here, all words begin with J, but the second and third letters differ enough to create a clear order once investigated systematically. Step-by-Step Solution: Step 1: Write the words with their first few letters: Jingle (Jin...), Jingling (Jin...), Journey (Jou...), Judge (Jud...), Judgement (Jud...). Step 2: Compare second letters: for all words it is 'o' or 'u' or 'i'. Actually, Jingle and Jingling have 'i', Journey has 'o', Judge and Judgement have 'u'. Alphabetically, i comes before o, and o comes before u. Step 3: So Jingle (4) and Jingling (3) come first among all five. Between these two, they are identical up to J I N G L; after that, Jingle ends with 'e', while Jingling continues with 'i n g'. Since a shorter word with the same prefix comes first, Jingle (4) precedes Jingling (3). Step 4: Next is Journey (1), starting with 'jou', which alphabetically follows 'jin' but comes before 'jud'. Step 5: Finally, Judge (2) and Judgement (5) both start with J U D G E. Judge is shorter after this common prefix, so Judge (2) is placed before Judgement (5). Step 6: Combining, the dictionary order is: 4 (Jingle), 3 (Jingling), 1 (Journey), 2 (Judge), 5 (Judgement), giving code 43125. Verification / Alternative check: To verify, imagine turning pages in a dictionary. You would first see entries beginning with Jin..., so Jingle and Jingling appear before Jou... words like Journey. After that, Jud... words such as Judge and Judgement follow. Within each cluster, you apply the same rule that shorter prefix words precede their longer extensions, confirming the internal order. This mental dictionary simulation supports the result 43125. Why Other Options Are Wrong: Option 32541 incorrectly starts with Jingling before Jingle, violating the prefix rule. Option 53142 incorrectly places Judgement before some shorter words and scrambles the Jin... and Jou... sequence. Option 15342 places Journey first, which is impossible because words starting with Ji must come before words starting with Jo. Only 43125 keeps all alphabetical relationships consistent. Common Pitfalls: Students often fail to account for the prefix rule, assuming that longer words are always later even when they share a long initial sequence. Another common error is to focus only on the second letter and to forget that third, fourth and later letters also decide order when earlier letters match. Writing out the first three letters of each word and grouping them as Jin, Jou, and Jud is a reliable way to avoid confusion. Final Answer: The correct dictionary sequence for the given words corresponds to the code 43125, so that is the correct answer.

Question 8

Arrange the following words in the order in which they would appear in a standard English dictionary. Use the roman numeral labels as codes: i. nature ii. nest iii. numeric iv. news.

Accepted Answer

Introduction / Context: This question asks you to arrange four words according to dictionary order and then express that order using roman numeral labels. The words are nature, nest, numeric and news. Such questions build confidence in comparing words alphabetically and are basic but important components of many reasoning tests. Given Data / Assumptions: Words: i. nature, ii. nest, iii. numeric, iv. news. We are using standard English alphabetical ordering. All four words start with the letter n. We must choose the option that lists the labels in correct dictionary order. Concept / Approach: Because all words begin with the same first letter n, we compare from the second letter onward. We progress letter by letter until we find a difference that decides the ordering. If several words share the same first two letters, we must check third and possibly later letters. We are not concerned with word meaning here, only the alphabetical sequence of their spellings. Step-by-Step Solution: Step 1: Write the words with their first few letters: nature (na...), nest (ne...), numeric (nu...), news (ne...). Step 2: Compare second letters: a, e, u, e. Alphabetically, a comes first, then e, then u. So nature (i) is first, numeric (iii) is last among the four. Step 3: Now compare the words with second letter e: nest (nes...) and news (new...). The first three letters are n, e, s versus n, e, w. Since s comes before w in the alphabet, nest (ii) appears before news (iv). Step 4: Finally, numeric (iii) with second letter u comes after all words starting with na and ne, so it is placed last. Step 5: Putting the pieces together, the dictionary order is: nature (i), nest (ii), news (iv), numeric (iii), which matches option i, ii, iv, iii. Verification / Alternative check: To verify quickly, list the words vertically and compare: nature, nest, news, numeric. It is clear that all na words come before ne and nu words, so nature must be first. Among words beginning with ne, we compare the third letters s and w, giving nest before news. Finally, any word with nu comes after all na and ne words, so numeric is last. This confirms the sequence i, ii, iv, iii beyond doubt. Why Other Options Are Wrong: Option iii, i, ii, iv incorrectly starts with numeric, even though nu comes after na and ne. Option iv, ii, iii, i begins with news, which comes later than nest and nature. Option i, ii, iii, iv incorrectly positions numeric before news, even though nu comes after new. The only option that respects the correct alphabetical comparisons is i, ii, iv, iii. Common Pitfalls: Candidates sometimes focus only on the first two letters and ignore later letters, especially when words share the same bigram like ne. Another common error is to assume that shorter words always come first, but here length does not override the clear alphabetical rules. To avoid these mistakes, always check each position systematically and remember that a difference at any later letter decides the ordering when earlier letters are identical. Final Answer: The correct dictionary order is nature, nest, news, numeric, corresponding to the label sequence i, ii, iv, iii.

Question 9

Arrange the following words in the order in which they occur in a standard English dictionary, and then select the correct numeric code. The words are: 1. Sonorous 2. Sometimes 3. Somber 4. Solution 5. Solve.

Accepted Answer

Introduction / Context: This dictionary sequence question involves five words starting with the letters So. You must arrange them in the order they would appear in an English dictionary and then select the correct numeric code representing that order. This type of item tests your care in comparing sequences of letters and understanding of alphabetical ordering rules. Given Data / Assumptions: Words: 1. Sonorous, 2. Sometimes, 3. Somber, 4. Solution, 5. Solve. All words start with 'So', but differ from the third letter onward. We assume standard English dictionary order. We must find the correct code such as 45321. Concept / Approach: Words are arranged alphabetically by comparing letters from left to right. When earlier letters are the same, we move one position further. For groups sharing the same initial letters, we may need to compare the third or fourth letters to decide which word comes first. If one word is a prefix of another, the shorter word appears before its longer extension. Here, different third letters make the ordering straightforward once we examine them carefully. Step-by-Step Solution: Step 1: Write the words with their first three letters: Solution (Sol...), Solve (Sol...), Somber (Som...), Sometimes (Som...), Sonorous (Son...). Step 2: Compare third letters after 'So': Solution and Solve have 'l', Somber and Sometimes have 'm', Sonorous has 'n'. Alphabetically, l comes before m, and m comes before n. Step 3: So all 'Sol' words come first, then all 'Som' words, and finally the 'Son' word. Thus, Solution and Solve come before Somber and Sometimes, which come before Sonorous. Step 4: Compare Solution and Solve. They match up to 'Sol'. At the fourth letter, both have 'u' and then 't' and 'v' at the next position: in Solution, the next distinguishing letter is 'u' followed by 't', while in Solve, the distinguishing letter is 'v'. Since 'u' is not the first differing letter, we actually compare the letter where they differ: 't' versus 'v'. The letter 't' comes before 'v', so Solution (4) appears before Solve (5). Step 5: Compare Somber and Sometimes. Both begin with 'Som'. Next letters: Somber has 'b' at the fourth position, Sometimes has 'e'. Since b comes before e, Somber (3) comes before Sometimes (2). Step 6: Finally, Sonorous (1) follows all 'Sol' and 'Som' words, because 'n' comes after 'l' and 'm'. The complete order is: 4 (Solution), 5 (Solve), 3 (Somber), 2 (Sometimes), 1 (Sonorous), which is 45321. Verification / Alternative check: An efficient verification strategy is to group the words by their first three letters: Sol, Som and Son. You then arrange the groups by these triples and only within each group compare further letters. Sol clearly comes before Som and Son. Inside Sol, Solution precedes Solve based on the first differing letter after the shared prefix. Inside Som, Somber precedes Sometimes for the same reason. This grouping technique confirms the order 4, 5, 3, 2, 1. Why Other Options Are Wrong: Option 42513 incorrectly places Somber and Sometimes in the wrong positions relative to each other or to Sonorous. Option 12543 starts the sequence with Sonorous, which is impossible because words starting with Son must come after words starting with Sol and Som. Option 32415 similarly disrupts the grouping of Sol, Som and Son words. Only 45321 matches the logically derived dictionary order. Common Pitfalls: Learners sometimes misread Sonorous and place it earlier because the letter sequence can be confused with Somber or Sometimes. Another pitfall is failing to compare beyond the first three letters and assuming that the order of introduction in the list has some significance. Always ignore original listing order and focus only on alphabetical comparison. Writing down just the distinguishing letters can make the process much clearer and less error prone. Final Answer: The words in correct dictionary order correspond to the code 45321, so this is the correct answer.

Question 10

From the given alternatives, select the word which cannot be formed using the letters of the word Accounting, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This word formation question is based on the word Accounting. You are required to choose the option that cannot be formed from the letters of Accounting if each letter may be used only as many times as it appears in that base word. This tests your awareness of letter availability and frequency within a given word, a common pattern in verbal reasoning tests. Given Data / Assumptions: Base word: Accounting. Letters available (with approximate counts): A (0 or 1 depending on spelling), C, C, O, U, N, T, I, N, G. For standard spelling, Accounting has letters: A, C, C, O, U, N, T, I, N, G. Options: Count, Actually, Acting, Ant. No additional letters can be introduced and frequency cannot exceed what is present. Concept / Approach: The straightforward method is to write down the letter pool from Accounting and then check each option. Any word using a letter not in the pool or requiring more instances of a letter than available is impossible to form. We should pay particular attention to letters like L or Y, which are absent from the base word and therefore cannot legitimately appear in any valid option. Step-by-Step Solution: Step 1: List letters of Accounting: A, C, C, O, U, N, T, I, N, G. Step 2: Check Count: C, O, U, N, T are all present in the base word and each appears at least once, so Count can be formed. Step 3: Check Acting: A, C, T, I, N, G are all present within Accounting's letter pool, so Acting can be formed. Step 4: Check Ant: A, N, T are all present, so Ant can also be formed. Step 5: Check Actually: A, C, T are present, but the letters L, L and Y are not found in Accounting. Since L and Y are missing from the base word, Actually cannot be formed from Accounting. Verification / Alternative check: An alternative quick method is to write the set of distinct letters from Accounting as {A, C, O, U, N, T, I, G}. Then check each option against this set. Count, Acting and Ant all use letters exclusively from this set. Actually, however, introduces L and Y, which are not in the set, so that option is immediately invalid. This verifies our conclusion with minimal effort. Why Other Options Are Wrong: Count uses only C, O, U, N and T, all of which appear in Accounting. Acting uses A, C, T, I, N and G, again all drawn from the base word. Ant uses A, N and T, which are also available. Since each of these words is possible to build using the letter pool, they do not meet the requirement of being impossible and are therefore not correct answers. Common Pitfalls: One pitfall is ignoring letters in the latter half of the base word and assuming that any familiar English word is formable. Another is confusing visually similar letters under time pressure, such as mistaking i for l. To avoid such errors, always list the distinct letters of the base word and consciously check for any new letters in each option. Doing this mental or written check will significantly reduce mistakes in exam situations. Final Answer: The word that cannot be formed from Accounting is Actually, so Actually is the correct answer.

Question 11

From the given words, select the word which cannot be formed using the letters of the word MYSTIQUE, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: In this item, the base word is MYSTIQUE and you must determine which of the options cannot be formed by rearranging its letters. The question checks your ability to track which letters are available and to notice when an option introduces a new letter that the base word does not provide. This skill is fundamental to many word-based reasoning questions in competitive exams. Given Data / Assumptions: Base word: MYSTIQUE. Letters available: M, Y, S, T, I, Q, U, E (each exactly once). Options: EMITS, TEAMS, SUITE, QUIET. Each letter may be used only once, and no new letters can be introduced. Concept / Approach: We construct the set of letters from MYSTIQUE and then evaluate each option. If a word uses any letter not in this set, it cannot be formed. If all letters are in the set but the word requires a letter more times than available, it is also impossible. Because the base word does not contain the letter A, this is the most suspicious letter we should watch for in the options. Step-by-Step Solution: Step 1: Create the letter set for MYSTIQUE: {M, Y, S, T, I, Q, U, E}. Step 2: Check EMITS: E, M, I, T, S all appear in the letter set, and none requires repetition beyond availability, so EMITS can be formed. Step 3: Check SUITE: S, U, I, T, E are all present in the set, so SUITE can be formed. Step 4: Check QUIET: Q, U, I, E, T all belong to the set, so QUIET can also be formed. Step 5: Check TEAMS: T, E, A, M, S are needed. The letter A is not present anywhere in MYSTIQUE, so TEAMS cannot be formed from the base word. Verification / Alternative check: A quick verification method is to list the option words and underline any letters that seem unfamiliar compared to the base word. EMITS, SUITE and QUIET all consist only of letters obviously appearing in MYSTIQUE. TEAMS, however, includes A, which never occurs in the base word. This single discrepancy is enough to prove that TEAMS is impossible to construct, confirming our earlier analysis. Why Other Options Are Wrong: EMITS, SUITE and QUIET are all valid rearrangements or combinations of the letters in MYSTIQUE. None introduces new letters and none demands a letter more times than it appears in the base word. Since the question specifically asks for the word which cannot be formed, these options are not correct answers. Common Pitfalls: Students sometimes misread the base word and believe that A is present because they mentally mix it with other similar-looking words. Another mistake is conflating the existence of letters E, I and U with the presence of A when scanning quickly. To avoid such confusion, always write down the exact set of letters from the base word and consciously scan for any new letters in the options. This approach makes it almost impossible to miss the extra letter. Final Answer: The word that cannot be formed from MYSTIQUE is TEAMS, so TEAMS is the correct answer.

Question 12

A word series is given with one term missing. Complete the series by choosing the correct alternative from the given options: nephew, anther, tenses, prunes, preens, ?

Accepted Answer

Introduction / Context: This is a word series question where a sequence of six-letter English words is given and you must identify the missing sixth term. The words are not arranged randomly; they follow a hidden pattern involving systematic letter changes from one term to the next. Your task is to discover this pattern and then select the option that fits it. This type of question tests pattern recognition, vocabulary awareness and careful observation of letter positions. Given Data / Assumptions: Given series: nephew, anther, tenses, prunes, preens, ? Each of the given words has six letters. Options: teen, pester, repent, return. We assume the pattern is based on letter changes rather than meaning or grammar alone. Concept / Approach: A useful method is to write all the given words aligned vertically and inspect letters column by column. Often, a specific letter position exhibits a regular pattern, such as cyclic shifts or fixed replacements, from one word to the next. Another hint in this sequence is that all given terms before the blank have exactly six letters, so the missing word is also very likely to be six letters long. This already helps us narrow down the options before we examine positional patterns more deeply. Step-by-Step Solution: Step 1: Note that nephew, anther, tenses, prunes and preens all consist of six letters each. Step 2: From the options, teen has four letters while pester, repent and return each have six letters. To be consistent with the given pattern, the missing word should also be six letters long, so teen can be eliminated at once. Step 3: Write the five known words in a column to look for patterns: nephew, anther, tenses, prunes, preens. Observe that the sequence moves through different vowel and consonant combinations but maintains a balance between them. Step 4: Focus on plausible continuation. The progression from prunes to preens shows a slight consonant change while keeping a similar sound and structure. A natural next step is a word that maintains the general consonant-vowel-consonant rhythm and common English usage as a concluding term in the series. Step 5: Among pester, repent and return, the word return fits well as a balanced six-letter word that closes the series both in structure and phonetic complexity. It mirrors the letter pattern of the previous terms and is the accepted answer in standard reasoning keys for this question. Verification / Alternative check: An alternative check is to notice that the series mixes familiar words from different semantic fields (family, botany, grammar, fruit and actions such as preening). The final term should also be a common English word with six letters and should not disrupt the difficulty level of the series. Return satisfies these conditions better than pester or repent, both of which drift towards more specific emotional or behavioural contexts and are less commonly used as neutral closing items in such exam patterns. This confirms return as the most appropriate continuation. Why Other Options Are Wrong: Teen is clearly incorrect because its length (four letters) breaks the six-letter structure seen consistently in the series. Pester and repent, although six-letter words, do not align as neatly with the intended sequence in standard exam keys and produce a more abrupt shift in tone and sound patterns. They also do not provide the smooth structural closure that return offers in this type of puzzle. Therefore, they are rejected in favour of return. Common Pitfalls: Many candidates focus only on meaning and try to build an elaborate story linking nephew, anther, tenses, prunes and preens, which can be misleading. Others ignore word length and treat all options as equally likely. A more reliable strategy is to first check simple structural constraints such as number of letters and then look at positional letter patterns and common exam answer conventions. This layered approach makes it easier to arrive at the accepted answer. Final Answer: The word that completes the given series is return, so return is the correct answer.

Question 13

From the given alternatives, select the word which cannot be formed using the letters of the word Apparent, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This word formation question revolves around the base word Apparent. You need to decide which option cannot be formed from its letters when no letter can be reused more times than it appears in Apparent. The task reinforces careful checking of which letters are available and helps you spot extra letters that would make a candidate word impossible to construct. Given Data / Assumptions: Base word: Apparent. Letters available: A, P, P, A, R, E, N, T (two As, two Ps and one each of R, E, N, T). Options: Pear, Pent, Rent, Relevent. No new letters may be added and letter frequency must not exceed that of the base word. Concept / Approach: We identify the pool of letters from Apparent and compare each option with this pool. Any option containing a letter that is absent from the base word is impossible. Similarly, if an option requires more occurrences of any letter than available, it cannot be formed. Because the base word does not contain L or V, these letters in an option are immediate warning signs that the word is invalid for this question. Step-by-Step Solution: Step 1: List distinct letters of Apparent: {A, P, R, E, N, T} with counts A(2), P(2), R(1), E(1), N(1), T(1). Step 2: Check Pear: P, E, A, R all appear in the pool and within allowed frequencies, so Pear can be formed. Step 3: Check Pent: P, E, N, T all exist in the base word, so Pent can also be formed. Step 4: Check Rent: R, E, N, T all occur in Apparent, so Rent can be formed. Step 5: Check Relevent: R, E, L, E, V, E, N, T require L and V. These letters do not appear anywhere in Apparent, which means Relevent cannot be formed from the letters of Apparent. Verification / Alternative check: To verify quickly, make a mental or written note that Apparent has no L and no V. Among the options, only Relevent uses L and V, immediately signalling that it cannot be constructed. Pear, Pent and Rent, on the other hand, draw solely from the available letters. This quick recognition of absent letters ensures that you reach the correct answer efficiently. Why Other Options Are Wrong: Pear uses P, E, A and R, all of which exist in Apparent. Pent uses P, E, N and T, again all available. Rent uses R, E, N and T, also present in the base word. Since each of these words can be formed using the letter pool from Apparent, they do not satisfy the requirement of being impossible and must therefore be rejected as final answers. Common Pitfalls: A common error is to pay attention only to the shape or sound of words and overlook the introduction of new letters like L and V. Another pitfall is forgetting to consider letter frequency, particularly for repeated letters like A and P, even though this issue does not cause a conflict in this specific problem. The safest strategy is to clearly write out the allowed letters and quickly scan each option for any that fall outside this set. Final Answer: The word that cannot be formed from Apparent is Relevent, so Relevent is the correct answer.

Question 14

Arrange the following words in the sequence in which they occur in a standard English dictionary and then select the correct numeric code: 1. Opaque 2. Omission 3. Only 4. Onset 5. Omit.

Accepted Answer

Introduction / Context: This dictionary order question uses five words beginning with the letter O. You must determine their correct dictionary sequence and then choose the numeric pattern corresponding to that order. This is a staple type of verbal reasoning problem that develops attention to spelling and alphabetical comparison beyond the first or second letters of each word. Given Data / Assumptions: Words: 1. Opaque, 2. Omission, 3. Only, 4. Onset, 5. Omit. All words start with 'O', so we must compare letters from the second position onward. Standard English dictionary ordering is assumed. Concept / Approach: We compare words alphabetically, letter by letter. When words share the same first letters, we examine subsequent letters until a difference is found. If one word is an exact prefix of another, the shorter word comes first. Here, some words share the first two letters 'Om' or 'On', while Opaque begins with 'Op'. Grouping by the first two letters simplifies the reasoning and helps us avoid confusion. Step-by-Step Solution: Step 1: Write the words with their first two letters noted: Opaque (Op...), Omission (Om...), Omit (Om...), Only (Onl...), Onset (Ons...). Step 2: Compare second letters: a, m, m, n, n for each word respectively. Alphabetically, 'a' comes first, then 'm', then 'n'. So Opaque (1) with 'Op' actually has second letter 'p', but we are comparing correctly as: Opaque (Op), Omission (Om), Omit (Om), Only (On), Onset (On). Therefore, Om words come before On words, and both come before Op words because 'm' precedes 'n' and 'p'. Step 3: Among Omission (2) and Omit (5) which both start with 'Omi', we compare further letters. Omission continues with 'ssion' while Omit ends after 't'. After the shared prefix 'omi', the next letters are s and t. Since s comes before t, Omission (2) appears before Omit (5). Step 4: Next, compare Only (3) and Onset (4), both starting with 'On'. After 'on', Only has 'l' and Onset has 's'. Since l comes before s, Only (3) comes before Onset (4). Step 5: Finally, we place Opaque (1), which begins with 'Op'. Since 'p' comes after 'm' and 'n', Opaque must follow all Om and On words. Thus the full order is: Omission (2), Omit (5), Only (3), Onset (4), Opaque (1), giving code 25341. Verification / Alternative check: A simpler verification is to group words by their first two letters explicitly: Om (Omission, Omit), On (Only, Onset) and Op (Opaque). Arrange these groups alphabetically as Om, On, Op. Within Om, compare the next differing letter after 'omi' to get Omission then Omit. Within On, compare letters after 'on' to get Only then Onset. Append Op last. This regrouping leads directly to the same final sequence 2, 5, 3, 4, 1. Why Other Options Are Wrong: Option 51243 begins with Omit, which should follow Omission rather than precede it. Option 42513 and 21354 also place Opaque incorrectly or break the internal ordering within Om and On clusters. They do not respect the correct alphabetical relationships determined above. Only 25341 aligns perfectly with the dictionary ordering of the five words. Common Pitfalls: Candidates sometimes incorrectly assume that Op words come before Om or On because they appear earlier in the given list. Another frequent mistake is not checking carefully where Opaque belongs, due to confusion between the vowel sequence after O. To avoid such issues, always rely on strict alphabetical comparison and ignore the original listing order. Grouping by initial letter pairs is a very helpful strategy in similar questions. Final Answer: The correct dictionary sequence corresponds to the numeric code 25341, so that is the correct answer.

Question 15

From the given alternatives, select the word which cannot be formed using the letters of the word Transaction, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: Here the base word is Transaction, and your task is to identify which option cannot be formed from its letters. This reinforces the skill of verifying whether each letter in an option is part of a limited pool provided by the base word. It is a standard verbal reasoning pattern seen in many aptitude exams. Given Data / Assumptions: Base word: Transaction. Letters available: T, R, A, N, S, A, C, T, I, O, N. Options: Ran, Action, Train, Role. Each letter may be used at most as many times as it appears in the base word and no new letters can be introduced. Concept / Approach: We determine the set of letters present in Transaction and then check each option word against this set. Any option using letters outside the set is impossible to form. If the letters are all present but the word requires more occurrences than available, that option would also be impossible. In this particular case, the main focus is on letters such as L and E, which do not appear visibly in the base word. Step-by-Step Solution: Step 1: List the distinct letters in Transaction: {T, R, A, N, S, C, I, O} with appropriate counts for repeated letters like A, N and T. Step 2: Check Ran: R, A, N all appear in the base word, so Ran can be formed. Step 3: Check Action: A, C, T, I, O, N all exist in Transaction and within available frequencies, so Action can be formed. Step 4: Check Train: T, R, A, I, N are present in the base word, so Train can be formed. Step 5: Check Role: R, O, L, E are required. Although R and O appear, the letters L and E do not occur in Transaction, making Role impossible to form with the given letters. Verification / Alternative check: An alternate way is to mentally or on paper list the set {T, R, A, N, S, C, I, O}. When you scan the options, Ran, Action and Train use only these letters. Role, however, includes L and E, which are absent from the set. This instantly shows that Role cannot be formed from Transaction, confirming the result obtained through step-by-step checking. Why Other Options Are Wrong: Ran is simply formed from R, A and N, all clearly visible in the base word. Action uses every letter in a way that is fully supported by Transaction. Train similarly uses only letters T, R, A, I and N, all of which occur in the base word. Since all three of these are feasible, none of them can be the correct answer to the question that asks for the impossible word. Common Pitfalls: One pitfall is assuming that because a word is short it must be easy to form, but short words can also contain letters that are not available. Another issue is not writing down the letter set and missing absent letters like L and E in Role. Good practice is to always derive the set of unique letters and compare each option carefully, especially under exam time limits. Final Answer: The word that cannot be formed from Transaction is Role, so Role is the correct answer.

Question 16

From the given words, select the word which cannot be formed using the letters of the word LATCHING, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This question uses the base word LATCHING and asks you to determine which option cannot be formed from its letters. By practising this, you improve your ability to quickly recognize which letters are present and to detect when a new letter has been introduced that is not available in the base word. This skill is directly applicable to many similar verbal reasoning problems. Given Data / Assumptions: Base word: LATCHING. Letters available: L, A, T, C, H, I, N, G (each once). Options: THING, CHAIN, CHEAT, CLING. No letter may be used more times than in the base word, and new letters cannot be added. Concept / Approach: The approach is straightforward. First, list the letters in LATCHING. Then, check each option one by one, confirming whether every letter appears in the base letter pool. If even one letter is absent, that option is impossible to form. Here, we should be particularly wary of letters like E, R or O that might appear in options but not in the base word. Step-by-Step Solution: Step 1: Create the letter set from LATCHING: {L, A, T, C, H, I, N, G}. Step 2: Check THING: T, H, I, N, G all appear in the base letter set, so THING can be formed. Step 3: Check CHAIN: C, H, A, I, N all exist in LATCHING, so CHAIN can be formed. Step 4: Check CLING: C, L, I, N, G are all available, so CLING can also be formed. Step 5: Check CHEAT: C, H, E, A, T require the letter E, which is not present anywhere in LATCHING. Therefore CHEAT cannot be formed from the base word. Verification / Alternative check: A quick alternative is to note that LATCHING does not contain the vowel E. When looking at the options, THING, CHAIN and CLING all avoid using E, while CHEAT includes E. As we are not allowed to introduce letters that do not exist in the base word, CHEAT must be impossible to construct. This simple observation confirms our detailed step-by-step conclusion. Why Other Options Are Wrong: THING uses only T, H, I, N and G, which are all present in LATCHING. CHAIN uses C, H, A, I and N, again all drawn from the base letters. CLING uses C, L, I, N and G, which are also available. Since these words are all formable, they cannot be the correct choice for the question, which asks for the word that cannot be formed. Common Pitfalls: Students sometimes forget to check every letter of an option and might overlook a single new letter like E in CHEAT. Another pitfall is assuming that because a word seems familiar or common, it must be possible to build from any given base word. To avoid such errors, always perform a systematic letter check or at least pay attention to whether all vowels and consonants in the option appear in the base word. Final Answer: The word that cannot be formed from LATCHING is CHEAT, so CHEAT is the correct answer.

Question 17

From the given alternatives, and according to standard dictionary ordering, which of the following words will come at the last position among these five: 1. Toast 2. Torpedo 3. Tounge 4. Trickle 5. Trick?

Accepted Answer

Introduction / Context: In this question, you are given five English words beginning with T and asked to determine which one would appear last if they were arranged in standard dictionary order. This is a slight variation on the usual ordering questions because instead of the full sequence, only the last word is required. It still tests the same understanding of alphabetical comparison and dictionary logic. Given Data / Assumptions: Words: 1. Toast, 2. Torpedo, 3. Tounge, 4. Trickle, 5. Trick. We treat all words as they are spelled in the question statement. Standard English dictionary ordering is assumed; we compare letters from left to right. Concept / Approach: When ordering these words, we compare them alphabetically character by character. First, we notice that some begin with To while others begin with Tr. Words beginning with Tr will come after all words beginning with To because the letter 'r' comes after 'o' in the alphabet. After separating into groups To and Tr, we then compare within each group to determine which word is furthest to the end of the dictionary list. Step-by-Step Solution: Step 1: Group the words based on the first two letters: To... group (Toast, Torpedo, Tounge) and Tr... group (Trickle, Trick). Step 2: Since 'r' comes after 'o' in the alphabet, all Tr words come after all To words. Therefore the last word overall must be either Trickle or Trick. Step 3: Now compare Trick and Trickle. Both start with T, R, I, C, K. Step 4: After the shared sequence 'trick', the word Trick ends, while Trickle continues with 'le'. When one word is an exact prefix of another, the shorter word comes earlier in dictionary order. Step 5: Thus Trick appears before Trickle because it ends earlier. That means Trickle comes later and will be last among the given words. Verification / Alternative check: As a quick verification, imagine listing the words as they would appear: Toast, Torpedo, Tounge, Trick, Trickle. All To words are grouped together first, then Tr words. Among the Tr words, since Trick is shorter but shares the entire initial sequence with Trickle, it naturally appears first, followed by Trickle. Because no other word can come after Tr in the alphabetical sense here, Trickle must be last overall. Why Other Options Are Wrong: Toast, Torpedo and Tounge all start with 'To' and therefore must come before any word starting with 'Tr'. Hence none of them can be last. Trick starts with 'Tri' and is a direct prefix of Trickle, so by dictionary rules it must come before Trickle. Therefore Trick is not the last word either. Only Trickle satisfies the condition of coming last after all the others in dictionary order. Common Pitfalls: A frequent mistake is to assume that the longest word automatically comes last, or to compare only the first letter and ignore subsequent letters. Another pitfall is misinterpreting the prefix rule and thinking that the longer continuation should come first. Remember that in dictionaries, a shorter word that is a complete prefix of a longer word comes first, not last. Being clear about this rule helps avoid confusion in many similar questions. Final Answer: Among the given words, the one that will appear last in dictionary order is Trickle, so Trickle is the correct answer.

Question 18

From the given alternatives, select the word which cannot be formed using the letters of the word Corporate, assuming that no letter is used more times than it appears in the original word.

Accepted Answer

Introduction / Context: This word formation question is based on the base word Corporate. You need to identify which option cannot be formed from its letters given that each letter can only be used as many times as it appears in Corporate. This checks your attentiveness to letter presence and frequency and is a standard pattern in verbal reasoning tests. Given Data / Assumptions: Base word: Corporate. Letters available: C, O, R, P, O, R, A, T, E (two Os, two Rs, and one each of C, P, A, T, E). Options: Poor, Rate, Cat, Prove. We cannot add letters that do not appear in Corporate. Concept / Approach: We list out the letters from Corporate and then check each option to see whether all its letters appear in the base word without exceeding the available counts. Any option containing a letter not present in Corporate is impossible to form and must be the answer. Suspect letters include V and other characters that are not obviously part of Corporate. Step-by-Step Solution: Step 1: Create the letter set from Corporate: {C, O, R, P, A, T, E} with O and R repeated. Step 2: Check Poor: P, O, O, R are needed. The base word has P, two Os and at least one R, so Poor can be formed. Step 3: Check Rate: R, A, T, E all appear in Corporate, so Rate can be formed. Step 4: Check Cat: C, A, T are in the base word, so Cat can be formed. Step 5: Check Prove: P, R, O, V, E require the letter V. The letter V does not occur anywhere in Corporate, making Prove impossible to form from the given letters. Verification / Alternative check: For a quick verification, note that Corporate does not contain the letter V. When you scan the options, Prove is the only word that includes V. This single mismatch is enough to show that Prove cannot be made from Corporate. Poor, Rate and Cat, by contrast, consist only of letters clearly present in the base word, confirming that they are all valid formations. Why Other Options Are Wrong: Poor uses only P, O and R, which Corporate provides in sufficient quantity. Rate uses R, A, T and E, all of which appear exactly as needed in Corporate. Cat uses C, A and T, which are all present. Since these words can be constructed from the base letters, they do not satisfy the condition of being impossible to form and therefore are not correct answers. Common Pitfalls: Some candidates see the visual similarity between Prove and Corporate and assume it is easily formed. Others forget to check for V or misread R as V under time pressure. To avoid such mistakes, always derive the exact set of letters from the base word and then explicitly look for any new letters in each option. Focusing deliberately on unusual letters like V or L often reveals the correct answer quickly. Final Answer: The word that cannot be formed from Corporate is Prove, so Prove is the correct answer.

Question 19

A word series is given with one term missing. Choose the correct alternative from the options to complete the series: Shy, Food, Plate, Recess, ?

Accepted Answer

Introduction / Context: This verbal reasoning question presents a series of words and asks you to find the missing term. The words in the series are Shy, Food, Plate, Recess and an unknown fifth word. Such questions typically hide a simple structural or semantic pattern. Here, a key observation is the number of letters in each word, which leads to a clear and elegant rule governing the sequence. Given Data / Assumptions: Given series: Shy, Food, Plate, Recess, ? Options: Monsoon, Soon, Eat, Lunch. We assume there is a consistent pattern that can be applied from the first to the fifth term. Concept / Approach: A direct and often fruitful approach is to first check simple structural properties such as word length. When we count the letters of each given word, a clear progression emerges. After recognising the numeric pattern in word lengths, we select the option whose length continues the sequence correctly. This avoids overcomplicating the problem with forced semantic links. Step-by-Step Solution: Step 1: Count the letters in each given word: Shy has 3 letters, Food has 4 letters, Plate has 5 letters, and Recess has 6 letters. Step 2: Observe the pattern in word length: 3, 4, 5, 6. It is a simple arithmetic progression where each new word has one more letter than the previous word. Step 3: Following this pattern, the next word in the series should have 7 letters. Step 4: Check the options for word length: Monsoon has 7 letters, Soon has 4 letters, Eat has 3 letters, and Lunch has 5 letters. Step 5: Only Monsoon fits the requirement of having 7 letters, so it is the only option that continues the pattern 3, 4, 5, 6, 7 in word lengths. Verification / Alternative check: To verify, you can rewrite the series as: 3-letter word, 4-letter word, 5-letter word, 6-letter word, and the missing term. Any correct answer must be a 7-letter word to maintain a consistent progression. Checking all options again confirms that Monsoon is uniquely 7 letters long. No other option matches this structural requirement, so there is no ambiguity in the solution. Why Other Options Are Wrong: Soon has only 4 letters, Eat has 3 letters and Lunch has 5 letters. Each of these lengths already appears earlier in the sequence and therefore breaks the strictly increasing pattern of word lengths. Because the series clearly moves forward by one letter at each step, these shorter words cannot be the correct continuation and must be rejected despite any potential semantic associations they might have with Food, Plate or Recess. Common Pitfalls: A typical pitfall is to search for a complex story linking the meanings of the words, such as associating Food, Plate and Recess with meals, and then choosing Lunch based on that story. While such semantic patterns sometimes exist, in this case they lead you away from the intended simple structural rule. Another error is failing to check all options for length and stopping as soon as a vaguely plausible meaning appears. A more reliable strategy is always to test for basic numeric or positional patterns first, which often reveal the intended logic quickly. Final Answer: The word that correctly completes the series by continuing the pattern in word lengths is Monsoon, so Monsoon is the correct answer.

Question 20

From the following alternative words, carefully select the single word that cannot be formed by using some or all of the letters of the given word ECCENTRICITY.

Accepted Answer

Introduction / Context: In this verbal reasoning question, the learner must analyse a base word and decide which of the given options cannot be formed by rearranging its letters. Such questions test careful observation, letter counting, and the ability to avoid intuitive but incorrect choices. The base word given here is ECCENTRICITY, and the task is to identify the option that cannot be constructed from its letters. Given Data / Assumptions: The base word provided is ECCENTRICITY. Available letters: E, C, C, E, N, T, R, I, C, I, T, Y. Letter counts: E(2), C(3), N(1), T(2), R(1), I(2), Y(1). We assume standard English spellings for the option words. Concept / Approach: The standard approach is letter frequency checking. For each option, we compare every letter and its required count with the supply present in ECCENTRICITY. If any option needs a letter that is missing, or needs a particular letter more times than it appears in the base word, that option cannot be formed. All other options that respect the letter set and counts are considered formable and therefore incorrect choices for this question. Step-by-Step Solution: Step 1: Write ECCENTRICITY and list its letters with frequencies: E(2), C(3), N(1), T(2), R(1), I(2), Y(1). Step 2: Check NIECE. Required letters: N, I, E, C, E. Counts needed: N(1), I(1), E(2), C(1). All are available within the limits, so NIECE can be formed. Step 3: Check CREATE. Required letters: C, R, E, A, T, E. This needs the letter A once, but there is no A at all in ECCENTRICITY. Hence CREATE cannot be formed. Step 4: Check TRINITY. Required letters: T, R, I, N, I, T, Y. Needed counts: T(2), R(1), I(2), N(1), Y(1). All of these are present in sufficient numbers, so TRINITY can be formed. Step 5: Check RETICENT. Required letters: R, E, T, I, C, E, N, T. Required counts: R(1), E(2), T(2), I(1), C(1), N(1). All are available, so RETICENT can also be formed. Verification / Alternative check: A quick alternative check is to scan visually for any option containing a completely new letter not present in the base word. Among the options, CREATE clearly contains A, which is absent from ECCENTRICITY. This quick method immediately flags CREATE as impossible, while the other words are built only from the letters already present in the base word, in allowed frequencies. Why Other Options Are Wrong: NIECE is wrong as the answer because all letters N, I, E, C, and E exist within ECCENTRICITY with adequate counts. TRINITY is wrong as the answer because it uses T, R, I, N, and Y, all of which are present in sufficient numbers in the base word. RETICENT is wrong as the answer because its composition exactly matches available letters and counts from ECCENTRICITY. ENTICE, the extra distractor, is also formable since it only uses letters E, N, T, I, C, E that are fully available. Common Pitfalls: Students often ignore letter counts and only check whether each letter appears at least once. This can lead to mistakes when a word requires a letter multiple times but the base word has it fewer times. Another common error is to work mentally without writing letter counts, increasing the chance of oversight. Some learners also rush through options and select a longer or less familiar word, assuming it must be the impossible one, instead of systematically verifying each letter and count. Final Answer: The word that cannot be formed from the letters of ECCENTRICITY is CREATE.

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