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Microbiology
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Transcription
Comments
Question
The sigma factor
Options
A. is responsible for recognizing the termination sequence
B. provides the catalytic function of cleaving off pyrophosphates during mRNA synthesis
C. recognizes the promotor
D. accomplishes DNA restriction
Correct Answer
recognizes the promotor
Transcription problems
Search Results
1. The synthesis of mRNA based on a DNA template is called
Options
A. DNA replication
B. transcription
C. translation
D. DNA restriction
Show Answer
Scratch Pad
Discuss
Correct Answer: transcription
2. What is the usual sequence of a Pribnow box?
Options
A. AUAUA
B. TATAAT
C. UUUUU
D. TTGACA
Show Answer
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Discuss
Correct Answer: TATAAT
3. Which of the following statement defines a replicon?
Options
A. A DNA molecule that encodes pili for conjugation
B. A DNA molecule that is able to replicate and be maintained
C. A DNA template which is used in transcription
D. The enzyme responsible for transposition
Show Answer
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Discuss
Correct Answer: A DNA molecule that is able to replicate and be maintained
4. A level of regulation, demonstrated by the termination of transcription if tryptophan is abundant, by the tryptophan operon in E.coli cells is called
Options
A. activation
B. attenuation
C. corepression
D. desiccation
Show Answer
Scratch Pad
Discuss
Correct Answer: attenuation
5. Which of the following is a product of transcription?
Options
A. mRNA
B. tRNA
C. rRNA
D. all of these
Show Answer
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Discuss
Correct Answer: all of these
6. A specific __________ factor helps RNA polymerase bind to late promoters and transcribe late genes.
Options
A. sigma
B. beta
C. delta
D. gamma
Show Answer
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Discuss
Correct Answer: sigma
7. Which of these catalyzes the synthesis of RNA from a DNA template?
Options
A. DNA gyrase
B. DNA ligase
C. DNA polymerase
D. RNA polymerase
Show Answer
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Discuss
Correct Answer: RNA polymerase
8. The location of first hexameric sequence typically found in pro-karyotic promoters is
Options
A. at the transcription start site
B. approximately 35 bases upstream of the transcription start site
C. approximately 10 bases upstream of the transcription start site
D. approximately 25 bases upstream of the transcription start site
Show Answer
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Correct Answer: approximately 35 bases upstream of the transcription start site
9. Thymine dimers are directly repaired with the help of visible light by process known as
Options
A. phosphorylation
B. excision repair
C. photosynthesis
D. photoreactivation
Show Answer
Scratch Pad
Discuss
Correct Answer: photoreactivation
10. A nonsense mutation may result into
Options
A. an abnormal elongation of a polypeptide
B. a large deletion within the reading frame of a gene
C. a premature termination of the synthesis of a polypeptide
D. modification of mRNA
Show Answer
Scratch Pad
Discuss
Correct Answer: a premature termination of the synthesis of a polypeptide
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Transcription
Translation and Regulation
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