Question 1

Choose the odd number: In 143, 257, 195, and 15, three are composite, while one is prime. Identify the prime number.

Accepted Answer

Introduction / Context:Prime vs composite classification: factor quickly to isolate the prime.Given Data / Assumptions:143 = 11 * 13.195 = 3 * 5 * 13.15 = 3 * 5.257 = ?Concept / Approach:Test divisibility for 257 by small primes up to sqrt(257) ≈ 16 (i.e., 2, 3, 5, 7, 11, 13).Step-by-Step Solution:257 mod 2 ≠ 0; mod 3 → 2+5+7=14 → not divisible; mod 5 → not 0 or 5; mod 7, 11, 13 → not divisible.Thus 257 has no small factors → prime.143, 195, 15 are composite by explicit factorization.Verification / Alternative check:Nearby products show no 257 = p * q with small primes; hence prime.Why Other Options Are Wrong:Each factors non-trivially (11*13, 3*5*13, 3*5).Common Pitfalls:Assuming a number near a square (16^2=256) must be composite; 257 is prime.Final Answer:257 is the odd number (prime).

Question 2

Identify the odd term: Three of the following are birds, while one is a mammal that flies. Choose the non-bird.

Accepted Answer

Introduction / Context:Biological classification questions frequently contrast classes such as birds and mammals.Given Data / Assumptions:Cuckoo, Crow, Parrot → birds (Aves).Bat → mammal (Mammalia) with powered flight.Concept / Approach:Group by taxonomic class rather than ability to fly.Step-by-Step Solution:Cuckoo → bird (lays eggs, feathers, beak).Crow → bird.Parrot → bird.Bat → mammal (fur, live young, mammary glands).Verification / Alternative check:Although both birds and bats fly, their anatomy (feathers vs skin membranes), reproduction, and classification differ.Why Other Options Are Wrong:They share the same class (Aves).Common Pitfalls:Equating “flies” with “bird.” Flight is not exclusive to birds.Final Answer:Bat is the odd term (a mammal).

Question 3

Choose the odd term: Fruit, Flower, and Leaf are plant parts; Tree is an entire plant. Identify the outlier.

Accepted Answer

Introduction / Context:Hierarchy-based grouping distinguishes components from wholes.Given Data / Assumptions:Fruit, Flower, Leaf → parts of a plant.Tree → a whole plant organism.Concept / Approach:Identify category level: part vs whole.Step-by-Step Solution:Fruit → reproductive/edible structure.Flower → reproductive organ.Leaf → photosynthetic organ.Tree → entire organism.Verification / Alternative check:Ask, “Is this a component or the complete plant?” Only Tree is the complete plant.Why Other Options Are Wrong:They are parts, not wholes.Common Pitfalls:Overlooking category level and grouping all as “botanical terms.”Final Answer:Tree is the odd term.

Question 4

Identify the odd number: Among 39, 69, 57, and 117, exactly one is a multiple of 19. Choose that number.

Accepted Answer

Introduction / Context:Targeted-divisor checks (like 19) often produce a unique outlier in a small set.Given Data / Assumptions:Candidates: 39, 69, 57, 117.We test divisibility by 19.Concept / Approach:Compare with nearby multiples: 19, 38, 57, 76, 95, 114, 133, …Step-by-Step Solution:57 = 19 * 3 → multiple of 19.39 = 3 * 13 → not a multiple of 19.69 = 3 * 23 → not a multiple of 19.117 = 9 * 13 → not a multiple of 19 (note: 19 * 6 = 114).Verification / Alternative check:Dividing each by 19: only 57/19 = 3 is an integer.Why Other Options Are Wrong:They are not multiples of 19; 117 is close (114 is 19 * 6) but not equal.Common Pitfalls:Choosing numbers near a multiple of 19 (e.g., 117) instead of exact multiples.Final Answer:57 is the only multiple of 19 and hence the odd number.

Question 5

Choose the odd term: Tree, Plant, and Shrub are categories/types of vegetation, whereas Farm is a place where plants are cultivated. Identify the outlier.

Accepted Answer

Introduction / Context:Semantic grouping can distinguish a taxonomy label from a location label.Given Data / Assumptions:Tree, Plant, Shrub → vegetation types/categories.Farm → agricultural place.Concept / Approach:Ask whether the word denotes “what it is” (a type of plant) or “where it is grown” (a place).Step-by-Step Solution:Tree → vegetation type.Plant → general vegetation term.Shrub → subcategory of woody plants.Farm → location/facility.Verification / Alternative check:Phrase test: “This is a …” fits Tree/Plant/Shrub; “This is a farm” changes to place.Why Other Options Are Wrong:They are all plant-type nouns.Common Pitfalls:Grouping “farm” with plants because of contextual association; classification is by semantic role.Final Answer:Farm is the odd term.

Question 6

Identify the odd item: Three are basic stationery tools for writing/erasing (Pencil, Eraser, Sharpener). One is an electronic computation device. Choose the outlier.

Accepted Answer

Introduction / Context:Object classification can hinge on function and technology (manual vs electronic).Given Data / Assumptions:Pencil → writing implement.Eraser → removes pencil marks.Sharpener → maintains pencil point.Calculator → electronic computation device.Concept / Approach:Group by function: three form a writing kit; one is a separate electronic tool.Step-by-Step Solution:Pencil, Eraser, Sharpener → manual stationery trio.Calculator → electronic, not directly part of the write/erase cycle.Verification / Alternative check:Ask which item requires power/electronics; only the Calculator does.Why Other Options Are Wrong:They are functionally integrated with writing by pencil.Common Pitfalls:Treating all as “school items” without considering functional grouping.Final Answer:Calculator is the odd item.

Question 7

Choose the odd number: 17, 19, and 23 are primes. One number is composite. Identify the composite number.

Accepted Answer

Introduction / Context:Prime recognition again isolates the outlier.Given Data / Assumptions:Candidates: 17, 19, 23, 27.Definition: prime vs composite.Concept / Approach:Use small-prime divisibility tests (especially 3).Step-by-Step Solution:27 → 2+7=9 → divisible by 3 → composite (3^3).17, 19, 23 → not divisible by 2,3,5 → primes.Verification / Alternative check:Direct factorization: 27 = 3 * 9 confirms compositeness.Why Other Options Are Wrong:They are prime.Common Pitfalls:Assuming all odd numbers are prime.Final Answer:27 is the odd number.

Question 8

Identify the odd pair: Three pairs express a relation of increasing intensity (mild action/state → stronger one): Flurry→Blizzard, Moisten→Drench, Prick→Stab. One pair does not represent the same intensity relation. Choose the mismatching pair.

Accepted Answer

Introduction / Context:Analogy/classification items often rely on scalar intensity: a weaker state/action relates to a stronger one.Given Data / Assumptions:Flurry → Blizzard: light snowfall vs severe snowstorm.Moisten → Drench: slight wetness vs soaking wet.Prick → Stab: minor piercing vs forceful penetration.Scrub → Polish: cleaning action vs finishing/shine, not a simple weak→strong of the same action.Concept / Approach:Check whether the right-hand term is an intensified version of the left-hand term along the same scale.Step-by-Step Solution:Flurry → Blizzard: same domain (snow), higher intensity.Moisten → Drench: same domain (wetness), higher intensity.Prick → Stab: same domain (piercing), higher intensity.Scrub → Polish: different process/result; polish implies finishing/shine, not just a stronger “scrub.”Verification / Alternative check:Replace with “more intense version of”: works for the first three, not for Scrub→Polish.Why Other Options Are Wrong:They obey a clear weak→strong scale within the same action/state.Common Pitfalls:Assuming “more cleaning” equals “polish.” Polishing is qualitatively different from scrubbing.Final Answer:Scrub : Polish is the odd pair.

Question 9

Choose the odd term: Thyroxine, Adrenaline, and Insulin are hormones; Iodine is a chemical element (nutrient), not a hormone. Identify the outlier.

Accepted Answer

Introduction / Context:Biology/chemistry classification contrasts biochemical messengers with a chemical element.Given Data / Assumptions:Thyroxine, Adrenaline, Insulin → hormones secreted by endocrine glands.Iodine → trace element required for thyroid hormone synthesis, not itself a hormone.Concept / Approach:Group by functional role in physiology: messenger hormone vs essential nutrient element.Step-by-Step Solution:Classify three as hormones with signaling roles.Classify Iodine as an element (I), necessary but not a hormone.Verification / Alternative check:Thyroxine contains iodine atoms, yet iodine is the raw element, not a secreted messenger.Why Other Options Are Wrong:They are authentic hormones.Common Pitfalls:Confusing “component of a hormone” (iodine in thyroxine) with “is a hormone.”Final Answer:Iodine is the odd term.

Question 10

Identify the odd pair: Three pairs are antonyms (Dim–Bright, Wrong–Right, Shallow–Deep). One pair consists of synonyms (same/near meaning). Choose the synonym pair.

Accepted Answer

Introduction / Context:Antonym–synonym classification checks lexical relations. Among the four, three are clear antonym pairs; one is a synonym pair.Given Data / Assumptions:Dim vs Bright → antonyms (low vs high brightness).Wrong vs Right → antonyms (incorrect vs correct).Shallow vs Deep → antonyms (less vs greater depth).Genuine vs Real → synonyms (authentic).Concept / Approach:Determine whether each pair expresses opposition or equivalence in meaning.Step-by-Step Solution:Mark three as antonym pairs.Mark one as synonym pair (Genuine ~ Real).Verification / Alternative check:Substitute in definitions or paraphrases: “genuine = real” reads naturally; the others read as opposites.Why Other Options Are Wrong:They are antonyms, not synonyms.Common Pitfalls:Over-focusing on nuanced usage; here, core dictionary senses suffice.Final Answer:Genuine : Real is the odd (synonym) pair.

Question 11

Classification – Odd one out (relationship type) Each pair shows a relation between two objects. Three pairs follow the whole–part relation (object → its component), while one pair shows an instrument → product relation. Identify the pair that does …

Accepted Answer

Introduction / Context:Odd-one-out questions on verbal analogies typically hinge on identifying the governing relation the majority of options share (e.g., whole–part, cause–effect, producer–product, tool–material) and then finding the dissenting pair. This item contrasts whole–part relations with a producer/product relation, testing your ability to name and apply relation types precisely rather than relying on surface familiarity.Given Data / Assumptions:Book : PageTable : DrawerLoom : ClothCar : WheelTask: pick the pair that is not whole–part.Concept / Approach:Label each pair’s semantic relation. Whole–part means the second noun is a constituent part of the first (pages are parts of a book; wheels are parts of a car). Producer/product (or instrument/product) means the first noun creates or yields the second (a loom produces cloth). Once the majority relation is recognized, eliminating the exception is straightforward.Step-by-Step Solution:Book : Page → whole–part (pages constitute a book).Car : Wheel → whole–part (wheels are components of a car).Table : Drawer → commonly construed as whole–part when the table in question includes drawers (a table with drawers). In analogy items, this pairing is widely accepted as a component relation similar to “desk : drawer.”Loom : Cloth → instrument/product (a loom manufactures cloth) → different relation.Verification / Alternative check:If you swap the order (part → whole), the semantics break (e.g., “wheel : car” is not whole–part in that direction). This asymmetry reaffirms that for three pairs the second term is a typical component. “Loom : Cloth” does not exhibit componenthood; its direction is maker → made, not whole → part.Why Other Options Are Wrong:Book : Page → legitimate whole–part relation.Table : Drawer → acceptable whole–part interpretation in verbal reasoning sets.Car : Wheel → canonical whole–part relation.None of these → there is a clear single outlier (Loom : Cloth).Common Pitfalls:Penalizing “Table : Drawer” because not every table has drawers. In classification items, typical or common componenthood is sufficient to establish relation type. Focus on the intended semantic class, not universality.Final Answer:Loom : Cloth

Question 12

Classification – Odd one out (synonym vs antonym) Each pair relates two words. Three pairs are antonyms or complementary opposites, whereas one pair is a clear synonym set. Identify the synonym pair as the odd one out.

Accepted Answer

Introduction / Context:Verbal classification often sets up a majority class (e.g., antonym pairs) against a single exception (e.g., a synonym pair). The skill being tested is precision: can you name the relation and check it consistently across all options? This prevents being misled by general “relatedness.”Given Data / Assumptions:Stale : FreshTruth : LieSlow : SluggishTeach : LearnConcept / Approach:Antonyms express opposition (semantic contrast). Synonyms express similarity. “Teach : Learn” are complementary roles in a process (teacher ↔ learner), which many tests still categorize under oppositional/complementary roles. The single unambiguous synonym set here is “Slow : Sluggish.”Step-by-Step Solution:Stale ↔ Fresh → antonyms.Truth ↔ Lie → antonyms.Teach ↔ Learn → complementary/contrastive roles within education (often treated as oppositional in analogy sets).Slow ↔ Sluggish → synonyms (both mean lacking speed/energy) → odd one out.Verification / Alternative check:Substitute in sentences: replacing “slow” with “sluggish” preserves meaning, unlike substituting “stale” with “fresh” or “truth” with “lie,” which reverses meaning. “Teach” and “learn” invert roles rather than preserve meaning, aligning with the majority’s contrastive spirit.Why Other Options Are Wrong:Stale : Fresh → clear antonyms.Truth : Lie → clear antonyms.Teach : Learn → contrastive roles; not synonymous.None of these → there is exactly one synonym pair.Common Pitfalls:Assuming any non-antonym pair is the outlier. Ensure it is specifically synonymous to fit the intended pattern.Final Answer:Slow : Sluggish

Question 13

Classification – Odd one out (product vs category) Three pairs show fruit/vegetable → processed product (e.g., jam, squash, puree). One pair shows item → category (hyponym → hypernym). Identify the odd relation.

Accepted Answer

Introduction / Context:Many analogy/classification questions contrast “derivative/product” relations with “taxonomic” (category) relations. Correctly naming the relation type is the key to quick, consistent answers across options that otherwise all feel related to food.Given Data / Assumptions:Apple : Jam (apple can be processed into jam)Lemon : Citrus (lemon is a member of the citrus category)Orange : Squash (orange can be processed into a squash/juice)Tomato : Puree (tomato can be processed into puree)Concept / Approach:Decide whether the second term is a processed product of the first (product relation) or a class label that subsumes the first (category relation). Three pairs are clearly “produce → processed product.” One pair is “member → class.”Step-by-Step Solution:Apple : Jam → product relation.Orange : Squash → product relation.Tomato : Puree → product relation.Lemon : Citrus → taxonomic (hyponym → hypernym) → odd one out.Verification / Alternative check:Flip each pair: “Jam : Apple,” “Squash : Orange,” “Puree : Tomato” are still meaningful as product → source, while “Citrus : Lemon” becomes class → member, not a process/product inversion. The relational asymmetry confirms the category case is different from the product cases.Why Other Options Are Wrong:Apple : Jam → processed product.Orange : Squash → processed product.Tomato : Puree → processed product.None of these → there is a single category relation (Lemon : Citrus).Common Pitfalls:Over-focusing on the food domain and missing relation types. Always identify whether the second term is a product, a place, a tool, or a class label.Final Answer:Lemon : Citrus

Question 14

Classification – Odd one out (food vs habitat) Three pairs are animal → typical food; one pair is animal → typical place (habitat/setting). Identify the pair that does not follow the food relationship.

Accepted Answer

Introduction / Context:This item juxtaposes “animal → food” against “animal → place.” Correctly separating consumption relations from locational relations is a staple in classification tasks about living things.Given Data / Assumptions:Cow : Fodder (diet)Crow : Carrion (diet)Poultry : Farm (place of rearing/habitat)Vulture : Prey (diet)Concept / Approach:Mark whether the second term is eaten by the first (food) or is a typical place associated with the first (habitat/farm). Choose the non-food relation as the outlier.Step-by-Step Solution:Cow : Fodder → food relation.Crow : Carrion → food relation.Vulture : Prey → food relation.Poultry : Farm → place/habitat relation → odd one out.Verification / Alternative check:Attempt substitution: “Poultry eats farm” is nonsensical, while “cow eats fodder,” “crow eats carrion,” and “vulture eats prey” are semantically valid. This confirms the relational mismatch.Why Other Options Are Wrong:Cow : Fodder → diet relation.Crow : Carrion → diet relation.Vulture : Prey → diet relation.None of these → a single place relation exists (Poultry : Farm).Common Pitfalls:Confusing “where” with “what.” Farms are locations for poultry but not their food.Final Answer:Poultry : Farm

Question 15

Classification – Odd one out (alphabetic jumps) Each string consists of 3 letters. In three strings, the jumps are +2 then +3 in alphabet positions; in one string, the second jump deviates. Identify the deviating string.

Accepted Answer

Introduction / Context:Letter-series classification problems encode position jumps (e.g., +2, +3). Recognizing the numeric pattern behind letter steps converts a verbal puzzle into a simple arithmetic check on alphabet indices (A=1 … Z=26).Given Data / Assumptions:HJM, OQT, BDG, VXZIndexing: A=1, B=2, …, Z=26Concept / Approach:Compute successive jumps: second − first, third − second. The intended pattern is +2 then +3 for most strings.Step-by-Step Solution:H(8)→J(10)=+2; J(10)→M(13)=+3 → fits.O(15)→Q(17)=+2; Q(17)→T(20)=+3 → fits.B(2)→D(4)=+2; D(4)→G(7)=+3 → fits.V(22)→X(24)=+2; X(24)→Z(26)=+2 → deviates (not +3).Verification / Alternative check:Any reindexing (e.g., A=0) preserves the relative difference property; the single departure persists for VXZ.Why Other Options Are Wrong:HJM, OQT, BDG → all follow +2 then +3.None of these → there is one clear deviation (VXZ).Common Pitfalls:Counting letters rather than positions (forgetting that the jump is about indices, not “letters in between”).Final Answer:VXZ

Question 16

Classification – Odd one out (constant +6 jumps) Four 3-letter strings are tested for uniform alphabet jumps. In three strings, both jumps are +6; one string breaks this pattern. Identify the odd one.

Accepted Answer

Introduction / Context:Another common letter-series pattern is a constant jump (e.g., +6, +7). The task is to verify both gaps. A single mismatch identifies the outlier.Given Data / Assumptions:GMS, EKQ, JOU, LRXIndexing: A=1 … Z=26Concept / Approach:Calculate both position differences in each string. The intended majority pattern is +6 and +6.Step-by-Step Solution:G(7)→M(13)=+6; M(13)→S(19)=+6 → fits.E(5)→K(11)=+6; K(11)→Q(17)=+6 → fits.L(12)→R(18)=+6; R(18)→X(24)=+6 → fits.J(10)→O(15)=+5; O(15)→U(21)=+6 → breaks first gap.Verification / Alternative check:Cyclic wrap (beyond Z) is not needed here; all letters are within range. The single non-conforming first gap confirms the outlier.Why Other Options Are Wrong:GMS, EKQ, LRX → both jumps +6.None of these → one clear mismatch (JOU).Common Pitfalls:Miscounting positions or treating letters as 0-indexed in one place and 1-indexed in another.Final Answer:JOU

Question 17

Classification – Odd one out (letter–letter with numeric mean) In these alphanumeric items, the number equals the average (arithmetic mean) of the alphabet positions of the two letters. Three items follow this rule; one does not. Identify the except…

Accepted Answer

Introduction / Context:Alphanumeric classifications often tie letters to numbers via a consistent arithmetic (sum, difference, mean). Here, the embedded rule is the mean of positions (A=1 … Z=26). Spotting the arithmetic relation cleanly exposes the single misfit.Given Data / Assumptions:KQ14, AY13, MR11, GW15Indexing: A=1, …, Z=26; mean = (pos(L1)+pos(L2))/2Concept / Approach:Compute the mean for each letter pair and compare with the trailing number. The outlier fails to match.Step-by-Step Solution:K(11), Q(17) → mean = (11+17)/2 = 14 → matches 14.A(1), Y(25) → mean = (1+25)/2 = 13 → matches 13.G(7), W(23) → mean = (7+23)/2 = 15 → matches 15.M(13), R(18) → mean = (13+18)/2 = 15.5 → does not match 11 → exception.Verification / Alternative check:The three conforming items also show symmetric spacing around their mean letter (e.g., K and Q around N). MR cannot map to an integer mean, reinforcing the mismatch.Why Other Options Are Wrong:KQ14, AY13, GW15 → satisfy the mean rule exactly.None of these → there is a single mismatch (MR11).Common Pitfalls:Mistaking the rule for “difference” or “sum” instead of “mean,” which would not uniquely isolate the same item.Final Answer:MR11

Question 18

Classification – Odd one out (paired vs unpaired body parts) Among these body parts, three normally occur as paired organs in humans; one is not typically paired. Identify the odd one out.

Accepted Answer

Introduction / Context:Human-body classification items often leverage anatomical pairing. Many organs/limbs occur in left/right pairs, while others are singular or not thought of as strictly “one per side.” Recognizing this biological regularity guides the choice.Given Data / Assumptions:Eyes (paired), Ears (paired), Hands (paired)Intestines (not typically described as a single paired organ; rather a system of small and large intestines)Concept / Approach:Check whether the noun denotes a standard lateral pair in humans (left and right counterpart). Reject items that are not lateral pairs.Step-by-Step Solution:Eyes → left/right pair.Ears → left/right pair.Hands → left/right pair.Intestines → digestive organs, not a left/right pair → odd one out.Verification / Alternative check:Substitute with “one of the two …”: works for eyes/ears/hands but not for intestines. The linguistic check mirrors the anatomical fact.Why Other Options Are Wrong:Eyes → paired.Ears → paired.Hands → paired.None of these → there is one clear non-paired item (Intestines).Common Pitfalls:Confusing “lungs” (paired) with “intestines” (a tract composed of parts). The test targets lateral pairing, not organ multiplicity.Final Answer:Intestines

Question 19

Classification – Odd one out (tool → object of action) Three pairs name a tool and the typical object it acts upon. One pair names two similar stationary items rather than a tool–target relation. Identify the odd pair.

Accepted Answer

Introduction / Context:Tool–target relations are common: the first item is used to act on/with the second (shovel→mud, screwdriver→screw, hammer→nail). A distractor may pair two peer items without an action relation. Spotting the presence or absence of directed action is decisive.Given Data / Assumptions:Shovel : MudScrewdriver : ScrewHammer : NailPen : PencilConcept / Approach:Ask: “Is the second noun the usual object the first acts on?” Three are yes. One is simply two writing instruments, not instrument→target.Step-by-Step Solution:Shovel moves/handles mud → tool→material.Screwdriver drives/removes a screw → tool→object.Hammer drives a nail → tool→object.Pen and pencil are co-category writing tools → not tool→target → odd one out.Verification / Alternative check:Swap order: “nail : hammer,” “screw : screwdriver,” “mud : shovel” remain meaningful as target→tool. “pencil : pen” gives peer→peer, not actional symmetry, confirming the mismatch.Why Other Options Are Wrong:Shovel : Mud → action relation present.Screwdriver : Screw → action relation present.Hammer : Nail → action relation present.None of these → only one lacks the relation (Pen : Pencil).Common Pitfalls:Accepting “pen : pencil” due to domain similarity. Classification demands relation uniformity, not mere topical similarity.Final Answer:Pen : Pencil

Question 20

Classification – Odd one out (letter sequences with growing gaps) Four 5-letter sequences are examined. Three progress with increasing step sizes +2, +3, +4, +5. One sequence breaks this growth pattern. Identify the odd sequence.

Accepted Answer

Introduction / Context:Letter chains often encode steadily increasing gaps. Validating each inter-letter difference exposes any sequence that fails the pattern.Given Data / Assumptions:DFIMR, CEHLQ, GILPU, HJMPTIndexing: A=1 … Z=26Concept / Approach:Compute successive differences. The majority pattern is +2, +3, +4, +5 across the 5 letters.Step-by-Step Solution:D(4)→F(6)=+2; F→I(9)=+3; I→M(13)=+4; M→R(18)=+5 → fits.C(3)→E(5)=+2; E→H(8)=+3; H→L(12)=+4; L→Q(17)=+5 → fits.G(7)→I(9)=+2; I→L(12)=+3; L→P(16)=+4; P→U(21)=+5 → fits.H(8)→J(10)=+2; J→M(13)=+3; M→P(16)=+3; P→T(20)=+4 → breaks the +4 then +5 ending.Verification / Alternative check:No wrap-around is involved; a simple table of gaps suffices to isolate the outlier.Why Other Options Are Wrong:DFIMR, CEHLQ, GILPU → clean +2,+3,+4,+5.None of these → a single mismatch exists (HJMPT).Common Pitfalls:Miscounting the third step in HJMPT (+3 instead of the required +4).Final Answer:HJMPT

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