Question 1

Classification – Odd one out (vowels vs consonant): Which letter does not belong with the others: A, E, I, Z?

Accepted Answer

Introduction / Context: A quick alphabet classification: three entries are vowels in English; one is a consonant. Identify the consonant among the vowels. Given Data / Assumptions: A — vowel. E — vowel. I — vowel. Z — consonant. Concept / Approach: Apply the standard English vowel set {A, E, I, O, U}. Any letter outside this set is a consonant. Among the given letters, Z alone is a consonant; the rest are vowels. Therefore, Z is the odd one out. Step-by-Step Solution: 1) Compare each letter to the vowel set.2) Mark A/E/I → vowels; Z → consonant.3) Select Z as the single consonant. Verification / Alternative check: Pronunciation check confirms Z produces a consonantal sound, unlike the vowel phonemes for A/E/I. Why Other Options Are Wrong: They are all vowels and thus belong together. Common Pitfalls: None—this is a straightforward vowel-consonant test. Final Answer: Z

Question 2

Classification – Odd one out (vowel vs consonants): Which letter is different from the others: A, D, F, K?

Accepted Answer

Introduction / Context: This is another vowel-consonant discrimination task. Three of the listed letters are consonants; one is a vowel. Identify the vowel to find the odd one out. Given Data / Assumptions: A — vowel. D — consonant. F — consonant. K — consonant. Concept / Approach: Use the standard vowel set {A, E, I, O, U}. Only A among the given letters is a vowel; the others are consonants. Hence, A is the outlier. Step-by-Step Solution: 1) Mark A as vowel; D/F/K as consonants.2) Pick A as the single vowel. Verification / Alternative check: Phonetic classification aligns with the orthographic classification; there is no ambiguity. Why Other Options Are Wrong: D/F/K share “consonant” status and thus belong together. Common Pitfalls: Overcomplicating with alphabet positions; the simplest category works here. Final Answer: A

Question 3

Classification – Odd one out (letter triplets – fixed +6 jumps): Which triplet breaks the pattern of +6 alphabet jumps in both gaps: GMS, EKQ, JOU, LRX?

Accepted Answer

Introduction / Context: Letter-series classification often uses constant step sizes between consecutive letters. Here, three triplets follow the pattern “second letter = first + 6; third letter = second + 6.” One triplet does not. Convert letters to positions A=1, …, Z=26 and verify the step sizes. Given Data / Assumptions: GMS → G(7)→M(13)=+6; M(13)→S(19)=+6. EKQ → E(5)→K(11)=+6; K(11)→Q(17)=+6. LRX → L(12)→R(18)=+6; R(18)→X(24)=+6. JOU → J(10)→O(15)=+5; O(15)→U(21)=+6. Concept / Approach: Compute the gaps. If both gaps equal +6, the triplet fits the rule. Any deviation in either gap breaks the pattern. JOU has +5 then +6, so it is the outlier. Step-by-Step Solution: 1) Calculate differences for each option.2) Identify the sole non-conforming set: JOU. Verification / Alternative check: Reading backward yields −6 steps for the three valid triplets; JOU still fails to give equal-magnitude steps, confirming the mismatch from either direction. Why Other Options Are Wrong: GMS, EKQ, and LRX strictly maintain +6, +6. Common Pitfalls: Accepting “near” matches (like +5, +6). Classification requires exact rule conformity. Final Answer: JOU

Question 4

Classification – Odd one out (four-letter series – monotonic order): Identify the string that is not strictly increasing alphabetically: PQXZ, BCQN, ABDF, MNPR.

Accepted Answer

Introduction / Context: A common discriminator in letter quartets is whether the sequence of letters moves strictly forward in the alphabet. Three options list letters in left-to-right increasing order (though by unequal steps). One option breaks monotonicity by moving backward at the end. Given Data / Assumptions: Convert letters to positions A=1…Z=26 to inspect order: PQXZ → 16,17,24,26 (increasing). ABDF → 1,2,4,6 (increasing). MNPR → 13,14,16,18 (increasing). BCQN → 2,3,17,14 (increase, then decrease from 17 to 14). Concept / Approach: We only need strict monotonicity, not equal steps. Any backward move disqualifies the string. BCQN rises B→C→Q, then falls Q→N, hence it is the outlier. Step-by-Step Solution: 1) Check each adjacent pair for forward motion.2) Identify the unique backward step: Q to N in BCQN. Verification / Alternative check: Even if PQXZ jumps by +7 and +2 at the end, it remains strictly increasing; thus it still conforms. Only BCQN violates monotonicity. Why Other Options Are Wrong: ABDF, MNPR, PQXZ each preserves A→Z order throughout. Common Pitfalls: Expecting equal step sizes. The test only demanded “increasing,” not “arithmetic progression.” Final Answer: BCQN

Question 5

Classification – Odd one out (triplets with +2 then +3 and vowel center): Which set does not share the same internal pattern: MOR, GIL, SUX, ACF?

Accepted Answer

Introduction / Context: These triplets share two layered properties in many exam keys: (1) letter steps of +2 then +3 (left→middle, middle→right), and (2) the middle letter being a vowel. Three triplets satisfy both; one fails the vowel condition despite matching the numeric steps. The outlier is the only set whose middle letter is a consonant. Given Data / Assumptions: MOR → M(13)→O(15)=+2; O(15)→R(18)=+3; middle letter O is a vowel. GIL → G(7)→I(9)=+2; I(9)→L(12)=+3; middle letter I is a vowel. SUX → S(19)→U(21)=+2; U(21)→X(24)=+3; middle letter U is a vowel. ACF → A(1)→C(3)=+2; C(3)→F(6)=+3; middle letter C is a consonant. Concept / Approach: While all four meet the numeric +2,+3 progression, only one breaks the “vowel as the center” pattern. Reasoning questions often layer such dual cues to force careful checking beyond arithmetic alone. Step-by-Step Solution: 1) Verify step sizes → all four pass.2) Check middle-letter vowel status → MOR/GIL/SUX pass; ACF fails.3) Therefore, ACF is the odd one out. Verification / Alternative check: Try the vocalic center test on a different set; you will see the same discriminator works reliably across many exam patterns. Why Other Options Are Wrong: They satisfy both numeric progression and vowel-center conditions. Common Pitfalls: Stopping after verifying only arithmetic steps and missing the layered vowel cue. Final Answer: ACF

Question 6

Classification – Odd one out (triplets with +3 then −2 pattern): Which triplet breaks the +3, then −2 letter-step rule: HKI, UXV, CFD, MQN?

Accepted Answer

Introduction / Context: In many pattern sets, the first jump is a forward move of a fixed size and the second jump is a backward move of a different fixed size. Here, three triplets follow +3 then −2 (positions A=1 to Z=26). One triplet does not and is the outlier. Given Data / Assumptions: HKI → H(8)→K(11)=+3; K(11)→I(9)=−2. UXV → U(21)→X(24)=+3; X(24)→V(22)=−2. CFD → C(3)→F(6)=+3; F(6)→D(4)=−2. MQN → M(13)→Q(17)=+4; Q(17)→N(14)=−3 (not +3 then −2). Concept / Approach: Compute the two gaps for each option and compare with the target signature (+3, −2). Any deviation in size identifies the odd one. MQN uses +4 then −3, so it breaks the rule. Step-by-Step Solution: 1) Calculate both step sizes per triplet.2) Select the unique non-matching triplet: MQN. Verification / Alternative check: Reversing the order yields the inverse ( +2 then −3 ) for the valid sets; MQN still fails to align, confirming the mismatch. Why Other Options Are Wrong: HKI, UXV, CFD faithfully implement +3 then −2. Common Pitfalls: Confusing letter cases or reading left-to-right inconsistently. Stick to one direction for comparisons. Final Answer: MQN

Question 7

Classification – Odd one out (mixed-case quartets – +1, −3, +1 pattern): Which string fails the +1, −3, +1 positional change: CdaB, VwtU, LmjK, RsqP?

Accepted Answer

Introduction / Context: Ignore letter case and convert each character to its alphabet index (A/a=1 … Z/z=26). Three strings follow a consistent step pattern across their four letters: +1, then −3, then +1. One string deviates in the middle steps and is therefore the odd one out. Given Data / Assumptions: C d a B → 3,4,1,2 → +1, −3, +1. V w t U → 22,23,20,21 → +1, −3, +1. L m j K → 12,13,10,11 → +1, −3, +1. R s q P → 18,19,17,16 → +1, −2, −1 (fails). Concept / Approach: Compute consecutive differences for each string and match against the target signature. The one that does not read (+1, −3, +1) is the outlier. RsqP reads +1, −2, −1, so it breaks the rule. Step-by-Step Solution: 1) Translate letters → indices and take differences.2) Confirm three match (+1, −3, +1).3) Identify RsqP as the only mismatch. Verification / Alternative check: Reversing the strings flips the sign pattern; the mismatch persists for RsqP, confirming its difference regardless of direction. Why Other Options Are Wrong: CdaB, VwtU, LmjK all adhere exactly to the required differences. Common Pitfalls: Letting letter case distract you; positions are case-insensitive for this test. Final Answer: RsqP

Question 8

Classification – Odd one out (quartets – +2, +1, +2 stepping): Which string breaks the +2, +1, +2 advance between letters: BdEg, PrSu, KmNp, TwXz?

Accepted Answer

Introduction / Context: Across these mixed-case strings, ignore case and consider letter indices. Three strings show a repeating step pattern: +2, then +1, then +2. One string starts with a larger first jump and thus violates the rule. Given Data / Assumptions: B d E g → 2,4,5,7 → +2, +1, +2. P r S u → 16,18,19,21 → +2, +1, +2. K m N p → 11,13,14,16 → +2, +1, +2. T w X z → 20,23,24,26 → +3, +1, +2 (breaks). Concept / Approach: Compute the three successive steps. Only TwXz begins with +3. Because the pattern required +2 at the first step, TwXz is the odd one out. Step-by-Step Solution: 1) Translate to indices; compute deltas.2) Compare to the target (+2, +1, +2).3) Flag TwXz for the mismatched first jump. Verification / Alternative check: Checking backward differences yields −2, −1, −2 for the valid strings; TwXz still does not align in reverse, corroborating the mismatch. Why Other Options Are Wrong: BdEg, PrSu, KmNp each fits the specified step rule exactly. Common Pitfalls: Letting the visual irregularity of mixed case distract from the consistent numeric pattern. Final Answer: TwXz

Question 9

Classification – Odd one out (letter quartets – consecutive endings): Which quartet does not end with two consecutive letters: ABYZ, CDWX, EFUV, GHTV?

Accepted Answer

Introduction / Context: In these four-letter strings, the last two letters can be checked for being consecutive in the alphabet (e.g., YZ, WX, UV). Three options satisfy this “consecutive tail” property; one does not. Identify the string whose final pair is not consecutive. Given Data / Assumptions: ABYZ → Y(25), Z(26) consecutive. CDWX → W(23), X(24) consecutive. EFUV → U(21), V(22) consecutive. GHTV → T(20), V(22) not consecutive (gap of +2). Concept / Approach: Because the first two letters vary across options, focus on the tail property. ABYZ, CDWX, and EFUV each ends with two immediately successive letters. GHTV ends with T and V, which are separated by one letter (U) and are not consecutive. Therefore, GHTV is the odd one out. Step-by-Step Solution: 1) Extract the last two letters in each quartet.2) Check if they differ by exactly +1 in index.3) Only GHTV fails; select it as the answer. Verification / Alternative check: Even if you inspect the first two letters (AB, CD, EF, GH), they are consecutive pairs, but the discriminator intentionally lives at the end to create a single outlier. Why Other Options Are Wrong: They maintain the “consecutive pair” pattern at the tail. Common Pitfalls: Overanalyzing step sizes across all four letters; the simpler tail check is sufficient and robust. Final Answer: GHTV

Question 10

Classification – Odd one out (5-letter chains with +2, +3, +4, +5): Which sequence fails the progressive step pattern +2, +3, +4, +5: DFIMR, CEHLQ, GILPU, HJMPT?

Accepted Answer

Introduction / Context: Five-letter chains often encode steadily growing forward steps. Here the intended pattern is: from letter1 to letter2 add +2; letter2→letter3 add +3; letter3→letter4 add +4; letter4→letter5 add +5. Three options follow this staircase. One breaks it and is the outlier. Given Data / Assumptions: Using A=1 … Z=26: DFIMR → D(4)→F(6)=+2; F(6)→I(9)=+3; I(9)→M(13)=+4; M(13)→R(18)=+5. CEHLQ → C(3)→E(5)=+2; E(5)→H(8)=+3; H(8)→L(12)=+4; L(12)→Q(17)=+5. GILPU → G(7)→I(9)=+2; I(9)→L(12)=+3; L(12)→P(16)=+4; P(16)→U(21)=+5. HJMPT → H(8)→J(10)=+2; J(10)→M(13)=+3; M(13)→P(16)=+3 (should be +4); P(16)→T(20)=+4 (should be +5). Concept / Approach: Compute successive differences and match against the target staircase. HJMPT loses one step of growth partway through, so it fails the +2,+3,+4,+5 requirement. Step-by-Step Solution: 1) Calculate the four gaps for each sequence.2) Confirm DFIMR/CEHLQ/GILPU follow +2, +3, +4, +5.3) Identify HJMPT as the rule-breaker due to +2, +3, +3, +4. Verification / Alternative check: Reverse-direction checks still reveal the same inconsistency in HJMPT’s internal spacing. Why Other Options Are Wrong: They maintain the exact progressive step pattern throughout. Common Pitfalls: Stopping after checking only the first two gaps. The later gaps (+4, +5) are crucial to confirm rule adherence. Final Answer: HJMPT

Question 11

Classification (letters): Identify the odd group among the following three-letter sequences, where each group may or may not follow a consistent positional jump pattern in the English alphabet. Choose the one that does not follow the same rule as th…

Accepted Answer

Introduction / Context: In many verbal reasoning classification questions, the groups of letters follow a consistent positional rule based on the English alphabet. The task is to spot the group that breaks the common rule. Here, each option is a triad (three letters), and we examine the step sizes between consecutive letters. Given Data / Assumptions: Alphabet positions: A=1, B=2, …, Z=26. Options: HJN, JLP, PRU, QSW. We check the deltas (step sizes) between consecutive letters inside each triad. Concept / Approach: The dominant pattern in three of the groups is +2 followed by +4 in letter positions (for example, H→J is +2 and J→N is +4). Any triad that does not show the same pair of jumps is the odd one out. Step-by-Step Solution: For HJN: H(8)→J(10) = +2; J(10)→N(14) = +4.For JLP: J(10)→L(12) = +2; L(12)→P(16) = +4.For QSW: Q(17)→S(19) = +2; S(19)→W(23) = +4.For PRU: P(16)→R(18) = +2; R(18)→U(21) = +3 (not +4). Verification / Alternative check: An alternative way is to write each triad as numerical positions and compute differences. Only PRU yields +2 and +3; others yield +2 and +4, confirming the anomaly. Why Other Options Are Wrong: HJN follows +2, +4.JLP follows +2, +4.QSW follows +2, +4. Common Pitfalls: Mixing up alphabet indices or miscounting steps by off-by-one errors is common. Another pitfall is assuming constant increments (+2, +2) instead of checking both steps separately. Final Answer: PRU

Question 12

Classification (letter sequences): Find the odd four-letter sequence. Three options move back by a constant number of letters each time; one does not follow the same decrement pattern.

Accepted Answer

Introduction / Context: This is a classification problem involving 4-letter sequences. The common pattern to look for is a fixed decrement in alphabet positions from one letter to the next within a sequence. We must choose the sequence that fails to maintain that constant step size. Given Data / Assumptions: Alphabet indices: A=1 to Z=26. Options: NKHE, MIDA, KHEB, WTQN. We check consecutive differences for each sequence. Concept / Approach: Compute positional differences for each jump inside a sequence. If all three jumps are equal (e.g., −3, −3, −3), the sequence is consistent. Any deviation marks the odd one out. Step-by-Step Solution: NKHE: N(14)→K(11)=−3; K(11)→H(8)=−3; H(8)→E(5)=−3 (consistent).KHEB: K(11)→H(8)=−3; H(8)→E(5)=−3; E(5)→B(2)=−3 (consistent).WTQN: W(23)→T(20)=−3; T(20)→Q(17)=−3; Q(17)→N(14)=−3 (consistent).MIDA: M(13)→I(9)=−4; I(9)→D(4)=−5; D(4)→A(1)=−3 (not consistent). Verification / Alternative check: Visualize as numerical arrays and subtract; only MIDA has unequal decrements (−4, −5, −3). Why Other Options Are Wrong: NKHE keeps −3 at all steps.KHEB keeps −3 at all steps.WTQN keeps −3 at all steps. Common Pitfalls: Confusing direction (adding vs subtracting) or missing the negative sign. Always compute from left to right consistently. Final Answer: MIDA

Question 13

Classification (numbers): Split each 4-digit number into its first two digits and last two digits. Identify the number in which both halves share a special property that the others do not.

Accepted Answer

Introduction / Context: Number classification often depends on embedded patterns when a number is split into parts. Here, each 4-digit number can be read as two 2-digit numbers (first two digits and last two digits). We check for a distinctive common property across the halves. Given Data / Assumptions: Options: 3216, 2338, 3205, 2015. Interpret each as XYZW → (XY) and (ZW). Target property to investigate: powers of 2 among 2-digit numbers. Concept / Approach: Powers of 2 within two digits are 16, 32, 64. We check whether each half belongs to this set. If both halves are powers of 2, that number is special compared to the others. Step-by-Step Solution: 3216 → 32 and 16: both are powers of 2 (32=2^5, 16=2^4).2338 → 23 (not a power of 2), 38 (not a power of 2).3205 → 32 (power of 2), 05 (5, not a power of 2).2015 → 20 (not), 15 (not). Verification / Alternative check: You could test divisibility by repeatedly halving the number. 32 and 16 successively half to 1 without remainder; others do not. Why Other Options Are Wrong: 2338 has neither half as a power of 2.3205 has only one half (32) as a power of 2.2015 has neither half as a power of 2. Common Pitfalls: Misreading 05 as 0 or overlooking leading zero formatting. Treat 05 as 5 for the property check. Final Answer: 3216

Question 14

Classification (tool–result): Three pairs show a tool and the result it produces on a material; one pair does not match this relationship. Identify the odd pair.

Accepted Answer

Introduction / Context: Verbal classification frequently uses semantic relationships. Here, we compare pairs for a shared relation: a tool producing a characteristic result on a material. Three options fit; one breaks the pattern. Given Data / Assumptions: Needle → Prick (effect on skin/fabric). Auger → Bore (effect: drill/make a hole in wood etc.). Chisel → Carve (effect: shape/cut a solid material like wood/stone). Gun → Fire (word “fire” here denotes an action, not a result produced on a material). Concept / Approach: The shared relation is “tool produces a result on an external object/material.” We identify the pair deviating from this noun-result mapping. Step-by-Step Solution: Needle-Prick: tool → effect (prick).Auger-Bore: tool → effect (bore a hole).Chisel-Carve: tool → effect (carve/shape material).Gun-Fire: “fire” names the act of discharging, not the result formed on the target. Verification / Alternative check: Reword each as “Tool is used to …”: needle is used to prick; auger to bore; chisel to carve; gun to shoot, not to “fire” as a product/result noun. Why Other Options Are Wrong: Needle-Prick correctly encodes tool→result.Auger-Bore correctly encodes tool→result.Chisel-Carve correctly encodes tool→result. Common Pitfalls: Equating “fire” with a persistent result rather than an action; the consistent form should be an effect noun like “hole” or “carving.” Final Answer: Gun-Fire

Question 15

Classification (animal–sound): Three pairs correctly match an animal to its characteristic sound; one pair is mismatched. Choose the mismatched pair.

Accepted Answer

Introduction / Context: Vocabulary and world knowledge are tested by matching animals to their characteristic sounds. Most pairs are correct; one is intentionally incorrect to test recognition of standard associations. Given Data / Assumptions: Lion → Roar (correct). Snake → Hiss (correct). Bees → Hum (correct; also “buzz” is used). Frog → Croak (standard), not “bleat.” Concept / Approach: Check each animal’s widely accepted sound word in English usage. Identify the pair where the mapping is wrong. Step-by-Step Solution: Confirm typical sounds: lion→roar; snake→hiss; bees→hum/buzz; frog→croak.Detect mismatch: “Frog-Bleat” is incorrect; bleating is associated with goats/sheep. Verification / Alternative check: Cross-validate by recalling common idioms: “roaring lion,” “hissing snake,” “buzzing bees,” “croaking frogs.” Why Other Options Are Wrong: Bees-Hum is correct.Lion-Roar is correct.Snake-Hiss is correct. Common Pitfalls: Confusing “bleat” (goats/sheep) with amphibians. Avoid transferring sounds across unrelated animals. Final Answer: Frog-Bleat

Question 16

Classification (association): In three pairs, the first item is the input/resource used by the second; in one pair the relation is different. Identify the odd pair.

Accepted Answer

Introduction / Context: Association-based classification checks whether the semantic relation is consistent across options. Here, the pattern is “resource used by device/tool.” One pair deviates because the first item is not a resource used by the second; rather, it is what the second removes. Given Data / Assumptions: Petrol powers a car. Electricity powers a television. Ink is a resource used by a pen to write. Dust is not a resource used by a vacuum cleaner; it is the unwanted material removed. Concept / Approach: Identify device→resource pairs. The odd pair will invert or contradict the resource direction. Step-by-Step Solution: Petrol-Car: resource → consumer (consistent).Electricity-Television: resource → consumer (consistent).Ink-Pen: resource → consumer (consistent).Dust-Vacuum Cleaner: consumer removes the first item (inconsistent). Verification / Alternative check: Paraphrase as “X is used by Y to function.” Only dust fails this template. Why Other Options Are Wrong: Petrol-Car fits resource usage.Electricity-Television fits resource usage.Ink-Pen fits resource usage. Common Pitfalls: Confusing “input” vs “output/waste.” Dust is not an input to vacuum cleaners. Final Answer: Dust-Vacuum Cleaner

Question 17

Classification (relation type): Three pairs show an object and its inherent property (quality); one pair shows a container and its content. Choose the odd pair.

Accepted Answer

Introduction / Context: This item tests recognition of semantic relation types. Most options express an object → inherent property linkage. One option instead encodes a container → content relationship, which is categorically different. Given Data / Assumptions: Ice cube → cold (intrinsic state/quality). Iron → hard (inherent property). Marble → smooth (typical surface quality; spelling corrected from “Marbale”). Purse → money (content carried, not an inherent property). Concept / Approach: Classify each pair as “object–property” or “container–content.” The odd pair will be of the latter type only. Step-by-Step Solution: Ice cube : Cold → object–property.Iron : Hard → object–property.Marble : Smooth → object–property.Purse : Money → container–content (different). Verification / Alternative check: Ask: Can the right-hand term be described as a characteristic adjective? “Cold,” “hard,” and “smooth” are qualities; “money” is a noun denoting content. Why Other Options Are Wrong: Ice cube, iron, and marble pairs consistently describe inherent qualities. Common Pitfalls: Overlooking part-of-speech clues (adjective vs noun). Adjectives typically indicate properties in such questions. Final Answer: Purse : Money

Question 18

Classification (antonyms): Three pairs are true antonym pairs; one pair is not a genuine opposite in meaning. Identify the non-antonym pair.

Accepted Answer

Introduction / Context: Antonym recognition is central to verbal reasoning. Three pairs are legitimate opposites; one pair is merely related adjectives that measure different attributes rather than direct opposition. Given Data / Assumptions: Hard ↔ Soft (texture/resistance opposites). Pointed ↔ Blunt (shape/edge opposites). Sweet ↔ Sour (taste opposites). Long ↔ High (measure different dimensions, not strict opposites). Concept / Approach: Check whether each pair expresses a binary contrast along the same dimension. If the adjectives do not oppose each other along a single axis, the pair is not an antonym pair. Step-by-Step Solution: Hard vs Soft → opposite textures.Pointed vs Blunt → opposite sharpness/edge qualities.Sweet vs Sour → opposite tastes.Long vs High → different spatial dimensions (length vs height), not opposites. Verification / Alternative check: Replace one adjective with its true opposite: Long vs Short, High vs Low. The given pair does not match that structure. Why Other Options Are Wrong: Hard-Soft, Pointed-Blunt, and Sweet-Sour are canonical antonyms. Common Pitfalls: Assuming that co-occurring descriptors (long and high) must be opposites. They are orthogonal attributes. Final Answer: Long-High

Question 19

Classification (leader–group): In three pairs, the first term denotes the leader of the second (group/body). One pair instead shows a member and a group. Identify the odd pair.

Accepted Answer

Introduction / Context: This problem checks awareness of role–collective relations. Three pairs encode “leader → group led,” while one pair encodes “member → group belonging,” which is categorically different. Given Data / Assumptions: Captain → Team (leader of the team). Boss → Gang (leader of a gang). Prime Minister → Cabinet (heads/coordinates cabinet decisions in many systems). Artist → Troupe (member of the troupe, not its designated leader). Concept / Approach: Determine whether the first term is a leader role relative to the second. The pair that expresses “member of” rather than “leader of” is the odd one out. Step-by-Step Solution: Captain- Team → leader relationship.Boss- Gang → leader relationship.Prime Minister-Cabinet → executive leadership relationship.Artist-Troupe → membership relationship, not leadership. Verification / Alternative check: Rephrase as “X leads Y.” The first three read naturally; “Artist leads Troupe” does not necessarily follow. Why Other Options Are Wrong: Captain- Team, Boss- Gang, and Prime Minister-Cabinet consistently encode leadership. Common Pitfalls: Assuming a prominent member (artist) automatically implies leadership; leadership is a specific role (e.g., director, leader, or captain). Final Answer: Artist-Troupe

Question 20

Classification (resource requirement): Three pairs show a resource required by the second item to function or exist; one pair reverses the direction (source → content). Identify the odd pair.

Accepted Answer

Introduction / Context: Many classification questions turn on whether the semantic direction of “requirement” is preserved. Three pairs show a resource needed by an entity; one pair names a source that supplies a resource, flipping the relation. Given Data / Assumptions: Oil is required by a lamp (as fuel) to burn. Power is required by a machine to operate. Oxygen is required for life processes. Water : Tap actually denotes a source → provided substance; a tap dispenses water. Concept / Approach: Check whether the first term is a prerequisite to the functioning/existence of the second. If instead the second term is a source that supplies the first, the relation is reversed and becomes the odd one out. Step-by-Step Solution: Oil : Lamp → fuel needed by lamp.Power : Machine → energy needed by machine.Oxygen : Life → substance needed for life.Water : Tap → tap is a source of water (reversed relation). Verification / Alternative check: Try stating “X is required by Y.” Oil is required by lamp; power by machine; oxygen by life. “Water is required by tap” is false; taps deliver water. Why Other Options Are Wrong: Oil-Lamp, Power-Machine, Oxygen-Life all encode a requirement correctly. Common Pitfalls: Confusing supply/source relationships with requirement relationships; note the directionality. Final Answer: Water : Tap

Classification Questions