Classification – Odd one out (constant +6 jumps) Four 3-letter strings are tested for uniform alphabet jumps. In three strings, both jumps are +6; one string breaks this pattern. Identify the odd one.

Introduction / Context:
Another common letter-series pattern is a constant jump (e.g., +6, +7). The task is to verify both gaps. A single mismatch identifies the outlier.

Given Data / Assumptions:

• GMS, EKQ, JOU, LRX
• Indexing: A=1 … Z=26

Concept / Approach:
Calculate both position differences in each string. The intended majority pattern is +6 and +6.

Step-by-Step Solution:
G(7)→M(13)=+6; M(13)→S(19)=+6 → fits.E(5)→K(11)=+6; K(11)→Q(17)=+6 → fits.L(12)→R(18)=+6; R(18)→X(24)=+6 → fits.J(10)→O(15)=+5; O(15)→U(21)=+6 → breaks first gap.

Verification / Alternative check:
Cyclic wrap (beyond Z) is not needed here; all letters are within range. The single non-conforming first gap confirms the outlier.

Why Other Options Are Wrong:

• GMS, EKQ, LRX → both jumps +6.
• None of these → one clear mismatch (JOU).

Common Pitfalls:
Miscounting positions or treating letters as 0-indexed in one place and 1-indexed in another.

Final Answer:
JOU