Classification – Odd one out (alphabetic jumps) Each string consists of 3 letters. In three strings, the jumps are +2 then +3 in alphabet positions; in one string, the second jump deviates. Identify the deviating string.

Introduction / Context:
Letter-series classification problems encode position jumps (e.g., +2, +3). Recognizing the numeric pattern behind letter steps converts a verbal puzzle into a simple arithmetic check on alphabet indices (A=1 … Z=26).

Given Data / Assumptions:

• HJM, OQT, BDG, VXZ
• Indexing: A=1, B=2, …, Z=26

Concept / Approach:
Compute successive jumps: second − first, third − second. The intended pattern is +2 then +3 for most strings.

Step-by-Step Solution:
H(8)→J(10)=+2; J(10)→M(13)=+3 → fits.O(15)→Q(17)=+2; Q(17)→T(20)=+3 → fits.B(2)→D(4)=+2; D(4)→G(7)=+3 → fits.V(22)→X(24)=+2; X(24)→Z(26)=+2 → deviates (not +3).

Verification / Alternative check:
Any reindexing (e.g., A=0) preserves the relative difference property; the single departure persists for VXZ.

Why Other Options Are Wrong:

• HJM, OQT, BDG → all follow +2 then +3.
• None of these → there is one clear deviation (VXZ).

Common Pitfalls:
Counting letters rather than positions (forgetting that the jump is about indices, not “letters in between”).

Final Answer:
VXZ