Solve this multiple-choice question and choose the correct option.

Home » Verbal Reasoning » Classification

Choose the odd number: 17, 19, and 23 are primes. One number is composite. Identify the composite number.

Difficulty: Easy

17
19
23
27
None of these

Correct Answer: 27

Explanation:

Introduction / Context:Prime recognition again isolates the outlier.

Given Data / Assumptions:

Candidates: 17, 19, 23, 27.
Definition: prime vs composite.

Concept / Approach:Use small-prime divisibility tests (especially 3).

Step-by-Step Solution:

27 → 2+7=9 → divisible by 3 → composite (3^3).17, 19, 23 → not divisible by 2,3,5 → primes.

Verification / Alternative check:Direct factorization: 27 = 3 * 9 confirms compositeness.

Why Other Options Are Wrong:They are prime.

Common Pitfalls:Assuming all odd numbers are prime.

Final Answer:27 is the odd number.

← Previous Question Next Question→

More Questions from Classification

Identify the odd pair: Three pairs express a relation of increasing intensity (mild action/state → stronger one): Flurry→Blizzard, Moisten→Drench, Prick→Stab. One pair does not represent the same intensity relation. Choose the mismatching pair.
Choose the odd term: Thyroxine, Adrenaline, and Insulin are hormones; Iodine is a chemical element (nutrient), not a hormone. Identify the outlier.
Identify the odd pair: Three pairs are antonyms (Dim–Bright, Wrong–Right, Shallow–Deep). One pair consists of synonyms (same/near meaning). Choose the synonym pair.
Classification – Odd one out (relationship type) Each pair shows a relation between two objects. Three pairs follow the whole–part relation (object → its component), while one pair shows an instrument → product relation. Identify the pair that does not follow the whole–part pattern.
Classification – Odd one out (synonym vs antonym) Each pair relates two words. Three pairs are antonyms or complementary opposites, whereas one pair is a clear synonym set. Identify the synonym pair as the odd one out.
Classification – Odd one out (product vs category) Three pairs show fruit/vegetable → processed product (e.g., jam, squash, puree). One pair shows item → category (hyponym → hypernym). Identify the odd relation.
Classification – Odd one out (food vs habitat) Three pairs are animal → typical food; one pair is animal → typical place (habitat/setting). Identify the pair that does not follow the food relationship.
Classification – Odd one out (alphabetic jumps) Each string consists of 3 letters. In three strings, the jumps are +2 then +3 in alphabet positions; in one string, the second jump deviates. Identify the deviating string.
Classification – Odd one out (constant +6 jumps) Four 3-letter strings are tested for uniform alphabet jumps. In three strings, both jumps are +6; one string breaks this pattern. Identify the odd one.
Classification – Odd one out (letter–letter with numeric mean) In these alphanumeric items, the number equals the average (arithmetic mean) of the alphabet positions of the two letters. Three items follow this rule; one does not. Identify the exception.

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion