Question 1

Odd One Out — In the pairs Flag : Flagship, Court : Courtship, War : Worship, Friend : Friendship, choose the pair that does not follow the -ship suffix pattern.

Accepted Answer

Introduction / Context: This verbal analogy item checks whether a consistent morphological pattern is applied across pairs. Given Data / Assumptions: Pattern: base word + the suffix "ship" forming a noun (flagship, courtship, friendship). Worship is not formed from "war" + "ship"; the correct pairing for war would be warship. Concept / Approach: Test each pair for true base + "ship" formation. Step-by-Step Solution: Flag : Flagship — valid suffix relation.Court : Courtship — valid suffix relation.Friend : Friendship — valid suffix relation.War : Worship — invalid; worship is an unrelated word. Verification / Alternative check: Substitute "warship" and observe the single mismatch created by the given "worship" spelling. Why Other Options Are Wrong: Flag : Flagship — correct morphological pattern. Court : Courtship — correct morphological pattern. Friend : Friendship — correct morphological pattern. Common Pitfalls: Overlooking the subtle spelling difference between "warship" and "worship". Final Answer: War : Worship

Question 2

Odd One Out — Among the integers 6, 15, 12, and 17, identify the single prime and justify why the others are composite.

Accepted Answer

Introduction / Context: A quick primality screen separates one candidate from several small composites. Given Data / Assumptions: Numbers: 6, 15, 12, 17. Prime definition: exactly two positive divisors. Concept / Approach: Test divisibility by small primes (2, 3, 5). Step-by-Step Solution: 6 = 2 * 3, composite.12 = 3 * 4 or 2 * 6, composite.15 = 3 * 5, composite.17: not divisible by 2, 3, or 5; therefore prime. Verification / Alternative check: Square root of 17 is about 4.12, so testing primes up to 3 suffices. Why Other Options Are Wrong: 6: composite. 12: composite. 15: composite. Common Pitfalls: Assuming 15 is prime because it is not even; oddness does not imply primality. Final Answer: 17

Question 3

Odd One Out — From Whim, Quirk, Caprice, and Foible, identify the word that does not share the meaning of a sudden notion or unpredictable fancy.

Accepted Answer

Introduction / Context: Vocabulary classification hinges on synonymy. Three options are near-synonyms, and one differs in meaning. Given Data / Assumptions: Whim, Caprice: a sudden fancy or passing notion. Quirk: often a peculiar trait or idiosyncrasy; used loosely near the same idea of unpredictability. Foible: a minor weakness or flaw in character. Concept / Approach: Group words by shared core meaning: sudden notion or unpredictable fancy vs personal weakness. Step-by-Step Solution: Whim and Caprice align strongly as synonyms.Quirk, while broader, commonly overlaps with unpredictable peculiarities.Foible specifically indicates a small character weakness, not a sudden fancy. Verification / Alternative check: Substitute each into the phrase “a sudden _____ overtook her”; Foible fails the sense check. Why Other Options Are Wrong: Whim: synonym of caprice. Quirk: acceptable near-synonym in many contexts here. Caprice: the core sense itself. Common Pitfalls: Treating Quirk as strictly unrelated; in usage it can convey unpredictable oddness. Final Answer: Foible

Question 4

Odd One Out — In the letter groups FUEV, QPSR, VUXW, and YXWV, find the set that does not follow the consistent step pattern in alphabet positions.

Accepted Answer

Introduction / Context: Letter-sequence classification often relies on fixed positional steps (like -1, +3, -1). Three options share such a pattern; one does not. Given Data / Assumptions: Consider A=1, B=2, ..., Z=26 indexing. Options: FUEV, QPSR, VUXW, YXWV. Concept / Approach: Track successive letter differences for each 4-letter group and compare patterns. Step-by-Step Solution: QPSR: Q(17) to P(16) = -1; P(16) to S(19) = +3; S(19) to R(18) = -1.VUXW: V(22) to U(21) = -1; U(21) to X(24) = +3; X(24) to W(23) = -1.YXWV: Y(25) to X(24) = -1; X(24) to W(23) = -1; W(23) to V(22) = -1 (monotone -1 each step).FUEV: F(6) to U(21) = +15; U(21) to E(5) = -16; E(5) to V(22) = +17; this does not match -1, +3, -1 or any simple constant-step pattern. Verification / Alternative check: Two options share -1, +3, -1; one is monotone -1; FUEV alone has large irregular jumps. Why Other Options Are Wrong: QPSR: follows -1, +3, -1. VUXW: follows -1, +3, -1. YXWV: follows -1 repeatedly; still consistent. Common Pitfalls: Assuming YXWV must match the same alternation; consistency can be a different but simple rule. Final Answer: FUEV

Question 5

Odd One Out — Among IJKL, PONM, HGFE, and DCBA, identify the sequence that is arranged in increasing alphabetical order while the others are strictly decreasing.

Accepted Answer

Introduction / Context: Alphabetical order (ascending vs descending) is a frequent basis for odd-one-out questions on letter sequences. Given Data / Assumptions: Options: IJKL, PONM, HGFE, DCBA. Ascending means each next letter has a higher alphabet index; descending means lower. Concept / Approach: Check the direction of progression in each 4-letter block. Step-by-Step Solution: IJKL: I to J to K to L is ascending.PONM: P to O to N to M is descending.HGFE: H to G to F to E is descending.DCBA: D to C to B to A is descending. Verification / Alternative check: Count step signs; IJKL alone has all positive steps. Why Other Options Are Wrong: PONM: descending order. HGFE: descending order. DCBA: descending order. Common Pitfalls: Overthinking with letter positions; the direction check is sufficient. Final Answer: IJKL

Question 6

Odd One Out — From Elope, Degrade, Abase, and Humilate (read as Humiliate), choose the word that does not share the meaning of lowering status or dignity.

Accepted Answer

Introduction / Context: This vocabulary problem contrasts three near-synonyms about lowering or humiliating someone with a term denoting a different action entirely. Given Data / Assumptions: Degrade, Abase, Humiliate (spelled here as Humilate): to lower in rank, dignity, or respect. Elope: to run away secretly to get married. Concept / Approach: Group by semantic field: humiliation vs unrelated marital action. Step-by-Step Solution: Degrade: to bring down in dignity.Abase: to humble or belittle.Humiliate: to cause a loss of pride.Elope: unrelated to humiliation; refers to marriage behavior. Verification / Alternative check: Substitute in “to _____ someone publicly”; only the three humiliation verbs fit. Why Other Options Are Wrong: Degrade: matches the humiliation set. Abase: matches the humiliation set. Humilate: matches the humiliation set. Common Pitfalls: Being distracted by the misspelling “Humilate”; despite spelling, the intended word is Humiliate. Final Answer: Elope

Question 7

Odd One Out — In cricket terms, identify which among Swing, Googly, Bouncer, and Yorker is not the name of a specific delivery type in the same sense as the others.

Accepted Answer

Introduction / Context: This sports-classification question focuses on cricket bowling terminology, contrasting a ball-movement phenomenon with specific named deliveries. Given Data / Assumptions: Googly: a specific spin delivery that turns opposite to the leg-break expectation. Bouncer: a short-pitched ball rising toward the batter’s upper body. Yorker: a very full ball landing near the batter’s feet. Swing: describes lateral movement in the air, applicable to various length lines and not the name of one fixed delivery type. Concept / Approach: Classify items as fixed delivery types vs a general movement phenomenon. Step-by-Step Solution: Googly, Bouncer, Yorker are conventional delivery labels.Swing denotes a behavior of the ball; it can occur on different deliveries and lengths.Hence Swing is the odd one out. Verification / Alternative check: Ask whether umpires or commentators would label the ball solely by that term; Swing is usually coupled with a specific length (e.g., swinging yorker). Why Other Options Are Wrong: Googly: specific named delivery. Bouncer: specific named delivery. Yorker: specific named delivery. Common Pitfalls: Confusing swing bowling style with a single delivery label; it is a movement category. Final Answer: Swing

Question 8

Odd One Out — Among Catalysis, Condensation, Conduction, and Coagulation, find the term that belongs to physics heat-transfer vocabulary rather than standard chemistry process names.

Accepted Answer

Introduction / Context: This classification item separates typical chemistry process names from a physics heat-transfer term. Given Data / Assumptions: Catalysis: chemical acceleration due to a catalyst. Condensation: phase change gas to liquid. Coagulation: particles clumping into larger aggregates. Conduction: in standard usage, a mode of heat transfer in physics (along with convection and radiation). Concept / Approach: Group by disciplinary usage: chemistry processes vs physics heat-transfer terminology. Step-by-Step Solution: Catalysis, Condensation, Coagulation: commonly taught as chemistry processes.Conduction: the physics term for heat transfer by direct contact; not a distinct chemistry process name. Verification / Alternative check: Textbook chapter grouping: conduction sits with convection and radiation in physics sections. Why Other Options Are Wrong: Catalysis: chemistry process. Condensation: chemistry/thermodynamics phase change. Coagulation: chemistry/colloids process. Common Pitfalls: Assuming all four are chemistry because of the shared prefix co-/con-; focus on meaning and domain. Final Answer: Conduction

Question 9

Odd One Out — In the ordered pairs ( 2, 11 ), ( 3, 30 ), ( 7, 345 ), and ( 5, 128 ), identify the pair that does not satisfy the pattern y = x^3 + 3.

Accepted Answer

Introduction / Context: Recognizing a simple algebraic rule behind ordered pairs is a common pattern-recognition task. Three pairs follow one rule; one does not. Given Data / Assumptions: Pairs: (2, 11), (3, 30), (7, 345), (5, 128). Candidate rule: y = x^3 + 3. Concept / Approach: Compute x^3 + 3 for each x and compare with the given y. Step-by-Step Solution: x = 2: 2^3 + 3 = 8 + 3 = 11, matches.x = 3: 3^3 + 3 = 27 + 3 = 30, matches.x = 5: 5^3 + 3 = 125 + 3 = 128, matches.x = 7: 7^3 + 3 = 343 + 3 = 346, which does not match 345. Verification / Alternative check: Re-calc to avoid arithmetic slips; only the third pair misses by 1. Why Other Options Are Wrong: ( 2, 11 ): satisfies y = x^3 + 3. ( 3, 30 ): satisfies y = x^3 + 3. ( 5, 128 ): satisfies y = x^3 + 3. Common Pitfalls: Mistaking 7^3 as 342 or 344; 7^3 is 343 exactly. Final Answer: ( 7, 345 )

Question 10

Odd One Out — Among 24, 49, 80, and 15, choose the unique perfect square and justify why the others are not squares.

Accepted Answer

Introduction / Context: Perfect-square recognition is a classic skill in number classification tasks. Given Data / Assumptions: Numbers: 24, 49, 80, 15. Perfect square definition: equals n^2 for an integer n. Concept / Approach: Check whether each candidate equals some small n^2. Step-by-Step Solution: 49 = 7^2, a perfect square.24 is between 4^2 = 16 and 5^2 = 25, not a square.80 is between 8^2 = 64 and 9^2 = 81, not a square.15 is between 3^2 = 9 and 4^2 = 16, not a square. Verification / Alternative check: Prime-factor check: 49 = 7^2 has all exponents even; others do not. Why Other Options Are Wrong: 24: not an integer square. 80: not an integer square. 15: not an integer square. Common Pitfalls: Confusing proximity to a square (like 80 near 81) with being a square. Final Answer: 49

Question 11

Classification – Identify the odd one out among the following birds by focusing on ecological role and feeding behavior. Three belong to the same natural class, while one differs in a key biological trait. Which option does not belong to the group? …

Accepted Answer

Introduction / Context: Classification (odd-one-out) questions test your ability to recognize a unifying rule across most items and to detect the single exception. Here, all four names are birds, so the surface category is the same; the task is to probe deeper biological or ecological traits such as diet, behavior, or typical role in the ecosystem. Given Data / Assumptions: Parrot: primarily herbivorous/omnivorous, non-raptorial. Koel: a cuckoo, omnivorous/frugivorous, songbird, non-raptorial. Vulture: a raptor specialized as a scavenger. Swan: a waterfowl, mostly herbivorous/omnivorous, non-raptorial. Concept / Approach: Look for a shared functional category among three items (non-raptorial birds) and a contrasting category for one item (raptorial scavenger). The odd-one-out will violate the dominant grouping rule inferred from the majority. Step-by-Step Solution: Step 1: Note that Parrot, Koel, and Swan are generally non-raptorial birds.Step 2: Identify Vulture as a raptor with specialized scavenging habits and anatomical adaptations for tearing flesh.Step 3: Since three share a non-raptorial profile and one is raptorial, the exception is Vulture. Verification / Alternative check: Check diet and beak/talons morphology: vultures have hooked beaks and strong talons typical of birds of prey, unlike the other three, confirming the classification choice. Why Other Options Are Wrong: Parrot: Non-raptorial; fits the majority group. Koel: Non-raptorial; fits the majority group. Swan: Non-raptorial waterfowl; fits the majority group. Common Pitfalls: Avoid superficial cues (habitat or color). The decisive trait here is ecological role (raptor vs non-raptor). Final Answer: Vulture

Question 12

Classification – Pick the odd one out based on part of speech and exact lexical form. Three words are adjectives meaning “more than enough,” while one is a noun (and thus does not belong). Which option is different?  Options: Ample, Copious, Plentif…

Accepted Answer

Introduction / Context: Verbal classification often hinges on identifying the grammatical category or exact sense alignment of words. Here, three options are adjectives synonymous with “plenty,” while one option is a noun referring to the state of having plenty. Recognizing parts of speech quickly isolates the odd item. Given Data / Assumptions: Ample: adjective (sufficient, more than adequate). Copious: adjective (abundant in supply or quantity). Plentiful: adjective (present in large amounts). Abundance: noun (a very large quantity of something). Concept / Approach: Determine the dominant property among the majority—here, adjective form with similar meaning—and identify the single option that differs in grammatical role (noun) even though semantic fields are related. Step-by-Step Solution: Step 1: Mark parts of speech for each option.Step 2: Find that Ample, Copious, and Plentiful are adjectives.Step 3: Note that Abundance is a noun; therefore, it breaks the pattern. Verification / Alternative check: Substitute each before a noun (e.g., “ample time,” “copious notes,” “plentiful resources”). “Abundance time” is ungrammatical without “of” (“an abundance of time”), confirming it is not an adjective. Why Other Options Are Wrong: Ample: adjective, fits group. Copious: adjective, fits group. Plentiful: adjective, fits group. Common Pitfalls: Do not let semantic similarity overshadow grammatical category differences; part of speech is decisive. Final Answer: Abundance

Question 13

Classification – Among the following, identify the odd one out by considering biological class. Three are birds, while one is a mammal. Which option does not belong?  Options: Parrot, Bat, Crow, Sparrow.

Accepted Answer

Introduction / Context: Odd-one-out problems often exploit taxonomic distinctions. Here, three items are avian (birds), while one belongs to the class Mammalia. Recognizing high-level biological categories provides a quick and reliable rule for exclusion. Given Data / Assumptions: Parrot: bird. Crow: bird. Sparrow: bird. Bat: mammal, although capable of powered flight. Concept / Approach: The task is to identify which entity violates the majority taxonomic class. Even if two categories can share a surface trait (e.g., flight), the underlying classification (bird vs mammal) prevails. Step-by-Step Solution: Step 1: Label each option as bird or mammal.Step 2: Note that Parrot, Crow, and Sparrow are birds.Step 3: Note that Bat is a mammal; hence, it is the odd one out. Verification / Alternative check: Consider anatomical traits: birds have feathers and beaks; bats have fur, mammalian dentition, and nurse their young—confirming mammalian status. Why Other Options Are Wrong: Parrot/Crow/Sparrow: All are avian and thus fit the majority category. Common Pitfalls: Do not rely solely on the presence of flight; taxonomic class is the deciding factor. Final Answer: Bat

Question 14

Classification – Choose the odd one out by focusing on weapon type. Three are firearms that discharge projectiles using explosive force; one is a bladed melee weapon. Which option does not belong?  Options: Rifle, Cannon, Sword, Pistol.

Accepted Answer

Introduction / Context: In classification questions, grouping by mechanism or mode of action is often decisive. Firearms use propellant-based force to launch projectiles; melee weapons rely on physical contact and cutting or striking. Identifying the distinct mechanism isolates the exception. Given Data / Assumptions: Rifle: firearm (projectile weapon). Cannon: firearm/artillery (projectile weapon). Pistol: firearm (projectile weapon). Sword: melee, bladed weapon. Concept / Approach: Group by propulsion mechanism: explosive propellant vs hand-wielded cutting. The single melee weapon among three firearms is the odd one out. Step-by-Step Solution: Step 1: Tag each item as firearm or melee.Step 2: Observe that Rifle, Cannon, and Pistol share the firearm mechanism.Step 3: Sword is melee; therefore, it is the exception. Verification / Alternative check: Consider distance of engagement: firearms operate at range; swords require close contact—confirming the category difference. Why Other Options Are Wrong: Rifle/Cannon/Pistol: All are firearms and thus belong to the main group. Common Pitfalls: Avoid grouping by size or era; mechanism of action is the intended criterion. Final Answer: Sword

Question 15

Classification – Identify the odd one out among fruits by considering typical size/class and general characteristics. Three are large, bulky fruits; one is comparatively small. Which option does not belong?  Options: Papaya, Watermelon, Jackfruit, G…

Accepted Answer

Introduction / Context: Food-based classification problems often rely on salient physical properties such as size or typical culinary treatment. Here, three fruits are commonly recognized as very large or bulky, whereas one is generally small, making it the natural exception. Given Data / Assumptions: Papaya: typically large, single large fruit per plant. Watermelon: large, heavy fruit. Jackfruit: very large, among the heaviest tree-borne fruits. Guava: comparatively small fruit. Concept / Approach: Identify the majority pattern (large/bulky fruits) and select the item that deviates in size class. This forms a clear, objective criterion. Step-by-Step Solution: Step 1: Group fruits by typical size category.Step 2: Papaya, Watermelon, and Jackfruit fall under large/bulky.Step 3: Guava is small; hence, it is the odd one out. Verification / Alternative check: Consider average market handling and unit size: guavas are sold in small counts; the others are often single large units requiring cutting. Why Other Options Are Wrong: Papaya/Watermelon/Jackfruit: All align with the large-fruit category. Common Pitfalls: Do not overfit to seed count or rind texture; the intended rule is overall typical size category. Final Answer: Guava

Question 16

Classification – World cities: choose the odd one out based on political status. Three are national capitals; one is not a national capital. Which option is different?  Options: Beijing, Melbourne, Paris, Athens.

Accepted Answer

Introduction / Context: Geography classification questions often use political or administrative status. While several cities may be globally famous, only some are designated national capitals. Identifying this status yields the odd one out. Given Data / Assumptions: Beijing: Capital of China. Paris: Capital of France. Athens: Capital of Greece. Melbourne: Major Australian city; national capital is Canberra. Concept / Approach: Determine whether each city is a national capital. The single non-capital city is the exception. Step-by-Step Solution: Step 1: Tag each city as capital or not.Step 2: Beijing/Paris/Athens are capitals.Step 3: Melbourne is not a national capital; hence, it is the odd one out. Verification / Alternative check: Australia’s federal capital is Canberra; Melbourne, while historically significant, lacks current capital status. Why Other Options Are Wrong: Beijing/Paris/Athens: All are national capitals and thus belong to the main group. Common Pitfalls: Do not confuse “largest” or “famous” with “capital.” Capital status is a specific designation. Final Answer: Melbourne

Question 17

Classification – Animal life stages: identify the odd one out. Three terms denote juvenile (young) animals; one denotes an adult. Which option does not belong?  Options: Stag, Kitten, Colt, Fawn.

Accepted Answer

Introduction / Context: Animal terminology frequently distinguishes between juvenile and adult stages. Understanding these labels enables quick classification in odd-one-out tasks. Given Data / Assumptions: Kitten: a young cat. Colt: a young male horse. Fawn: a young deer. Stag: an adult male deer. Concept / Approach: Find the majority group (juveniles) and identify the outlier (adult). Step-by-Step Solution: Step 1: Label each term as juvenile or adult.Step 2: Kitten, Colt, and Fawn denote juveniles.Step 3: Stag denotes an adult; thus, it is the odd one out. Verification / Alternative check: Cross-check definitions in standard zoological/glossary sources; usage is consistent with common English. Why Other Options Are Wrong: Kitten/Colt/Fawn: All are juvenile terms and fit the majority. Common Pitfalls: Do not conflate species with life-stage terminology; the category distinction is age-based. Final Answer: Stag

Question 18

Classification – Birds and mammals: select the odd one out. Three are birds; one is a mammal that flies. Which option does not belong?  Options: Crow, Vulture, Sparrow, Bat.

Accepted Answer

Introduction / Context: Despite shared abilities (e.g., flight), biological class remains the primary classification rule. Three options are birds; one is a mammal capable of powered flight. Given Data / Assumptions: Crow: bird. Vulture: bird of prey. Sparrow: bird. Bat: mammal. Concept / Approach: Classify by taxonomic class instead of function. The mammal among birds is the odd one. Step-by-Step Solution: Step 1: Tag each as bird or mammal.Step 2: Crow/Vulture/Sparrow are birds.Step 3: Bat is a mammal; thus, it is the exception. Verification / Alternative check: Consider anatomical traits (feathers vs fur; beak vs teeth) for confirmation. Why Other Options Are Wrong: Crow/Vulture/Sparrow: All are avian; hence, they belong with the majority. Common Pitfalls: Do not be misled by common ability (flight). Classification is taxonomic. Final Answer: Bat

Question 19

Classification – Visual representations: choose the odd one out. Three are primarily 2D drawn or plotted representations; one is a representation type that is often conceptual or 3D. Which option is different?  Options: Graph, Chart, Model, Drawing.

Accepted Answer

Introduction / Context: Representation types vary by medium and dimensionality. Graphs, charts, and drawings are typically 2D visual artifacts, whereas a “model” can be a conceptual abstraction or a 3D physical/digital construct, distinguishing it from the others. Given Data / Assumptions: Graph: 2D plotting of relationships between variables. Chart: 2D visual summary of data. Drawing: 2D visual depiction by hand or tool. Model: can be conceptual, mathematical, or 3D physical/digital representation. Concept / Approach: Group items by standard dimensional form: primarily 2D visuals vs broader/3D/conceptual constructs. Step-by-Step Solution: Step 1: Assign typical dimensionality to each item.Step 2: Graph, Chart, Drawing are 2D outputs.Step 3: Model transcends 2D, often 3D or abstract; thus, it is the odd one out. Verification / Alternative check: In practice, “model” frequently means a 3D CAD model or a mathematical construct; the others imply flat presentations. Why Other Options Are Wrong: Graph/Chart/Drawing: All fit 2D-presentational outputs and thus align with the majority. Common Pitfalls: Do not overinterpret edge cases (e.g., 3D charts). The default/typical sense is intended. Final Answer: Model

Question 20

Classification – Household linens vs furnishings: pick the odd one out. Three are bedding items; one is primarily a window furnishing. Which option does not belong?  Options: Mattress, Pillow, Bed sheet, Curtain.

Accepted Answer

Introduction / Context: Domestic-item classifications often use functional context. Bedding comprises items used on a bed for sleeping comfort; curtains are window treatments for privacy and light control. Given Data / Assumptions: Mattress: bedding base. Pillow: bedding support. Bed sheet: bedding cover/linen. Curtain: window furnishing. Concept / Approach: Group items by the “bed” usage context and separate the one associated with windows. Step-by-Step Solution: Step 1: Tag each item as bedding or non-bedding.Step 2: Mattress, Pillow, Bed sheet are bedding.Step 3: Curtain is not bedding; it is the odd one out. Verification / Alternative check: Consider typical store categories: bedding vs curtains/drapes are separate sections. Why Other Options Are Wrong: Mattress/Pillow/Bed sheet: All are bedding items. Common Pitfalls: Avoid grouping by fabric alone; function and placement are key. Final Answer: Curtain

Classification Questions