Classification – Odd one out (letter triplets – fixed +6 jumps): Which triplet breaks the pattern of +6 alphabet jumps in both gaps: GMS, EKQ, JOU, LRX?

Introduction / Context:
Letter-series classification often uses constant step sizes between consecutive letters. Here, three triplets follow the pattern “second letter = first + 6; third letter = second + 6.” One triplet does not. Convert letters to positions A=1, …, Z=26 and verify the step sizes.

Given Data / Assumptions:

• GMS → G(7)→M(13)=+6; M(13)→S(19)=+6.
• EKQ → E(5)→K(11)=+6; K(11)→Q(17)=+6.
• LRX → L(12)→R(18)=+6; R(18)→X(24)=+6.
• JOU → J(10)→O(15)=+5; O(15)→U(21)=+6.

Concept / Approach:
Compute the gaps. If both gaps equal +6, the triplet fits the rule. Any deviation in either gap breaks the pattern. JOU has +5 then +6, so it is the outlier.

Step-by-Step Solution:
1) Calculate differences for each option.2) Identify the sole non-conforming set: JOU.

Verification / Alternative check:
Reading backward yields −6 steps for the three valid triplets; JOU still fails to give equal-magnitude steps, confirming the mismatch from either direction.

Why Other Options Are Wrong:
GMS, EKQ, and LRX strictly maintain +6, +6.

Common Pitfalls:
Accepting “near” matches (like +5, +6). Classification requires exact rule conformity.

Final Answer:
JOU