Classification – Odd one out (mixed-case quartets – +1, −3, +1 pattern): Which string fails the +1, −3, +1 positional change: CdaB, VwtU, LmjK, RsqP?

Introduction / Context:
Ignore letter case and convert each character to its alphabet index (A/a=1 … Z/z=26). Three strings follow a consistent step pattern across their four letters: +1, then −3, then +1. One string deviates in the middle steps and is therefore the odd one out.

Given Data / Assumptions:

• C d a B → 3,4,1,2 → +1, −3, +1.
• V w t U → 22,23,20,21 → +1, −3, +1.
• L m j K → 12,13,10,11 → +1, −3, +1.
• R s q P → 18,19,17,16 → +1, −2, −1 (fails).

Concept / Approach:
Compute consecutive differences for each string and match against the target signature. The one that does not read (+1, −3, +1) is the outlier. RsqP reads +1, −2, −1, so it breaks the rule.

Step-by-Step Solution:
1) Translate letters → indices and take differences.2) Confirm three match (+1, −3, +1).3) Identify RsqP as the only mismatch.

Verification / Alternative check:
Reversing the strings flips the sign pattern; the mismatch persists for RsqP, confirming its difference regardless of direction.

Why Other Options Are Wrong:
CdaB, VwtU, LmjK all adhere exactly to the required differences.

Common Pitfalls:
Letting letter case distract you; positions are case-insensitive for this test.

Final Answer:
RsqP