Difficulty: Easy
Correct Answer: X
Explanation:
Introduction / Context:End seats and center seats are fixed; a single relative clue pins down the neighbor of P.
Given Data / Assumptions:
Concept / Approach:If A were at seat 1, “R to the left of A” would be impossible. Hence A must be seat 6 and P seat 1. Seats 3 and 4 are S and Z, leaving seats 2 and 5 for R and X.
Step-by-Step Solution:
A at 6; P at 1.S and Z at 3 and 4.Remaining: R and X at 2 and 5. The seat immediately to the right of P (seat 2) must be X (since R is not among the given options that could violate other constraints).Verification / Alternative check:Placing R at seat 2 still satisfies “R left of A,” leaving X as P’s right neighbor; options include X but not R.
Why Other Options Are Wrong:A is at the opposite end; S and Z are constrained to middle seats.
Common Pitfalls:Trying A at the left end contradicts “R to the left of A.”
Final Answer:X
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