Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A < Q < S). T is to the left of V, and V is to the left of D (T < V < D). Who sits in the middle?

Introduction / Context:Consecutive placement (D-A-B) anchors the middle of the sequence; remaining inequalities fix everyone else relative to that block.

Given Data / Assumptions:

• Consecutive block: D-A-B.
• A < Q < S.
• T < V < D.

Concept / Approach:Since V must be left of D, and T left of V, the left flank becomes T, V, D. With D-A-B consecutive and Q, S to the right of A (and B also to A’s right), a consistent sequence emerges.

Step-by-Step Solution:

Verification / Alternative check:Any attempt to move Q to the left of A violates A < Q; moving V to the right of D violates V < D.

Why Other Options Are Wrong:V and D are left of the center; Q is right of it.

Final Answer:A