Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A

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Solve this multiple-choice question and choose the correct option.

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Introduction / Context:Consecutive placement (D-A-B) anchors the middle of the sequence; remaining inequalities fix everyone else relative to that block. Given Data / Assumptions: Consecutive block: D-A-B. A < Q < S. T < V < D. Concept / Approach:Since V must be left of D, and T left of V, the left flank becomes T, V, D. With D-A-B consecutive and Q, S to the right of A (and B also to A’s right), a consistent sequence emerges. Step-by-Step Solution: One valid linearization is: T < V < D < A < B < Q < S.The middle (4th) position is A. Verification / Alternative check:Any attempt to move Q to the left of A violates A < Q; moving V to the right of D violates V < D. Why Other Options Are Wrong:V and D are left of the center; Q is right of it. Final Answer:A

Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A < Q < S). T is to the left of V, and V is to the left of D (T < V < D). Who sits in the middle?

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Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A &lt; Q &lt; S). T is to the left of V, and V is to the left of D (T &lt; V &lt; D). Who sits in the middle?

More Questions from Seating Arrangement

Discussion & Comments

Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A < Q < S). T is to the left of V, and V is to the left of D (T < V < D). Who sits in the middle?