Six members sit in one row. E is to the left of B but to the right of A (A < E < B). F is to the right of B but to the left of G (B < F < G), and G is to the left of C (G < C). Which two members occupy the central seats?

Introduction / Context:
Linking three local inequalities yields a strict left-to-right order for six members; the two central seats follow immediately.

Given Data / Assumptions:

• A < E < B.
• B < F < G.
• G < C.

Concept / Approach:
Combine the chains to get a total order.

Step-by-Step Solution:

Why Other Options Are Wrong:
A and E are left of center; G and C are right of center; F and G are consecutive but not both middle.

Final Answer:
B F