Five members sit in a row. A is to the left of B but to the right of C (C … A … B). D is to the right of B but to the left of E (B … D … E). Who is in the middle seat?

Introduction / Context:
Combine two local orderings into a single consistent left-to-right arrangement, then pick the central seat.

Given Data / Assumptions:

• A left of B and right of C ⇒ C < A < B.
• D right of B and left of E ⇒ B < D < E.
• Five distinct people: C, A, B, D, E.

Concept / Approach:
Chain the inequalities into one sequence.

Step-by-Step Solution:

Verification / Alternative check:
Any deviation would break one of the two given local orders.

Why Other Options Are Wrong:
C and A are left of the middle; D and E are right of it.

Common Pitfalls:
Placing D to the left of B or A to the right of B contradicts the clues.

Final Answer:
B