Six friends A, B, C, D, E, F sit in a row facing East. C is between A and E (A … C … E or E … C … A). B is immediately to the right of E and to the left of D (E–B–D consecutive). F is not at the right end. Who sits between B and C?

Difficulty: Medium

Correct Answer: D

Explanation:


Introduction / Context:
Consecutive block (E–B–D) plus “C between A and E” and the end restriction for F together force a unique layout.



Given Data / Assumptions:

  • Row positions 1–6 left to right; all face East.
  • E–B–D occupy three consecutive seats in that order.
  • C lies between A and E (in order E–C–A or A–C–E).
  • F is not at the rightmost seat.


Concept / Approach:
Place E–B–D starting at seats 2–4 to leave room for “C between A and E” to the right while keeping F off the right end. This yields a consistent, unique arrangement.



Step-by-Step Solution (one valid derivation):

Place E, B, D at seats 2, 3, 4.To satisfy “E … C … A”, set C at 5 and A at 6; then F must be at seat 1 (so F is not at right end).Row becomes: 1=F, 2=E, 3=B, 4=D, 5=C, 6=A.Between B (seat 3) and C (seat 5) sits D at seat 4.


Verification / Alternative check:
Any attempt to place F at seat 6 violates “F not at right end.” Shifting E–B–D block breaks the “C between A and E” condition.



Final Answer:
D

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