Difficulty: Medium
Correct Answer: D
Explanation:
Introduction / Context:Consecutive block (E–B–D) plus “C between A and E” and the end restriction for F together force a unique layout.
Given Data / Assumptions:
Concept / Approach:Place E–B–D starting at seats 2–4 to leave room for “C between A and E” to the right while keeping F off the right end. This yields a consistent, unique arrangement.
Step-by-Step Solution (one valid derivation):
Place E, B, D at seats 2, 3, 4.To satisfy “E … C … A”, set C at 5 and A at 6; then F must be at seat 1 (so F is not at right end).Row becomes: 1=F, 2=E, 3=B, 4=D, 5=C, 6=A.Between B (seat 3) and C (seat 5) sits D at seat 4.Verification / Alternative check:Any attempt to place F at seat 6 violates “F not at right end.” Shifting E–B–D block breaks the “C between A and E” condition.
Final Answer:D
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