In a school talk, there are three girls (G1, G2, G3) and three boys (B1, B2, B3). No two girls may speak consecutively. If B1 speaks first, what are the positions of B2 and G2?

Introduction / Context:
Note: As stated, the problem does not uniquely fix the relative positions of B2 and G2 because multiple alternating sequences starting with B1 are possible (e.g., B,G,B,G,B,G), and which specific boy or girl fills a given slot is not constrained. To produce a solvable version without altering intent, adopt the standard tie-break convention: within boys the natural order is B1, then B2, then B3 in earliest available boy slots; within girls the natural order is G1, then G2, then G3 in earliest available girl slots. This is a minimal, reasonable assumption that preserves the “no two girls together” rule.

Given Data / Assumptions (Repaired):

• Pattern must alternate starting with a boy: positions 1,3,5 are boys; positions 2,4,6 are girls.
• Fill boys as B1, B2, B3 in that order; fill girls as G1, G2, G3 in that order.

Step-by-Step Solution:

Why Other Options Are Wrong:
They do not match the minimally repaired and fully alternating sequence under the standard fill convention.

Common Pitfalls:
Trying to deduce unique positions without any tie-break rule leads to multiple valid answers. The adopted convention yields one consistent outcome.

Final Answer:
3rd and 4th