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Seven members sit in one row. X is to the left of Y and to the right of O (O < X < Y). P is to the right of Y but to the left of N (Y < P < N). M is to the left of Z, and Z is to the left of O (M < Z < O). Who sits in the middle?

Difficulty: Medium

Correct Answer: X

Explanation:

Introduction / Context:All clues are strict left–right inequalities that chain into a single total order of seven people, revealing the central position.

Given Data / Assumptions:

O < X < Y.
Y < P < N.
M < Z < O.

Concept / Approach:Concatenate the three inequalities into a single sequence from leftmost to rightmost.

Step-by-Step Solution:

M < Z < O < X < Y < P < N.The middle (4th) seat belongs to X.

Verification / Alternative check:Any deviation breaks at least one of the inequalities (e.g., moving Z to the right of O violates Z < O).

Why Other Options Are Wrong:Z, O lie left of center; Y, P lie right of it.

Common Pitfalls:Failing to maintain the M–Z–O segment to the left of O–X–Y.

Seven members sit in one row. X is to the left of Y and to the right of O (O < X < Y). P is to the right of Y but to the left of N (Y < P < N). M is to the left of Z, and Z is to the left of O (M < Z < O). Who sits in the middle?

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Discussion & Comments

Seven members sit in one row. X is to the left of Y and to the right of O (O &lt; X &lt; Y). P is to the right of Y but to the left of N (Y &lt; P &lt; N). M is to the left of Z, and Z is to the left of O (M &lt; Z &lt; O). Who sits in the middle?

More Questions from Seating Arrangement

Discussion & Comments

Seven members sit in one row. X is to the left of Y and to the right of O (O < X < Y). P is to the right of Y but to the left of N (Y < P < N). M is to the left of Z, and Z is to the left of O (M < Z < O). Who sits in the middle?