Seven members sit in one row. X is to the left of Y and to the right of O (O < X < Y). P is to the right of Y but to the left of N (Y < P < N). M is to the left of Z, and Z is to the left of O (M < Z < O). Who sits in the middle?

Introduction / Context:
All clues are strict left–right inequalities that chain into a single total order of seven people, revealing the central position.

Given Data / Assumptions:

• O < X < Y.
• Y < P < N.
• M < Z < O.

Concept / Approach:
Concatenate the three inequalities into a single sequence from leftmost to rightmost.

Step-by-Step Solution:

Verification / Alternative check:
Any deviation breaks at least one of the inequalities (e.g., moving Z to the right of O violates Z < O).

Why Other Options Are Wrong:
Z, O lie left of center; Y, P lie right of it.

Common Pitfalls:
Failing to maintain the M–Z–O segment to the left of O–X–Y.

Final Answer:
X