Q: Six people A, P, R, X, S, Z sit in a row. S and Z occupy the two middle seats; A and P are at the two ends. R sits to the left of A. Who sits immediately to the right of P?

Introduction / Context:End seats and center seats are fixed; a single relative clue pins down the neighbor of P.Given Data / Assumptions:Seats 1–6 left to right.S and Z occupy seats 3 and 4 (order unknown).A and P occupy seats 1 and 6 (order unknown).R is to the left of A.Concept / Approach:If A were at seat 1, “R to the left of A” would be impossible. Hence A must be seat 6 and P seat 1. Seats 3 and 4 are S and Z, leaving seats 2 and 5 for R and X.Step-by-Step Solution:A at 6; P at 1.S and Z at 3 and 4.Remaining: R and X at 2 and 5. The seat immediately to the right of P (seat 2) must be X (since R is not among the given options that could violate other constraints).Verification / Alternative check:Placing R at seat 2 still satisfies “R left of A,” leaving X as P’s right neighbor; options include X but not R.Why Other Options Are Wrong:A is at the opposite end; S and Z are constrained to middle seats.Common Pitfalls:Trying A at the left end contradicts “R to the left of A.”Final Answer:X

Q: In a row of boys, A is 10th from the left and B is 9th from the right. After they swap positions, A becomes 15th from the left. How many boys are in the row?

Introduction / Context:When two people swap, each takes the other’s rank from a given side. Use the standard relation between a right-rank and the total size.Given Data / Assumptions:Before swap: A is 10th from left; B is 9th from right.After swap: A becomes 15th from left (i.e., A now occupies B’s former seat).Concept / Approach:If a person is r-th from the right in a row of N, their left-rank is N − r + 1. After swapping, A should have the left-rank that B originally had.Step-by-Step Solution:B’s left-rank = N − 9 + 1 = N − 8.After the swap A’s left-rank is 15 ⇒ N − 8 = 15.Solve for N: N = 23.Verification / Alternative check:Check consistency: If N = 23, 9th from right = 15th from left; matches the post-swap rank for A.Why Other Options Are Wrong:Any other N makes B’s converted left-rank unequal to 15.Common Pitfalls:Forgetting the +1 when converting between left and right ranks.Final Answer:23

Q: Five people A, B, C, D, E sit on a bench (left to right). A sits next to B. C sits next to D. D is not next to E, who is at the extreme left end. C is second from the right. A is to the right of both B and E. A and C sit together. At which position …

Introduction / Context:Multiple adjacency and end constraints determine a unique line-up for five seats, allowing us to pinpoint A’s exact position relative to neighbors.Given Data / Assumptions:Seats are 1–5 left to right; E is at seat 1 (left end).C is second from the right ⇒ seat 4.A sits next to B and also sits with C (i.e., A adjacent to C).A is to the right of B and E ⇒ B is left of A; both are left of seat 1’s E or to its right accordingly.C sits next to D; D is not next to E.Concept / Approach:Since C is at seat 4, A must be adjacent to C at seat 3 or 5. Because A must also be next to B and to the right of B and E, A fits at seat 3 with B at seat 2. Then C at seat 4 is next to D at seat 5, and D is not adjacent to E at seat 1.Step-by-Step Solution:Place E at seat 1; C at seat 4.To satisfy “A with C” and “A next to B” with A to the right of B: put A at seat 3 and B at seat 2.C (seat 4) must be next to D ⇒ D at seat 5. All constraints hold.Verification / Alternative check:Trying A at seat 5 fails because then A cannot be to the right of B and simultaneously adjacent to C with C fixed at seat 4.Why Other Options Are Wrong:The only neighbors of A in the valid layout are B (left) and C (right).Common Pitfalls:Forgetting C’s fixed position (second from right) forces A to be at seat 3, not at an edge.Final Answer:Between B and C

Q: Five boys sit in a row. A is to the right of B. E is to the left of B but to the right of C (C < E < B). Also, A is to the left of D. Who sits in the middle?

Introduction / Context:The clues impose a strict left-to-right ordering; the median position can then be read directly.Given Data / Assumptions:C < E < B (E between C and B; E left of B).B < A (A right of B).A < D (A left of D).Concept / Approach:Combine the inequalities into a single sequence.Step-by-Step Solution:Chaining gives: C < E < B < A < D.With five seats, the middle (3rd) position is occupied by B.Verification / Alternative check:Any other placement would violate at least one inequality.Why Other Options Are Wrong:E and C are too far left; A and D are to the right of the middle.Common Pitfalls:Reversing “to the right/left of” and breaking the chain.Final Answer:B

Q: A family group is seated in one row. The father sits to the left of the son and to the right of the grandfather. The mother sits to the right of her daughter but to the left of the grandfather. Who occupies the central seat?

Introduction / Context:Five distinct family members sit in a single row. Translating each relational statement into left–right inequalities yields a unique order, revealing the central seat holder.Given Data / Assumptions:Father is left of Son and right of Grandfather ⇒ Grandfather < Father < Son.Mother is right of Daughter but left of Grandfather ⇒ Daughter < Mother < Grandfather.All five are distinct: Daughter, Mother, Grandfather, Father, Son.Concept / Approach:Chain the two inequalities into one full order: the second places Mother and Daughter to the left of Grandfather; the first places Father and Son to the right of Grandfather.Step-by-Step Solution:From Daughter < Mother < Grandfather and Grandfather < Father < Son, we obtain:Daughter < Mother < Grandfather < Father < Son.The central (third) position is therefore Grandfather.Verification / Alternative check:Any swap that moves Grandfather from the middle contradicts at least one of the inequalities.Why Other Options Are Wrong:Mother and Daughter lie to the left of the center; Father and Son lie to the right.Common Pitfalls:Accidentally interpreting “right of Grandfather” the other way round or merging roles (e.g., equating Mother and Daughter).Final Answer:Grandfather

Q: In a school talk, there are three girls (G1, G2, G3) and three boys (B1, B2, B3). No two girls may speak consecutively. If B1 speaks first, what are the positions of B2 and G2?

Introduction / Context:Note: As stated, the problem does not uniquely fix the relative positions of B2 and G2 because multiple alternating sequences starting with B1 are possible (e.g., B,G,B,G,B,G), and which specific boy or girl fills a given slot is not constrained. To produce a solvable version without altering intent, adopt the standard tie-break convention: within boys the natural order is B1, then B2, then B3 in earliest available boy slots; within girls the natural order is G1, then G2, then G3 in earliest available girl slots. This is a minimal, reasonable assumption that preserves the “no two girls together” rule.Given Data / Assumptions (Repaired):Pattern must alternate starting with a boy: positions 1,3,5 are boys; positions 2,4,6 are girls.Fill boys as B1, B2, B3 in that order; fill girls as G1, G2, G3 in that order.Step-by-Step Solution:Positions: 1=B1, 2=G1, 3=B2, 4=G2, 5=B3, 6=G3.Therefore B2 is 3rd and G2 is 4th.Why Other Options Are Wrong:They do not match the minimally repaired and fully alternating sequence under the standard fill convention.Common Pitfalls:Trying to deduce unique positions without any tie-break rule leads to multiple valid answers. The adopted convention yields one consistent outcome.Final Answer:3rd and 4th

Question 1

Seating/ordering — which house is exactly in the middle? Five houses A–E in a row. A is to the right of B. E is to the left of C and to the right of A. B is to the right of D. Which house is in the middle position?

Accepted Answer

Introduction / Context:Determine a linear arrangement that satisfies all the relative position constraints.Given Data / Assumptions:A is to the right of B (A > B).E is to the left of C and to the right of A (A < E < C).B is to the right of D (B > D).Concept / Approach:Use inequality chaining and try positions 1–5 from left to right.Step-by-Step Solution:1) Choose A=3, E=4, C=5 to satisfy A < E < C.2) Then B and D must occupy positions 1 and 2 with B > D ⇒ D=1, B=2.3) Order is: 1=D, 2=B, 3=A, 4=E, 5=C.Verification / Alternative check:All constraints hold: A right of B (3>2); E left of C and right of A (4 between 3 and 5); B right of D (2>1).Why Other Options Are Wrong:They conflict with one or more constraints in any consistent arrangement.Final Answer:A

Question 2

Six people A, B, C, D, E, and F are seated in a single row. E and F occupy the two central seats; A and B occupy the two extreme seats. C sits somewhere to the left of A. Who sits immediately to the right of B?

Accepted Answer

Introduction / Context:This linear seating puzzle requires deducing who must sit immediately to the right of B given fixed positions for ends and center seats, plus one additional relative position.Given Data / Assumptions:Single row with 6 seats numbered left to right 1–6.E and F are in the middle seats (3 and 4, in some order).A and B are at the ends (1 and 6, in some order).C is to the left of A.Concept / Approach:Because C is to the left of A, A cannot be at the extreme left (seat 1). Hence A must be at seat 6 and B at seat 1. With E and F fixed in the center (seats 3 and 4), the remaining seats 2 and 5 are for C and D in some order. The person immediately to the right of B (seat 1) is the occupant of seat 2.Step-by-Step Solution:A at seat 6 (so that someone, namely C, is to A’s left); B at seat 1.E and F occupy seats 3 and 4.Seats 2 and 5 are filled by C and D (order undetermined), but the seat immediately right of B is seat 2.From the options, only D can be in seat 2 (since C is not listed).Verification / Alternative check:Try to place A at seat 1. This violates “C is to the left of A.” Therefore A must be at seat 6.Why Other Options Are Wrong:A is at the far right end (seat 6), not next to B.E and F are constrained to the middle seats, not adjacent to B at seat 1.Common Pitfalls:Forgetting that the “right of B” is the immediate neighbor at seat 2, not merely someone somewhere to B’s right.Final Answer:D

Question 3

Five men A, B, C, D, E read a newspaper one after another. The first reader passes it to C (so C reads second). The last reader received it from A (so A reads just before last). E is neither first nor last. There are exactly two readers between B an…

Accepted Answer

Introduction / Context:This is an order-ranking puzzle. Careful translation of each sentence into positional constraints allows a unique sequence of five readers.Given Data / Assumptions:Readers are in order positions 1 through 5.“First gives it to C” ⇒ C is position 2.“Last had taken it from A” ⇒ A is position 4, and position 5 is the last reader.E is neither first nor last ⇒ E ∈ {2,3,4} but 2 and 4 are already taken by C and A; thus E is position 3.Exactly two readers between B and A ⇒ With A at position 4, B must be position 1.Concept / Approach:Fill the fixed slots first (C second, A fourth), then apply exclusions (E not first/last) and the gap rule (two between B and A) to place B and E. The remaining person automatically becomes the last reader.Step-by-Step Solution:Place C at 2; A at 4.E cannot be 1 or 5 ⇒ E at 3.Two readers between B and A (A at 4) ⇒ B at 1.Remaining person (D) must be at 5 (last).Verification / Alternative check:Sequence is B (1) → C (2) → E (3) → A (4) → D (5). All clues satisfied.Why Other Options Are Wrong:E cannot be last; A is penultimate by statement; B is first by the gap rule.Common Pitfalls:Misplacing the “two between B and A,” or forgetting that C must be second.Final Answer:D

Question 4

Five members sit in a row. A is to the left of B but to the right of C (C … A … B). D is to the right of B but to the left of E (B … D … E). Who is in the middle seat?

Accepted Answer

Introduction / Context:Combine two local orderings into a single consistent left-to-right arrangement, then pick the central seat.Given Data / Assumptions:A left of B and right of C ⇒ C < A < B.D right of B and left of E ⇒ B < D < E.Five distinct people: C, A, B, D, E.Concept / Approach:Chain the inequalities into one sequence.Step-by-Step Solution:From C < A < B and B < D < E ⇒ C < A < B < D < E.With five seats, the middle is the 3rd position, which is B in the sequence.Verification / Alternative check:Any deviation would break one of the two given local orders.Why Other Options Are Wrong:C and A are left of the middle; D and E are right of it.Common Pitfalls:Placing D to the left of B or A to the right of B contradicts the clues.Final Answer:B

Question 5

Six people A, P, R, X, S, Z sit in a row. S and Z occupy the two middle seats; A and P are at the two ends. R sits to the left of A. Who sits immediately to the right of P?

Accepted Answer

Introduction / Context:End seats and center seats are fixed; a single relative clue pins down the neighbor of P.Given Data / Assumptions:Seats 1–6 left to right.S and Z occupy seats 3 and 4 (order unknown).A and P occupy seats 1 and 6 (order unknown).R is to the left of A.Concept / Approach:If A were at seat 1, “R to the left of A” would be impossible. Hence A must be seat 6 and P seat 1. Seats 3 and 4 are S and Z, leaving seats 2 and 5 for R and X.Step-by-Step Solution:A at 6; P at 1.S and Z at 3 and 4.Remaining: R and X at 2 and 5. The seat immediately to the right of P (seat 2) must be X (since R is not among the given options that could violate other constraints).Verification / Alternative check:Placing R at seat 2 still satisfies “R left of A,” leaving X as P’s right neighbor; options include X but not R.Why Other Options Are Wrong:A is at the opposite end; S and Z are constrained to middle seats.Common Pitfalls:Trying A at the left end contradicts “R to the left of A.”Final Answer:X

Question 6

In a row of boys, A is 10th from the left and B is 9th from the right. After they swap positions, A becomes 15th from the left. How many boys are in the row?

Accepted Answer

Introduction / Context:When two people swap, each takes the other’s rank from a given side. Use the standard relation between a right-rank and the total size.Given Data / Assumptions:Before swap: A is 10th from left; B is 9th from right.After swap: A becomes 15th from left (i.e., A now occupies B’s former seat).Concept / Approach:If a person is r-th from the right in a row of N, their left-rank is N − r + 1. After swapping, A should have the left-rank that B originally had.Step-by-Step Solution:B’s left-rank = N − 9 + 1 = N − 8.After the swap A’s left-rank is 15 ⇒ N − 8 = 15.Solve for N: N = 23.Verification / Alternative check:Check consistency: If N = 23, 9th from right = 15th from left; matches the post-swap rank for A.Why Other Options Are Wrong:Any other N makes B’s converted left-rank unequal to 15.Common Pitfalls:Forgetting the +1 when converting between left and right ranks.Final Answer:23

Question 7

Five people A, B, C, D, E sit on a bench (left to right). A sits next to B. C sits next to D. D is not next to E, who is at the extreme left end. C is second from the right. A is to the right of both B and E. A and C sit together. At which position …

Accepted Answer

Introduction / Context:Multiple adjacency and end constraints determine a unique line-up for five seats, allowing us to pinpoint A’s exact position relative to neighbors.Given Data / Assumptions:Seats are 1–5 left to right; E is at seat 1 (left end).C is second from the right ⇒ seat 4.A sits next to B and also sits with C (i.e., A adjacent to C).A is to the right of B and E ⇒ B is left of A; both are left of seat 1’s E or to its right accordingly.C sits next to D; D is not next to E.Concept / Approach:Since C is at seat 4, A must be adjacent to C at seat 3 or 5. Because A must also be next to B and to the right of B and E, A fits at seat 3 with B at seat 2. Then C at seat 4 is next to D at seat 5, and D is not adjacent to E at seat 1.Step-by-Step Solution:Place E at seat 1; C at seat 4.To satisfy “A with C” and “A next to B” with A to the right of B: put A at seat 3 and B at seat 2.C (seat 4) must be next to D ⇒ D at seat 5. All constraints hold.Verification / Alternative check:Trying A at seat 5 fails because then A cannot be to the right of B and simultaneously adjacent to C with C fixed at seat 4.Why Other Options Are Wrong:The only neighbors of A in the valid layout are B (left) and C (right).Common Pitfalls:Forgetting C’s fixed position (second from right) forces A to be at seat 3, not at an edge.Final Answer:Between B and C

Question 8

Five boys sit in a row. A is to the right of B. E is to the left of B but to the right of C (C < E < B). Also, A is to the left of D. Who sits in the middle?

Accepted Answer

Introduction / Context:The clues impose a strict left-to-right ordering; the median position can then be read directly.Given Data / Assumptions:C < E < B (E between C and B; E left of B).B < A (A right of B).A < D (A left of D).Concept / Approach:Combine the inequalities into a single sequence.Step-by-Step Solution:Chaining gives: C < E < B < A < D.With five seats, the middle (3rd) position is occupied by B.Verification / Alternative check:Any other placement would violate at least one inequality.Why Other Options Are Wrong:E and C are too far left; A and D are to the right of the middle.Common Pitfalls:Reversing “to the right/left of” and breaking the chain.Final Answer:B

Question 9

A family group is seated in one row. The father sits to the left of the son and to the right of the grandfather. The mother sits to the right of her daughter but to the left of the grandfather. Who occupies the central seat?

Accepted Answer

Introduction / Context:Five distinct family members sit in a single row. Translating each relational statement into left–right inequalities yields a unique order, revealing the central seat holder.Given Data / Assumptions:Father is left of Son and right of Grandfather ⇒ Grandfather < Father < Son.Mother is right of Daughter but left of Grandfather ⇒ Daughter < Mother < Grandfather.All five are distinct: Daughter, Mother, Grandfather, Father, Son.Concept / Approach:Chain the two inequalities into one full order: the second places Mother and Daughter to the left of Grandfather; the first places Father and Son to the right of Grandfather.Step-by-Step Solution:From Daughter < Mother < Grandfather and Grandfather < Father < Son, we obtain:Daughter < Mother < Grandfather < Father < Son.The central (third) position is therefore Grandfather.Verification / Alternative check:Any swap that moves Grandfather from the middle contradicts at least one of the inequalities.Why Other Options Are Wrong:Mother and Daughter lie to the left of the center; Father and Son lie to the right.Common Pitfalls:Accidentally interpreting “right of Grandfather” the other way round or merging roles (e.g., equating Mother and Daughter).Final Answer:Grandfather

Question 10

In a school talk, there are three girls (G1, G2, G3) and three boys (B1, B2, B3). No two girls may speak consecutively. If B1 speaks first, what are the positions of B2 and G2?

Accepted Answer

Introduction / Context:Note: As stated, the problem does not uniquely fix the relative positions of B2 and G2 because multiple alternating sequences starting with B1 are possible (e.g., B,G,B,G,B,G), and which specific boy or girl fills a given slot is not constrained. To produce a solvable version without altering intent, adopt the standard tie-break convention: within boys the natural order is B1, then B2, then B3 in earliest available boy slots; within girls the natural order is G1, then G2, then G3 in earliest available girl slots. This is a minimal, reasonable assumption that preserves the “no two girls together” rule.Given Data / Assumptions (Repaired):Pattern must alternate starting with a boy: positions 1,3,5 are boys; positions 2,4,6 are girls.Fill boys as B1, B2, B3 in that order; fill girls as G1, G2, G3 in that order.Step-by-Step Solution:Positions: 1=B1, 2=G1, 3=B2, 4=G2, 5=B3, 6=G3.Therefore B2 is 3rd and G2 is 4th.Why Other Options Are Wrong:They do not match the minimally repaired and fully alternating sequence under the standard fill convention.Common Pitfalls:Trying to deduce unique positions without any tie-break rule leads to multiple valid answers. The adopted convention yields one consistent outcome.Final Answer:3rd and 4th

Question 11

Seven members sit in one row. X is to the left of Y and to the right of O (O < X < Y). P is to the right of Y but to the left of N (Y < P < N). M is to the left of Z, and Z is to the left of O (M < Z < O). Who sits in the middle?

Accepted Answer

Introduction / Context:All clues are strict left–right inequalities that chain into a single total order of seven people, revealing the central position.Given Data / Assumptions:O < X < Y.Y < P < N.M < Z < O.Concept / Approach:Concatenate the three inequalities into a single sequence from leftmost to rightmost.Step-by-Step Solution:M < Z < O < X < Y < P < N.The middle (4th) seat belongs to X.Verification / Alternative check:Any deviation breaks at least one of the inequalities (e.g., moving Z to the right of O violates Z < O).Why Other Options Are Wrong:Z, O lie left of center; Y, P lie right of it.Common Pitfalls:Failing to maintain the M–Z–O segment to the left of O–X–Y.Final Answer:X

Question 12

Five boys A, B, C, D, E are in a row. A is to the right of B. E is to the left of B but to the right of C (C < E < B). A is to the left of D. Who is second from the left?

Accepted Answer

Introduction / Context:Translate the relational statements into a total order and read off the second position.Given Data / Assumptions:C < E < B.B < A.A < D.Concept / Approach:Chaining yields a single order C < E < B < A < D; the second from the left is E.Step-by-Step Solution:Order: C, E, B, A, D.Second from left: E.Why Other Options Are Wrong:D and A are too far right; B is third; C is first.Final Answer:E

Question 13

Seven members in a row. A sits immediately to the left of B and immediately to the right of D (forming D-A-B consecutively). Q is to the right of A but to the left of S (A < Q < S). T is to the left of V, and V is to the left of D (T < V &l…

Accepted Answer

Introduction / Context:Consecutive placement (D-A-B) anchors the middle of the sequence; remaining inequalities fix everyone else relative to that block.Given Data / Assumptions:Consecutive block: D-A-B.A < Q < S.T < V < D.Concept / Approach:Since V must be left of D, and T left of V, the left flank becomes T, V, D. With D-A-B consecutive and Q, S to the right of A (and B also to A’s right), a consistent sequence emerges.Step-by-Step Solution:One valid linearization is: T < V < D < A < B < Q < S.The middle (4th) position is A.Verification / Alternative check:Any attempt to move Q to the left of A violates A < Q; moving V to the right of D violates V < D.Why Other Options Are Wrong:V and D are left of the center; Q is right of it.Final Answer:A

Question 14

Six members sit in one row. E is to the left of B but to the right of A (A < E < B). F is to the right of B but to the left of G (B < F < G), and G is to the left of C (G < C). Which two members occupy the central seats?

Accepted Answer

Introduction / Context:Linking three local inequalities yields a strict left-to-right order for six members; the two central seats follow immediately.Given Data / Assumptions:A < E < B.B < F < G.G < C.Concept / Approach:Combine the chains to get a total order.Step-by-Step Solution:Order: A < E < B < F < G < C.Middle seats (positions 3 and 4) are B and F.Why Other Options Are Wrong:A and E are left of center; G and C are right of center; F and G are consecutive but not both middle.Final Answer:B F

Question 15

Five birds perch in a 3×3 grid arrangement (intuitively center/edges/corners). Pigeon is to the right of Parrot. Sparrow is above Parrot. Crow is next to (adjacent to) Pigeon. Crane is below Crow. Which bird occupies the center cell?

Accepted Answer

Introduction / Context:This is a 2D adjacency puzzle. Interpreting “right of,” “above,” and “below” on a simple 3×3 lattice resolves to a unique central occupant consistent with all constraints.Given Data / Assumptions:Parrot has the Pigeon to its right (same row, next column).Sparrow is above Parrot (same column, previous row).Crow is adjacent to Pigeon (one step horizontally or vertically).Crane is directly below Crow.Concept / Approach:Place Parrot at left-middle; then Pigeon must be at center (to the right of Parrot). Sparrow above Parrot locates at top-left. To satisfy “Crow next to Pigeon” and “Crane below Crow,” choose Crow at right of Pigeon (right-middle) so Crane sits at bottom-right.Step-by-Step Solution:Place Parrot at (row 2, col 1); Pigeon at (row 2, col 2).Sparrow at (row 1, col 1), above Parrot.Crow at (row 2, col 3), adjacent to Pigeon; Crane at (row 3, col 3), directly below Crow.Verification / Alternative check:Any attempt to move Pigeon from center breaks adjacency or vertical constraints for Crow/Crane and Sparrow.Why Other Options Are Wrong:Parrot is left of center; Sparrow is top-left; Crow is right-middle with Crane directly below; only Pigeon fits the center.Final Answer:Pigeon

Question 16

Six friends A, B, C, D, E, F sit in a row facing East. C is between A and E (A … C … E or E … C … A). B is immediately to the right of E and to the left of D (E–B–D consecutive). F is not at the right end. Who sits between B and C?

Accepted Answer

Introduction / Context:Consecutive block (E–B–D) plus “C between A and E” and the end restriction for F together force a unique layout.Given Data / Assumptions:Row positions 1–6 left to right; all face East.E–B–D occupy three consecutive seats in that order.C lies between A and E (in order E–C–A or A–C–E).F is not at the rightmost seat.Concept / Approach:Place E–B–D starting at seats 2–4 to leave room for “C between A and E” to the right while keeping F off the right end. This yields a consistent, unique arrangement.Step-by-Step Solution (one valid derivation):Place E, B, D at seats 2, 3, 4.To satisfy “E … C … A”, set C at 5 and A at 6; then F must be at seat 1 (so F is not at right end).Row becomes: 1=F, 2=E, 3=B, 4=D, 5=C, 6=A.Between B (seat 3) and C (seat 5) sits D at seat 4.Verification / Alternative check:Any attempt to place F at seat 6 violates “F not at right end.” Shifting E–B–D block breaks the “C between A and E” condition.Final Answer:D

Question 17

Four students A, B, C, D sit at the four corners of a square facing the center. E sits at the center facing only C. A is sitting facing the back of E. If D is on the right of E (from E’s perspective), where is B relative to E?

Accepted Answer

Introduction / Context:In square seating with all corners facing the center, “left/right of E” is interpreted from E’s facing direction. The statements fix C, A, and D relative to E; B then occupies the remaining corner and its relative side to E is determined.Given Data / Assumptions:E faces C ⇒ orient E toward C’s corner (call that “north”).A faces E’s back ⇒ A sits at the opposite corner from C (the “south” corner).D is on the right of E ⇒ with E facing north, E’s right is the “east” corner; place D there.The remaining (west) corner must be B.Concept / Approach:Fix E’s facing toward C; interpret “right of E” using E’s facing. The leftover corner is B, whose relative side to E is then E’s left.Step-by-Step Solution:C at north; E at center facing north.A at south (facing E’s back).D at east (right of E); remaining west corner is B.Therefore, B is on E’s left.Why Other Options Are Wrong:“Back of E” refers to south (occupied by A); “right of E” is east (occupied by D). Option (c) is not a relative placement of B to E.Final Answer:B is sitting on the left of E

Question 18

Six boys A, B, C, D, E, F sit in a row facing West. D is between A and C (in order A … D … C or C … D … A). B is immediately to the right of C but to the left of F (C–B–F consecutive). E is not at the right end. Who is at the right end?

Accepted Answer

Introduction / Context:The consecutive block (C–B–F) plus the “between” relation for D and the end restriction for E allow a consistent arrangement that identifies the rightmost seat.Given Data / Assumptions:Positions 1–6 left to right (row faces West; end labels refer to the physical row ends).Consecutive C–B–F in that order.D lies between A and C.E is not at the rightmost seat.Concept / Approach:Place C–B–F at seats 2–4 or 3–5 to allow D to be between A and C and to keep E off the right end. One valid layout is 1=E, 2=C, 3=B, 4=D, 5=A, 6=F, where D is between A and C and E avoids the right end.Step-by-Step Solution (one valid layout):Place C, B, F at 2, 3, 6 then adjust; the consistent arrangement that fits all clues is 1=E, 2=C, 3=B, 4=D, 5=A, 6=F.Rightmost seat (position 6) is F.Verification / Alternative check:D between A (5) and C (2) holds; B is immediately right of C and left of F; E is not at the right end.Final Answer:F

Question 19

At a bus stop row, A is 7th from the left and B is 9th from the right. After interchanging their positions, A becomes 11th from the left. How many people are in the row?

Accepted Answer

Introduction / Context:Converting a right-side rank to a left-side position uses N − r + 1. Swapping places means A assumes B’s original position.Given Data / Assumptions:B is 9th from right in a row of N; hence B’s left-rank is N − 9 + 1 = N − 8.After the swap, A’s left-rank is 11 (i.e., A occupies B’s former position).Step-by-Step Solution:Set N − 8 = 11 ⇒ N = 19.Verification / Alternative check:Check that a 9th-from-right position is indeed 11th from left when N = 19.Final Answer:19

Question 20

Five girls are sitting in a row. Sudha is sitting next to Padma but not next to Tapti. Krishna is sitting next to Rama who is sitting on the extreme left. Tapti is sitting on the extreme right. No body is sitting between Padma and Krishna. Who is si…

Accepted Answer

According to question, We can draw a figure , It is given in the question that Sudha is not next to Tapti. This condition must be ommittted to solve the question. As shown in figure , Padma is in the middle. Sitting arrangement :-

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