Ranking test – family ages ordering: Seema's younger brother Sohan is older than Seeta. Sweta is younger than Deepti but older than Seema. From these facts, who is the eldest among Deepti, Sweta, Seema, Sohan, and Seeta?

Introduction / Context:
This is a classic ranking/ordering puzzle involving relative ages. We must translate comparative statements into an ordered chain and identify the oldest (maximum) element.

Given Data / Assumptions:

• Sohan is Seema's younger brother ⇒ Sohan is younger than Seema.
• Sohan is older than Seeta ⇒ Sohan > Seeta.
• Sweta is younger than Deepti but older than Seema ⇒ Deepti > Sweta > Seema.
• All people are distinct individuals; ages are comparable (no ties stated).

Concept / Approach:
Convert each comparison into a chain and then merge the chains carefully. The symbol “>” means “older than.”

Step-by-Step Solution:

Verification / Alternative check:
Every statement is satisfied by the merged chain: Sohan younger than Seema, yet older than Seeta; Sweta between Deepti and Seema; Deepti above all those three. No conflicts appear.

Why Other Options Are Wrong:
Seema is below Sweta; Sweta is below Deepti; Seeta is second youngest. Hence none of them is the eldest.

Common Pitfalls:
Forgetting “younger brother” implies strict order, not equality; or reversing “older than/younger than.”

Final Answer:
Deepti