Tallest building: Four buildings A, B, C, D have distinct heights. A is only higher than D. B is shorter than C but higher than A. Which building is the highest?

Difficulty: Easy

Correct Answer: C

Explanation:


Introduction / Context:
We are to find the maximum (tallest) in a partially ordered set of four items using concise comparative statements.



Given Data / Assumptions:

  • A is only higher than D ⇒ A > D and A < (B, C).
  • B is shorter than C but higher than A ⇒ C > B > A.
  • All heights are distinct.


Concept / Approach:
Combine the inequalities: C sits above B, which sits above A, which sits above D. Therefore, C is the tallest and D is the shortest.



Step-by-Step Ordering:

From “A only higher than D” we place A above D and below both B and C.From “B shorter than C but higher than A,” place B between C and A.Final chain: C > B > A > D.


Verification / Alternative check:
Every original relation is satisfied by C > B > A > D.


Why Other Options Are Wrong:

  • A, B, D: Not the maximum in the derived chain.
  • None of these: A specific correct choice exists (C).


Common Pitfalls:
Misinterpreting “only higher than D” (it fixes A exactly one place above D and below the other two).


Final Answer:
C

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