Ranking test – totals of two separate rows: Row–1: Jeevan is 7th from the start and 11th from the end. Row–2: Vikas is 10th from the start and 12th from the end. How many boys are there in both rows together?

Difficulty: Easy

Correct Answer: 38

Explanation:


Introduction / Context:
Each row's total can be found from a single student’s top and bottom ranks using the same identity as earlier; then we add the two row totals.



Given Data / Assumptions:

  • Row–1 (Jeevan): top 7th, bottom 11th.
  • Row–2 (Vikas): top 10th, bottom 12th.


Concept / Approach:
For each row: N = top_rank + bottom_rank − 1. Sum both Ns.



Step-by-Step Solution:

Row–1 total = 7 + 11 − 1 = 17.Row–2 total = 10 + 12 − 1 = 21.Combined = 17 + 21 = 38.


Verification / Alternative check:
The counts are independent across rows; nothing in the statement suggests shared students.



Why Other Options Are Wrong:
40 and 32 arise from arithmetic slips; “Cannot be determined” is incorrect because each row’s total is uniquely determined.



Common Pitfalls:
Missing the −1 in each row; adding ranks and subtracting −1 only once.



Final Answer:
38

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