Ranking in a row (facing North): Ritesh is 12th from the left end. Sudhir is 22nd from the right end and sits 4 positions to the right of Ritesh. Find the total number of children in the row.

Introduction / Context:
This is a classic single-row ranking problem. Two positions are given from opposite ends, and a relative offset between the two people is also provided. We need to convert between left-rank and right-rank to compute the total strength of the row.

Given Data / Assumptions:

• Row faces North (orientation does not affect left/right counting, but confirms standard convention).
• Ritesh is 12th from the left.
• Sudhir is 22nd from the right.
• Sudhir is 4th to the right of Ritesh (i.e., Sudhir's left-rank = Ritesh's left-rank + 4).

Concept / Approach:
Use the identity: right_rank = N − left_rank + 1, where N is the total. Express Sudhir's left-rank from the relative information, then equate it to the formula derived from his right-rank to solve for N.

Step-by-Step Solution:

Verification / Alternative check:
Convert Sudhir's left-rank back to right with N = 37: right = 37 − 16 + 1 = 22, matching the given.

Why Other Options Are Wrong:

• 34, 35, 36: Each fails to satisfy the conversion right = N − 16 + 1 = 22.
• None of these: There is a valid choice (37).

Common Pitfalls:
Confusing “to the right of” with a right-end rank; or forgetting the +1 in right = N − left + 1.

Final Answer:
37