Difficulty: Medium
Correct Answer: E
Explanation:
Introduction / Context:We must infer a full order (or enough of it) from pairwise comparisons. “D is only shorter than B” pins D as the second-tallest and B as tallest. Another clause pushes E below A and C. Combined, these fix E at the bottom.
Given Data / Assumptions:
Concept / Approach:Since D is taller than everyone except B, D > A, D > C, and D > E. Also B > D. Because E is shorter than A and C, and also shorter than D (second-tallest) and B (tallest), E must be the global minimum.
Step-by-Step Ordering:
1) Fix B at top, D second.2) E is below A and C, and also below D and B ⇒ E is below all others.3) The relative order among A and C is unspecified, but the shortest (E) is uniquely determined.Verification / Alternative check:Try any heights consistent with B > D and D > (A, C, E) and (A, C) > E. E always ends up at the bottom.
Why Other Options Are Wrong:
Common Pitfalls:Misreading “only shorter than B” as “shorter than only B and someone else.” It strictly means D is second-tallest.
Final Answer:E
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