According to the question,
A + B = C + D; B + D > A + C; A > B
Now, B + D > A + C and A > B
? B + D > A + C > B + C ? B + D > B + C ? D > C
Now, B + D > A + C ? B + D = A + C + K
Also, A + B = C + D ? B - D = C - A
? 2B = 2C + K ? B > C ? A > B > C
D > C
Clearly, each one of A, D and b has more amount than C. Hence, C has the least amount.
According to question,
R is heavier than S but lighter than T.
R > S But T > R
Then T > R > S
P is lighter than S.
S > P
Then
T > R > S, S > P ? T > R > S > P
But information about Q is not given, Hence, either T or Q is the heaviest.
_______________________________________________
According to | Leave Date
__________________|____________________________
Seema | 22, 23, 24, 25, 26
__________________|_____________________________
but Seema was present on 23rd. Also, it was holiday on 24th and 26th October was Sunday. Hence, possible date may be either 22nd or 25th October
From among those who passed Neeta is 22nd from the top and Kalyan is 22 +5 = 27th from the top and 34th from the bottom. Therefore, total number of students who passed the examination = 27 + 34 - 1 = 60.
Therefore, total number of students in the class = (60/4) X 5 = 75
Position of Rekha is 20th from the right which is occupied by Jaya after interchanging takes place and Jaya becomes 22nd from the left. Therefore, total number of students in the row.
(20 + 22) - 1 = 41
Dilip is 10th from the left and the same position is occupied by Jagdish after interchanging takes place and he becomes 23rd from the right.
Therefore, total number of student in the row = (10 + 23) - 1 = 32
Given, Siya > Priya > Tiya ........(i)
Siya > Riya > Priya ........(ii)
and Riya > Tiya > Diya .........(iii)
On combining Eqs. (i), (ii) and (iii), we get
Siya > Riya > Priya > Tiya > Diya
As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
From the above taste (sweet) ranking, we find that Z is the sweetest.
As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
It is clear that both Z and U are sweeter and more deadly than V.
The compound can be arranged according to their taste and effectiveness as shown below.
Taste (sweet) Z, U, V, Y, X, WW
Effectiveness (deadly) X, Y, U, W, Z, V
Compound U is sweeter than Y and More deadly and W.
As per question for sweetness,
U is sweeter than V.
1. U > V.
V is sweeter than Y.
2. V > Y.
W is less sweet than X.
3. X > W.
X is less sweet than Y
4. X < Y.
Y is less sweet than U.
5. Y < U.
Z is sweeter than U.
6. Z > U.
From 1 and 2,
7. U > V > Y.
From 6 and 7,
8. Z > U > V > Y.
from 4 and 8,
9. Z > U > V > Y > X
from 3 and 9,
Z > U > V > Y > X > W
Taste (sweet) Z, U, V, Y, X, W == (Z > U > V > Y > X > W)
As per question for deadly,
U is more deadly than Z
1. U > Z.
V is less deadly than Z.
2. V < Z.
W is less deadly than U.
3. W < U.
X is more deadly than Y.
4. X > Y.
Y is more deadly than U.
5. Y > U.
Z is less deadly than W.
6. Z < W.
Now from 1 and 2,
7. U > Z > V
from 7 and 5,
8. Y > U > Z > V
from 4 and 8,
9. X > Y > U > Z > V
from 3, 6 and 9,
X > Y > U > W > Z > V
Effectiveness (deadly) X, Y, U, W, Z, V
Statement V does not add any new information about the sweetness of compound.
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