TTL output current specification: Evaluate — “The maximum current for a LOW output on a standard TTL gate is 100 µA.”
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AIncorrect
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BCorrect
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CCorrect only for high-impedance outputs
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DCorrect for open-collector outputs at no load
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EDepends only on ambient temperature
Answer
Correct Answer: Incorrect
Explanation
Introduction / Context:Understanding TTL output drive is crucial for reliable interfacing. Standard TTL can sink substantial current in the LOW state, which defines its fan-out capability. The claim of only 100 µA is drastically lower than actual specifications and would imply almost no fan-out.
Given Data / Assumptions:
- Standard TTL IOL(max) is typically on the order of 16 mA for a logic LOW.
- TTL input LOW current (IIL) per input is around 1.6 mA in classic TTL.
- Fan-out ≈ IOL/IIL ≈ 10 for LOW state.
Concept / Approach:If a TTL output LOW could only sink 100 µA, it would barely drive a single TTL input (which might demand around 1.6 mA). Actual TTL data contradicts this; therefore the statement is incorrect by more than an order of magnitude.
Step-by-Step Solution:
Check standard TTL specs: IOL(max) ≈ 16 mA at VOL spec.Compare to the claim: 0.1 mA is far smaller than 16 mA.Conclude the statement is incorrect.Verification / Alternative check:Referencing vendor datasheets for 7400 family confirms typical sink capability and corresponding loading calculations.
Why Other Options Are Wrong:
- Correct / temperature-only / open-collector caveats: None reconcile the large discrepancy with standard specs; open-collector capability is determined by sink current and pull-up, not “no load.”
Common Pitfalls:Confusing input current with output current; misreading µA vs. mA; using LS/ALS/HCT values without understanding the order of magnitude.
Final Answer:Incorrect