Totem-pole TTL output behavior Consider a TTL gate with a totem-pole output stage. The statement claims: “The upper (pull-up) transistor is OFF when the gate output is LOW.”

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
TTL gates often use a totem-pole (push-pull) output stage: an upper transistor sources current to drive a HIGH, and a lower transistor sinks current to drive a LOW. Proper operation avoids both devices conducting heavily at the same time, which would waste power and stress the devices.



Given Data / Assumptions:

  • In a LOW output state, the output node is pulled toward ground.
  • To achieve a strong LOW, the lower (pull-down) transistor turns ON to sink current.
  • To prevent shoot-through, the upper (pull-up) transistor must be OFF (or minimally conducting during transitions) when the output is LOW.


Concept / Approach:
The totem-pole arrangement alternately sources or sinks current. Logic design ensures complementary action: pull-up drives HIGH, pull-down drives LOW. When the output is LOW, keeping the pull-up off prevents contention and reduces static power dissipation.



Step-by-Step Solution:

Assess the LOW state: output near ground.Confirm pull-down path is active while pull-up is inactive.Recognize this aligns with typical TTL totem-pole behavior.Conclude the statement is correct.


Verification / Alternative check:
Timing diagrams show brief crossover currents during transitions, but in steady LOW the upper device is OFF and the lower device holds the node LOW.



Why Other Options Are Wrong:
“Incorrect” contradicts standard totem-pole operation. Open-collector outputs lack the upper transistor entirely, making option “True only for open-collector” inapplicable. Floating inputs are unrelated to the output topology’s intended steady state.



Common Pitfalls:
Confusing transient overlap during switching with steady-state conditions. The question concerns the steady LOW state.



Final Answer:
Correct

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