Monostable 74121 (nonretriggerable) timing A 74121 one-shot uses REXT = 49 kΩ and CEXT = 0.2 µF. Approximately what is the output pulse width tW?
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A6.9 µs
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B6.9 ms
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C69 ms
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D690 ms
Answer
Correct Answer: 6.9 ms
Explanation
Introduction / Context:The nonretriggerable 74121 monostable produces a fixed-width pulse determined by an external resistor and capacitor. Designers use a simple proportional formula with a device-specific constant to estimate pulse duration from component values.
Given Data / Assumptions:
- Device: 74121 (nonretriggerable) monostable.
- REXT = 49 kΩ.
- CEXT = 0.2 µF.
- Approximate timing relation: tW ≈ 0.7 * REXT * CEXT (typical for 74121).
Concept / Approach:First compute the RC time constant, then multiply by the typical coefficient. Ensure unit conversions are correct (kΩ to Ω, µF to F) to avoid order-of-magnitude mistakes.
Step-by-Step Solution:
Compute RC: 49,000 Ω * 0.2 × 10^-6 F = 9.8 × 10^-3 s = 9.8 ms.Apply coefficient: tW ≈ 0.7 * 9.8 ms ≈ 6.86 ms.Round to one decimal place: 6.9 ms.Therefore, the expected pulse width is about 6.9 ms.Verification / Alternative check:A bench check with nominal parts will produce a pulse near this value, noting tolerance on R and C (often ±5% to ±20%) and supply/temperature effects; the actual width will vary accordingly.
Why Other Options Are Wrong:
- 6.9 µs: Off by a factor of 1000 due to unit error (µF vs nF).
- 69 ms / 690 ms: Too large; would require larger C or R.
Common Pitfalls:Mixing microfarads and nanofarads or forgetting that kΩ * µF yields milliseconds when scaled by a sub-unity constant.
Final Answer:6.9 ms