Monostable 74121 (nonretriggerable) timing A 74121 one-shot uses REXT = 49 kΩ and CEXT = 0.2 µF. Approximately what is the output pulse width tW?

Difficulty: Medium

Correct Answer: 6.9 ms

Explanation:


Introduction / Context:
The nonretriggerable 74121 monostable produces a fixed-width pulse determined by an external resistor and capacitor. Designers use a simple proportional formula with a device-specific constant to estimate pulse duration from component values.


Given Data / Assumptions:

  • Device: 74121 (nonretriggerable) monostable.
  • REXT = 49 kΩ.
  • CEXT = 0.2 µF.
  • Approximate timing relation: tW ≈ 0.7 * REXT * CEXT (typical for 74121).


Concept / Approach:
First compute the RC time constant, then multiply by the typical coefficient. Ensure unit conversions are correct (kΩ to Ω, µF to F) to avoid order-of-magnitude mistakes.


Step-by-Step Solution:

Compute RC: 49,000 Ω * 0.2 × 10^-6 F = 9.8 × 10^-3 s = 9.8 ms.Apply coefficient: tW ≈ 0.7 * 9.8 ms ≈ 6.86 ms.Round to one decimal place: 6.9 ms.Therefore, the expected pulse width is about 6.9 ms.


Verification / Alternative check:
A bench check with nominal parts will produce a pulse near this value, noting tolerance on R and C (often ±5% to ±20%) and supply/temperature effects; the actual width will vary accordingly.


Why Other Options Are Wrong:

  • 6.9 µs: Off by a factor of 1000 due to unit error (µF vs nF).
  • 69 ms / 690 ms: Too large; would require larger C or R.


Common Pitfalls:
Mixing microfarads and nanofarads or forgetting that kΩ * µF yields milliseconds when scaled by a sub-unity constant.


Final Answer:
6.9 ms

More Questions from Flip-Flops

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion