Question 1

How many 18 ' s are there in 3712 ?

Accepted Answer

37 1 2 = 75 2 Required number = 75 2 1 8 = 75 x 4 = 300

Question 2

The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is :

Accepted Answer

Let the number of 20 paise coins be x. Then the no of 25 paise coins = (324 - x). 0.20 * (x) + 0.25 (324 - x) = 71 => x = 200..

Question 3

Simplify 1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8

Accepted Answer

Apply a 3 + b 3 + c 3 - 3 a b c a 2 + b 2 + c 2 - a b - b c - c a = a + b + c Hence the answer is 1.5 + 4.7 + 3.8 = 10.

Question 4

The highest score in an inning was 3/11 of the total and the next highest was 3/11 of the reminder . If the score differ by 9, the total score was :

Accepted Answer

Let the score be x. Then the highest score = 3x/11. Reminder = (x - 3x/11) = 8x/11 .Next the highest score = 3/11 of 8x/11 = 24x/121. 3x/11 - 24x/11 = 9 <=> 33x - 24x = 9*121 <=> x= 121..

Question 5

92613 x 62742241 = ? + 89 Find the value of '?'

Accepted Answer

Given 9261 3 x 62742241 = ? + 89 Using unit digit method, On LHS, 1 x 1 x 1 = 1 sqrt of last digit 1 => it must end with either 9 or 1 so now 1 x 1 = 1 1 x 9 = 9 On RHS, ? + 89 => ? = ...1 - 89 = last digit is 11- 9 = 2 or => ? = ...9 - 89 = last digit is 9 - 9 = 0 Here in the options last digit 2 is option C.

Question 6

112 × 54 =

Accepted Answer

112 × 5 4 112 × 10 2 4 = 112 × 10000 2 4 = 1120000 / 16 = 70,000.

Question 7

In a group of buffaloes and ducks, the number of legs are 24 more than twice the number of heads. What is the number of buffaloes in the group ?

Accepted Answer

Let the number of buffaoes be x and number of ducks be y. Then 4x + 2y = 2(x + y) + 24 => 2x = 24 => x = 12.

Question 8

Simplify the following and find the value of ? 13 of ? + 47 of 114 of 539 = 31% of 2000

Accepted Answer

1 3 x ? + 4 7 x 11 4 x 539 = 31 100 x 2000 ? = 378 x 3 ? = 1134

Question 9

Simplify 2392-21+8-72=?2

Accepted Answer

? 2 = 2 × 7 8 - 21 + 8 + 49 - 14 8 = 57 - 21 = 36 = > ? = ± 6

Question 10

By how much is three-fifth of 350 greater than four-seventh of 210 ?

Accepted Answer

3/5 of 350 - 4/7 of 210 = 210 - 120 = 90.

Question 11

The price of 2 oranges, 3 bananas and 4 apples is Rs. 15. The price of 3 oranges, 2 bananas and 1 apple is Rs. 10. What will be price of 4 oranges, 4 bananas and 4 apples ?

Accepted Answer

Let the Oranges be 'O', Bananas be 'B' and Apples be 'A' From the given data, 2O + 3B + 4A = 15 ...... (I) 3O + 2B + A = 10 ..... (II) On adding (I) and (II), 5O + 5B + 5A = 25 O + B + A = 5 4O + 4B + 4A = 20.

Question 12

38% of 7500 + ?% of 375 = 50% of 6000

Accepted Answer

Let ? = p 38 x 7500/100 + p x 375/100 = 50 x 6000/100 => 38 x 75 + 3.75p = 3000 => 3.75p = 3000 - 2850 => p = 150/3.75 => p = ? = 40

Question 13

1747 + 13212 - ? = 1123

Accepted Answer

17 4 7 + 13 2 12 - ? = 11 2 3 123 7 + 158 12 - ? = 35 3 => ? = 123 7 + 158 12 - 35 3 => ? = 1476 + 1106 - 980 84 => ? = 19.07

Question 14

Simplify 413 + 215 + 414 = ?

Accepted Answer

The given equation is in Mixed fraction. Now to solve this type of fractions, 4 1 3 + 2 1 5 + 4 1 4 = ? ? = 4 + 2 + 4 + 1 3 + 1 5 + 1 4 ? = 10 + 47 60 ? = 10 47 60

Question 15

If a+b=5 and 3a+2b=20,then (3a+b)will be :

Accepted Answer

a+b=5 ...(1) and 3a+2b=20 ...(2) Multiplying (1) by 2 and subtracting from (2), we get : a=10. Putting a=10 in (1), we get : b=-5 Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.

Question 16

If 3x-y=27 , 3x+y=243 then find the x value

Accepted Answer

Given that 3 x - y = 27 , 3 x + y = 243 ⇒ 3 x - y = 3 3 , 3 x + y = 3 5 => x-y=3, x+y=5 => x = 4

Question 17

Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ?

Accepted Answer

Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 60 5k = 130 k = 26 so 26 correct sums.

Question 18

217 x 217 + 183 x 183 = ?

Accepted Answer

217 2 + 183 2 = 200 + 17 2 + 200 - 17 2 It is in the form of a + b 2 + a - b 2 = 2 a 2 + b 2 = 2(40000 + 289) = 80578.

Question 19

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ?

Accepted Answer

Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => - 150 + x 2 + 5 x multiplying both sides by -1/10x => x 2 + 15 x - 10 x - 150 = 0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.

Simplification Questions