Question 1

Add the mixed numbers carefully and report the sum as a mixed number: 3 2/3 + 2 3/4 + 1 1/2 = ?

Accepted Answer

Introduction / Context: This problem assesses your fluency with mixed numbers: converting them to improper fractions, finding a common denominator, adding, and finally reconverting to a mixed number. Accuracy with fractional arithmetic and least common multiples is the key skill tested here. Given Data / Assumptions: Add 3 2/3, 2 3/4, and 1 1/2. All numbers are positive mixed numbers. Final answer should be simplified, preferably as a mixed number. Concept / Approach: Convert each mixed number to an improper fraction, use a common denominator (12 suits denominators 3, 4, and 2), add the numerators, and reduce if possible. Then convert back to a mixed number for a clean, readable final form. Step-by-Step Solution: 3 2/3 = (3*3 + 2)/3 = 11/3 = 44/12.2 3/4 = (2*4 + 3)/4 = 11/4 = 33/12.1 1/2 = (1*2 + 1)/2 = 3/2 = 18/12.Sum = (44 + 33 + 18)/12 = 95/12.Convert to mixed: 95/12 = 7 remainder 11 → 7 11/12. Verification / Alternative check: As decimals: 3.666..., 2.75, and 1.5 sum to 7.9166..., which equals 7 + 11/12 (since 11/12 ≈ 0.9166...). This confirms consistency. Why Other Options Are Wrong: 8 1/12 and 8 11/12 overshoot the true sum; 7 5/12 and 6 11/12 undershoot. Only 7 11/12 matches the exact computation. Common Pitfalls: Using incorrect common denominators, forgetting to convert mixed numbers to improper fractions, or mishandling the reconversion back to a mixed number. Final Answer: 7 11/12

Question 2

Evaluate the expression with roots and exponents: (5568 ÷ 87)^(1/3) + (72 × 2)^(1/2) = (?)^(1/2). Find the value of ?.

Accepted Answer

Introduction / Context: This item tests correct interpretation of fractional exponents and order of operations. You must carefully compute a cube root and a square root, add the results, and then express the sum as the square root of an unknown number (?^(1/2)). Given Data / Assumptions: (5568 ÷ 87)^(1/3) + (72 × 2)^(1/2) = (?)^(1/2). Principal (non-negative) roots are intended. Exact arithmetic is expected (no rounding needed). Concept / Approach: Evaluate the division 5568 ÷ 87 exactly, then take its cube root. Next, compute 72 × 2 and take the square root. Add the two results to obtain a value that must equal √?. Finally, square this sum to recover ?. Step-by-Step Solution: 5568 ÷ 87 = 64 (since 87 × 64 = 5568).Cube root: 64^(1/3) = 4.Compute the second term: 72 × 2 = 144; √144 = 12.Sum of roots: 4 + 12 = 16.Since 16 = √?, we have ? = 16^2 = 256. Verification / Alternative check: Plug back: √256 = 16; left side is 4 + 12 = 16. Both sides match exactly. Why Other Options Are Wrong: 4 and 16 are intermediate root values, not ?. √2 is unrelated. 144 is the product 72 × 2 before taking the square root, not the required ?. Common Pitfalls: Taking square root before multiplication, or misreading the cube root as a square root. Keep radical operations in the correct order. Final Answer: 256

Question 3

Power and base pattern recognition: Evaluate (0.49)^4 × (0.343)^4 ÷ (0.2401)^4 and express it as (70/100)^?. Determine the integer exponent ?.

Accepted Answer

Introduction / Context: This problem checks your ability to convert recurring decimal bases into powers of a common prime (here, 7) over powers of 10 and then simplify using exponent rules. The goal is to match the simplified result to a clean form (70/100)^?. Given Data / Assumptions: Compute (0.49)^4 × (0.343)^4 ÷ (0.2401)^4. Express the final answer as (70/100)^?. All exponents are integers and operations follow standard power rules. Concept / Approach: Rewrite each decimal with base 7 and 10: 0.49 = 7^2/10^2, 0.343 = 7^3/10^3, 0.2401 = 7^4/10^4. Apply exponent laws to combine the powers, then simplify the net exponents to match the target base 70/100 = 7/10. Step-by-Step Solution: (0.49)^4 = (7^2/10^2)^4 = 7^8/10^8.(0.343)^4 = (7^3/10^3)^4 = 7^12/10^12.(0.2401)^4 = (7^4/10^4)^4 = 7^16/10^16.Combine: (7^8·7^12)/(7^16) over (10^8·10^12)/(10^16) = 7^(20−16) / 10^(20−16) = 7^4/10^4.Since 7^4/10^4 = (7/10)^4 = (70/100)^4, the required exponent is 4. Verification / Alternative check: Numerically, 0.7^4 = 0.2401, which is consistent with the original decimal pattern. Why Other Options Are Wrong: 3, 1, 2, and 7 do not match the simplified exponent balance. Only 4 preserves the equality. Common Pitfalls: Mixing addition and subtraction of exponents, or failing to recognize that dividing by (7^4/10^4)^4 subtracts powers in both numerator and denominator. Final Answer: 4

Question 4

Evaluate the identity-based expression exactly: [0.5*0.5*0.5 + 0.2*0.2*0.2 + 0.3*0.3*0.3 − 3*0.5*0.3*0.2] / [0.5*0.5 + 0.2*0.2 + 0.3*0.3 − 0.5*0.2 − 0.2*0.3 − 0.5*0.3].

Accepted Answer

Introduction / Context: This expression is a classic application of the identity (a^3 + b^3 + c^3 − 3abc) = (a + b + c)(a^2 + b^2 + c^2 − ab − bc − ca). Recognizing this structure turns a messy-looking fraction into a simple sum a + b + c. Given Data / Assumptions: a = 0.5, b = 0.2, c = 0.3. Numerator matches a^3 + b^3 + c^3 − 3abc. Denominator matches a^2 + b^2 + c^2 − ab − bc − ca. Concept / Approach: Use the identity directly. Provided a + b + c ≠ 0, the ratio simplifies exactly to a + b + c. Compute that sum with the given decimal values. Step-by-Step Solution: Identify the pattern: Numerator = a^3 + b^3 + c^3 − 3abc.Denominator = a^2 + b^2 + c^2 − ab − bc − ca.Therefore, fraction = (a + b + c).Compute a + b + c = 0.5 + 0.2 + 0.3 = 1.0. Verification / Alternative check: Plugging numbers explicitly gives the same result; however, the identity provides a faster and exact path with less arithmetic risk. Why Other Options Are Wrong: 0.6, 0.4, 0.03, and 0.5 are arbitrary decimals not equal to a + b + c for the given values. Common Pitfalls: Failing to spot the identity leads to tedious computations and rounding errors. Another frequent error is misplacing minus signs in the denominator terms −ab − bc − ca. Final Answer: 1

Question 5

Use sum-of-cubes factorization to simplify exactly: [725^3 + 371^3] / [725^2 − 725×371 + 371^2] = ?

Accepted Answer

Introduction / Context: Recognizing algebraic identities is crucial for simplification. Here the numerator is a sum of cubes, and the denominator is the quadratic factor associated with that identity. Given Data / Assumptions: Numerator: a^3 + b^3 with a = 725 and b = 371. Denominator: a^2 − ab + b^2. We assume exact integer arithmetic. Concept / Approach: Use the identity a^3 + b^3 = (a + b)(a^2 − ab + b^2). Dividing by (a^2 − ab + b^2) cancels that factor, leaving just (a + b). Step-by-Step Solution: Apply identity: (a^3 + b^3) / (a^2 − ab + b^2) = a + b.Compute a + b = 725 + 371 = 1096. Verification / Alternative check: Multiplying back: (a + b)(a^2 − ab + b^2) reconstructs a^3 + b^3, confirming the correctness. Why Other Options Are Wrong: 9610, 1960, 1016, and 1090 are distractors derived from mis-adding or misordering digits; none equal 725 + 371. Common Pitfalls: Using the difference-of-cubes formula incorrectly, or trying to expand cubes numerically instead of leveraging the identity. Final Answer: 1096

Question 6

Given a^2 + b^2 = 234 and ab = 108, compute the ratio (a + b) / (a − b). Provide the exact simplified value.

Accepted Answer

Introduction / Context: Here you are given symmetric information about two unknowns: sum of squares and product. The task is to deduce (a + b)/(a − b) without solving for a and b individually, by using identities for squared sums and differences. Given Data / Assumptions: a^2 + b^2 = 234. ab = 108. Assume a ≠ b so that a − b ≠ 0. Concept / Approach: Use (a + b)^2 = a^2 + b^2 + 2ab and (a − b)^2 = a^2 + b^2 − 2ab to find the magnitudes of (a + b) and (a − b). The ratio of the square roots then simplifies cleanly. Step-by-Step Solution: (a + b)^2 = 234 + 2*108 = 234 + 216 = 450.Hence a + b = √450 = √(225*2) = 15√2.(a − b)^2 = 234 − 216 = 18.Hence a − b = √18 = 3√2.Therefore (a + b)/(a − b) = (15√2)/(3√2) = 5. Verification / Alternative check: If desired, construct numbers with these invariants (for instance via solving t^2 − (a + b)t + ab = 0) and verify the ratio numerically; it will still reduce to 5. Why Other Options Are Wrong: 10, 8, 4, and 6 do not respect the exact square-root simplifications from the given invariants. Common Pitfalls: Forgetting factors of 2 in the identities or attempting to solve for a and b explicitly, which is unnecessary and time-consuming. Final Answer: 5

Question 7

If x + 1/x = 2, evaluate the rational expression (2x^2 + 2) / (3x^2 + 5x + 3). Provide the exact simplified fraction.

Accepted Answer

Introduction / Context: This algebra simplification hinges on interpreting the condition x + 1/x = 2. For real numbers, this equality forces x = 1 (since x + 1/x ≥ 2 with equality at x = 1). Substituting x = 1 into the given rational expression yields an exact fraction. Given Data / Assumptions: Condition: x + 1/x = 2 (real x). Expression to evaluate: (2x^2 + 2) / (3x^2 + 5x + 3). Principal arithmetic and exact fractions are expected. Concept / Approach: From the AM ≥ GM inequality or by direct algebra, x + 1/x = 2 implies x = 1. Plug this into the rational expression and simplify carefully to obtain the final fraction. Step-by-Step Solution: Since x + 1/x = 2, conclude x = 1.Compute numerator: 2x^2 + 2 → 2(1)^2 + 2 = 4.Compute denominator: 3x^2 + 5x + 3 → 3(1)^2 + 5(1) + 3 = 11.Hence value = 4 / 11. Verification / Alternative check: Try any x ≠ 1 and the condition fails; thus no other real x satisfies the premise. Therefore the direct substitution is valid and unique. Why Other Options Are Wrong: 1/2, 13/4, 7, and 2/11 are distractors that result from mis-substitution or arithmetic slips; none match the exact evaluation at x = 1. Common Pitfalls: Attempting to manipulate x symbolically without first using the key implication x = 1, or miscomputing the denominator 3 + 5 + 3. Final Answer: 4/11

Question 8

If a, b, c are non-zero and satisfy a + (1/b) = 1 and b + (1/c) = 1, determine the exact value of the product abc.

Accepted Answer

Introduction / Context: This problem involves linked linear-fractional relations between a, b, and c. The goal is to deduce the product abc without solving for each variable individually, by expressing the variables in terms of a single parameter. Given Data / Assumptions: a + 1/b = 1. b + 1/c = 1. a, b, c ≠ 0. Concept / Approach: Isolate a and b in terms of b and c respectively, then substitute progressively to express a in terms of c alone. Multiply a, b, and c to compute abc. Watch the algebraic signs carefully. Step-by-Step Solution: From a + 1/b = 1 ⇒ a = 1 − 1/b = (b − 1)/b.From b + 1/c = 1 ⇒ b = 1 − 1/c = (c − 1)/c.Express a in terms of c: a = (b − 1)/b = (( (c − 1)/c ) − 1) / ((c − 1)/c).Simplify numerator: (c − 1 − c)/c = (−1)/c; divide by (c − 1)/c gives a = −1/(c − 1).Compute product: abc = [−1/(c − 1)] * [(c − 1)/c] * c = −1. Verification / Alternative check: Pick any convenient c ≠ 0,1 (e.g., c = 2) and compute b and a from the relations; the product abc numerically evaluates to −1 every time, confirming the derivation. Why Other Options Are Wrong: −3, 1, 3, and 0 do not satisfy the derived identity; abc is constant and equals −1 regardless of the choice of c (excluding singular cases). Common Pitfalls: Dropping negative signs during simplification or forgetting to divide by the compound fraction when solving for a in terms of c. Final Answer: -1

Question 9

Given a + b + c = 14 and a^2 + b^2 + c^2 = 96, compute the exact value of (ab + bc + ca).

Accepted Answer

Introduction / Context: This is a textbook application of the identity (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca). Using the given sum and sum of squares, we can isolate the symmetric sum ab + bc + ca directly. Given Data / Assumptions: a + b + c = 14. a^2 + b^2 + c^2 = 96. All quantities are real numbers. Concept / Approach: Square the total sum to link it with the sum of squares and twice the pairwise products. Solve for ab + bc + ca algebraically, keeping track of coefficients precisely. Step-by-Step Solution: (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca).Compute left side: 14^2 = 196.Substitute right side: 196 = 96 + 2(ab + bc + ca).Rearrange: 2(ab + bc + ca) = 196 − 96 = 100.Therefore ab + bc + ca = 100 / 2 = 50. Verification / Alternative check: Plugging back into the identity reproduces 196 on the left, confirming correctness. Why Other Options Are Wrong: 51, 55, 65, and 49 reflect arithmetic slips (wrong difference or a missing division by 2). Only 50 satisfies the identity exactly. Common Pitfalls: Forgetting the factor of 2 in front of (ab + bc + ca), or squaring 14 incorrectly. Final Answer: 50

Question 10

Cricket scoring logic: The highest score in an innings was 3/11 of the total, and the next highest was 3/11 of the remainder after removing the highest. If these two scores differ by 18, find the total score.

Accepted Answer

Introduction / Context: This word problem tests proportional reasoning and careful setup of fractional parts of a whole. We translate the narrative into algebra involving the total score T and compute the two specified top scores. Given Data / Assumptions: Highest score H = (3/11) * T. Remainder after removing H is T − H. Next highest N = (3/11) * (T − H). Difference H − N = 18 (highest exceeds next highest). Concept / Approach: Express both H and N in terms of T, then take their difference and equate it to 18. Solve for T using straightforward linear algebra. Fractions must be handled carefully; adopting a common denominator helps avoid mistakes. Step-by-Step Solution: H = (3/11)T.Remainder = T − H = T − (3/11)T = (8/11)T.N = (3/11) * (8/11)T = (24/121)T.Difference: H − N = (3/11 − 24/121)T = (33/121 − 24/121)T = (9/121)T.Set (9/121)T = 18 ⇒ T = 18 * 121 / 9 = 2 * 121 = 242. Verification / Alternative check: Compute scores: H = (3/11)*242 = 66; N = (24/121)*242 = 48; difference = 18, matching the condition. Why Other Options Are Wrong: 244, 294, 255, and 231 do not satisfy the difference equation H − N = 18 when substituted. Common Pitfalls: Using 3/11 of the total again for the second score instead of 3/11 of the remainder, or subtracting in the wrong order leading to a negative difference. Final Answer: 242

Question 11

Algebraic identity under the condition a + b + c = 0 Evaluate the product: [(a + b)/c + (b + c)/a + (c + a)/b] × [a/(b + c) + b/(c + a) + c/(a + b)].

Accepted Answer

Introduction / Context: This algebra question probes symmetry and substitution when a + b + c = 0. Recognizing how this constraint transforms compound fractions allows a short, elegant evaluation without heavy computation. Given Data / Assumptions: a + b + c = 0 (none of a, b, c, or their pairwise sums are zero in denominators unless expressly implied by the identity). Target expression: S1 × S2 where S1 = (a + b)/c + (b + c)/a + (c + a)/b and S2 = a/(b + c) + b/(c + a) + c/(a + b). Concept / Approach: From a + b + c = 0, we have a + b = −c, b + c = −a, and c + a = −b. Substitute these into each fraction to simplify immediately. Step-by-Step Solution: S1 termwise: (a + b)/c = (−c)/c = −1; (b + c)/a = (−a)/a = −1; (c + a)/b = (−b)/b = −1.Hence S1 = (−1) + (−1) + (−1) = −3.S2 termwise: a/(b + c) = a/(−a) = −1; b/(c + a) = b/(−b) = −1; c/(a + b) = c/(−c) = −1.Hence S2 = (−1) + (−1) + (−1) = −3.Product: S1 × S2 = (−3) * (−3) = 9. Verification / Alternative check: Pick a simple triple satisfying a + b + c = 0, e.g., a = 1, b = 2, c = −3, and evaluate numerically to confirm S1 = S2 = −3. Why Other Options Are Wrong: 0, 8, −3, and 3 ignore the paired substitutions that force each sum to −3; only the product 9 matches. Common Pitfalls: Forgetting that b + c = −a, etc.; attempting to find a common denominator instead of using the given linear constraint for direct simplification. Final Answer: 9

Question 12

Telescoping product with consecutive odd numerators and denominators Compute (2 − 1/3)(2 − 3/5)(2 − 5/7) … (2 − 997/999).

Accepted Answer

Introduction / Context: This product is crafted to telescope. Each factor uses consecutive odd integers in the fraction, enabling massive cancellation when expressed with a common pattern. Given Data / Assumptions: General term: 2 − k/(k + 2), where k runs over odd integers 1, 3, 5, …, 997. All denominators are nonzero and positive. Concept / Approach: Rewrite each factor: 2 − k/(k + 2) = (2(k + 2) − k)/(k + 2) = (k + 4)/(k + 2). This turns the entire product into a chain of ratios that cancel successively. Step-by-Step Solution: For k = 1: (k + 4)/(k + 2) = 5/3.For k = 3: 7/5. For k = 5: 9/7. … For k = 997: 1001/999.Product P = (5/3) × (7/5) × (9/7) × … × (1001/999).Everything cancels except the smallest denominator 3 and the largest numerator 1001.Hence P = 1001/3. Verification / Alternative check: Write out the first few and last few terms to see direct cancellation of intermediate numerators and denominators. Why Other Options Are Wrong: 1001/999 and 999/1001 reflect partial cancellation; 5/1001 and 3/1001 invert endpoints incorrectly. Common Pitfalls: Losing the pattern of consecutive odds or not expressing each factor as (k + 4)/(k + 2) before multiplying. Final Answer: 1001/3

Question 13

Workforce composition and family status In an office, 1/3 of the workers are women. Of the women, 1/2 are married and 1/3 of the married women have children. Of the men, 3/4 are married and 2/3 of the married men have children. What fraction of all …

Accepted Answer

Introduction / Context: This is a layered fraction problem about classifications (women/men, married, with children). The solution adds proportions stepwise and then complements to find the share without children. Given Data / Assumptions: Total workforce = 1 (for convenience). Women = 1/3; Men = 2/3. Married women = (1/2) of women = 1/6; with children = (1/3) of married women = 1/18. Married men = (3/4) of men = 1/2; with children = (2/3) of married men = 1/3. Concept / Approach: Compute the total fraction with children by summing the women-with-children and men-with-children shares. Subtract this from 1 to get the fraction without children. Step-by-Step Solution: Women with children = 1/18.Men with children = 1/3.Total with children = 1/18 + 1/3 = 1/18 + 6/18 = 7/18.Therefore, without children = 1 − 7/18 = 11/18. Verification / Alternative check: Convert to decimals as a quick check: 7/18 ≈ 0.3889, so without children ≈ 0.6111 which equals 11/18. Why Other Options Are Wrong: 5/11, 4/9, and 17/36 arise from partial or incorrect aggregation; 7/18 is actually the fraction with children, not without. Common Pitfalls: Multiplying instead of taking fractions of group sizes; forgetting to complement at the end. Final Answer: 11/18

Question 14

Surd manipulation and rationalization If x = √3 + √2, find the exact value of x + 1/x.

Accepted Answer

Introduction / Context: Questions of this type test comfort with surds and rationalizing denominators. The trick is to find 1/x by multiplying numerator and denominator by the conjugate. Given Data / Assumptions: x = √3 + √2. We need x + 1/x. Concept / Approach: Use the conjugate of x, namely √3 − √2, to compute the reciprocal exactly. Then add the expressions and simplify. Step-by-Step Solution: 1/x = 1/(√3 + √2) = (√3 − √2)/[(√3)^2 − (√2)^2] = (√3 − √2)/(3 − 2) = √3 − √2.Therefore, x + 1/x = (√3 + √2) + (√3 − √2) = 2√3. Verification / Alternative check: Let √3 ≈ 1.732, √2 ≈ 1.414. Then x ≈ 3.146; 1/x ≈ 0.318; sum ≈ 3.464, which equals 2√3 ≈ 3.464. Why Other Options Are Wrong: 2 and 3 ignore surd terms; 2√2 and √6 come from adding or multiplying the roots incorrectly. Common Pitfalls: Using √3 + √2 as its own reciprocal or forgetting to divide by the difference of squares when rationalizing. Final Answer: 2√3

Question 15

Evaluate a^3 + b^3 + c^3 − 3abc for consecutive integers Find the value when a = 225, b = 226, c = 227.

Accepted Answer

Introduction / Context: This classic identity simplifies dramatically for three consecutive integers. Recognizing the pattern avoids any need to compute large cubes. Given Data / Assumptions: a = 225, b = 226, c = 227 (consecutive integers). Expression: a^3 + b^3 + c^3 − 3abc. Concept / Approach: Use the identity a^3 + b^3 + c^3 − 3abc = (a + b + c)(a^2 + b^2 + c^2 − ab − bc − ca). For consecutive integers with common difference 1, this further reduces numerically to 3(a + b + c). Step-by-Step Solution: Sum: a + b + c = 225 + 226 + 227 = 678.For three consecutive integers n − 1, n, n + 1, the expression equals 3(n − 1 + n + n + 1) = 3(3n) = 9n. With n = 226, 9n = 2034.Therefore, value = 2034. Verification / Alternative check: Directly applying the general identity also leads to the same result; evaluating differences confirms the simplification. Why Other Options Are Wrong: 2304, 2430, and 2340 are distractors near the true value; 226 is the average, not the expression’s value. Common Pitfalls: Attempting to cube and multiply huge numbers; forgetting the special simplification for consecutive integers. Final Answer: 2034

Question 16

Careful bracket evaluation — nested subtraction Simplify the expression: 6 − [9 − {18 − (15 − 12 − 9)}].

Accepted Answer

Introduction / Context: Nestled parentheses with multiple minus signs commonly produce sign errors. The key is to evaluate from the innermost bracket outward and apply subtraction carefully at each level. Given Data / Assumptions: Expression: 6 − [9 − {18 − (15 − 12 − 9)}]. Standard operation order: parentheses/brackets first; proceed left to right for subtraction within the same level. Concept / Approach: Resolve the innermost parentheses, then move outward step by step, watching sign changes when subtracting a negative result. Step-by-Step Solution: Innermost: (15 − 12 − 9) → 15 − 12 = 3; 3 − 9 = −6.Next: {18 − (…)} = 18 − (−6) = 18 + 6 = 24.Then: [9 − {…}] = 9 − 24 = −15.Finally: 6 − [ … ] = 6 − (−15) = 6 + 15 = 21. Verification / Alternative check: Rewrite as 6 − 9 + {18 − (15 − 12 − 9)}; compute inner part as 24; then 6 − 9 + 24 = 21. Why Other Options Are Wrong: Values like 4, 5, 3, or 1 arise from sign mistakes, such as treating 18 − (−6) as 12 or dropping the final negative in 9 − 24. Common Pitfalls: Not handling “minus a negative” correctly; skipping the left-to-right evaluation inside the innermost parentheses. Final Answer: 21

Question 17

Decimal multiplication — compute exactly Evaluate 10.8 × 5.5 × 8.4 and report the exact product.

Accepted Answer

Introduction / Context: Accurate decimal multiplication benefits from breaking the task into manageable parts and accounting for decimal places at the end or by stagewise multiplication. Given Data / Assumptions: Compute P = 10.8 × 5.5 × 8.4. Standard decimal arithmetic applies. Concept / Approach: Multiply two factors at a time, then multiply the result by the third. Keep track of decimal placement or do integer multiplication with scaled factors. Step-by-Step Solution: First pair: 10.8 × 5.5 = (10.8 × 5) + (10.8 × 0.5) = 54 + 5.4 = 59.4.Then multiply by 8.4: 59.4 × 8 = 475.2 and 59.4 × 0.4 = 23.76.Sum: 475.2 + 23.76 = 498.96. Verification / Alternative check: Use integer scaling: 108 × 55 × 84 = 498960; adjust by 4 decimal places total → 498.96. Why Other Options Are Wrong: 489.96 and 485.69 come from partial products or misplaced decimals; 458.69 and 509.86 are miscalculations. Common Pitfalls: Forgetting to include the 0.5 part of 5.5, or misplacing decimal points after the final multiplication. Final Answer: 498.96

Question 18

Linear equation from a difference and a factor Compute ? such that 8648 − 7652 = ? × 40.

Accepted Answer

Introduction / Context: Turning a worded arithmetic statement into a simple linear equation is a basic but essential skill. Here, we isolate the unknown multiplier from a known difference and a given factor. Given Data / Assumptions: Equation: 8648 − 7652 = ? × 40. All numbers are exact integers. Concept / Approach: First compute the left-hand difference. Then divide that difference by 40 to isolate the unknown ?. This is a direct application of reversing multiplication by division. Step-by-Step Solution: Compute the difference: 8648 − 7652 = 996.Set up: 996 = ? × 40.Solve for ?: ? = 996 / 40 = 24.9. Verification / Alternative check: Multiply back: 24.9 × 40 = 996, which matches the computed difference. Why Other Options Are Wrong: 28.9, 27.4, 25.9, and 24.7 are close distractors; only 24.9 satisfies the exact equality. Common Pitfalls: Arithmetic slip in the subtraction or rounding the quotient instead of keeping the exact decimal 24.9. Final Answer: 24.9

Question 19

Sequential subtraction with decimals Evaluate 683.46 − 227.39 − 341.85 and choose the exact result.

Accepted Answer

Introduction / Context: Accurate decimal arithmetic requires aligning place values and performing operations in sequence. Here we subtract two amounts from a starting value. Given Data / Assumptions: Compute V = 683.46 − 227.39 − 341.85. Operations are left to right. Concept / Approach: Perform the first subtraction, then subtract the second result. Keep two decimal places consistently to avoid rounding drift. Step-by-Step Solution: First: 683.46 − 227.39 = 456.07.Second: 456.07 − 341.85 = 114.22. Verification / Alternative check: Use regrouping or a calculator check: both steps confirm 114.22 exactly. Why Other Options Are Wrong: 141.22 and 144.22 swap digits; 112.22 and 111.42 reflect carry/borrow mistakes. Common Pitfalls: Not aligning decimal points, or subtracting out of order. Final Answer: 114.22

Question 20

Scoring with positive and negative marks Mohan gets +3 for each correct answer and −2 for each wrong answer. He attempts 30 questions and scores 40 marks in total. How many answers did he get correct?

Accepted Answer

Introduction / Context: This is a linear system framed by total attempts and net score under positive and negative marking. We create two equations and solve for the number of correct answers. Given Data / Assumptions: Total attempts = 30. Marks: +3 per correct, −2 per wrong. Total score = 40. Concept / Approach: Let c be the number of correct answers and w be the number of wrong answers. Then c + w = 30 and 3c − 2w = 40. Solve the system by substitution or elimination. Step-by-Step Solution: From c + w = 30, we get w = 30 − c.Substitute into 3c − 2w = 40 → 3c − 2(30 − c) = 40.Simplify: 3c − 60 + 2c = 40 → 5c = 100.Hence c = 100/5 = 20. Verification / Alternative check: Compute score with c = 20, w = 10: 20 × 3 − 10 × 2 = 60 − 20 = 40, which matches. Why Other Options Are Wrong: 25, 10, 15, and 18 do not satisfy both equations simultaneously. Common Pitfalls: Mixing up signs for wrong answers or forgetting that c + w must equal 30. Final Answer: 20

Simplification Questions