Q: If 16% of an electricity bill is deducted as a discount and Rs 1806 is still payable, what was the original bill amount in rupees?

Introduction / Context: This is a classic percentage and discount question from aptitude tests. It models a real electricity bill situation where a certain percentage is deducted as a rebate or concession, and we must recover the original bill amount from the net amount paid. Given Data / Assumptions: Let the original bill amount be B rupees. Discount given is 16% of B. After the discount, the payable amount is Rs 1806. We assume all amounts are in rupees and the percentage is applied on the full bill. Concept / Approach: If a discount of d% is given, the customer pays (100 - d)% of the original amount. Here the customer pays 84% of the bill, because 100% - 16% = 84%. Therefore, 0.84 * B = 1806. We can solve this linear equation to find B. Step-by-Step Solution: Let B be the original electricity bill. After a 16% deduction, the payable fraction is 84% = 84 / 100 = 0.84. So, 0.84 * B = 1806. Rewrite in fraction form: (84 / 100) * B = 1806. Therefore, B = 1806 * (100 / 84). Simplify 100 / 84 = 25 / 21. So B = 1806 * 25 / 21. First compute 1806 / 21 = 86. Then multiply 86 * 25 = 2150. Hence the original bill was Rs 2150. Verification / Alternative check: Check by recalculating the discount: 16% of 2150 = (16 / 100) * 2150 = 0.16 * 2150 = 344. Subtract the discount from the original bill: 2150 - 344 = 1806. This matches the given payable amount, confirming the answer. Why Other Options Are Wrong: Rs 1557, Rs 1593, Rs 2186 and Rs 2250 all give different net amounts when 16% is deducted, not equal to 1806. For example, 16% of 2186 is 349.76, and 2186 - 349.76 is not 1806. Common Pitfalls: Students sometimes treat 16% as the remaining part instead of the discount, leading to equations like 0.16B = 1806 which is incorrect. Another error is rounding too early or mishandling division by 84. Keeping the fraction form and simplifying step by step usually reduces mistakes. Final Answer: The original electricity bill was Rs 2150.

Question 1

If x - 5 ≤ 2x - 3 and 2x - 1/2 ≥ 5x + 2 hold simultaneously, then which of the following values can x take?

Accepted Answer

Introduction / Context: This aptitude question tests the ability to solve and interpret simultaneous linear inequalities in one variable. Such inequalities frequently appear in school mathematics, competitive exams, and real life situations where a quantity has to satisfy more than one condition at the same time. Given Data / Assumptions: x is a real number. Inequality 1: x - 5 ≤ 2x - 3 Inequality 2: 2x - 1/2 ≥ 5x + 2 We must find which option satisfies both inequalities simultaneously. Concept / Approach: To solve a system of inequalities in a single variable, we solve each inequality separately to obtain an interval for x. Then we intersect the intervals to get the common solution set. Finally, we check which option values lie in that common interval. Step-by-Step Solution: From x - 5 ≤ 2x - 3, subtract x from both sides to get -5 ≤ x - 3. Add 3 on both sides: -2 ≤ x, so x ≥ -2. Now consider 2x - 1/2 ≥ 5x + 2. Subtract 2x: -1/2 ≥ 3x + 2. Subtract 2 on both sides: -1/2 - 2 ≥ 3x, which gives -5/2 ≥ 3x. Divide by 3 (positive), so x ≤ -5/6. Combined solution: -2 ≤ x ≤ -5/6. Check the options: -1 lies in the interval, 1 and 3 are greater than -5/6, and -3 is less than -2, while 0 is also greater than -5/6. So only x = -1 satisfies both inequalities. Verification / Alternative check: Substitute x = -1 into both inequalities: First: -1 - 5 = -6 and 2(-1) - 3 = -5, so -6 ≤ -5 is true. Second: 2(-1) - 1/2 = -2.5 and 5(-1) + 2 = -3, so -2.5 ≥ -3 is also true. Thus x = -1 is correct. Why Other Options Are Wrong: x = 1 gives 1 - 5 ≤ 2 - 3 which simplifies to -4 ≤ -1 (true), but 2(1) - 1/2 ≥ 5(1) + 2 gives 1.5 ≥ 7 which is false. x = 3 satisfies neither inequality simultaneously. x = -3 fails the first inequality because -3 - 5 ≤ -6 - 3 becomes -8 ≤ -9 which is false. x = 0 gives 0 ≥ -2 but fails the second inequality because -0.5 ≥ 2 is false. Common Pitfalls: Students often forget to find the intersection of solution sets and may stop after solving only one inequality. Another frequent mistake is mishandling signs when moving terms across the inequality, which changes the direction only when multiplying or dividing by a negative number, not by a positive number like 3 here. Final Answer: The only value of x that satisfies both inequalities is -1.

Question 2

Evaluate the product 199992 × 200008 using an appropriate algebraic identity.

Accepted Answer

Introduction / Context: This question tests quick calculation using algebraic identities instead of direct multiplication. Numbers that lie symmetrically around a round figure like 100000 or 200000 can be handled very efficiently using the identity for the product of a sum and a difference. Given Data / Assumptions: We need to compute 199992 × 200008. Both numbers are close to 200000. No calculator is assumed in an exam setting, so algebraic simplification is expected. Concept / Approach: When two numbers are equidistant from a central value a, say a - b and a + b, their product can be written as (a - b)(a + b) = a^2 - b^2. Here that central value is 200000, and the distance b is 8. This reduces large multiplications to simple squaring and subtraction. Step-by-Step Solution: Write 199992 as 200000 - 8 and 200008 as 200000 + 8. So 199992 × 200008 = (200000 - 8)(200000 + 8). Apply the identity (a - b)(a + b) = a^2 - b^2. Here a = 200000 and b = 8, so the product is 200000^2 - 8^2. Compute 200000^2 = 200000 * 200000 = 40,000,000,000. Compute 8^2 = 64. Subtract: 40,000,000,000 - 64 = 39,999,999,936. Thus the required value is 39,999,999,936, which matches option 39999999936. Verification / Alternative check: We can check the order of magnitude. Both numbers are about 2 × 10^5, so their product should be close to 4 × 10^10. Our result 3.9999999936 × 10^10 is extremely close to 4 × 10^10, so it is numerically reasonable. Why Other Options Are Wrong: 39999799936 is smaller by 200000 from the correct result, which would correspond to an incorrect adjustment term. 39999999836 and 39999999926 differ from the correct value by 100 or 10, reflecting likely arithmetic slips in subtracting 64. 39999999736 is also off by 200, indicating an incorrect square of 8 or a mis-subtraction. Common Pitfalls: A common mistake is to try direct multiplication, which is lengthy and error prone. Another frequent error is squaring 200000 incorrectly or miscomputing 8^2 or the final subtraction step. Remembering and confidently applying the identity (a - b)(a + b) = a^2 - b^2 is the fastest and safest approach here. Final Answer: The value of 199992 × 200008 is 39999999936.

Question 3

For which of the following quadratic equations do the roots remain real numbers?

Accepted Answer

Introduction / Context: This question checks understanding of when a quadratic equation has real roots. The condition for real roots is based on the discriminant, a fundamental concept in algebra and quadratic equations used widely in aptitude tests and school examinations. Given Data / Assumptions: General quadratic equation: ax^2 + bx + c = 0. Options are different quadratic equations. We must identify which one has real roots. Concept / Approach: For ax^2 + bx + c = 0, the discriminant D is given by D = b^2 - 4ac. If D > 0, there are two distinct real roots. If D = 0, there is one repeated real root. If D < 0, the roots are complex and not real. We simply compute D for each option and check its sign. Step-by-Step Solution: Option A: 4x^2 - 9x + 6 = 0, here a = 4, b = -9, c = 6. D = (-9)^2 - 4*4*6 = 81 - 96 = -15 (negative, no real roots). Option B: 3x^2 - 2x + 6 = 0, a = 3, b = -2, c = 6. D = (-2)^2 - 4*3*6 = 4 - 72 = -68 (negative, no real roots). Option C: 2x^2 - 7x + 6 = 0, a = 2, b = -7, c = 6. D = (-7)^2 - 4*2*6 = 49 - 48 = 1 (positive, two distinct real roots). Option D: x^2 - 2x + 2 = 0, a = 1, b = -2, c = 2. D = (-2)^2 - 4*1*2 = 4 - 8 = -4 (negative, no real roots). Option E: x^2 + 4x + 5 = 0, a = 1, b = 4, c = 5. D = 4^2 - 4*1*5 = 16 - 20 = -4 (negative, no real roots). Hence only 2x^2 - 7x + 6 = 0 has real roots. Verification / Alternative check: We can factor option C: 2x^2 - 7x + 6 = 0 as (2x - 3)(x - 2) = 0. This gives real roots x = 3/2 and x = 2, which confirms that the discriminant result is correct. None of the other equations factor nicely into real linear factors. Why Other Options Are Wrong: Options A, B, D and E all have negative discriminants, which means their roots are complex conjugates, not real numbers. Even though coefficients look simple, a negative discriminant disqualifies them immediately for real roots. Common Pitfalls: Many learners guess based on factorisation attempts without computing the discriminant. This can be risky when factorisation is not obvious. Always remember that the discriminant test is decisive and quick, especially in multiple choice exams where you must justify real versus complex roots efficiently. Final Answer: The quadratic equation that has real roots is 2x^2 - 7x + 6 = 0.

Question 4

Solve the simultaneous equations 4x - 3y = 10 and 3x + y = 14 and identify the correct ordered pair (x, y).

Accepted Answer

Introduction / Context: This problem involves solving a system of two linear equations in two variables. Such questions are fundamental in algebra and aptitude tests and model real life scenarios where two linear conditions must be satisfied simultaneously by the same pair of values. Given Data / Assumptions: Equation 1: 4x - 3y = 10 Equation 2: 3x + y = 14 We must find the ordered pair (x, y) that satisfies both equations. Concept / Approach: To solve simultaneous linear equations, standard methods include substitution, elimination, or matrix methods. For two simple equations, the elimination method is very efficient. We eliminate one variable by combining the equations so that its coefficient becomes zero, then solve for the remaining variable and back substitute. Step-by-Step Solution: From Equation 2, express y in terms of x: 3x + y = 14 implies y = 14 - 3x. Substitute this into Equation 1: 4x - 3(14 - 3x) = 10. Simplify: 4x - 42 + 9x = 10, so 13x - 42 = 10. Add 42 to both sides: 13x = 52. Divide by 13: x = 52 / 13 = 4. Now substitute x = 4 back into y = 14 - 3x. y = 14 - 3*4 = 14 - 12 = 2. Therefore the solution is (x, y) = (4, 2). Verification / Alternative check: Check in both equations: Equation 1: 4*4 - 3*2 = 16 - 6 = 10, which is satisfied. Equation 2: 3*4 + 2 = 12 + 2 = 14, which is also satisfied. Since the pair satisfies both equations, it is the unique solution for this system. Why Other Options Are Wrong: (5, 3) gives 4*5 - 3*3 = 20 - 9 = 11, not 10, so it fails the first equation. (11, 1) fails the second equation because 3*11 + 1 = 34, not 14. (2, 3) fails both equations as 4*2 - 3*3 = 8 - 9 = -1 and 3*2 + 3 = 9. (6, 4) gives 24 - 12 = 12 for the first equation, not 10, so it is incorrect. Common Pitfalls: Typical mistakes include arithmetic errors when distributing or combining like terms, or substituting incorrectly. Another common issue is mixing up x and y when checking ordered pairs. Writing the substitution step clearly and checking the final candidate in both equations avoids such errors. Final Answer: The correct ordered pair is (4, 2).

Question 5

If 16% of an electricity bill is deducted as a discount and Rs 1806 is still payable, what was the original bill amount in rupees?

Accepted Answer

Introduction / Context: This is a classic percentage and discount question from aptitude tests. It models a real electricity bill situation where a certain percentage is deducted as a rebate or concession, and we must recover the original bill amount from the net amount paid. Given Data / Assumptions: Let the original bill amount be B rupees. Discount given is 16% of B. After the discount, the payable amount is Rs 1806. We assume all amounts are in rupees and the percentage is applied on the full bill. Concept / Approach: If a discount of d% is given, the customer pays (100 - d)% of the original amount. Here the customer pays 84% of the bill, because 100% - 16% = 84%. Therefore, 0.84 * B = 1806. We can solve this linear equation to find B. Step-by-Step Solution: Let B be the original electricity bill. After a 16% deduction, the payable fraction is 84% = 84 / 100 = 0.84. So, 0.84 * B = 1806. Rewrite in fraction form: (84 / 100) * B = 1806. Therefore, B = 1806 * (100 / 84). Simplify 100 / 84 = 25 / 21. So B = 1806 * 25 / 21. First compute 1806 / 21 = 86. Then multiply 86 * 25 = 2150. Hence the original bill was Rs 2150. Verification / Alternative check: Check by recalculating the discount: 16% of 2150 = (16 / 100) * 2150 = 0.16 * 2150 = 344. Subtract the discount from the original bill: 2150 - 344 = 1806. This matches the given payable amount, confirming the answer. Why Other Options Are Wrong: Rs 1557, Rs 1593, Rs 2186 and Rs 2250 all give different net amounts when 16% is deducted, not equal to 1806. For example, 16% of 2186 is 349.76, and 2186 - 349.76 is not 1806. Common Pitfalls: Students sometimes treat 16% as the remaining part instead of the discount, leading to equations like 0.16B = 1806 which is incorrect. Another error is rounding too early or mishandling division by 84. Keeping the fraction form and simplifying step by step usually reduces mistakes. Final Answer: The original electricity bill was Rs 2150.

Question 6

Evaluate the expression (5.6 × 0.36 + 0.42 × 3.2) ÷ (0.8 × 2.1).

Accepted Answer

Introduction / Context: This question involves decimal multiplication and division, and it can be simplified neatly using basic arithmetic and factorisation. It checks comfort with decimal operations and recognition that many decimals can be treated as simple fractions for easier calculation. Given Data / Assumptions: We must evaluate: Numerator: 5.6 × 0.36 + 0.42 × 3.2 Denominator: 0.8 × 2.1 The final value is (5.6 × 0.36 + 0.42 × 3.2) ÷ (0.8 × 2.1). Concept / Approach: Decimals can be converted into fractions in order to cancel common factors. For example, 5.6 = 56 / 10, 0.36 = 36 / 100, 0.42 = 42 / 100, 3.2 = 32 / 10, 0.8 = 8 / 10 and 2.1 = 21 / 10. Simplifying with fractions often reveals cancellations that make the computation quick and accurate. Step-by-Step Solution: First compute 5.6 × 0.36. As fractions this is (56 / 10) * (36 / 100) = (56 * 36) / 1000. 56 * 36 = 2016, so the product is 2016 / 1000 = 2.016. Now compute 0.42 × 3.2. This is (42 / 100) * (32 / 10) = (42 * 32) / 1000. 42 * 32 = 1344, so the product is 1344 / 1000 = 1.344. Add the two products: 2.016 + 1.344 = 3.36. Now compute the denominator 0.8 × 2.1 = (8 / 10) * (21 / 10) = 168 / 100 = 1.68. Therefore the required value is 3.36 ÷ 1.68. Compute 3.36 ÷ 1.68 = 2. Verification / Alternative check: We can scale numerator and denominator by 100 to avoid decimals: 3.36 ÷ 1.68 = 336 ÷ 168. Divide both by 168 to get 336 / 168 = 2. This confirms the result. Why Other Options Are Wrong: 1, 3, 3/2 and 5/2 would only be obtained if intermediate products or the final division were computed incorrectly. For instance, miscalculating 5.6 × 0.36 as 2.016 and then adding a wrong value for 0.42 × 3.2 could lead to a wrong numerator and hence a wrong final result. Common Pitfalls: Errors often arise from mishandling decimal places or ignoring that 0.8 × 2.1 is not 1.6 but 1.68. Converting decimals to fractions and simplifying helps avoid such mistakes. Careful alignment of decimal places when multiplying and adding is also critical for accuracy. Final Answer: The value of the given expression is 2.

Question 7

If a = 1.2, b = 0.8 and c = 0.7, then what is the value of (a^3 + b^3 + c^3 - 2.016) ÷ [1.35((1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56)]?

Accepted Answer

Introduction / Context: This question is based on the algebraic identity for the sum of cubes of three numbers. The expression looks complicated because of decimals and many terms, but it is cleverly structured so that well known identities simplify it dramatically. Given Data / Assumptions: We are told: a = 1.2, b = 0.8, c = 0.7 Numerator: a^3 + b^3 + c^3 - 2.016 Denominator: 1.35[(1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56] Note that 2.016 = 3 * 1.2 * 0.8 * 0.7 and that 0.96, 0.84 and 0.56 are pairwise products of a, b and c. Concept / Approach: The key algebraic identities are: a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca) and the structure in the denominator resembles (a + b + c) or a multiple of it times (a^2 + b^2 + c^2 - ab - bc - ca). Recognising that 2.016 = 3abc and that 1.35 equals (a + b + c) / 2 allows us to reduce the entire expression to a simple constant. Step-by-Step Solution: First compute a + b + c = 1.2 + 0.8 + 0.7 = 2.7. Compute abc = 1.2 * 0.8 * 0.7 = 0.672. Then 3abc = 3 * 0.672 = 2.016, which matches the term in the numerator. So numerator = a^3 + b^3 + c^3 - 3abc. Using the identity, numerator = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca). Compute a^2 + b^2 + c^2: 1.2^2 = 1.44, 0.8^2 = 0.64, 0.7^2 = 0.49, total = 2.57. Compute ab + bc + ca: ab = 0.96, bc = 0.56, ca = 0.84, total = 2.36. Hence a^2 + b^2 + c^2 - ab - bc - ca = 2.57 - 2.36 = 0.21. So numerator = (2.7) * (0.21) = 0.567. Next, observe that 1.35 = 2.7 / 2 = (a + b + c) / 2. Denominator = 1.35 * (a^2 + b^2 + c^2 - ab - bc - ca) = (2.7 / 2) * 0.21 = 0.2835. Therefore the required value is 0.567 / 0.2835 = 2. Verification / Alternative check: Direct calculator based computation also yields about 2.000, confirming the algebraic simplification. The identity based approach is more instructive and avoids round off errors in competitive exams. Why Other Options Are Wrong: 1/4, 1/2 and 1 are much smaller than 2 and would arise only if a student forgot the factor 1.35 in the denominator or misapplied the identity. 3/4 is also inconsistent with the ratio 0.567 to 0.2835, which is almost exactly 2. Common Pitfalls: A frequent mistake is to cube decimals incorrectly or to ignore that 2.016 equals 3abc. Another common error is to assume that 1.35 is arbitrary and not related to a + b + c. Recognising patterns in expressions and linking them to standard identities is crucial for solving such problems quickly and accurately. Final Answer: The value of the given expression is 2.

Question 8

Let S = 1/(1 × 3 × 5) + 1/(1 × 4) + 1/(3 × 5 × 7) + 1/(4 × 7) + 1/(5 × 7 × 9) + 1/(7 × 10) + ... up to 20 terms. What is the value of S?

Accepted Answer

Introduction / Context: This is a challenging series simplification problem from higher level aptitude exams. The series S consists of alternating terms with three factors in the denominator and two factors in the denominator. The denominators follow a clear pattern, and the sum up to 20 terms must be evaluated exactly as a rational number. Given Data / Assumptions: We are given: S = 1/(1 × 3 × 5) + 1/(1 × 4) + 1/(3 × 5 × 7) + 1/(4 × 7) + 1/(5 × 7 × 9) + 1/(7 × 10) + ... The pattern continues in the same way up to 20 terms. The terms alternate between a fraction with three consecutive odd numbers and a fraction with two numbers that form an arithmetic progression with common difference 3. Concept / Approach: The key idea is to identify a general term for the sequence and then express each term using partial fraction decomposition so that the overall series telescopes. Telescoping means that many intermediate terms cancel out when we sum the series, leaving only a few boundary terms to evaluate. This technique is common in advanced series problems. Step-by-Step Solution: Observe the triple denominator terms: (1,3,5), (3,5,7), (5,7,9), ... These form consecutive odd numbers. For the n-th triple term, the denominator can be written as (2n - 1)(2n + 1)(2n + 3). Similarly, the double denominator terms are (1,4), (4,7), (7,10), ... which follow the pattern (3n - 2, 3n + 1). Hence S can be written as the sum from n = 1 to 10 of two terms for each n: 1/[(2n - 1)(2n + 1)(2n + 3)] + 1/[(3n - 2)(3n + 1)]. Now use partial fractions for the triple term: 1/[(2n - 1)(2n + 1)(2n + 3)] can be expressed as a difference of two fractions with denominators (2n - 1)(2n + 1) and (2n + 1)(2n + 3). Similarly, 1/[(3n - 2)(3n + 1)] can be decomposed into a difference involving 1/(3n - 2) and 1/(3n + 1). When we write out several terms explicitly, most intermediate fractions cancel in a telescoping manner, leaving only a few starting and ending contributions. Carrying this algebra through up to n = 10 gives a final exact fraction S = 6070/14973. Verification / Alternative check: We can verify numerically by computing all 20 terms using a calculator or a computer algebra system. Evaluating the exact rational sum confirms that S equals 6070/14973, which also matches the option given. Why Other Options Are Wrong: 6179/15275, 7191/15174 and 5183/16423 are close looking rational numbers but result from incorrect partial fraction decomposition or an incorrect count of terms. Because the cancellation pattern is subtle, losing or adding one extra term at either end of the telescoping series easily leads to one of these incorrect distractors. The option 4501/12025 is an additional plausible fraction but does not match the carefully computed exact sum. Common Pitfalls: Students may misread the pattern and assume pure arithmetic or geometric progression instead of the given alternating structure. Another common mistake is to stop telescoping too early or mishandle the indices for the first and last terms, which leads to a slightly wrong rational result. Writing down the first few terms clearly and checking the cancellation process step by step is essential. Final Answer: The value of S up to 20 terms is 6070/14973.

Question 9

Consider the three integers 1123, 1294 and 15. Which of the following chained inequalities using “greater than” is true?

Accepted Answer

Introduction / Context: This is a basic comparison and ordering question. It tests whether you can quickly compare three given integers and write them in the correct decreasing order using the greater than symbol. Such questions appear as simple warm up items in quantitative aptitude tests. Given Data / Assumptions: The integers are 1123, 1294 and 15. We must select the option that lists them in a correct decreasing order using the symbol “>”. Concept / Approach: To order numbers, compare their magnitudes: The number with the highest value should appear first in a decreasing chain. The smallest number should appear at the end. We compare thousands, hundreds, tens and units place where appropriate to rank the integers. Step-by-Step Solution: Compare 1294 and 1123. Both are four digit numbers, but 1294 has 12 hundreds and 94 units while 1123 has 11 hundreds and 23 units. Clearly, 1294 > 1123. Next compare 1123 and 15. 1123 is a four digit number while 15 is only a two digit number, so 1123 > 15. From these comparisons we obtain the order: 1294 > 1123 > 15. Hence the correct chained inequality is 1294 > 1123 > 15. Verification / Alternative check: If needed, think in terms of approximate sizes: 1294 is close to 1300, 1123 is close to 1100, 15 is very small compared to any four digit number. This confirms the order 1294 > 1123 > 15. Why Other Options Are Wrong: 1123 > 1294 > 15 is incorrect because the first comparison 1123 > 1294 is false. 15 > 1123 > 1294 and 15 > 1294 > 1123 are both impossible since 15 is clearly the smallest number. 1123 > 15 > 1294 is wrong because 15 is not greater than 1294. Common Pitfalls: Sometimes students misread digits or focus only on the last digits rather than comparing from the highest place value. Always compare from left to right: thousands, hundreds, tens and units. It is also easy to read the chained inequality backwards, so double check that you are interpreting “>” correctly as “greater than”. Final Answer: The true inequality is 1294 > 1123 > 15.

Question 10

A and B are positive integers with A, B ≤ 15 and A + B + AB = 65. What is the difference between A and B?

Accepted Answer

Introduction / Context: This problem is a neat application of algebraic manipulation to transform a seemingly complicated expression into a factorised form. It appears often in aptitude exams under algebra and number system topics, using a classic trick A + B + AB = constant. Given Data / Assumptions: A and B are positive integers. A, B ≤ 15. A + B + AB = 65. We must find the absolute difference between A and B. Concept / Approach: A key identity is: A + B + AB + 1 = (A + 1)(B + 1). By adding 1 to both sides of the given equation, we obtain a factorised form that allows us to find integers A and B as factors of 66. Then we can enforce the condition A, B ≤ 15 and compute the difference between the valid pair. Step-by-Step Solution: Given A + B + AB = 65. Add 1 to both sides: A + B + AB + 1 = 66. Recognise the factorisation (A + 1)(B + 1) = 66. Now list factor pairs of 66: (1, 66), (2, 33), (3, 22), (6, 11) and their reverses. So possible pairs for (A + 1, B + 1) are (1, 66), (2, 33), (3, 22), (6, 11), (11, 6), (22, 3), (33, 2), (66, 1). A and B must be positive and at most 15. Thus A + 1 and B + 1 must be at most 16. The only factor pair within this limit is (6, 11), giving A + 1 = 6, B + 1 = 11 or A + 1 = 11, B + 1 = 6. Hence (A, B) is either (5, 10) or (10, 5). The difference |A - B| = |5 - 10| = 5. Verification / Alternative check: Check with A = 5, B = 10: A + B + AB = 5 + 10 + 5*10 = 15 + 50 = 65, which satisfies the condition. Similarly, A = 10 and B = 5 gives the same sum, so the pair is valid and unique under the given constraints. Why Other Options Are Wrong: Differences 3, 4, 6 and 2 correspond to other factor pairs, but those factor pairs either do not multiply to 66 or lead to A or B values greater than 15 or non positive, which are not allowed. Common Pitfalls: One frequent mistake is to treat A + B + AB as (A + B)^2, which is incorrect. Another common error is to forget to add 1 before factorising. Recognising the standard transformation A + B + AB = (A + 1)(B + 1) - 1 is a powerful trick in many exam problems of this style. Final Answer: The required difference between A and B is 5.

Question 11

Evaluate the sum 14^3 + 16^3 + 18^3 + ... + 30^3.

Accepted Answer

Introduction / Context: This problem involves summing cubes of even integers in an arithmetic progression. It tests knowledge of series, in particular the formula for the sum of cubes, and the ability to transform a sum over even numbers into a more manageable form. Given Data / Assumptions: We need to compute S = 14^3 + 16^3 + 18^3 + ... + 30^3. The numbers 14, 16, 18, ..., 30 form an arithmetic progression with common difference 2. All calculations are exact integer computations. Concept / Approach: One useful observation is that each term is the cube of an even number, so we can factor out powers of 2. Specifically, (2k)^3 = 8k^3. This allows us to rewrite the sum over even numbers as a constant multiple of a sum over consecutive integers. We then use the standard formula for the sum of cubes: 1^3 + 2^3 + ... + n^3 = [n(n + 1)/2]^2. Step-by-Step Solution: Write each term as the cube of an even integer: 14 = 2*7, 16 = 2*8, ..., 30 = 2*15. Therefore, 14^3 = (2*7)^3 = 8*7^3, 16^3 = 8*8^3, ..., 30^3 = 8*15^3. So S = 8(7^3 + 8^3 + ... + 15^3). Now consider T = 1^3 + 2^3 + ... + 15^3 and U = 1^3 + 2^3 + ... + 6^3. Then 7^3 + 8^3 + ... + 15^3 = T - U. Using the sum of cubes formula, T = [15*16 / 2]^2 = (120)^2 = 14400. Similarly, U = [6*7 / 2]^2 = (21)^2 = 441. Thus 7^3 + 8^3 + ... + 15^3 = 14400 - 441 = 13959. Now S = 8 * 13959 = 111672. Verification / Alternative check: We can directly compute each cube and add: 14^3 = 2744, 16^3 = 4096, 18^3 = 5832, 20^3 = 8000, 22^3 = 10648, 24^3 = 13824, 26^3 = 17576, 28^3 = 21952, 30^3 = 27000. Adding these step by step yields 111672, confirming the formula based result. Why Other Options Are Wrong: 134576, 120212, 115624 and 125000 arise from partial sums, misapplied formulas or arithmetic errors when adding cubes. Because each cube is quite large, even a small mistake in one term can push the total toward one of these incorrect options. Common Pitfalls: A common mistake is to confuse the sum of cubes formula with the sum of squares formula, or to forget to subtract the first few cubes when using T - U. Another error is incorrectly computing cubes of two digit numbers. Using the factorisation (2k)^3 = 8k^3 and the standard sum of cubes formula keeps the work organised and reliable. Final Answer: The value of 14^3 + 16^3 + 18^3 + ... + 30^3 is 111672.

Question 12

Evaluate the nested radical expression √(4600 + √(540 + √(1280 + √(250 + √36)))).

Accepted Answer

Introduction / Context: Nested square root expressions are popular in aptitude exams because they look intimidating but often simplify to neat integers if evaluated carefully from the inside out. This problem tests comfort with square roots and recognition of perfect squares hidden inside larger numbers. Given Data / Assumptions: We must evaluate: S = √(4600 + √(540 + √(1280 + √(250 + √36))). All roots are principal square roots. The structure suggests that each nested expression becomes a perfect square at each step. Concept / Approach: The strategy is to work from the innermost radical outward. We repeatedly simplify each square root, checking whether the expression inside is a perfect square. If it is, the square root simplifies to an integer, which then feeds into the next level. These carefully designed chains commonly collapse to an integer at each step. Step-by-Step Solution: Start with the innermost term: √36 = 6. Next layer: √(250 + √36) = √(250 + 6) = √256. Since 256 = 16^2, √256 = 16. Move one level out: √(1280 + 16) = √1296. 1296 is 36^2, so this root equals 36. Next level: √(540 + 36) = √576. 576 is 24^2, so the value is 24. Finally evaluate the outermost root: √(4600 + 24) = √4624. 4624 is 68^2, so √4624 = 68. Therefore the overall value of the nested radical is 68. Verification / Alternative check: We can verify by squaring the final answer: 68^2 = (70 - 2)^2 = 70^2 - 2*70*2 + 2^2 = 4900 - 280 + 4 = 4624. This matches the outermost inner value 4600 + 24. Since each inner radical was also checked as a perfect square, the entire computation is consistent. Why Other Options Are Wrong: 69, 70 and 72 correspond to nearby squares 4761, 4900 and 5184, all of which are larger than 4624. 64 gives 4096 when squared, which is too small. These distractors would arise if a step such as 540 + 36 were miscomputed, or if a root like √576 were misread as 25 instead of 24. Common Pitfalls: A common mistake is to rush and treat 250 + 36 as 286 or misread 1296 as 34^2 rather than 36^2. Another issue is not recognising perfect squares like 256, 576 and 4624 quickly. Practising squares of integers up to 50 makes such questions much faster and more reliable. Final Answer: The value of the nested radical is 68.

Question 13

If x + y + z = 0, then what is the value of (3y^2 + x^2 + z^2) ÷ (2y^2 - xz)?

Accepted Answer

Introduction / Context: This algebraic simplification question uses a condition linking x, y and z to reduce a seemingly complicated rational expression to a simple constant. Such identities are common in competitive exams and test how well a student can manipulate expressions using given relations. Given Data / Assumptions: x, y and z are real numbers. Condition: x + y + z = 0. We must evaluate (3y^2 + x^2 + z^2) ÷ (2y^2 - xz). Concept / Approach: The key is to use the condition x + y + z = 0 to express x + z in terms of y and then relate x^2 + z^2 and xz to y. By rewriting x^2 + z^2 using (x + z)^2 and xz, we can simplify the numerator and denominator in a systematic way. Such manipulations rely on standard algebraic identities like (x + z)^2 = x^2 + z^2 + 2xz. Step-by-Step Solution: Given x + y + z = 0, rearrange to x + z = -y. Square both sides: (x + z)^2 = (-y)^2. So x^2 + z^2 + 2xz = y^2. Hence x^2 + z^2 = y^2 - 2xz. Now rewrite the numerator: 3y^2 + x^2 + z^2 = 3y^2 + (y^2 - 2xz) = 4y^2 - 2xz. The denominator is 2y^2 - xz. Observe that 4y^2 - 2xz = 2(2y^2 - xz). Therefore, (3y^2 + x^2 + z^2) ÷ (2y^2 - xz) = [2(2y^2 - xz)] ÷ (2y^2 - xz) = 2. Verification / Alternative check: Choose any convenient numbers satisfying x + y + z = 0, for example x = 1, y = 2, z = -3. Compute numerator: 3y^2 + x^2 + z^2 = 3*(4) + 1 + 9 = 12 + 1 + 9 = 22. Compute denominator: 2y^2 - xz = 2*4 - (1 * -3) = 8 + 3 = 11. Then numerator / denominator = 22 / 11 = 2, which matches the derived value. Why Other Options Are Wrong: Values 1, 3/2, 5/3 and 4/3 would arise only if the relation x + y + z = 0 were not fully used or if the identity for x^2 + z^2 was applied incorrectly. Because the simplification leads exactly to 2, any other constant conflicts with both algebra and the numeric check. Common Pitfalls: Learners sometimes attempt to substitute z = -x - y directly into the expression and expand everything blindly, which can be done but is lengthy and error prone. Using structured identities like (x + z)^2 makes the work much cleaner. Another mistake is to forget that (-y)^2 = y^2, not -y^2. Final Answer: The value of the expression is 2.

Question 14

If P = 7 + 4√3 and PQ = 1, then what is the value of 1/P^2 + 1/Q^2?

Accepted Answer

Introduction / Context: This question uses properties of surds and reciprocal pairs. When the product PQ is 1, P and Q are reciprocals of each other. For expressions involving 1/P^2 and 1/Q^2, recognising that Q = 1/P allows us to reduce the problem to finding P^2 + 1/P^2, which can be computed using simple algebra. Given Data / Assumptions: P = 7 + 4√3. PQ = 1, so Q = 1/P. We must find 1/P^2 + 1/Q^2. Concept / Approach: Since Q = 1/P, we have: 1/P^2 + 1/Q^2 = 1/P^2 + Q^2. But Q^2 = (1/P)^2 = 1/P^2, so it is simpler to note that 1/P^2 + 1/Q^2 = P^2 + 1/P^2 because Q = 1/P. A more straightforward route is to first compute Q explicitly using the conjugate of P, then compute P^2 + Q^2 and use that as the required value. Step-by-Step Solution: We have P = 7 + 4√3. If PQ = 1, then Q must be 1/P. For surds of the form a + b√3, the reciprocal is a - b√3 divided by a^2 - 3b^2. Compute P * (7 - 4√3) = (7 + 4√3)(7 - 4√3) = 7^2 - (4√3)^2 = 49 - 16*3 = 49 - 48 = 1. So Q = 7 - 4√3. Now compute P^2: (7 + 4√3)^2 = 7^2 + 2*7*4√3 + (4√3)^2 = 49 + 56√3 + 48 = 97 + 56√3. Similarly, Q^2 = (7 - 4√3)^2 = 49 - 56√3 + 48 = 97 - 56√3. Then P^2 + Q^2 = (97 + 56√3) + (97 - 56√3) = 194. Because PQ = 1, 1/P^2 = Q^2 and 1/Q^2 = P^2, so 1/P^2 + 1/Q^2 = P^2 + Q^2 = 194. Verification / Alternative check: Note that P * Q = 1 implies P^2 * Q^2 = 1, so P^2 and Q^2 are also reciprocals. The sum of a number and its reciprocal is symmetric, so the result being a rational integer 194 makes sense and matches our explicit computation. Why Other Options Are Wrong: 196, 206 and 182 could appear if one computes only P^2 or only Q^2 rather than their sum, or if 7^2 + 48 is miscalculated. 200 is an attractive round number but does not match the exact algebraic simplification. Common Pitfalls: Some learners forget to use the conjugate to find Q, or they incorrectly compute (4√3)^2 as 16√3 instead of 48. Another common issue is mixing up 1/P^2 + 1/Q^2 with P^2 + Q^2; for reciprocal pairs arising from surds, these two sums are actually equal, which is a powerful shortcut. Final Answer: The value of 1/P^2 + 1/Q^2 is 194.

Question 15

If a^3 + 3a^2 + 9a = 1, then what is the value of a^3 + 3/a?

Accepted Answer

Introduction / Context: This problem tests algebraic manipulation using a given cubic equation in a. Instead of solving explicitly for a, we are expected to transform the given relation to evaluate another expression involving a. This technique appears frequently in algebra and aptitude questions to save time and avoid unnecessary root calculations. Given Data / Assumptions: a is a real number satisfying a^3 + 3a^2 + 9a = 1. We need the value of a^3 + 3/a. Concept / Approach: The idea is to manipulate the given equation to express 1/a in terms of a, then substitute into a^3 + 3/a. Dividing the original equation by a is helpful because it creates 1/a on one side. Once we express 1/a as a polynomial in a, we can combine terms to reach a constant value. Step-by-Step Solution: Given a^3 + 3a^2 + 9a = 1. Divide both sides by a (a is non zero, otherwise the left side would be 0, not 1): a^2 + 3a + 9 = 1/a. We want the value of a^3 + 3/a. Using 1/a = a^2 + 3a + 9, we can rewrite: a^3 + 3/a = a^3 + 3(a^2 + 3a + 9). Expand the right side: a^3 + 3a^2 + 9a + 27. From the original equation, a^3 + 3a^2 + 9a = 1. So a^3 + 3a^2 + 9a + 27 = 1 + 27 = 28. Hence a^3 + 3/a = 28. Verification / Alternative check: We could, in principle, solve the cubic equation for a and then compute the expression numerically, but that is unnecessary. The direct manipulation approach already yields a unique constant, and any real root will satisfy this derived relation. Numerical software also confirms that the real root of the equation indeed gives approximately 28 when substituted into a^3 + 3/a. Why Other Options Are Wrong: 26, 24, 30 and 31 could arise from misplacing the constant term 27 or incorrectly using the relation for 1/a. For example, forgetting to add 27 or miscomputing 3*9 as 18 instead of 27 would give an incorrect answer. Common Pitfalls: A frequent mistake is dividing the original equation incorrectly or assuming that a is 0, which contradicts the equation. Another issue is trying to solve the cubic exactly, which is time consuming and unnecessary here. Recognising that the combination a^3 + 3a^2 + 9a already appears in the target expression is the main insight. Final Answer: The value of a^3 + 3/a is 28.

Question 16

If x, y and z are real numbers such that x^3 + y^3 + z^3 = 13, x + y + z = 1 and xyz = 1, then what is the value of xy + yz + zx?

Accepted Answer

Introduction / Context: This algebra question uses symmetric identities involving the sum of cubes of three numbers, their sum and their product. We are asked to find the sum of pairwise products xy + yz + zx, which is a standard symmetric expression. Such problems are common in algebraic identities and polynomial root based questions. Given Data / Assumptions: x, y, z are real numbers. x^3 + y^3 + z^3 = 13. x + y + z = 1. xyz = 1. We must find S = xy + yz + zx. Concept / Approach: The key identity is: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx). We will use the given values to convert this identity into an equation involving S. We also use the identity: (x + y + z)^2 = x^2 + y^2 + z^2 + 2(xy + yz + zx). These two together allow us to solve for S. Step-by-Step Solution: Let S1 = x + y + z and S2 = xy + yz + zx. Given S1 = 1 and xyz = 1. Use the cubes identity: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx). Substitute given values: 13 - 3*1 = 10. So 10 = S1(x^2 + y^2 + z^2 - S2) = 1*(x^2 + y^2 + z^2 - S2). Hence x^2 + y^2 + z^2 - S2 = 10, so x^2 + y^2 + z^2 = 10 + S2. Now use (x + y + z)^2 = x^2 + y^2 + z^2 + 2S2. S1^2 = 1^2 = 1 = (10 + S2) + 2S2 = 10 + 3S2. Thus 3S2 = 1 - 10 = -9. So S2 = -9 / 3 = -3. Therefore xy + yz + zx = -3. Verification / Alternative check: We can verify the logic by observing that the calculation depends only on symmetric combinations of x, y, z. Any triple of numbers satisfying the given conditions will produce the same S2. There is no need to find x, y and z individually, which would be complicated. Why Other Options Are Wrong: Values -1, 1, 0 and 3 would appear if the identities were misapplied or if 3xyz was forgotten in the sum of cubes formula. For instance, setting 13 equal directly to (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) would produce a different incorrect value. Common Pitfalls: Students often forget the full form of the identity x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx). Another pitfall is mishandling the square (x + y + z)^2, especially the middle term 2(xy + yz + zx). Keeping track of each symbol using S1, S2 and xyz helps to avoid confusion. Final Answer: The value of xy + yz + zx is -3.

Question 17

If (a + b)/c = 6/5 and (b + c)/a = 9/2, then what is the value of (a + c)/b?

Accepted Answer

Introduction / Context: This ratio based algebra problem relates three variables a, b and c through two fractional equations. It is a typical aptitude question that checks comfort with manipulating linear equations involving ratios and expressing one required ratio in terms of the given ones. Given Data / Assumptions: We are given: (a + b)/c = 6/5 (b + c)/a = 9/2 a, b, c are non zero real numbers. We must find (a + c)/b. Concept / Approach: Convert the given fractional equations into linear equations by cross multiplication. Then express a and c in terms of b, or otherwise, and simplify the ratio (a + c)/b. The problem is designed so that the resulting fractions simplify nicely to a simple rational number. Step-by-Step Solution: From (a + b)/c = 6/5, cross multiply to get 5(a + b) = 6c. Thus c = 5(a + b)/6. From (b + c)/a = 9/2, cross multiply: 2(b + c) = 9a. Substitute c into this: 2[b + 5(a + b)/6] = 9a. Inside the brackets, b + 5(a + b)/6 = (6b + 5a + 5b)/6 = (5a + 11b)/6. So 2 * (5a + 11b)/6 = 9a. Simplify: (5a + 11b)/3 = 9a. Multiply both sides by 3: 5a + 11b = 27a. Then 11b = 22a, so b = 2a. Now compute c using c = 5(a + b)/6 = 5(a + 2a)/6 = 5*3a/6 = 5a/2. We need (a + c)/b. Substitute b = 2a and c = 5a/2. a + c = a + 5a/2 = (2a + 5a)/2 = 7a/2. So (a + c)/b = (7a/2) / (2a) = 7a/2 * 1/(2a) = 7/4. Verification / Alternative check: Choose a convenient value for a, say a = 2. Then b = 4, c = 5a/2 = 5. Check the given ratios: (a + b)/c = (2 + 4)/5 = 6/5 which matches. (b + c)/a = (4 + 5)/2 = 9/2 which also matches. Now (a + c)/b = (2 + 5)/4 = 7/4, confirming the result. Why Other Options Are Wrong: Ratios 9/5, 11/7, 7/11 and 5/4 correspond to various incorrect manipulations such as interchanging a and c or dropping a factor in cross multiplication. Because the relationships are linear, a small algebraic slip in isolating a, b or c leads to these distractors. Common Pitfalls: Common errors include cross multiplying incorrectly or forgetting to substitute c in terms of a and b consistently. Another issue is simplifying fractions too quickly and losing track of factors. Writing each step clearly and solving systematically for one variable in terms of another is the safest approach. Final Answer: The value of (a + c)/b is 7/4.

Question 18

If x^3 + y^3 + z^3 = 3(1 + xyz) and P = y + z - x, Q = z + x - y, R = x + y - z, then what is the value of P^3 + Q^3 + R^3 - 3PQR?

Accepted Answer

Introduction / Context: This is a higher level algebra identity problem. It links the sum of cubes of x, y, z with the specially defined variables P, Q and R. The expression P^3 + Q^3 + R^3 - 3PQR is a well known symmetric form that can often be simplified using the identity for the sum of cubes of three numbers and relationships between x, y, z and P, Q, R. Given Data / Assumptions: x, y, z are real numbers. x^3 + y^3 + z^3 = 3(1 + xyz). P = y + z - x, Q = z + x - y, R = x + y - z. We need T = P^3 + Q^3 + R^3 - 3PQR. Concept / Approach: For any three numbers u, v, w, we have the identity: u^3 + v^3 + w^3 - 3uvw = (u + v + w)(u^2 + v^2 + w^2 - uv - vw - wu). We apply this identity to P, Q and R. The trick is to express P + Q + R and the combination P^2 + Q^2 + R^2 - PQ - QR - RP in terms of x, y, z using their definitions, and then exploit the given relation involving x^3 + y^3 + z^3 and xyz. Step-by-Step Solution: First compute P + Q + R: P + Q + R = (y + z - x) + (z + x - y) + (x + y - z). When we add, terms cancel neatly, leaving P + Q + R = x + y + z. Now apply the cubes identity to x, y, z: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx). Given x^3 + y^3 + z^3 = 3(1 + xyz), move 3xyz to the left side: x^3 + y^3 + z^3 - 3xyz = 3. Hence (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) = 3. Using P + Q + R = x + y + z, this becomes (P + Q + R)(x^2 + y^2 + z^2 - xy - yz - zx) = 3. Now a direct but routine algebraic computation shows that: P^2 + Q^2 + R^2 - PQ - QR - RP = 4(x^2 + y^2 + z^2 - xy - yz - zx). Substitute into the identity for P, Q, R: T = P^3 + Q^3 + R^3 - 3PQR = (P + Q + R)(P^2 + Q^2 + R^2 - PQ - QR - RP). So T = (x + y + z) * 4(x^2 + y^2 + z^2 - xy - yz - zx) = 4 * (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx). From the earlier relation, (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) = 3. Therefore T = 4 * 3 = 12. Verification / Alternative check: As a numerical test, we can pick a specific triple (x, y, z) that satisfies x^3 + y^3 + z^3 = 3(1 + xyz) and evaluate P, Q, R and T numerically. Using a computer algebra system, such a triple confirms that T is always 12, independent of the particular solution, which matches the identity based result. Why Other Options Are Wrong: Values 9, 8 and 6 are the sort of constants that appear if the factor 4 in the relation between P, Q, R and x, y, z is omitted or miscalculated. 3 is too small and would correspond to mistakenly equating T directly to x^3 + y^3 + z^3 - 3xyz. Common Pitfalls: The main difficulty is managing the algebra when expressing P^2 + Q^2 + R^2 - PQ - QR - RP in terms of x, y, z. Without careful organisation, it is easy to lose or double count terms. Recognising the symmetry and using known identities rather than expanding every term blindly significantly reduces errors. Final Answer: The value of P^3 + Q^3 + R^3 - 3PQR is 12.

Question 19

If x1, x2 and x3 satisfy x1 x2 x3 = 4(4 + x1 + x2 + x3), then what is the value of [1/(2 + x1)] + [1/(2 + x2)] + [1/(2 + x3)]?

Accepted Answer

Introduction / Context: This is a clever algebra problem involving three variables constrained by a symmetric equation. The task is to evaluate a symmetric sum of reciprocals of linear expressions in x1, x2 and x3. Problems like this are designed to test algebraic insight and the ability to simplify by substitution rather than solving explicitly for each variable. Given Data / Assumptions: x1, x2, x3 are real numbers. x1 x2 x3 = 4(4 + x1 + x2 + x3). We must compute S = 1/(2 + x1) + 1/(2 + x2) + 1/(2 + x3). Concept / Approach: Introduce new variables yi = 2 + xi for i = 1, 2, 3. Then xi = yi - 2. The given condition becomes a relation between y1, y2 and y3. The required sum S becomes 1/y1 + 1/y2 + 1/y3, which often simplifies nicely when the product relation is expressed in terms of the yi. Such substitutions are standard for problems where x appears only in the combination (2 + x). Step-by-Step Solution: Let y1 = 2 + x1, y2 = 2 + x2 and y3 = 2 + x3. Then x1 = y1 - 2, x2 = y2 - 2 and x3 = y3 - 2. The given condition becomes (y1 - 2)(y2 - 2)(y3 - 2) = 4(4 + x1 + x2 + x3). Since x1 + x2 + x3 = (y1 - 2) + (y2 - 2) + (y3 - 2) = y1 + y2 + y3 - 6, we have: 4 + x1 + x2 + x3 = 4 + (y1 + y2 + y3 - 6) = y1 + y2 + y3 - 2. So the relation becomes (y1 - 2)(y2 - 2)(y3 - 2) = 4(y1 + y2 + y3 - 2). Expand the left side symbolically as a cubic in y1, y2, y3. While the full expansion is lengthy, the key outcome is that, after rearrangement, the relation can be written in a symmetric form leading to a constant value for 1/y1 + 1/y2 + 1/y3. A more direct way is to treat y1 and y2 as parameters and solve for y3, then compute S to see if it is constant. For example, take y1 = 3 and y2 = 4. Solving (3 - 2)(4 - 2)(y3 - 2) = 4(3 + 4 + y3 - 2) gives (1 * 2)(y3 - 2) = 4(5 + y3). So 2(y3 - 2) = 4y3 + 20, leading to 2y3 - 4 = 4y3 + 20, hence -24 = 2y3 and y3 = -12. Now S = 1/y1 + 1/y2 + 1/y3 = 1/3 + 1/4 + 1/(-12) = 4/12 + 3/12 - 1/12 = 6/12 = 1/2. Trying other simple values for y1 and y2 that satisfy the relation always yields the same S = 1/2, which shows this value is independent of the particular solution. Verification / Alternative check: The invariance of S under different choices confirmed by algebraic manipulation and computer algebra indicates that S is uniquely determined by the given relation. Therefore, S = 1/2 is the correct constant value for all solutions of the original constraint. Why Other Options Are Wrong: Values 1, 2, 1/3 and 3/2 may arise from incorrect rearrangements of the cubic relation or from miscomputing the reciprocals. For instance, if one mistakenly sets y1 y2 y3 equal to a simple constant without including the shifts, the sum of reciprocals can come out as 1 or 2. Common Pitfalls: The most common pitfall is trying to solve explicitly for x1, x2 and x3, which leads to a complicated cubic equation. Introducing the substitution yi = 2 + xi early and focusing on symmetric expressions is a much more efficient approach. Careful algebra or using a specific numeric example to test invariance is a good strategy in exam conditions. Final Answer: The value of [1/(2 + x1)] + [1/(2 + x2)] + [1/(2 + x3)] is 1/2.

Question 20

If α and β are the roots of the quadratic equation x^2 − x + 1 = 0, then which of the following equations has roots α^3 and β^3?

Accepted Answer

Introduction / Context: This algebra problem connects the roots of a given quadratic equation with the roots of a new quadratic formed from powers of the original roots. Specifically, if α and β are roots of a given quadratic, we are asked to find the quadratic whose roots are α^3 and β^3. This is a common technique in polynomial and root transformation questions. Given Data / Assumptions: α and β are roots of x^2 − x + 1 = 0. We must determine which equation has roots α^3 and β^3. Concept / Approach: For a quadratic with roots r1 and r2, we know: r1 + r2 = sum of roots = coefficient of x with negative sign over coefficient of x^2. r1 r2 = product of roots = constant term over coefficient of x^2. Given the original equation x^2 − x + 1 = 0, we can find α + β and αβ. Then we compute α^3 + β^3 and α^3 β^3, and use these as the sum and product of roots for the required quadratic x^2 − (sum)x + product = 0. Step-by-Step Solution: From x^2 − x + 1 = 0, the coefficient of x is −1 and the constant term is 1. Thus α + β = 1 and αβ = 1. We need the sum S = α^3 + β^3 and the product P = α^3 β^3. Use the identity α^3 + β^3 = (α + β)^3 − 3αβ(α + β). Substitute α + β = 1 and αβ = 1: S = 1^3 − 3*1*1 = 1 − 3 = −2. For the product, α^3 β^3 = (αβ)^3 = 1^3 = 1. Therefore, the quadratic whose roots are α^3 and β^3 is: x^2 − Sx + P = x^2 − (−2)x + 1 = x^2 + 2x + 1 = 0. Verification / Alternative check: Note that x^2 + 2x + 1 = 0 can be written as (x + 1)^2 = 0, so both roots are −1. Indeed, if α and β are the complex cube roots associated with the original equation, their cubes both equal −1, making the derived quadratic consistent. This supports our algebraic derivation. Why Other Options Are Wrong: x^2 − 2x − 1 = 0 and x^2 − 3x + 1 = 0 correspond to different sums and products of roots that do not match S = −2 and P = 1. x^2 + 3x − 1 = 0 and x^2 + x + 1 = 0 are similarly inconsistent with the required sum and product for α^3 and β^3. Common Pitfalls: Common mistakes include forgetting the sign in the sum of roots formula, or misapplying the identity for α^3 + β^3. Always remember that for ax^2 + bx + c = 0, sum of roots is −b/a and product is c/a. Using these correctly and applying the cube identity systematically leads directly to the correct transformed quadratic. Final Answer: The equation whose roots are α^3 and β^3 is x^2 + 2x + 1 = 0.

Simplification Questions