Question 1

If the quadratic relationship x^2 + x = 19 holds for a real number x, what is the exact value of the expression (x + 5)^2 + 1 / (x + 5)^2?

Accepted Answer

Introduction / Context: This question involves transforming a given quadratic condition into a new expression involving a shifted variable. You must use algebraic identities carefully to compute a sum of a square and its reciprocal square without explicitly solving for x. This technique is common in aptitude exams where exact numeric solutions for x are not required. Given Data / Assumptions: x satisfies the equation x^2 + x = 19. x is a real number. We must find (x + 5)^2 + 1/(x + 5)^2. The expression is defined, so x + 5 is non zero. Concept / Approach: Introduce a new variable t = x + 5 to simplify the expression. Rewrite the original equation in terms of t, which leads to a quadratic equation in t. From that quadratic, deduce a simple relation between t and 1/t. Then use the identity (t + 1/t)^2 = t^2 + 2 + 1/t^2 to obtain t^2 + 1/t^2, which is exactly the required expression. Step-by-Step Solution: Let t = x + 5, so x = t − 5.Substitute x = t − 5 into x^2 + x = 19 to express in terms of t.Compute (t − 5)^2 + (t − 5) = 19, which expands to t^2 − 10t + 25 + t − 5 = 19.Simplify: t^2 − 9t + 20 = 19, so t^2 − 9t + 1 = 0.Divide by t (t is non zero): t − 9 + 1/t = 0, giving t + 1/t = 9.Square both sides: (t + 1/t)^2 = t^2 + 2 + 1/t^2 = 81.Therefore, t^2 + 1/t^2 = 81 − 2 = 79. Since t = x + 5, (x + 5)^2 + 1/(x + 5)^2 = 79. Verification / Alternative check: We can solve x^2 + x − 19 = 0 directly using the quadratic formula, get two real roots, then compute (x + 5)^2 + 1/(x + 5)^2 numerically for each root. For both roots, the value of the expression is 79. This numerical check confirms that the identity based method is correct and that the expression is independent of which root of the quadratic is chosen. Why Other Options Are Wrong: 77 and 81 are close but arise from small arithmetic mistakes, such as forgetting to subtract 2 after squaring. 83 and 75 are further away and suggest incorrect manipulation of the quadratic in t or an error in the t + 1/t step. Only 79 agrees exactly with the identity t^2 + 1/t^2 = 81 − 2. Common Pitfalls: Forgetting to define t = x + 5 and instead trying to handle the expression in terms of x directly, which is more cumbersome. Incorrectly expanding (t − 5)^2 or miscombining the linear terms when forming the quadratic in t. Misusing the identity for (t + 1/t)^2 and forgetting the extra +2 term before isolating t^2 + 1/t^2. Final Answer: 79

Question 2

Using standard trigonometric identities, what is the simplified value of the expression sec^4 θ − sec^2 θ tan^2 θ, expressed in terms of a single basic trigonometric function of θ?

Accepted Answer

Introduction / Context: This problem tests knowledge of basic trigonometric identities and algebraic simplification. The expression involves powers of secant and tangent, and the goal is to rewrite it as a simpler single trigonometric function. Such simplifications are common in many trigonometry questions in aptitude tests. Given Data / Assumptions: The expression to simplify is sec^4 θ − sec^2 θ tan^2 θ. Angle θ is such that all trigonometric functions sec θ and tan θ are defined. We must express the result in terms of a single standard trigonometric function. Concept / Approach: We use the Pythagorean identity tan^2 θ + 1 = sec^2 θ. The idea is to factor the expression and then replace tan^2 θ with sec^2 θ − 1 or vice versa. This reduces the expression step by step to something much simpler. Algebraic factoring is an essential step here. Step-by-Step Solution: Start with the expression E = sec^4 θ − sec^2 θ tan^2 θ.Factor out sec^2 θ from both terms: E = sec^2 θ(sec^2 θ − tan^2 θ).Use the identity tan^2 θ = sec^2 θ − 1. Then sec^2 θ − tan^2 θ = sec^2 θ − (sec^2 θ − 1) = 1.Substitute this back: E = sec^2 θ * 1 = sec^2 θ.Therefore, the simplified value of the expression is sec^2 θ. Verification / Alternative check: Pick a convenient angle, for example θ = 45 degrees. Then sec 45° = sqrt(2), tan 45° = 1. Compute E directly: sec^4 θ = (sqrt(2))^4 = 4, and sec^2 θ tan^2 θ = (2)(1) = 2. So E = 4 − 2 = 2. Now compute sec^2 θ at 45 degrees: sec^2 45° = 2. Both results match, verifying that E simplifies correctly to sec^2 θ for at least one angle. The identity ensures this holds for all valid θ. Why Other Options Are Wrong: cosec^2 θ and cot^2 θ involve reciprocal functions of sine, which do not appear naturally from sec and tan in this context. sec θ tan θ and tan^2 θ have different powers and cannot match sec^4 θ − sec^2 θ tan^2 θ after correct simplification. Only sec^2 θ emerges directly when the Pythagorean identity and factoring are applied correctly. Common Pitfalls: Failing to factor out sec^2 θ at the beginning, which makes simplification more difficult. Misusing the identity tan^2 θ + 1 = sec^2 θ or writing it incorrectly. Attempting to convert everything to sine and cosine unnecessarily, which may lead to algebraic mistakes. Final Answer: sec^2 θ

Question 3

Consider the trigonometric product (sin A − cosec A)(sec A − cos A)(tan A + cot A) for an angle A where all these functions are defined. What is the simplified numerical value of this entire expression?

Accepted Answer

Introduction / Context: This problem involves simplifying a product of several trigonometric expressions. It tests understanding of reciprocal relationships between sine, cosine, and their reciprocals, along with how tangent and cotangent can be rewritten in terms of sine and cosine. The final result turns out to be a constant, independent of the specific angle A, as long as the functions are defined. Given Data / Assumptions: The expression is (sin A − cosec A)(sec A − cos A)(tan A + cot A). Angle A is such that sin A, cos A, sec A, cosec A, tan A, and cot A are all defined and non zero where needed. We must simplify this expression to a single numerical value if possible. Concept / Approach: Rewrite all trigonometric functions in terms of sine and cosine. Use the reciprocal relations cosec A = 1/sin A, sec A = 1/cos A, tan A = sin A / cos A, and cot A = cos A / sin A. Simplify each bracket separately to express them as algebraic fractions in sin A and cos A. Then multiply them to see if massive cancellation occurs, leading to a constant value. Step-by-Step Solution: First simplify sin A − cosec A: this is sin A − 1/sin A = (sin^2 A − 1)/sin A = −(1 − sin^2 A)/sin A = −cos^2 A / sin A.Next simplify sec A − cos A: this is 1/cos A − cos A = (1 − cos^2 A)/cos A = sin^2 A / cos A.Simplify tan A + cot A: this is (sin A / cos A) + (cos A / sin A) = (sin^2 A + cos^2 A)/(sin A cos A) = 1/(sin A cos A).Multiply the first two results: (−cos^2 A / sin A) * (sin^2 A / cos A) = −(cos^2 A sin^2 A)/(sin A cos A) = −sin A cos A.Now multiply this with the third factor: (−sin A cos A) * (1/(sin A cos A)) = −1.Thus the entire expression simplifies to the constant value −1. Verification / Alternative check: Choose a specific angle A where all functions are defined, for example A = 45 degrees. Compute each term numerically using a calculator: sin 45° = cos 45° = sqrt(2)/2, so the simplified step by step expression should give a result very close to −1. Carrying out this numerical evaluation confirms the algebraic simplification and shows the expression is indeed constant for all valid A. Why Other Options Are Wrong: 1 and 2 would require different sign structures or incomplete cancellations. 0 would require one of the factors to be zero, but none of the simplified factors is zero for a general valid A. −2 does not appear naturally from the algebraic manipulations of the expression. Only −1 matches the exact result from the complete simplification. Common Pitfalls: Making algebraic sign errors when rewriting sin A − cosec A and sec A − cos A. Incorrectly adding tan A and cot A, for example forgetting to combine over a common denominator. Failing to recognise that massive cancellation happens, and stopping at a more complicated intermediate expression rather than the constant −1. Final Answer: -1

Question 4

If the trigonometric equation (1 / cos θ) − (1 / cot θ) = 1 / P holds for a parameter P and an angle θ where all functions are defined, what is the value of cos θ expressed purely in terms of P?

Accepted Answer

Introduction / Context: This problem tests skill in manipulating trigonometric expressions involving secant, cotangent, and a parameter P. You must rewrite the expression in terms of sine and cosine, use identities relating sec θ and tan θ, and then solve for cos θ in terms of P. It is a classic algebra plus trigonometry manipulation question. Given Data / Assumptions: The equation is (1 / cos θ) − (1 / cot θ) = 1 / P. Angle θ is such that cos θ and cot θ are defined and non zero. P is a non zero real parameter so that 1 / P is defined. We must find cos θ as an explicit expression in terms of P. Concept / Approach: First rewrite each term in basic trigonometric functions. Note that 1 / cos θ = sec θ and 1 / cot θ = tan θ. The left side becomes sec θ − tan θ. There is a useful identity (sec θ − tan θ)(sec θ + tan θ) = 1, which implies sec θ − tan θ is the reciprocal of sec θ + tan θ. Using this, we can express sec θ + tan θ in terms of P. Then, by letting sec θ = s and tan θ = t, and using the identity t^2 = s^2 − 1, we can solve for s and hence for cos θ = 1/s. Step-by-Step Solution: Rewrite the equation: (1 / cos θ) − (1 / cot θ) = sec θ − tan θ = 1 / P.Use the identity (sec θ − tan θ)(sec θ + tan θ) = 1, so sec θ − tan θ = 1 / (sec θ + tan θ).Therefore 1 / (sec θ + tan θ) = 1 / P, which implies sec θ + tan θ = P.Let s = sec θ and t = tan θ. Then we have s + t = P.Use the Pythagorean identity t^2 = s^2 − 1.From s + t = P, write t = P − s and substitute into t^2 = s^2 − 1: (P − s)^2 = s^2 − 1.Expand: P^2 − 2Ps + s^2 = s^2 − 1, which simplifies to P^2 − 2Ps = −1. Hence 2Ps = P^2 + 1.Solve for s: s = (P^2 + 1) / (2P). But s = sec θ, so cos θ = 1 / s = 2P / (P^2 + 1). Verification / Alternative check: Choose a particular value of P, for example P = 1. Then cos θ is predicted to be 2 * 1 / (1^2 + 1) = 2/2 = 1. This implies θ = 0 degrees. Check the original equation: (1 / cos θ) − (1 / cot θ) = 1 − 0 is not defined because cot 0 is undefined, so P = 1 is actually not valid in this case. For a suitable value, for example P = 2, cos θ = 4 / 5. One can compute sin θ from sin^2 θ = 1 − cos^2 θ = 1 − 16/25 = 9/25, so sin θ = 3/5 with a suitable sign. Substituting back into the original equation verifies that 1 / P is satisfied, confirming the derived formula for cos θ. Why Other Options Are Wrong: (P + 1)/(P − 1) and (P^2 − 1)/(2P) arise from incorrect algebra, often by mishandling the squared equation or signs. (P^2 + 1)/(2P) is the value of sec θ, not cos θ, so it is not the correct final expression. 2(P^2 + 1)/P fails to invert the fraction and does not correspond to any standard trigonometric function obtained in the derivation. Common Pitfalls: Confusing sec θ − tan θ with sec θ + tan θ in the identity and using the wrong reciprocal. Forgetting that tan^2 θ = sec^2 θ − 1, which is essential for linking t and s. Stopping the solution at sec θ instead of taking its reciprocal to find cos θ. Final Answer: 2P / (P^2 + 1)

Question 5

Using standard trigonometric identities for powers of cosecant and cotangent, what is the simplified numerical value of the expression cosec^6 A − cot^6 A − 3 cosec^2 A cot^2 A?

Accepted Answer

Introduction / Context: This question focuses on algebraic manipulation of higher powers of trigonometric functions, specifically cosec A and cot A. By recognising a pattern of cubes and using the identity relating cosec^2 A and cot^2 A, you can simplify the expression to a simple constant. This type of problem checks both algebraic insight and familiarity with trigonometric identities. Given Data / Assumptions: The expression is E = cosec^6 A − cot^6 A − 3 cosec^2 A cot^2 A. Angle A is such that cosec A and cot A are defined and finite. We must simplify E to a single numerical value if possible. Concept / Approach: Notice that cosec^6 A and cot^6 A can be viewed as cubes of cosec^2 A and cot^2 A. This suggests using the algebraic identity a^3 − b^3 = (a − b)(a^2 + ab + b^2). Also, there is an important trigonometric identity: cosec^2 A − cot^2 A = 1. Introducing variables u = cosec^2 A and v = cot^2 A allows us to rewrite the expression in a purely algebraic form, which simplifies nicely. Step-by-Step Solution: Let u = cosec^2 A and v = cot^2 A. Then cosec^6 A = u^3 and cot^6 A = v^3, and cosec^2 A cot^2 A = uv.The expression becomes E = u^3 − v^3 − 3uv.Use the identity for difference of cubes: u^3 − v^3 = (u − v)(u^2 + uv + v^2).So E = (u − v)(u^2 + uv + v^2) − 3uv.We know from trigonometric identities that cosec^2 A − cot^2 A = 1, so u − v = 1.Thus E = (u^2 + uv + v^2) − 3uv = u^2 − 2uv + v^2 = (u − v)^2.Since u − v = 1, we have E = (1)^2 = 1. Verification / Alternative check: Choose a particular angle A where sine and cosine are simple, for example A = 45 degrees. Then sin 45° = sqrt(2)/2, so cosec 45° = sqrt(2), and cot 45° = 1. Compute E numerically: cosec^2 45° = 2, cot^2 45° = 1. Then cosec^6 45° = 8 and cot^6 45° = 1. Also, 3 cosec^2 45° cot^2 45° = 3 * 2 * 1 = 6. So E = 8 − 1 − 6 = 1. This matches the algebraic result and confirms the simplification. Why Other Options Are Wrong: Values −2, −1, 0, or 2 do not appear from the algebraic transformation using the correct identities. These incorrect values usually arise from mishandling the difference of cubes identity or misusing the identity cosec^2 A − cot^2 A = 1. Only 1 corresponds to (u − v)^2 when u − v = 1. Common Pitfalls: Failing to see that cosec^6 A and cot^6 A can be expressed as u^3 and v^3 with u = cosec^2 A and v = cot^2 A. Using the wrong identity, for example confusing cosec^2 A − cot^2 A with some other relation. Forgetting to subtract 3uv after expanding u^3 − v^3, which prevents the expression from collapsing into a perfect square. Final Answer: 1

Question 6

If tan A = 1/2 and tan B = 1/3 for two acute angles A and B, what is the exact value of the compound trigonometric expression tan(2A + B)?

Accepted Answer

Introduction / Context: This question tests the use of trigonometric angle addition and double angle formulas. You are given tan A and tan B and must compute tan(2A + B). This requires first finding tan 2A using the double angle formula and then applying the general tangent addition formula for tan(2A + B). Given Data / Assumptions: tan A = 1/2. tan B = 1/3. A and B are chosen so that tangent is defined and likely acute for simplicity. We must find tan(2A + B). Concept / Approach: Use the double angle formula for tangent: tan 2A = 2 tan A / (1 − tan^2 A). Then use the angle addition formula for tangent: tan(2A + B) = (tan 2A + tan B) / (1 − tan 2A tan B). By substituting the given values, the expression simplifies to a rational number. It is important to handle fractions carefully to avoid arithmetic errors. Step-by-Step Solution: First compute tan 2A using tan A = 1/2. The formula is tan 2A = 2 tan A / (1 − tan^2 A).Substitute: tan 2A = 2 * (1/2) / (1 − (1/2)^2) = 1 / (1 − 1/4) = 1 / (3/4) = 4/3.We know tan B = 1/3. Now use the angle addition formula: tan(2A + B) = (tan 2A + tan B) / (1 − tan 2A tan B).Compute the numerator: tan 2A + tan B = 4/3 + 1/3 = 5/3.Compute the denominator: 1 − tan 2A tan B = 1 − (4/3)*(1/3) = 1 − 4/9 = 5/9.Therefore tan(2A + B) = (5/3) / (5/9) = (5/3) * (9/5) = 3. Verification / Alternative check: As a consistency check, we can approximate angles A and B. If tan A = 1/2, then A is approximately 26.565 degrees. If tan B = 1/3, then B is approximately 18.435 degrees. Then 2A + B is roughly 2 * 26.565 + 18.435 ≈ 71.565 degrees. The tangent of about 71.565 degrees is approximately 3, which matches the exact result obtained by algebraic formulas. Why Other Options Are Wrong: 1 and 5 are too small or too large compared with the approximate tangent of about 71.565 degrees. 9 is much larger and would correspond to an angle closer to 84 degrees, which is not consistent with 2A + B. 7 is another large value that does not match the calculated result from the correct formulas. Common Pitfalls: Misapplying the double angle formula, especially the denominator 1 − tan^2 A which is easy to miswrite. Forgetting the correct form of the tangent addition formula or reversing the sign in the denominator. Making arithmetic mistakes when dealing with fractions like 4/3 and 1/3. Final Answer: 3

Question 7

If three real numbers a, b and c satisfy a^2 + b^2 + c^2 = 83 and a + b + c = 15, what is the exact value of the symmetric sum ab + bc + ca?

Accepted Answer

Introduction / Context: This question checks understanding of symmetric sums and the identity relating the square of a sum to the sum of squares and pairwise products. Such identities are very useful in algebra and in many aptitude exams to find expressions like ab + bc + ca without solving individually for a, b, and c. Given Data / Assumptions: a^2 + b^2 + c^2 = 83. a + b + c = 15. a, b, c are real numbers. We must find ab + bc + ca. Concept / Approach: Use the identity for the square of a sum of three numbers: (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca). This equation relates the given sum and the sum of squares to the unknown symmetric sum ab + bc + ca. Rearranging the identity makes it easy to solve for ab + bc + ca directly. Step-by-Step Solution: Start with the identity (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca).Substitute the given values: (15)^2 = 83 + 2(ab + bc + ca).Compute 15^2: 225 = 83 + 2(ab + bc + ca).Subtract 83 from both sides: 225 − 83 = 2(ab + bc + ca).This gives 142 = 2(ab + bc + ca), so ab + bc + ca = 142 / 2 = 71. Verification / Alternative check: If a, b, and c are roots of some cubic equation, their symmetric sums would appear in the coefficients. The identity used is a standard result and holds for all real a, b, and c. Substituting back, we see that a^2 + b^2 + c^2 + 2(ab + bc + ca) = 83 + 2 * 71 = 83 + 142 = 225, which is exactly (a + b + c)^2 = 15^2. This confirms that the calculated value of 71 is consistent with the given data. Why Other Options Are Wrong: 69, 70, 72, and 68 do not satisfy the identity when substituted back, because they give different totals on the right side of (a + b + c)^2. For example, using 70 would give 83 + 2 * 70 = 223, which is not equal to 225. Only 71 leads to the correct equality 83 + 2 * 71 = 225. Common Pitfalls: Forgetting the factor of 2 in the identity or writing (a + b + c)^2 = a^2 + b^2 + c^2 + ab + bc + ca, which is incorrect. Making arithmetic errors when computing 225 − 83. Attempting to solve for individual values of a, b, and c instead of using the symmetric identity, which is unnecessary and complex. Final Answer: 71

Question 8

If sin(3x − 20°) = cos(3y + 20°) for angles x and y measured in degrees, what is the value of the sum (x + y) in degrees, assuming principal values within the standard acute angle range?

Accepted Answer

Introduction / Context: This question examines the relationship between sine and cosine through the complementary angle identity. It also tests the ability to equate angles inside trigonometric functions to find a relationship between x and y. We focus on principal values in a typical aptitude exam setting, avoiding complications from periodicity unless explicitly required. Given Data / Assumptions: The equation is sin(3x − 20°) = cos(3y + 20°). Angles are in degrees. x and y are chosen from a standard principal range so that a simple relationship can be found. We must determine the value of x + y in degrees. Concept / Approach: Use the complementary angle identity cos θ = sin(90° − θ). This allows us to rewrite cos(3y + 20°) as a sine function of a complementary angle. Once both sides are written as sine, we equate the arguments of the sine functions in the simplest principal case. This leads directly to a linear equation in x and y that gives x + y. Step-by-Step Solution: Start with sin(3x − 20°) = cos(3y + 20°).Use the identity cos θ = sin(90° − θ). Therefore cos(3y + 20°) = sin(90° − (3y + 20°)) = sin(70° − 3y).Thus the equation becomes sin(3x − 20°) = sin(70° − 3y).For principal values in the range usually used in aptitude exams, we equate the arguments directly: 3x − 20° = 70° − 3y.Rearrange: 3x + 3y = 70° + 20° = 90°, so 3(x + y) = 90°.Therefore x + y = 90° / 3 = 30°. Verification / Alternative check: We could consider the more general sine equality sin α = sin β, which has two primary cases: α = β + 360k° or α = 180° − β + 360k°. The principal simple case α = β gives 3x − 20° = 70° − 3y and leads to x + y = 30°. The alternative case would give a more complicated relationship and is usually not intended in standard multiple choice aptitude questions unless specifically mentioned. Checking with sample values that satisfy x + y = 30° confirms that the equation holds for suitable choices of x and y. Why Other Options Are Wrong: 90°, 60°, and 120° would come from different angle relations not supported by the principal simple identity used. 45° does not satisfy the linear equation 3(x + y) = 90° and is not consistent with the complementary relationship. Only 30° emerges naturally from the simplest and most standard manipulation. Common Pitfalls: Forgetting to convert cosine to sine using the complementary identity, and instead trying to manipulate both sides separately. Misapplying the general sine equality and creating unnecessary complexity. Arithmetic mistakes when rearranging 3x − 20° = 70° − 3y to obtain x + y. Final Answer: 30°

Question 9

If 1/2 is added to a certain real number and the resulting sum is multiplied by 3 to give a result of 21, what is the value of the original number before these operations were performed?

Accepted Answer

Introduction / Context: This is a straightforward linear equation problem framed in words. It checks the ability to translate a verbal description of operations on a number into an algebraic equation and then solve that equation to retrieve the original number. Such problems are standard in basic arithmetic and algebra sections of aptitude tests. Given Data / Assumptions: Half (1/2) is added to the original number. The resulting sum is then multiplied by 3. The final result after multiplication is 21. The original number is a real number we must find. Concept / Approach: Assign a variable, say x, to represent the original number. Translate the description step by step into an algebraic equation. First express the addition of 1/2, then the multiplication by 3, and set this equal to 21. Solve the resulting linear equation in x using basic algebra operations to isolate x. Step-by-Step Solution: Let x be the original number.Adding 1/2 to x gives x + 1/2.Multiplying this sum by 3 gives 3(x + 1/2).According to the problem statement, 3(x + 1/2) = 21.Divide both sides by 3: x + 1/2 = 21 / 3 = 7.Subtract 1/2 from both sides: x = 7 − 1/2 = 6.5. Verification / Alternative check: Substitute x = 6.5 back into the original description of the operations. First add 1/2: 6.5 + 0.5 = 7. Then multiply by 3: 7 * 3 = 21. This matches the final result specified in the question, confirming that the original number is indeed 6.5. Why Other Options Are Wrong: 5.5 and 4.5, when used in the same operations, produce results 18 and 15 respectively, which are not equal to 21. −6.5 gives a sum of −6 when 1/2 is added, and 3 * (−6) = −18, not 21. 7.5 yields (7.5 + 0.5) * 3 = 8 * 3 = 24, which is also incorrect. Common Pitfalls: Interpreting the operations in the wrong order, for example multiplying by 3 first and then adding 1/2. Making mistakes with fractional arithmetic when subtracting 1/2 from 7. Not checking the solution by substituting it back into the original word description. Final Answer: 6.5

Question 10

If α and β are the two roots of the quadratic equation 3x^2 − 13x + 14 = 0, what is the exact value of the expression (α / β) + (β / α)?

Accepted Answer

Introduction / Context: This question assesses understanding of relationships between roots and coefficients of a quadratic equation. Instead of solving for α and β directly, you can use Vieta's formulas to compute expressions involving α and β, such as α/β + β/α, in terms of the coefficients of the quadratic polynomial. Given Data / Assumptions: α and β are roots of 3x^2 − 13x + 14 = 0. The quadratic is 3x^2 − 13x + 14 with real coefficients. We must compute (α / β) + (β / α). Concept / Approach: Recall that for a quadratic ax^2 + bx + c = 0 with roots α and β, the sum of roots is α + β = −b/a and the product of roots is αβ = c/a. The expression α/β + β/α can be rewritten as (α^2 + β^2)/(αβ). We can find α^2 + β^2 using the identity α^2 + β^2 = (α + β)^2 − 2αβ, and then divide by αβ using the values given by Vieta's formulas. Step-by-Step Solution: For the equation 3x^2 − 13x + 14 = 0, identify a = 3, b = −13, c = 14.The sum of roots is α + β = −b/a = −(−13)/3 = 13/3.The product of roots is αβ = c/a = 14/3.Compute α^2 + β^2 using α^2 + β^2 = (α + β)^2 − 2αβ.(α + β)^2 = (13/3)^2 = 169/9, and 2αβ = 2 * (14/3) = 28/3 = 84/9.So α^2 + β^2 = 169/9 − 84/9 = 85/9.Now compute (α / β) + (β / α) = (α^2 + β^2)/(αβ) = (85/9) / (14/3) = (85/9) * (3/14).Simplify: (85 * 3) / (9 * 14) = 255/126 = 85/42 after dividing numerator and denominator by 3. Verification / Alternative check: We could solve the quadratic 3x^2 − 13x + 14 = 0 exactly to find α and β, then compute α/β + β/α numerically. The roots are real and can be found using the quadratic formula. Substituting them into the expression yields a numerical value that simplifies to 85/42, confirming the result obtained using Vieta's formulas and algebraic manipulation. Why Other Options Are Wrong: 9 is an integer and would require (α^2 + β^2) = 9αβ, which contradicts the calculated values. 65/28, 53/14, and 15/2 result from miscalculations in squaring the sum or subtracting 2αβ, or from dividing by αβ incorrectly. Only 85/42 matches the correct transformed expression. Common Pitfalls: Forgetting to square (α + β) correctly or miscomputing (13/3)^2. Errors in converting 2αβ into a fraction with the same denominator before subtraction. Misapplying Vieta's formulas, such as using c instead of c/a for αβ. Final Answer: 85/42

Question 11

If three real numbers a, b and c satisfy a + b + c = 9 and ab + bc + ca = 18, what is the exact value of the expression a^3 + b^3 + c^3 − 3abc?

Accepted Answer

Introduction / Context: This problem tests knowledge of a well known symmetric identity involving cubes of three numbers. The expression a^3 + b^3 + c^3 − 3abc can be rewritten in terms of the sum a + b + c and the symmetric sum ab + bc + ca. This allows evaluation of the expression without solving for a, b, and c individually. Given Data / Assumptions: a + b + c = 9. ab + bc + ca = 18. a, b, c are real numbers. We must compute a^3 + b^3 + c^3 − 3abc. Concept / Approach: Use the identity a^3 + b^3 + c^3 − 3abc = (a + b + c)(a^2 + b^2 + c^2 − ab − bc − ca). The given sums allow us to find a^2 + b^2 + c^2 from the square of a + b + c. Once we have a^2 + b^2 + c^2, we can compute the bracketed expression and multiply by a + b + c to obtain the value of a^3 + b^3 + c^3 − 3abc. Step-by-Step Solution: Start with the identity (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca).We know a + b + c = 9, so (a + b + c)^2 = 9^2 = 81.Substitute ab + bc + ca = 18 into the identity: 81 = a^2 + b^2 + c^2 + 2 * 18.Compute 2 * 18 = 36, giving 81 = a^2 + b^2 + c^2 + 36.Hence a^2 + b^2 + c^2 = 81 − 36 = 45.Now use the cube identity: a^3 + b^3 + c^3 − 3abc = (a + b + c)(a^2 + b^2 + c^2 − ab − bc − ca).Compute the bracket: a^2 + b^2 + c^2 − ab − bc − ca = 45 − 18 = 27.Therefore a^3 + b^3 + c^3 − 3abc = (a + b + c) * 27 = 9 * 27 = 243. Verification / Alternative check: If a, b, and c were the roots of some cubic equation, their symmetric sums would appear in the coefficients, and the identity used would still hold. Plugging back our values, we can check consistency: the bracket term is 27, and multiplying by 9 clearly yields 243. No contradictions arise with the given sums, confirming the calculated value is correct. Why Other Options Are Wrong: 189 and 162 would result from using incorrect values for a^2 + b^2 + c^2 or miscomputing the bracket term. 361 and 486 are too large and would require different sums than those given for a + b + c and ab + bc + ca. Only 243 fits the identity perfectly when the given numeric values are substituted. Common Pitfalls: Forgetting the identity a^3 + b^3 + c^3 − 3abc and instead trying to guess values for a, b, and c. Mishandling the calculation of a^2 + b^2 + c^2 from (a + b + c)^2. Incorrect subtraction when computing 45 − 18. Final Answer: 243

Question 12

If sec(3x − 20°) = cosec(3y + 20°) for angles x and y measured in degrees, what is the exact value of tan(x + y), assuming principal angle solutions are considered?

Accepted Answer

Introduction / Context: This question combines reciprocal trigonometric functions and complementary angle relationships. By connecting secant and cosecant through their reciprocal sine and cosine definitions, and then equating the resulting sine expressions, you can derive a linear relationship between x and y and finally evaluate tan(x + y). Given Data / Assumptions: The equation is sec(3x − 20°) = cosec(3y + 20°). Angles are measured in degrees. All trigonometric functions involved are defined for the given angles. We are asked to find tan(x + y), assuming principal solutions in a standard range. Concept / Approach: Rewrite secant and cosecant in terms of cosine and sine. Since sec θ = 1/cos θ and cosec φ = 1/sin φ, the equation 1/cos(3x − 20°) = 1/sin(3y + 20°) implies sin(3y + 20°) = cos(3x − 20°). Then use the complementary identity cos θ = sin(90° − θ) to express cos(3x − 20°) as a sine function and equate the arguments in the principal case. From the linear relationship between x and y, compute x + y and finally evaluate tan(x + y). Step-by-Step Solution: Given sec(3x − 20°) = cosec(3y + 20°), rewrite as 1/cos(3x − 20°) = 1/sin(3y + 20°).This implies cos(3x − 20°) = sin(3y + 20°).Use cos θ = sin(90° − θ). Hence cos(3x − 20°) = sin(90° − (3x − 20°)) = sin(110° − 3x).So the equation becomes sin(110° − 3x) = sin(3y + 20°).For principal values, equate the arguments: 110° − 3x = 3y + 20°.Rearrange: 110° − 20° = 3x + 3y, giving 90° = 3(x + y).Therefore x + y = 90° / 3 = 30°. The required value is tan(x + y) = tan 30° = 1/√3. Verification / Alternative check: We can choose a specific pair (x, y) satisfying x + y = 30° and check the original equation numerically. Suppose x = 20° and y = 10°. Then 3x − 20° = 40° and 3y + 20° = 50°. Compute sec 40° and cosec 50°. Since cos 40° and sin 50° are equal (due to complementary angles), their reciprocals are also equal, confirming that sec(3x − 20°) = cosec(3y + 20°) when x + y = 30°. The corresponding tan(x + y) is tan 30°, which is 1/√3, matching the derived value. Why Other Options Are Wrong: 1 and √3 correspond to tan 45° and tan 60°, which would require x + y to be 45° or 60°, not consistent with the equation. 2√3 is larger and corresponds to a different angle, far from 30°. 0 would require x + y to be a multiple of 180°, which does not solve the trigonometric relation given. Common Pitfalls: Forgetting to invert both sides correctly when passing from sec and cosec to cos and sin. Misapplying the complementary identity for cosine and sine. Ignoring the principal solution and overcomplicating the general sine equality, leading to non standard values of x + y. Final Answer: 1/√3

Question 13

In trigonometry, assume A and B are angles such that: cot A = n/(n + 1) and cot B = 1/(2n + 1).  Using the cotangent addition identity, find the value of cot(A + B) in simplest form (as a constant, independent of n, wherever defined).

Accepted Answer

Introduction / Context: This question tests the cotangent addition identity and algebraic simplification. The key skill is substituting given cot values and simplifying carefully to see whether the result depends on n or collapses to a constant. Given Data / Assumptions: • cot A = n/(n + 1) • cot B = 1/(2n + 1) • Use cot(A + B) identity wherever expressions are defined (denominators not zero) Concept / Approach: Use the identity: cot(A + B) = (cot A * cot B − 1) / (cot A + cot B). Substitute the given expressions, convert everything to a common denominator, and simplify. Watch for a common factor that cancels completely. Step-by-Step Solution: 1) Let u = cot A = n/(n + 1) and v = cot B = 1/(2n + 1) 2) Apply identity: cot(A + B) = (u*v − 1) / (u + v) 3) Compute u*v: u*v = [n/(n + 1)] * [1/(2n + 1)] = n / ((n + 1)(2n + 1)) 4) Numerator: u*v − 1 = [n − (n + 1)(2n + 1)] / ((n + 1)(2n + 1)) 5) Expand (n + 1)(2n + 1) = 2n^2 + 3n + 1 6) So numerator becomes: n − (2n^2 + 3n + 1) = −(2n^2 + 2n + 1) 7) Denominator: u + v = n/(n + 1) + 1/(2n + 1) 8) Common denominator gives: [n(2n + 1) + (n + 1)] / ((n + 1)(2n + 1)) = (2n^2 + 2n + 1) / ((n + 1)(2n + 1)) 9) Divide numerator by denominator: −(2n^2 + 2n + 1)/(2n^2 + 2n + 1) = −1 Verification / Alternative check: Pick a simple n (for example n = 1): cot A = 1/2 and cot B = 1/3. Then cot(A + B) = ((1/2)(1/3) − 1)/((1/2) + (1/3)) = (1/6 − 1)/(5/6) = (−5/6)/(5/6) = −1. Confirms the constant result. Why Other Options Are Wrong: • 0, 1, 2, −2: these would imply the expression depends on n or does not cancel, but the algebra cancels perfectly to −1. Common Pitfalls: • Using tan(A + B) identity instead of cot(A + B). • Mistakes in common denominators or expansion of (n + 1)(2n + 1). Final Answer: −1

Question 14

Two angles measure (5y + 62°) and (22° + y). If the two angles are supplementary (their sum is 180°), find the value of y in degrees.

Accepted Answer

Introduction / Context: This question checks a basic geometry fact: supplementary angles add up to 180°. Once you translate the statement into an equation, it becomes a simple linear equation in y. Given Data / Assumptions: • Angle 1 = (5y + 62°) • Angle 2 = (22° + y) • Supplementary means: Angle 1 + Angle 2 = 180° • Required: y (in degrees) Concept / Approach: Use the definition of supplementary angles: (5y + 62) + (22 + y) = 180. Combine like terms (y terms together and constants together), then isolate y by basic algebra. Step-by-Step Solution: 1) Form the equation from supplementary condition: (5y + 62) + (22 + y) = 180 2) Combine y terms: 5y + y = 6y 3) Combine constants: 62 + 22 = 84 4) So the equation becomes: 6y + 84 = 180 5) Subtract 84 from both sides: 6y = 96 6) Divide both sides by 6: y = 16 7) Therefore y = 16°. Verification / Alternative check: Substitute y = 16: Angle 1 = 5*16 + 62 = 80 + 62 = 142°. Angle 2 = 22 + 16 = 38°. Sum = 142° + 38° = 180°, so the condition holds exactly. Why Other Options Are Wrong: • 32°, 24°, 8°, 1°: substituting any of these values does not make the two expressions add to 180°. Common Pitfalls: • Treating supplementary as “equal” instead of “sum to 180°”. • Forgetting to combine y terms correctly (5y + y = 6y). Final Answer: 16°

Question 15

If the three quantities P, Q, and R satisfy the common equality: (3P)/5 = (7Q)/2 = (7R)/5, determine the simplest ratio P : Q : R.

Accepted Answer

Introduction / Context: This problem tests the standard “equal ratios” technique. When several expressions are equal to the same value, we introduce a common constant and express each variable in terms of that constant, then form the required ratio. Given Data / Assumptions: • (3P)/5 = (7Q)/2 = (7R)/5 • P, Q, R are real quantities (ratio requested in simplest whole numbers) Concept / Approach: Let the common value be k: 3P/5 = k, 7Q/2 = k, 7R/5 = k. Solve each for P, Q, R in terms of k. Then form P : Q : R and clear denominators by multiplying by the LCM of denominators. Step-by-Step Solution: 1) Set each equal to k: 3P/5 = k, 7Q/2 = k, 7R/5 = k 2) Solve for P: P = (5k)/3 3) Solve for Q: Q = (2k)/7 4) Solve for R: R = (5k)/7 5) Ratio becomes: P : Q : R = (5/3) : (2/7) : (5/7) 6) Multiply all parts by 21 (LCM of 3 and 7): (5/3)*21 = 35, (2/7)*21 = 6, (5/7)*21 = 15 7) So the simplest ratio is 35 : 6 : 15. Verification / Alternative check: Check by plugging ratio values: Let P = 35, Q = 6, R = 15. Then 3P/5 = 3*35/5 = 21, 7Q/2 = 7*6/2 = 21, and 7R/5 = 7*15/5 = 21. All equal, so ratio is consistent. Why Other Options Are Wrong: • Any other ordering or numbers fail the “all three expressions equal” check. Common Pitfalls: • Forgetting to use a common constant k. • Clearing denominators incorrectly when converting to whole-number ratio. Final Answer: 35 : 6 : 15

Question 16

For a non-zero real number x and real numbers p and q, consider the expression: 1/x^(p − q + 1) + 1/x^(q − p + 1).  Without any additional relationship between p and q, which statement best describes the value of this expression?

Accepted Answer

Introduction / Context: This question tests whether an algebraic expression can be uniquely evaluated or simplified to a single fixed value when key information is missing. Many exponent expressions look symmetric, but symmetry alone does not force a constant result unless we know something like p = q, p − q = 1, or a specific value of x. Given Data / Assumptions: • x is a non-zero real number • p and q are real numbers with no extra constraints given • Expression: 1/x^(p − q + 1) + 1/x^(q − p + 1) Concept / Approach: Rewrite each term using negative exponents to see the structure: 1/x^(p − q + 1) = x^(−(p − q + 1)) = x^(q − p − 1) 1/x^(q − p + 1) = x^(p − q − 1) So the expression becomes: x^(q − p − 1) + x^(p − q − 1). This depends on both (p − q) and x. Without knowing either a relation between p and q or a numerical value of x, it can take many different values. Step-by-Step Solution: 1) Convert to exponent form: E = x^(q − p − 1) + x^(p − q − 1) 2) Observe: if p = q, then E = x^(−1) + x^(−1) = 2/x 3) If p − q = 1, then E = x^(−2) + x^(0) = 1/x^2 + 1 4) These examples show E changes with different p, q choices. Verification / Alternative check: Take x = 2: If p = q, E = 2/2 = 1. If p − q = 1, E = 1/4 + 1 = 1.25. Same x, different (p, q), different value. So it is not uniquely determined. Why Other Options Are Wrong: • 0, 1, x, x^2: these claim a fixed value, but the expression varies with p and q. Common Pitfalls: • Assuming symmetry forces a constant result. • Treating p and q as integers or assuming p = q without it being stated. Final Answer: Cannot be determined uniquely from the information given

Question 17

Let x = √5 + √3. Find the exact simplified value of: x + 1/x  Give your answer in surd (radical) form, without decimal approximation.

Accepted Answer

Introduction / Context: This question tests rationalization of surds. When x is a sum of square roots, 1/x can be simplified by multiplying numerator and denominator by the conjugate. After that, adding x + 1/x becomes straightforward. Given Data / Assumptions: • x = √5 + √3 • Required: x + 1/x • Exact surd form (no decimals) Concept / Approach: Use the conjugate: 1/(√5 + √3) = (√5 − √3) / ((√5 + √3)(√5 − √3)). The denominator becomes 5 − 3 = 2, eliminating radicals from the denominator. Then add the resulting expression to x. Step-by-Step Solution: 1) Start with: x = √5 + √3 2) Compute 1/x by rationalizing: 1/x = 1/(√5 + √3) * (√5 − √3)/(√5 − √3) 3) Denominator: (√5 + √3)(√5 − √3) = 5 − 3 = 2 4) Therefore: 1/x = (√5 − √3)/2 5) Now add x + 1/x: x + 1/x = (√5 + √3) + (√5 − √3)/2 6) Write with common denominator 2: = (2√5 + 2√3 + √5 − √3)/2 7) Combine like terms: = (3√5 + √3)/2 Verification / Alternative check: Approximate check: √5 ≈ 2.236, √3 ≈ 1.732, so x ≈ 3.968. Then 1/x ≈ 0.252. Sum ≈ 4.220. Our exact result: (3√5 + √3)/2 ≈ (3*2.236 + 1.732)/2 = (6.708 + 1.732)/2 = 4.220. Matches well. Why Other Options Are Wrong: • 2√15, 3√5, √15: these do not match the rationalized sum and give different approximations. • (√5 + 3√3)/2 swaps coefficients incorrectly. Common Pitfalls: • Forgetting to use the conjugate (√5 − √3). • Incorrectly multiplying and not getting 5 − 3 = 2. Final Answer: (3√5 + √3) / 2

Question 18

Suppose p/q = (x + 3)/(x − 3), where x is a real number with x ≠ 3, x ≠ −3, and x ≠ 0. Find the simplified value of: (p^2 + q^2) / (p^2 − q^2) expressed purely in terms of x.

Accepted Answer

Introduction / Context: This question tests algebraic manipulation using a ratio. When p/q is known, expressions involving p^2 and q^2 can often be rewritten in terms of r = p/q, and then simplified into a clean formula in x. Given Data / Assumptions: • p/q = (x + 3)/(x − 3) • x ≠ 3, x ≠ −3, x ≠ 0 (to avoid invalid denominators and division by zero) • Required: (p^2 + q^2)/(p^2 − q^2) Concept / Approach: Let r = p/q. Then: (p^2 + q^2)/(p^2 − q^2) = (r^2 + 1)/(r^2 − 1), because dividing numerator and denominator by q^2 gives: (p^2/q^2 + 1)/(p^2/q^2 − 1) = (r^2 + 1)/(r^2 − 1). Then substitute r = (x + 3)/(x − 3) and simplify using common denominators and the identities for sum and difference of squares. Step-by-Step Solution: 1) Let r = p/q = (x + 3)/(x − 3) 2) Convert expression: (p^2 + q^2)/(p^2 − q^2) = (r^2 + 1)/(r^2 − 1) 3) Compute r^2 = (x + 3)^2/(x − 3)^2 4) Evaluate (r^2 + 1)/(r^2 − 1) using common denominator: = [ (x + 3)^2 + (x − 3)^2 ] / [ (x + 3)^2 − (x − 3)^2 ] 5) Expand: (x + 3)^2 = x^2 + 6x + 9, (x − 3)^2 = x^2 − 6x + 9 6) Sum: 2x^2 + 18 = 2(x^2 + 9) 7) Difference: (x^2 + 6x + 9) − (x^2 − 6x + 9) = 12x 8) Final: 2(x^2 + 9)/(12x) = (x^2 + 9)/(6x) Verification / Alternative check: Test x = 6: r = 9/3 = 3. Then (r^2 + 1)/(r^2 − 1) = (9 + 1)/(9 − 1) = 10/8 = 5/4. Formula gives (36 + 9)/(36) = 45/36 = 5/4. Matches. Why Other Options Are Wrong: • Using (x^2 − 9) or swapping numerator/denominator comes from incorrect expansion or sign errors in the difference. • 0 cannot be correct because the expression is not identically zero for valid x. Common Pitfalls: • Forgetting to square r before adding/subtracting 1. • Miscomputing (x + 3)^2 − (x − 3)^2 (it equals 12x, not x^2 − 9). Final Answer: (x^2 + 9) / (6x)

Question 19

Simplify the trigonometric-algebraic expression: (1 − sin A cos A)(sin A + cos A)  Choose the simplest equivalent expression (assume the expression is defined for the given angle A).

Accepted Answer

Introduction / Context: This question tests identity recognition. Expressions that contain (sin A + cos A) often combine nicely with sin^2 A + cos^2 A = 1. A common target form is sin^3 A + cos^3 A, which can be factorized as (sin A + cos A)(sin^2 A − sin A cos A + cos^2 A). Given Data / Assumptions: • Expression: (1 − sin A cos A)(sin A + cos A) • Identity: sin^2 A + cos^2 A = 1 • Required: simplest equivalent form Concept / Approach: Rewrite the factor (1 − sin A cos A) using sin^2 A + cos^2 A: 1 − sin A cos A = (sin^2 A + cos^2 A) − sin A cos A = sin^2 A − sin A cos A + cos^2 A. Then use the known factorization: u^3 + v^3 = (u + v)(u^2 − uv + v^2), with u = sin A and v = cos A. Step-by-Step Solution: 1) Start with: (1 − sin A cos A)(sin A + cos A) 2) Replace 1 by sin^2 A + cos^2 A: 1 − sin A cos A = sin^2 A + cos^2 A − sin A cos A 3) Rearrange: = sin^2 A − sin A cos A + cos^2 A 4) So the full expression becomes: (sin A + cos A)(sin^2 A − sin A cos A + cos^2 A) 5) Recognize as u^3 + v^3 factorization: = sin^3 A + cos^3 A Verification / Alternative check: Take A = 0°: sin A = 0, cos A = 1. Original: (1 − 0)(0 + 1) = 1. Right side: sin^3 A + cos^3 A = 0 + 1 = 1. Matches. This confirms the identity-based simplification. Why Other Options Are Wrong: • sin^2 A − cos^2 A is unrelated to the cube-sum structure. • 0 or 1 cannot be identically equal for all A (depends on A). • sin A + cos A misses the extra factor. Common Pitfalls: • Expanding blindly and not using sin^2 A + cos^2 A = 1. • Forgetting the identity for u^3 + v^3 factorization. Final Answer: sin^3 A + cos^3 A

Question 20

Simplify the trigonometric expression exactly: (1 − sin A) / (1 + sin A)  Write the simplest equivalent form using standard trigonometric identities (assume the denominator is not zero).

Accepted Answer

Introduction / Context: This question checks identity manipulation and rationalization in trigonometry. The expression (1 − sin A)/(1 + sin A) is commonly simplified by multiplying numerator and denominator by (1 − sin A) to remove the sum in the denominator and convert everything into cos A terms. Given Data / Assumptions: • Expression: (1 − sin A)/(1 + sin A) • Use identities: 1 − sin^2 A = cos^2 A • Assume 1 + sin A ≠ 0 so the expression is defined Concept / Approach: Multiply by the conjugate (1 − sin A)/(1 − sin A): (1 − sin A)/(1 + sin A) = (1 − sin A)^2 / (1 − sin^2 A). Then use 1 − sin^2 A = cos^2 A. Finally rewrite (1 − sin A)/cos A as sec A − tan A, and square it. Step-by-Step Solution: 1) Start: (1 − sin A)/(1 + sin A) 2) Multiply numerator and denominator by (1 − sin A): = (1 − sin A)^2 / ((1 + sin A)(1 − sin A)) 3) Denominator becomes a difference of squares: (1 + sin A)(1 − sin A) = 1 − sin^2 A 4) Use identity: 1 − sin^2 A = cos^2 A 5) So: (1 − sin A)/(1 + sin A) = (1 − sin A)^2 / cos^2 A 6) Separate as a square: = ((1 − sin A)/cos A)^2 7) Rewrite: (1 − sin A)/cos A = 1/cos A − sin A/cos A = sec A − tan A 8) Final: = (sec A − tan A)^2 Verification / Alternative check: Take A = 30°: sin A = 1/2, cos A = √3/2. LHS = (1 − 1/2)/(1 + 1/2) = (1/2)/(3/2) = 1/3. RHS: sec A − tan A = (2/√3) − (1/√3) = 1/√3, square gives 1/3. Matches. Why Other Options Are Wrong: • sec A − tan A (not squared) is not equal to the original ratio. • sec A + tan A corresponds to a different identity. • tan A or sec A alone cannot match the rationalized squared form. Common Pitfalls: • Forgetting to square after converting to (1 − sin A)^2/cos^2 A. • Mistakenly using 1 − sin^2 A = 1 − cos^2 A. Final Answer: (sec A − tan A)^2

Simplification Questions