Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context: A decade (modulus-10) counter cycles through ten states, representing decimal 0 to 9 in binary-coded form. Confusion often arises between the highest valid state and the binary pattern representing decimal 10, which is not part of the decade cycle.
Given Data / Assumptions:
Concept / Approach: In a typical BCD decade up-counter, the terminal valid state is 1001 (decimal 9). On the next clock, internal logic clears to 0000 (decimal 0). The pattern 1010 (decimal 10) is not a legal displayed state in BCD decade counting; it is either skipped by design or used transiently only for internal detect/reset.
Step-by-Step Solution:
List valid BCD states: 0000 through 1001.Identify terminal count: 1001 (9), not 1010 (10).Determine rollover action: next state after 1001 is 0000.Therefore the statement claiming 1010 as terminal count is incorrect.Verification / Alternative check:
Consult truth tables for BCD counters: detection of 1010 triggers reset to 0000.Why Other Options Are Wrong:
Correct / down-counters / with BCD correction: These do not change the definition of legal BCD states; 1010 is not a valid displayed state.Common Pitfalls:
Equating “binary 10” with “decimal 10” inside a BCD decade sequence.Misreading terminal count as the value that causes reset rather than the last valid state.Final Answer:
Incorrect
Discussion & Comments