States in a BCD (decade) counter: How many unique states are present in a Binary-Coded Decimal (BCD) decade counter sequence?

Difficulty: Easy

Correct Answer: 10

Explanation:


Introduction / Context:
BCD counters are used to represent decimal digits 0 through 9 using binary patterns. Understanding their number of states is essential for designing display drivers, timers, and digital instruments that need decimal outputs.



Given Data / Assumptions:

  • BCD encodes decimal digits 0..9 with four-bit binary codes.
  • After reaching 9, the counter resets to 0.
  • Illegal codes (1010..1111) are skipped or corrected.


Concept / Approach:
A BCD decade counter cycles through exactly ten valid states, corresponding to digits 0 to 9: 0000 to 1001. It then resets or recycles, giving a MOD-10 sequence. This behavior is different from a straight 4-bit binary counter, which would have 16 states (MOD-16).



Step-by-Step Solution:

List valid codes: 0000 (0) through 1001 (9).Count them: there are 10 valid states.Recognize that codes 1010..1111 are excluded by design.Therefore, the number of states in a BCD counter is 10.


Verification / Alternative check:
Datasheets for BCD counters (e.g., decade counters) label them MOD-10 and show reset logic to skip the six unused codes.



Why Other Options Are Wrong:

8 or 9: Too few; BCD must represent ten decimal digits.11: Too many; only ten valid BCD states are used.


Common Pitfalls:
Assuming a 4-bit register always cycles through 16 states; forgetting that BCD purposely avoids 1010..1111.


Final Answer:
10

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