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Digital Computer Electronics problems
1. A full-adder adds _____ bits, and producing a SUM and a _____
Options
A. 8, SUBTRACTION
B. 3, CARRY
C. 16, DIVIDE
D. All of the above
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 3, CARRY
2. The octal equivalent of decimal 324.987 is
Options
A. 504.771
B. 640.781
C. 815.234
D. 90.987
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 504.771
3. Conversion of an octal number 60
8
to binary number is
Options
A. 110000
2
B. 10011
2
C. 1100111
2
D. 1100110
2
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 110000
2
4. One way to simplify the sum-of-products equation is to use boolean algebra. Another way is the _____ map.
Options
A. De Morgan
B. Standard
C. Schottky
D. Karnaugh
E. None of the above
Show Answer
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Discuss
Correct Answer: Karnaugh
5. Addition of 110101101
2
, 111011101
2
, 000111111
2
, 100101101
2
, 111110111
2
is
Options
A. 1011010111010
2
B. 1111011000010
2
C. 1000101000101
2
D. 01001000000010
2
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 1011010111010
2
6. Conversion of a octal number 63
8
to its decimal number is
Options
A. 51
10
B. 61
10
C. 57
10
D. 53
10
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 51
10
7. A flip-flop is a _____ element that stores a binary digit as a low or high voltage.
Options
A. chip
B. bus
C. I/O
D. memory
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: memory
8. Conversion of binary number 1100011
2
to its decimal number is
Options
A. 29
10
B. 97
10
C. 99
10
D. 93
10
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 99
10
9. Conversion of decimal number 99
10
to hexadecimal number is
Options
A. 63
16
B. 8
16
C. 61
16
D. 50
16
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 63
16
10. Conversion of binary number 1101100111111000
2
to hexadecimal number is
Options
A. D8F8
16
B. A8B9
16
C. 789
16
D. D9F8
16
E. None of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: D9F8
16
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