Adult fare = ? 114
According to the question,
child fare = Adult fare x 1/6
= 144 x 1/6 = ? 19
? Total amount paid by 4 adults and 5 children are for the same distance.
= ?(4 x 144 + 5 x 19)
= ?(456 + 95) = ? 551

Let the cost of 1 pencil = x
? Cost of 1 pen = (x + 5)
According to the question,
12(x + 5) + 5x = 111
? 12x + 60 + 5x = 111
? 17x = 111 - 60 = 51
? x = 51/17 = 3
? Cost of 1 pencil = ? 3
Cost of 1 pen = ? 8
? Total Cost of 8 pens and 9 pencils
= (8 x 8 + 9 x 3)
= ?(64 + 27) = ? 91

Let the total amount = x
According to the question.
14 girls are getting x amount.
1 girl will get x/14 amount.
Similarly if
18 girls are getting x amount.
1 girl will get x/18 amount.
according to question,
x/14 - x/18 = 160
? (9x - 7x)/126 = 160
? 2x/126 = 160
? x/126 = 80
? x = 126 x 80 = ? 10080

Solution 1 :
Let the number of ? 50 notes = x, then the number of ? 100 notes = (170 - x)
According to question.
50x + 100(170 - x) = 10000
divide by 50 the above equation, we will get
? x + 2(170 - x) = 200
? x + 340 - 2x = 200
? -x = 200 - 340 = -140
? x = 140
? Required amount ? 50 x 140
= ? 7000


Solution 2 :
Let the number of ? 50 notes = x and the number of ? 100 notes = y.
according to given question,
x + y = 170 .............(1)
50x + 100y = 10000............(2)

Divide the equation (2) by 10 , we will get
5x + 17y = 1000............(3)
Multiply the equation (1) by 5
5x + 5y = 850 ------------(4)
Subtract the (4) equation from (3) equation, we will get,
5x +10y - ( 5x + 5y ) = 1000 - 850
? 5x +10y - 5x - 5y = 1000 - 850
? 10y - 5y = 1000 - 850
? 5y = 150
? y = 150/5
? y = 30
Number of ? 100 notes = y = 30;
since x + Y = 170
therefore x = 170 - y
? x = 170 - 30
? x = 140
Number of ? 50 notes = x = 140

Let the worker remains absent for x days.
Then, his working days = (120 - x) days.
According to the question,
20 x Working day - 3 x Absent day = 560
20(120 - x) - 3x = 560
? 2400 - 20x - 3x = 560
? x = 2400 - 560/23 = 1840/23
= 80 days

Let total number of apples in the crate = a
Then, number of bruised apples = a/40 .
Number of unsaleable apples
since 4 bruise apples containing 3 unsaleable apples.
therefore 1 bruise apples will contain 3/4 unsaleable apples
hence a/40 bruise apples will contain 3/4 x a/40 unsaleable apples
= 3/4 x a/40 = 3a/160
According to the question.
3a/160 = 9
? a = 9 x 160/3
a = 3 x 160 = 480

Let population of cities A and B become equal after x year.
According to the question.
Population of city A = Population of city B
Then,
136000 - 2400 x = 84000 + 1600 x.
? 4000x = 52000
? x = 52/4 = 13 year

? = 5 - [3/4 + {5/2 - (1/2 + 1/6 - 1/7)}]/2
= 5 - [3/4 + {5/2 - (1/2 + 7 - 6/42 )}]/2
= 5 - [3/4 + {5/2 - (1/2 + 1/42)}]/2
= 5 - [3/4 + {5/2 - (21 + 1/42)}]/2
= 5 - [3/4 + {5/2 - 22/42)}]/2
= 5 - [3/4 + {105 - 22/42)}]/2
= 5 - [3/4 + 83/42]/2 = 5 - [63 + 166/84]/2
= 5 - 229/84/2 = 420 - 229/84/2 = 191/84/2
= 191/84 x 2 = 191/168 = 1²³/₁₆₈

We know that, a³ + b³ + c³ - 3abc
= (a + b + c) (a² + b² + c² - ab - bc - ca)
? (a + b + c) = (a³ + b³ + c³ - 3abc/a² + b² + c² - ab - bc - ca) ....(i)
Given that,
(2.247)³ + (1.730)³ + (1.023)³ - 3 x 2.247 x 1.730 x 1.023/ (2.247)² + (1.730)² + (1.023)² - (2.247 x 1.730) - (1.730 x 1.023) - (2.247 x 1.023)
= 2.247 + 1.730 x 1.023) - (2.247 x 1.023)
= (2.247 + 1.730 + 1.023) [from Eq.(i)]
= 5.000 = 5

a² + 1 = a ? a + 1/a = 1
On squaring both sides, we get
a² + 1/a² + 2 = 1
? a² + 1/a² = -1
On cubing both sides, we get
(a² + 1/a²)³ = (-1)³
? a⁶ + 1/a⁶ + 3a² x 1/a²(a² + 1/a²) = -1
? a⁶ + 1/a⁶ + 3 x (-1) = -1
Now, a⁶ + 1/a⁶ + 1 = 3
As, a¹² + a⁶ + 1 can also be written as a⁶ + 1/a⁶ + 1
? a¹² + a⁶ + 1 = 3