Java programming — Evaluate bitwise operators step by step: class Bitwise { public static void main(String [] args) { int x = 11 & 9; int y = x ^ 3; System.out.println( y | 12 ); } }
Java Programming
Operators and Assignments
Difficulty: Easy
Choose an option
-
A0
-
B7
-
C8
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D14
Answer
Correct Answer: 14
Explanation
Introduction / Context:This checks understanding of Java's bitwise AND (&), XOR (^), and OR (|) using small integers, and requires converting between decimal and binary mentally.
Given Data / Assumptions:
- Compute x = 11 & 9.
- Then y = x ^ 3.
- Print y | 12.
Concept / Approach:Use binary forms: AND keeps bits set in both, XOR keeps bits set in exactly one, OR keeps bits set in either.
Step-by-Step Solution:
11 in binary = 1011; 9 in binary = 1001; so 11 & 9 = 1001 (decimal 9).Then y = 9 ^ 3. Write 9 = 1001 and 3 = 0011. XOR => 1010 (decimal 10).Finally y | 12: 10 = 1010, 12 = 1100. OR => 1110 (decimal 14).Verification / Alternative check:Cross-check by quick calculator or mental recomputation of each bit position.
Why Other Options Are Wrong:They correspond to misapplying XOR or OR, or mixing decimal and binary values incorrectly.
Common Pitfalls:Confusing XOR with OR, or forgetting leading zeros in alignment when writing binary.
Final Answer:14