Java programming — Nested conditional (ternary) operator evaluation: class Test { public static void main(String [] args) { int x=20; String sup = (x < 15)? "small" : (x < 22)? "tiny" : "huge"; System.out.println(sup); } }

Introduction / Context:
This checks understanding of nested ternary operators and left-to-right evaluation of conditions.

Given Data / Assumptions:

• x = 20.
• Expression form: cond1 ? A : (cond2 ? B : C).

Concept / Approach:
Evaluate the first condition. If false, evaluate the second condition in the nested ternary. The chosen string is then printed.

Step-by-Step Solution:

Verification / Alternative check:
Rewrite using if/else to confirm: if (x < 15) "small"; else if (x < 22) "tiny"; else "huge".

Why Other Options Are Wrong:
"small" would require x < 15; "huge" would require x >= 22; no compilation issues here.

Common Pitfalls:
Misgrouping nested ternary operators or forgetting that they are right-associative.

Final Answer:
tiny