In Java, what will be the output of the following program (note the use of pre-increment and short-circuit OR)? class Test { public static void main(String [] args) { int x = 0; int y = 0; for (int z = 0; z < 5; z++) { if ((++x > 2) || (++y > 2)) { x++; } } System.out.println(x + " " + y); } }

Introduction / Context:
This problem tests short-circuit OR (||) behavior with pre-increment. With OR, once the left operand is true, the right operand is not evaluated.

Given Data / Assumptions:

• x = 0, y = 0 initially.
• Condition: (++x > 2) || (++y > 2).
• If true, x++ inside the if-block.
• Loop runs 5 times.

Concept / Approach:
For ||, if the left-hand side becomes true, the right-hand side is skipped (no ++y). Therefore ++y happens only while (++x > 2) is still false.

Step-by-Step Solution:

Verification / Alternative check:
Instrument the loop with prints for x and y on each iteration to validate the sequence.

Why Other Options Are Wrong:
They assume y keeps increasing after left-hand side becomes true, ignoring short-circuit OR.

Common Pitfalls:
Not realizing that once (++x > 2) becomes true, (++y > 2) never executes again in later iterations.

Final Answer:
8 2