Java programming — Primitives are passed by value; confirm behavior with boolean: class Test { public static void main(String [] args) { Test p = new Test(); p.start(); } void start() { boolean b1 = false; boolean b2 = fix(b1); System.out.println(b1 + " " + b2); } boolean fix(boolean b1) { b1 = true; return b1; } }

Introduction / Context:
This question confirms that Java passes primitives by value, so reassigning a parameter inside a method does not change the caller's variable.

Given Data / Assumptions:

• Main creates b1 as false and calls fix(b1).
• fix assigns true to its local parameter and returns it.

Concept / Approach:
Primitives are copied when passed to methods. Changing the local copy does not affect the original variable. The return value may differ from the original.

Step-by-Step Solution:

Verification / Alternative check:
Print identity or use different names to emphasize the copy behavior.

Why Other Options Are Wrong:
They imply call-by-reference semantics, which Java does not use for primitives.

Common Pitfalls:
Assuming Java can pass primitives by reference; only object references are passed by value (and still by value).

Final Answer:
false true