In Java, what will be the output of the following program (note the use of pre-increment and short-circuit AND)? class Test { public static void main(String [] args) { int x = 0; int y = 0; for (int z = 0; z < 5; z++) { if ((++x > 2) && (++y > 2)) { x++; } } System.out.println(x + " " + y); } }

Introduction / Context:
This Java question checks your understanding of pre-increment (++x) and the short-circuit behavior of the logical AND operator (&&) inside a loop. The trick is tracking when the right-hand side (++y) executes and when it is skipped.

Given Data / Assumptions:

• x = 0, y = 0 before the loop.
• Loop runs for z = 0, 1, 2, 3, 4 (total 5 iterations).
• If condition: (++x > 2) && (++y > 2).
• Body: if condition true then x++.

Concept / Approach:
For &&, the right side is evaluated only if the left side is true. Therefore ++y happens only on iterations where ++x > 2 is true. Pre-increment changes the variable before comparison.

Step-by-Step Solution:

Verification / Alternative check:
Manually simulate or add trace prints inside the loop to confirm increments of x and y match the above sequence.

Why Other Options Are Wrong:
They assume that y increments on every iteration or that the right-hand side runs even when the left side is false, which contradicts short-circuit AND semantics.

Common Pitfalls:
Confusing pre-increment with post-increment and forgetting that with && the second operand does not always execute.

Final Answer:
6 3