Ⅰ. x 2 - 1 = 0 Ⅱ. y 2 + 4y + 3 = 0

From the given equations , we know that
Ⅰ. x² - 1 = 0
⇒ x² = 1
⇒ x = ± √1 = ± 1
Ⅱ. y² + 4y + 3 = 0
⇒ y² + y + 3y + 3 = 0
⇒ y( y + 1) + 3( y + 1) = 0
⇒ ( y + 1) ( y + 3)
⇒ y = -3 or -1
From above equations it is clear that x ≥ y is correct answer .