Compare greater roots from two quadratics (definition repaired): Let x be the greater root of 6x^2 + 41x + 63 = 0 and let y be the greater root of 4y^2 + 8y + 3 = 0. Choose the correct relation between x and y.

Difficulty: Medium

Correct Answer: x < y

Explanation:


Introduction / Context:
The original “I/II” style stem lacked the comparison rule. Using the Recovery-First Policy, we define x and y as the greater roots of the two quadratics and compare them. This is a common exam pattern in quantity comparison questions.


Given Data / Assumptions:

  • x is the larger root of 6x^2 + 41x + 63 = 0.
  • y is the larger root of 4y^2 + 8y + 3 = 0.


Concept / Approach:
Compute roots using the quadratic formula. For ax^2 + bx + c = 0, roots are (−b ± √(b^2 − 4ac)) / (2a). Identify the greater root for each equation, then compare numerically (exact fractions avoid rounding errors).


Step-by-Step Solution:

For 6x^2 + 41x + 63 = 0: Δ = 41^2 − 4*6*63 = 1681 − 1512 = 169 ⇒ √Δ = 13 Roots: (−41 ± 13)/12 ⇒ x1 = (−28)/12 = −7/3, x2 = (−54)/12 = −9/2. Greater root x = −7/3 (≈ −2.333) For 4y^2 + 8y + 3 = 0: Δ = 64 − 48 = 16 ⇒ √Δ = 4 Roots: (−8 ± 4)/8 ⇒ y = −1/2 or y = −3/4. Greater root y = −1/2 (−0.5) Comparison: −7/3 < −1/2 ⇒ x < y


Verification / Alternative check:
Because both larger roots are negative, the less negative (closer to zero) is the greater number; −0.5 is greater than −2.333…


Why Other Options Are Wrong:
x ≥ y, x > y, equality, or indeterminate are contradicted by the exact computed values.


Common Pitfalls:
Picking the more negative value as “larger” by mistake; always compare on the number line carefully.


Final Answer:
x < y

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