Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

Given Data

• Speeds = 60 km/hr and 90 km/hr (opposite directions)
• Lengths = 1.10 km and 0.90 km

Step 1: Relative speed & distancev_rel = 60 + 90 = 150 km/hrDistance to cross = 1.10 + 0.90 = 2.00 km

Step 2: Timet (hours) = 2.00 ÷ 150 = 1/75 ht (seconds) = (1/75) × 3600 = 48 s

Final AnswerTime taken = 48 s.