Generalized work formula with parameters: “P men” working “P hours/day” complete “P units” in “P days”. How much work is done by “Q men” at “Q hours/day” in “Q days” (in terms of P and Q)?

Difficulty: Easy

Correct Answer: Q3/P2 units

Explanation:


Introduction / Context:
This algebraic work-rate problem asks you to deduce per man-hour productivity from one scenario and then apply it to another. It tests understanding that total work equals (men) * (hours/day) * (days) * (productivity per man-hour).


Given Data / Assumptions:

  • P men at P h/day for P days produce P units
  • Find work by Q men at Q h/day for Q days
  • Productivity is constant across scenarios


Concept / Approach:
From the P-scenario, compute productivity k (units per man-hour). Then compute work for the Q-scenario using the same k. Finally, simplify the expression purely in terms of P and Q to match an option.


Step-by-Step Solution:

P men * P h/day * P days * k = P units⇒ P^3 * k = P ⇒ k = 1 / P^2For Q men: Work = Q men * Q h/day * Q days * k = Q^3 * (1/P^2) = Q^3 / P^2


Verification / Alternative check:
Dimensional check: if P = Q, expression gives P^3/P^2 = P, consistent with the original statement; hence the form is correct.


Why Other Options Are Wrong:

  • P2Q2, P2Q, Q2P2, PQ: These combine powers improperly and fail the sanity check when P = Q.


Common Pitfalls:
Assuming work is simply proportional to men*hours*days without factoring in k from the first scenario, or mis-simplifying exponents. Keep the per man-hour productivity explicit.


Final Answer:
Q3/P2 units

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