Question 1

In the letter series GLP, HNR, IPT, JRV, which of the following triplets should come next to extend the pattern correctly?

Accepted Answer

Introduction / Context: This question gives a series of three letter groups where each position changes according to its own rule. The challenge is to detect separate numeric progressions for each position. Such questions help you practise handling three simultaneous sequences, a skill that is useful for solving advanced alphabet and coding decoding problems in competitive examinations. Given Data / Assumptions: - Given series: GLP, HNR, IPT, JRV, ? - Each term is a three letter triplet. - A consistent progression is assumed for each letter position. - We use A = 1, B = 2, ..., Z = 26 for numeric analysis. Concept / Approach: The standard method is to split the series into three parallel sequences: first letters only, second letters only, and third letters only. We then convert letters into numbers and calculate the difference between consecutive elements in each sequence. As soon as a simple pattern emerges, such as a constant increase, we can extrapolate the next term. After solving for all three positions, we convert the predicted numbers back to letters to build the missing triplet. Step-by-Step Solution: Step 1: Convert all letters to positions. GLP: G (7), L (12), P (16). HNR: H (8), N (14), R (18). IPT: I (9), P (16), T (20). JRV: J (10), R (18), V (22). Step 2: First letters sequence: G, H, I, J. Positions: 7, 8, 9, 10. This clearly increases by +1 each step. Next first letter: 10 + 1 = 11, which is K. Step 3: Second letters sequence: L, N, P, R. Positions: 12, 14, 16, 18. This sequence increases by +2 each time. Next second letter: 18 + 2 = 20, which is T. Step 4: Third letters sequence: P, R, T, V. Positions: 16, 18, 20, 22. Again we see a constant increase of +2. Next third letter: 22 + 2 = 24, which is X. Step 5: Combine the three predicted letters. First letter K, second letter T, third letter X produce KTX. Verification / Alternative check: If we summarise, the first letters form a +1 series (7, 8, 9, 10, 11), while both the second and third letters form +2 series (12, 14, 16, 18, 20 and 16, 18, 20, 22, 24). These patterns are neat and consistent, which matches the style of well designed aptitude questions. Among the options, only KTX uses K as the first letter and T, X in the second and third positions, thereby respecting both progressions. This confirms that KTX is the only term that can extend the series correctly. Why Other Options Are Wrong: A) KUY would require second and third letters to be 21 and 25, which do not match the +2 sequences. B) KWA has correct first letter K but incorrect second and third letters for the established pattern. D) LVZ begins with L instead of K and so fails even on the first position progression. Common Pitfalls: Some test takers may observe that the second and third letters also increase but fail to compute exact steps, leading them to select visually similar but incorrect options. Another mistake is to assume that all three positions must share the same step size, when in fact the first position uses +1 while the others use +2. To avoid such errors, always measure the exact numeric difference rather than relying on rough spacing or partial patterns. Final Answer: The triplet that correctly completes the series GLP, HNR, IPT, JRV, ? is KTX.

Question 2

In the series SAY, TDD, UGI, VJN, which of the following triplets should come next to continue the pattern correctly?

Accepted Answer

Introduction / Context: This question presents a three letter series in which each position follows a distinct arithmetic progression along the alphabet. Such series questions are designed to test whether you can decouple multiple patterns happening in parallel. Identifying these independent sequences and then recombining them is a valuable reasoning skill for aptitude tests. Given Data / Assumptions: - Given series: SAY, TDD, UGI, VJN, ? - Each term consists of three capital letters. - We assume a consistent pattern for each letter position. - Alphabet positions: A = 1, B = 2, ..., Z = 26. Concept / Approach: The standard approach is to treat the first, second, and third letters as three separate sequences. For each sequence, convert letters to their numeric positions and calculate differences between consecutive terms. Often, the pattern will involve constant increments with possibly different step sizes for each position. After understanding the pattern in all three sequences, we use it to find the next value in each sequence and combine them into the final triplet. Step-by-Step Solution: Step 1: Represent each term with numeric positions. SAY: S (19), A (1), Y (25). TDD: T (20), D (4), D (4). UGI: U (21), G (7), I (9). VJN: V (22), J (10), N (14). Step 2: First letters sequence: S, T, U, V. Positions: 19, 20, 21, 22. This clearly increases by +1 each time. Next first letter: 22 + 1 = 23, which corresponds to W. Step 3: Second letters sequence: A, D, G, J. Positions: 1, 4, 7, 10. Here each step increases by +3. Next second letter: 10 + 3 = 13, which is M. Step 4: Third letters sequence: Y, D, I, N. Positions: 25, 4, 9, 14. From 25 to 4: in mod 26 terms, 25 + 5 = 30, and 30 - 26 = 4, so +5. From 4 to 9: +5. From 9 to 14: +5. So the third letters increase by +5 each time (with wrap around where needed). Next third letter: 14 + 5 = 19, which is S. Step 5: Combine the three predicted letters into a triplet. First W, second M, third S, giving WMS. Verification / Alternative check: Summarising the pattern: First letters: 19, 20, 21, 22, 23 (+1 each). Second letters: 1, 4, 7, 10, 13 (+3 each). Third letters: 25, 4, 9, 14, 19 (+5 each with wrap around). All three sequences independently show neat arithmetic progressions, making WMS the only option that fits all three simultaneously. If any other triplet were chosen, at least one of the positions would break the constant step rule, which is unlikely in a well designed exam question. Why Other Options Are Wrong: A) WMR has the correct first and second letters but uses R (18) instead of S (19), which breaks the +5 pattern in the third position. C) WNR has N (14) as the second letter, not 13, and so fails the +3 second letter progression. D) WNS fails on both the second and third letters, as N and S do not match the required numeric patterns for those positions. Common Pitfalls: Some candidates may assume that all positions increase by the same amount, which is not always the case. Others may be confused by the wrap around from Y to D in the third position and think the pattern is irregular. To avoid such issues, it is best to explicitly compute each difference and remember that alphabet sequences can loop from Z back to A. Once this is taken into account, the pattern becomes clear and consistent. Final Answer: The triplet that correctly completes the series SAY, TDD, UGI, VJN, ? is WMS.

Question 3

In the triplet series CDE, IHG, KLM, QPO, STU, which three letter group should come next to follow the same pattern?

Accepted Answer

Introduction / Context: This series alternates between triplets written in ascending and descending alphabetical order, and the starting letters of each triplet follow distinct numeric progressions. It is a multi layer pattern that tests your ability to recognise both the direction of ordering inside each term and the systematic movement of the starting letters. Such combinations are common in higher level alphabet series questions in reasoning exams. Given Data / Assumptions: - Given series: CDE, IHG, KLM, QPO, STU, ? - Each term is a three letter group. - Some groups are ascending (like CDE), others are descending (like IHG). - Alphabet positions are A = 1 to Z = 26. Concept / Approach: We identify two main ideas. First, we check whether each triplet is ascending or descending. Second, we examine the sequence of starting letters to see how they move numerically from one term to the next. The pattern here involves different step sizes that alternate in a regular way. Once we determine the next starting letter and whether the triplet should ascend or descend, we can write the final three letter group. Step-by-Step Solution: Step 1: Note the order of letters inside each triplet. CDE: C, D, E – ascending. IHG: I, H, G – descending. KLM: K, L, M – ascending. QPO: Q, P, O – descending. STU: S, T, U – ascending. So the pattern alternates: ascending, descending, ascending, descending, ascending... Thus the next triplet should be descending. Step 2: Analyse the starting letters: C, I, K, Q, S. Positions: 3, 9, 11, 17, 19. Differences: 3 to 9 is +6; 9 to 11 is +2; 11 to 17 is +6; 17 to 19 is +2. So the pattern of increments is +6, +2, +6, +2 and will likely continue with +6. Next starting position: 19 + 6 = 25, which is Y. Step 3: Construct the next descending triplet starting from Y. Descending from Y gives Y, X, W. So the next term is YXW. Verification / Alternative check: We can confirm by checking the alternating direction and starting letter pattern together. The sequence of directions is: up, down, up, down, up, and so the next must be down. The starting letters follow 3, 9, 11, 17, 19, 25, with increments +6, +2, +6, +2, +6. This continues the alternating increment pattern perfectly. Only YXW is a descending triplet starting at Y. None of the other options has both the correct starting letter and descending order, which confirms that YXW is the correct continuation. Why Other Options Are Wrong: B) WXY is ascending, but the next term must be descending. C) XYW does not maintain a simple ascending or descending order and starts from X instead of Y. D) XWY also fails the requirement of a clean descending run from the correct starting letter Y. Common Pitfalls: Candidates sometimes focus only on the internal direction (ascending or descending) and ignore how the starting letters move through the alphabet. Others may think the pattern is purely ascending then descending without checking step sizes. A careful strategy is to always note both the direction of each triplet and the numeric pattern of starting letters. This dual view ensures that your final choice aligns with all underlying rules instead of just one of them. Final Answer: The three letter group that correctly completes the series CDE, IHG, KLM, QPO, STU, ? is YXW.

Question 4

In the single letter series S, Q, N, J, which letter should come next to correctly continue the pattern?

Accepted Answer

Introduction / Context: This question is a simple single letter series featuring decreasing steps in the alphabet. It tests whether you can recognise a pattern where the size of the backward step increases in a regular way. Such questions are common in basic alphabet test sections and can usually be solved quickly using numeric positions of letters. Given Data / Assumptions: - Given series: S, Q, N, J, ? - Only capital English letters are used. - Alphabet positions: A = 1, B = 2, ..., Z = 26. - We assume a uniform pattern for differences between consecutive terms. Concept / Approach: We convert each letter into its numeric position and examine the differences between consecutive values. The pattern is likely to involve decreasing letters with an increasing step size. Once we recognise the sequence of differences, we can extend it to find the next numeric position and then map that position back into a letter. Careful attention to both sign and magnitude of the differences is important. Step-by-Step Solution: Step 1: Convert letters to positions. S = 19, Q = 17, N = 14, J = 10. Step 2: Compute differences between consecutive terms. From S (19) to Q (17): difference is -2. From Q (17) to N (14): difference is -3. From N (14) to J (10): difference is -4. Step 3: Identify the pattern. The series is decreasing, and the magnitude of the step increases by 1 each time: -2, -3, -4. Step 4: Predict the next difference. span style="display:block;">Following the pattern, the next step should be -5. Step 5: Apply this difference to the last known term. J corresponds to position 10, so 10 - 5 = 5. Position 5 is the letter E. Verification / Alternative check: We can rewrite the entire extended sequence numerically as 19, 17, 14, 10, 5. The differences are -2, -3, -4, -5. This confirms that our rule of decreasing letters by an increasing step size holds throughout. The letter E (position 5) fits perfectly as the next term. Any other letter would break the clean pattern of differences, which is unlikely in a composed exam question. Why Other Options Are Wrong: A) D has position 4, which would require a difference of -6 from 10, not -5. C) F has position 6, giving a difference of -4, which repeats the previous step instead of increasing it. D) G has position 7, and 10 - 7 = 3, which does not match the pattern at all. Common Pitfalls: Some learners miscount the steps between letters or ignore the fact that the step size itself is changing. Others may try to find a more complex pattern when a simple one is present. The safest approach is to work systematically: convert letters to numbers, compute each difference, and look for a clear sequence in those differences. Once you see the gradual change from -2 to -3 to -4, the next step of -5 becomes obvious. Final Answer: The letter that correctly continues the series S, Q, N, J, ? is E.

Question 5

In the triplet series CAL, AWF, YSZ, WOT, which of the following three letter groups should come next to extend the alphabet pattern correctly?

Accepted Answer

Introduction / Context: This series question involves three letter groups where each position in the triplet moves independently through the alphabet using negative steps of different sizes. It tests your ability to track multiple backward sequences and to apply modular thinking about the alphabet. Such multi position patterns are very common in advanced alphabet test sections in reasoning examinations. Given Data / Assumptions: - Given series: CAL, AWF, YSZ, WOT, ? - Each term is a three letter triplet. - All letters are capital English letters. - The pattern is consistent and typically made of fixed backward steps. Concept / Approach: We separate the series into sequences of first letters, second letters, and third letters. Each sequence is analysed numerically by converting letters to positions from 1 to 26. The differences between successive terms are computed, and we look for a constant negative step that may involve wrap around (for example from A moving backward to Z). Once we identify these consistent sub patterns, we can compute the next position in each sequence and reconstruct the next triplet in the series. Step-by-Step Solution: Step 1: Convert the letters to numeric positions. CAL: C (3), A (1), L (12). AWF: A (1), W (23), F (6). YSZ: Y (25), S (19), Z (26). WOT: W (23), O (15), T (20). Step 2: First letters sequence: C, A, Y, W. Positions: 3, 1, 25, 23. From 3 to 1: -2. From 1 to 25: when we step back 2 positions from A (1), we reach Z (26) then Y (25), so effectively -2. From 25 to 23: -2 again. So the first letters follow a constant step of -2. Next: 23 - 2 = 21, which is U. Step 3: Second letters sequence: A, W, S, O. Positions: 1, 23, 19, 15. From 1 to 23: stepping back 4 positions from A yields W, so -4. From 23 to 19: -4. From 19 to 15: -4. Next: 15 - 4 = 11, which is K. Step 4: Third letters sequence: L, F, Z, T. Positions: 12, 6, 26, 20. From 12 to 6: -6. From 6 to 26: again -6 with wrap around. From 26 to 20: -6. Next: 20 - 6 = 14, which is N. Step 5: Combine the predicted letters. First U, second K, third N, giving UKN. Verification / Alternative check: We can view all three sequences clearly: First letters: 3, 1, 25, 23, 21 (all -2 mod 26). Second letters: 1, 23, 19, 15, 11 (all -4). Third letters: 12, 6, 26, 20, 14 (all -6). The use of constant backward steps with wrap around is a classic exam pattern. Only UKN uses the correct letters at each position to respect all three independent subtraction rules. Hence, UKN is the unique term that extends the series consistently. Why Other Options Are Wrong: A) UJO matches the first letter but fails for the second and third letters, which do not follow the -4 and -6 progressions. B) VKP starts with V instead of U, breaking the -2 rule for first letters. D) VJP similarly misaligns all three positions with the established numeric patterns. Common Pitfalls: Candidates sometimes overlook the idea of constant negative steps and instead look for more complicated relationships. Others may become confused by wrap around movement from A to Z and think the pattern is irregular. The safe method is to note that subtraction can be applied modulo 26, so a move from 1 to 25 is a simple -2, and from 6 to 26 can be -6 with wrapping. Embracing this circular interpretation makes backward alphabet sequences much easier to handle. Final Answer: The triplet that correctly completes the series CAL, AWF, YSZ, WOT, ? is UKN.

Question 6

In the pair series UY, SV, QS, OP, which pair of letters should appear next to continue the pattern correctly?

Accepted Answer

Introduction / Context: This question involves a simple series of letter pairs where each position follows its own backward progression with a constant step size. Problems like this help build familiarity with decreasing sequences and modular reasoning across the alphabet, which is useful in many coding decoding and series based questions in reasoning exams. Given Data / Assumptions: - Given series: UY, SV, QS, OP, ? - Each term consists of two capital letters. - The first letters form one sequence and the second letters form another. - Alphabet positions: A = 1, B = 2, ..., Z = 26. Concept / Approach: We analyse the first letters as one sequence and the second letters as another sequence. In each case, we convert letters into numeric positions and examine the differences between consecutive terms. Here, the differences are negative, which means we are moving backward in the alphabet from left to right. If the step size is constant, we can apply the same difference to the last known term to predict the next one. Finally, we convert the predicted numbers back into letters to form the required pair. Step-by-Step Solution: Step 1: Convert letter pairs to positions. UY: U (21), Y (25). SV: S (19), V (22). QS: Q (17), S (19). OP: O (15), P (16). Step 2: Consider the first letters: U, S, Q, O. Positions: 21, 19, 17, 15. Differences: 21 to 19 is -2; 19 to 17 is -2; 17 to 15 is -2. So we subtract 2 each time. Next first letter: 15 - 2 = 13, which corresponds to M. Step 3: Consider the second letters: Y, V, S, P. Positions: 25, 22, 19, 16. Differences: 25 to 22 is -3; 22 to 19 is -3; 19 to 16 is -3. So we subtract 3 each time. Next second letter: 16 - 3 = 13, which is also M. Step 4: Combine the predicted letters into a pair. The pair is M (first position) and M (second position), giving MM. Verification / Alternative check: We can summarise the sequences as follows: First letters: 21, 19, 17, 15, 13 (constant step -2). Second letters: 25, 22, 19, 16, 13 (constant step -3). The simplicity and consistency of these backward steps, without any wrap around needed, indicate that MM is the only viable continuation. Any option that does not use M for both positions would break at least one of these two distinct arithmetic sequences. Why Other Options Are Wrong: A) NM has N (14) as first letter, which does not follow the -2 pattern from O (15). B) ML gives the correct first letter M but uses L (12) as the second letter, breaking the -3 pattern. D) KL fails for both positions, since K (11) is not two steps behind O (15) and L (12) is not three steps behind P (16). Common Pitfalls: Many learners try to infer some combined rule on the entire pair rather than checking each position separately. Others might miscount backward steps, especially when moving across several pairs. Always remember to extract sequences position wise and compute differences carefully. A small error in counting can lead to a completely incorrect option in multiple choice questions, even when the pattern itself is quite simple. Final Answer: The pair of letters that correctly completes the series UY, SV, QS, OP, ? is MM.

Question 7

In the pattern based series XYZXYZxYZ, XYZXYzXYZ, XYZXyZXYZ, XYZxYZXYZ, XYzXYZXYZ, which of the following terms should come next to follow the same trend of lowercase letter shifting?

Accepted Answer

Introduction / Context: This problem uses a visual pattern in which a single lowercase letter appears among otherwise uppercase letters, and both the position and identity of the lowercase letter change according to a regular rule. Instead of pure alphabet ordering, this question checks your ability to track the movement of a special character across a repeated base string. Such pattern recognition skills are very useful in coding decoding and series questions in reasoning exams. Given Data / Assumptions: - Base structure of each term is the nine letter string XYZXYZXYZ. - In each term, exactly one of these letters appears in lowercase. - Given sequence: 1) XYZXYZxYZ 2) XYZXYzXYZ 3) XYZXyZXYZ 4) XYZxYZXYZ 5) XYzXYZXYZ Concept / Approach: We consider two aspects: the position of the lowercase letter within the nine letter string, and which letter (X, Y, or Z) is made lowercase. First, we track the index of the lowercase character from left to right and see how it moves from one term to the next. Second, we check whether the lowercase character corresponds simply to whatever letter normally appears at that index in the base string. If both sets of observations align, we can predict the location and identity of the lowercase letter in the next term and write the complete term accordingly. Step-by-Step Solution: Step 1: Index the positions in the base string XYZXYZXYZ from 1 to 9. Positions: 1:X, 2:Y, 3:Z, 4:X, 5:Y, 6:Z, 7:X, 8:Y, 9:Z. Step 2: Note the position of the lowercase letter in each term. Term 1: XYZXYZxYZ – lowercase x at position 7. Term 2: XYZXYzXYZ – lowercase z at position 6. Term 3: XYZXyZXYZ – lowercase y at position 5. Term 4: XYZxYZXYZ – lowercase x at position 4. Term 5: XYzXYZXYZ – lowercase z at position 3. Step 3: Track how the index of the lowercase letter moves. Positions: 7, 6, 5, 4, 3. The lowercase character moves one step left each time. Next position should be 2. Step 4: Determine which letter is at position 2 in the base string. From the base XYZXYZXYZ, position 2 is Y. Thus, in the next term the letter Y at position 2 should be lowercase, giving y. Step 5: Construct the full next term. Base string is XYZXYZXYZ; we make the second letter lowercase. That produces XyZXYZXYZ. Verification / Alternative check: The identity of the lowercase letter is always the same as the original uppercase letter at that position in the base string. Whenever the position is 7, the lowercase letter is x; when it is 6, it is z; when 5, it is y; when 4, it is x; when 3, it is z. This confirms that the rule is not changing the letter type but only its case at a moving position. Following the leftward shift, the lowercase should next appear at index 2, where the base letter is Y. Therefore, XyZXYZXYZ precisely fits this rule and extends the sequence consistently. Why Other Options Are Wrong: A) xYZXYZXYZ has the lowercase character at position 1, skipping position 2 and breaking the leftward one step movement. B) XYZXYZxYZ repeats the first term instead of moving the lowercase position further to the left. D) XYZXYzXYZ repeats the second term and does not follow the continued shift pattern. Common Pitfalls: Some candidates may look only at the letters X, Y, and Z and ignore the importance of position indices. Others might think that the lowercase letters themselves follow a separate pattern (for example x, z, y, x, z, ...) and overlook the more fundamental rule that they simply mirror the base character at the moving position. To avoid confusion, always anchor your reasoning to the base string and track index movement carefully. This will usually reveal the simplest and most reliable pattern. Final Answer: The term that correctly continues the pattern XYZXYZxYZ, XYZXYzXYZ, XYZXyZXYZ, XYZxYZXYZ, XYzXYZXYZ, ? is XyZXYZXYZ.

Question 8

In the triplet series ENG, GQI, ITK, KWM, which of the following three letter groups should come next to correctly extend the alphabet pattern?

Accepted Answer

Introduction / Context: This series uses three letter groups where each position follows a separate numeric progression. The letters move forward in the alphabet by different constant steps, which is typical of many alphabet series questions in aptitude exams. Solving it requires you to track the three progressions in parallel and to apply arithmetic reasoning in the context of the alphabet. Given Data / Assumptions: - Given series: ENG, GQI, ITK, KWM, ? - Each term is a group of three capital letters. - The same pattern holds for each position throughout the series. - Alphabet positions: A = 1, B = 2, ..., Z = 26. Concept / Approach: We treat the first, second, and third letters of the triplets as independent sequences. For each sequence, we convert letters to numbering from 1 to 26, calculate the differences between consecutive terms, and look for constant increments. Once we know how each position progresses, we apply that rule once more to obtain the next numeric position. We then convert those positions back into letters to construct the missing triplet in the series. Step-by-Step Solution: Step 1: Convert letters into numeric positions. ENG: E (5), N (14), G (7). GQI: G (7), Q (17), I (9). ITK: I (9), T (20), K (11). KWM: K (11), W (23), M (13). Step 2: Analyse the first letters sequence: E, G, I, K. Positions: 5, 7, 9, 11. Each step increases by +2. Next first letter: 11 + 2 = 13, which is M. Step 3: Analyse the second letters sequence: N, Q, T, W. Positions: 14, 17, 20, 23. span style="display:block;">Again each step is +3. Next second letter: 23 + 3 = 26, which corresponds to Z. Step 4: Analyse the third letters sequence: G, I, K, M. Positions: 7, 9, 11, 13. Each step increases by +2. Next third letter: 13 + 2 = 15, which is O. Step 5: Combine the three predicted letters. First letter M, second letter Z, third letter O, giving MZO. Verification / Alternative check: We can summarise the sequences numerically: First position: 5, 7, 9, 11, 13 (+2 each). Second position: 14, 17, 20, 23, 26 (+3 each). Third position: 7, 9, 11, 13, 15 (+2 each). The symmetry of these progressions and the clean arithmetic confirm that MZO is the correct extension. Among the provided options, only MZO has M in the first position, Z in the second, and O in the third, matching the predicted numeric pattern exactly. Why Other Options Are Wrong: A) NAP uses N for the first letter instead of M and does not respect the +2 rule for the first position. C) MAO has M and O in the first and third positions but uses A (1) instead of Z (26) in the second position. D) NZP fails for both the second and third positions, as neither Z nor P fit the +3 and +2 sequences from the previous term. Common Pitfalls: Some exam takers may recognise that the first and third letters move by +2 but fail to consider that the second letter uses a different step size. Others might miscount positions, especially near the higher letters like W and Z. To avoid such mistakes, consistently convert letters to numbers and check differences step by step. Also, always consider that different positions in a triplet may follow different arithmetic progressions in multi position series problems. Final Answer: The three letter group that correctly completes the series ENG, GQI, ITK, KWM, ? is MZO.

Question 9

In the following alphabet series, one term is missing. Select the group of letters that best completes the series: DE, GI, KN, ?

Accepted Answer

Introduction / Context: This question tests your ability to recognize patterns in an alphabet series. Instead of numbers, we use pairs of letters and look for a logical rule that connects consecutive terms. Such questions are very common in aptitude and competitive exams because they check both observation skills and comfort with alphabetical positions. Given Data / Assumptions: • Given letter groups: DE, GI, KN, ? • We assume a standard English alphabet with positions A = 1, B = 2, ..., Z = 26. • The pattern is consistent across all consecutive pairs. • Exactly one of the given options completes the sequence correctly. Concept / Approach: To solve alphabet series questions, a reliable approach is to convert each letter to its numerical position in the alphabet and then observe how these numbers change. We normally examine each position in the pair separately: the first letters form one number sequence, and the second letters form another. Often the pattern involves adding or subtracting a fixed value, or increasing the difference step by step. Step-by-Step Solution: Step 1: Write numerical positions for each letter pair. DE = (D = 4, E = 5) GI = (G = 7, I = 9) KN = (K = 11, N = 14) Step 2: Look at the first letters: D (4), G (7), K (11). From 4 to 7 we add 3. From 7 to 11 we add 4. The increment itself increases by 1. Step 3: Continue the same pattern. The next jump for the first letter will be +5: 11 + 5 = 16, which is P. Step 4: Now consider the second letters: E (5), I (9), N (14). From 5 to 9 we add 4. From 9 to 14 we add 5. Again, the increment increases by 1. Step 5: Continue with +6 for the second letter: 14 + 6 = 20, which is T. Step 6: Therefore the missing term is PT. Verification / Alternative check: We can quickly verify by recomputing the pattern. First letters: 4, 7, 11, 16 correspond to D, G, K, P with increments +3, +4, +5. Second letters: 5, 9, 14, 20 correspond to E, I, N, T with increments +4, +5, +6. Both positions follow a smooth and consistent rule where the step size increases by 1 each time. This confirms that PT is the unique and correct completion of the series. Why Other Options Are Wrong: • PS: First letter P fits, but S corresponds to 19, not the required 20. The second letter pattern breaks. • PR: The first letter P is correct, but R corresponds to 18 and does not match the required +6 increment from N. • TP: Both letters break the established pattern. T would imply a different jump from K, and P does not match the second letter sequence. Common Pitfalls: Many learners only look at the overall feel of the letters and guess based on familiarity, without checking numeric positions. Another common mistake is to mix the patterns of the first and second letters instead of treating them as two separate sequences. Some candidates also assume a constant difference, while here the difference itself changes step by step. Carefully tracking each progression avoids such errors. Final Answer: The missing term that correctly completes the alphabet series is PT.

Question 10

In the following three letter groups, one term is missing. Identify the group of letters that correctly continues the pattern: DAF, FED, HIB, ?

Accepted Answer

Introduction / Context: This is an alphabet series question based on three letter clusters. You are asked to extend the pattern by selecting the next cluster from the given options. Such questions measure your ability to detect positional changes in letters and to apply them consistently across all parts of the series. Given Data / Assumptions: • Given groups: DAF, FED, HIB, ? • Options are three letter clusters that may continue the observed pattern. • Standard English alphabet positions are used (A = 1 to Z = 26). • The same rule applies to each of the three letter positions across the clusters. Concept / Approach: We treat each position in the triplets separately. That means we examine the first letters as an independent series, then the second letters, and finally the third letters. For each sequence we look for simple arithmetic patterns based on letter positions, such as adding, subtracting, or cyclic movement around the alphabet. When a pattern emerges in all three positions, we use it to determine the missing term. Step-by-Step Solution: Step 1: Convert the first letters to positions. First letters: D (4), F (6), H (8). We are adding 2 each time: 4 → 6 → 8, so the next first letter is 8 + 2 = 10, which is J. Step 2: Convert the second letters. Second letters: A (1), E (5), I (9). We add 4 each time: 1 → 5 → 9, so the next second letter is 9 + 4 = 13, which is M. Step 3: Convert the third letters. Third letters: F (6), D (4), B (2). Here we subtract 2 each time: 6 → 4 → 2, so the next would be 2 − 2 = 0. In a cyclic alphabet, position 0 wraps around to 26, which corresponds to Z. Step 4: Combine the results to obtain the missing term JMZ. Verification / Alternative check: Check consistency across the sequence: First column follows +2, second column follows +4, and third column follows −2 with wrapping at the end of the alphabet. DAF → FED → HIB → JMZ respects these rules perfectly: D to F to H to J, A to E to I to M, and F to D to B to Z. No alternative option matches all three position patterns. Why Other Options Are Wrong: • JOY: J and O do not fit the +2, +4 pattern correctly for the first two letters, and Y does not match the required wrapped value Z in the third position. • LUX: The first letter L would require a jump of +4 instead of +2 from H, and the second and third letters do not match the established sequences. • JOZ: The third letter Z is acceptable, but the first two letters J and O do not respect the +2 and +4 increments from H and I respectively. Common Pitfalls: Many test takers focus only on one of the positions and stop when they notice a partial pattern. A correct answer must satisfy all three letter positions simultaneously. Another pitfall is forgetting that letter series can wrap around from A to Z or Z to A. For the third letters, wrapping is essential to correctly arrive at Z from B using a subtraction pattern. Final Answer: The next three letter group in the series is JMZ.

Question 11

In the following series of letter pairs, one pair is missing. Identify the correct pair that continues the pattern: ZA, TG, NM, ?

Accepted Answer

Introduction / Context: This alphabet series question involves pairs of letters that move through the alphabet in a structured way. Your task is to discover the rule for how the first letters change and how the second letters change, then use the rule to find the missing pair. This type of problem strengthens pattern recognition skills used across many reasoning topics. Given Data / Assumptions: • Given pairs: ZA, TG, NM, ? • We work with the English alphabet, A = 1, B = 2, ..., Z = 26. • Movements can be forward or backward and can wrap around from Z to A. • The same arithmetic rule should apply step by step. Concept / Approach: We treat the first letters as one sequence and the second letters as another. We then convert each letter to its numerical position and look at the differences between consecutive terms. Once a consistent pattern is found for both positions, we extend it to determine the missing pair. This method avoids guesswork based only on visual similarity of letters. Step-by-Step Solution: Step 1: Translate first letters to numbers. First letters: Z (26), T (20), N (14). Differences: 26 → 20 is −6, 20 → 14 is −6. So we consistently subtract 6. Apply again: 14 − 6 = 8, which corresponds to H. Step 2: Translate second letters to numbers. Second letters: A (1), G (7), M (13). Differences: 1 → 7 is +6, 7 → 13 is +6. So we consistently add 6. Apply again: 13 + 6 = 19, which corresponds to S. Step 3: Combine the results. The missing pair is HS. Verification / Alternative check: The pattern is perfectly symmetric: the first letters move backward in the alphabet in steps of 6, while the second letters move forward in steps of 6. Using this rule from ZA to TG to NM, and then to HS, yields a smooth and consistent sequence. No other option fits both the first and second letter patterns simultaneously, which confirms that HS is the only valid answer. Why Other Options Are Wrong: • SH: This reverses the correct pair. It does not match the backward first letter and forward second letter pattern. • GT: Both letters break the exact −6 and +6 rules when checked against the previous term NM. • TG: This repeats an earlier term and does not show the necessary continuation of the backward and forward movements. Common Pitfalls: One common mistake is to look only at visual symmetry and select the reversed option SH without checking numeric positions. Another pitfall is to focus on one letter of the pair and ignore the second. Alphabet series questions usually require you to verify the pattern for both letters, otherwise apparently close answers can trick you. Final Answer: The letter pair that correctly completes the series is HS.

Question 12

In the following series of letter pairs, one pair is missing. Choose the pair that best completes the pattern: NM, PK, SI, ?

Accepted Answer

Introduction / Context: This problem presents a sequence of letter pairs that changes in a specific, predictable way. Your job is to identify that pattern and extend it to find the next pair. Letter pair questions like this check your familiarity with alphabet positions and your ability to spot progressively changing differences. Given Data / Assumptions: • Given pairs: NM, PK, SI, ? • We assume A = 1, B = 2, ..., Z = 26. • The first letters follow one numeric pattern and the second letters follow another, both consistent. • Movement may be forward or backward by different step sizes. Concept / Approach: We separate the first letters (N, P, S, ...) and second letters (M, K, I, ...). We then convert them into numbers and study the differences between consecutive terms. Often in such series, the jump size itself grows or shrinks in a simple way. Once we identify this change in steps, we can easily compute the next term in each sequence. Step-by-Step Solution: Step 1: Consider the first letters: N, P, S. Numerical positions: N = 14, P = 16, S = 19. Differences: 14 → 16 is +2, 16 → 19 is +3. The increment is increasing by 1 each step. So the next increment should be +4: 19 + 4 = 23, which is W. Step 2: Consider the second letters: M, K, I. Numerical positions: M = 13, K = 11, I = 9. Differences: 13 → 11 is −2, 11 → 9 is −2. So we consistently subtract 2. Apply again: 9 − 2 = 7, which is G. Step 3: Combine both results. The missing pair is WG. Verification / Alternative check: Write the full numeric sequence: first letters 14, 16, 19, 23; second letters 13, 11, 9, 7. The first series uses increments +2, +3, +4, while the second series uses a constant decrement of −2. This dual pattern explains all given terms and leads uniquely to WG. None of the other options matches these exact movements for both letters. Why Other Options Are Wrong: • VE: V is 22, which would mean an increment of only +3 from S instead of +4. E is 5, which does not match the constant −2 pattern from I. • WF: W is correct for the first letter, but F is 6 not 7, so the second letter sequence would be broken. • VG: G as second letter is correct, but V as first letter would require a different increment than the one dictated by the growing pattern. Common Pitfalls: A typical error is to assume the same constant step size for both letters, or to ignore that the increment for the first letters is changing. Another mistake is to check only approximate distances instead of computing exact numerical positions. Systematic calculation is the safest way to avoid such traps. Final Answer: The pair that correctly continues the series is WG.

Question 13

Fill in the blanks in the letter series “l_n_o_m_lm_o” by choosing the set of letters that completes a clear and consistent pattern.

Accepted Answer

Introduction / Context: This problem asks you to fill in several blanks in a letter series using one of the given sets of letters. The aim is to restore a structured pattern in the final string. Such questions often hide a repeated block or a symmetric arrangement, and you need to discover it by mentally or visually grouping the letters. Given Data / Assumptions: • Base pattern with blanks: l_n_o_m_lm_o • Candidate fillings: mnoln, mlnmn, monln, mnmno. • Each candidate letters are placed sequentially into the blanks in the order they appear. • The completed series should form a simple, meaningful letter pattern. Concept / Approach: When several blanks exist, trying each option by substitution is a practical strategy. After filling the blanks, you examine the resulting full string for any regular repetition or symmetry. A strong candidate will yield a recognizable repeated block, such as a sequence of consecutive letters forwards and backwards. Weak candidates usually produce a jumbled sequence without a clear rule. Step-by-Step Solution: Step 1: Substitute each option into the blanks. For option (c) “monln”, the series becomes: lmnoonmllmno. Step 2: Group the resulting string into equal parts. Write lmnoonmllmno as: lmno | onml | lmno. Step 3: Recognize the pattern in these groups. The first group “lmno” is letters L, M, N, O in ascending order. The second group “onml” is the same letters in exact reverse order. The third group again is “lmno” in ascending order. Step 4: This structure suggests a neat mirror pattern: lmno, onml, lmno. Such a symmetric forward and backward repetition is a strong and intentional pattern. Verification / Alternative check: Check the other options by substitution. None of them results in such a clean three block symmetry. They create irregular sequences that do not exhibit a simple repeated forward and backward order. Because competitive exam questions are designed with crisp logical patterns, the option that creates lmno | onml | lmno is almost certainly intended as the correct completion. Why Other Options Are Wrong: • “mnoln” produces a sequence without a clear division into repeated forward and reverse segments. • “mlnmn” leads to an inconsistent mixture of letters that fails to show any obvious repetition or symmetry. • “mnmno” similarly yields a jumbled result where no simple conceptual rule can be identified. Common Pitfalls: A frequent mistake is to focus only on local effects near each blank instead of examining the full final string. Another pitfall is to accept the first option that looks somewhat regular, rather than systematically checking all and searching for the clearest pattern. For letter series, exam setters usually design neat repeated structures rather than messy partial patterns. Final Answer: The correct set of letters to fill the blanks is monln.

Question 14

A series of three letter groups is given with one term missing. Select the alternative that correctly completes the pattern: VWX, BCD, HIJ, ?

Accepted Answer

Introduction / Context: This question presents a sequence of three letter clusters and asks you to identify the next cluster. The pattern involves cyclic movement through the alphabet, with a consistent shift applied to each letter. Understanding such patterns is a key part of letter based reasoning in aptitude exams. Given Data / Assumptions: • Given groups: VWX, BCD, HIJ, ? • Each group contains three consecutive letters in alphabetical order. • Movements between groups may wrap around from Z back to A. • The same numeric shift is applied to each letter position when moving from one group to the next. Concept / Approach: We map letters to their positions and observe how the starting letters of each group transform: V to B to H and so on. Because each group appears to be a block of three consecutive letters, once we know the starting letter pattern, we can reconstruct the entire missing group. The key is to spot a constant step size in these starting letters. Step-by-Step Solution: Step 1: List the starting letters of each group. VWX starts at V (22), BCD starts at B (2), HIJ starts at H (8). Step 2: Compute the movement between starting letters using modular arithmetic. From V (22) to B (2), we add 6 if we wrap around: 22 + 6 = 28, 28 − 26 = 2. From B (2) to H (8), we again add 6: 2 + 6 = 8. Step 3: Apply the same +6 pattern to H. H is position 8, so 8 + 6 = 14, which corresponds to N. Step 4: Build the full group starting at N. Since each group uses three consecutive letters, the next group is NOP. Verification / Alternative check: Check that the rule works for all letters in each group. VWX is V, W, X (22, 23, 24). Adding 6 yields B, C, D (2, 3, 4). Adding 6 again gives H, I, J (8, 9, 10). One more application yields N, O, P (14, 15, 16). This confirms a consistent pattern of +6 applied to each letter, with cyclic wrap around the alphabet, and validates NOP as the only correct continuation. Why Other Options Are Wrong: • MOQ: The letters are not three consecutive positions following the +6 transformation from HIJ, so the pattern breaks. • GHI: This simply repeats part of an earlier sequence and does not follow the starting letter shift from H to N. • TUV: This does not result from the established +6 offset from H, and therefore cannot be the next term. Common Pitfalls: A common mistake is to focus only on the visible alphabetical order inside each group and ignore how groups evolve relative to one another. Some test takers may also forget to consider wrap around arithmetic, which is essential whenever letters near Z are involved. Always check the consistent numeric shift across the entire sequence. Final Answer: The group that correctly completes the series is NOP.

Question 15

In the following series of letter pairs, one pair is missing. Choose the correct pair that continues the pattern: MN, PQ, TU, YZ, ?

Accepted Answer

Introduction / Context: This alphabet series question involves pairs of consecutive letters. The series moves forward through the alphabet with changing step sizes. You must determine the size of each jump and then use it to find the next pair. Identifying variable increments is an important pattern recognition skill. Given Data / Assumptions: • Given pairs: MN, PQ, TU, YZ, ? • Each pair contains two consecutive letters (M with N, P with Q, and so on). • Moves between pairs may wrap around the alphabet beyond Z. • The same rule is applied to both letters of each pair. Concept / Approach: To solve this kind of problem, look at the first letters only: M, P, T, Y. Convert them into numbers and check the differences. If the increment changes regularly, you can extrapolate the next step. Since each pair contains consecutive letters, once you know the starting letter, the second letter is determined automatically as the next one in the alphabet. Step-by-Step Solution: Step 1: Convert the first letters to positions. M = 13, P = 16, T = 20, Y = 25. Differences: 13 → 16 is +3, 16 → 20 is +4, 20 → 25 is +5. The increment itself increases by 1 each time. Step 2: Continue the pattern for the next first letter. The next jump should be +6: 25 + 6 = 31. Since the alphabet has 26 letters, 31 − 26 = 5, which corresponds to E. Step 3: Determine the second letter of the pair. Each pair contains consecutive letters, so the second letter is the next after E, which is F. Thus, the missing pair is EF. Verification / Alternative check: Check the full numeric sequence of first letters: 13, 16, 20, 25, 5. The differences are +3, +4, +5, +6 (with wrap around). If we build pairs from these starting letters, we get MN, PQ, TU, YZ, and finally EF. This respects the pattern perfectly. None of the other options produces a starting letter that matches the expected numeric result after wrapping. Why Other Options Are Wrong: • YZ: Repeating the last given pair fails to continue the increasing step pattern. • AB: A would correspond to position 1, and the step from 25 to 1 is −24 or +2, which does not match the expected +6 step. • EJ: While E appears, J is not the consecutive letter after E and therefore breaks the structure of consecutive letter pairs. Common Pitfalls: One pitfall is to assume that the sequence restarts at A after Y without checking the exact step size. Another is to focus only on visual closeness, such as AB appearing near the start of the alphabet, instead of actually computing numeric distances. Always confirm the increment pattern before choosing an answer. Final Answer: The letter pair that correctly completes the series is EF.

Question 16

Fill in the blanks in the letter series “MN_O_NN_M_NO” by choosing the set of letters that completes a simple repeated pattern.

Accepted Answer

Introduction / Context: This question involves a partially hidden letter pattern. Several blanks must be filled with a specific sequence of letters, chosen from the options, so that the entire string forms a clear and regular pattern. Often such questions are built around repeating blocks of letters. Given Data / Assumptions: • Base pattern: MN_O_NN_M_NO • Candidate fillings: NMMN, NMON, MNOO, NMMM. • Letters are placed sequentially into the blanks from left to right. • We seek a neat repetition or symmetry in the final sequence. Concept / Approach: When a letter series has multiple blanks, substitution and inspection is an efficient strategy. After inserting each candidate, you scan the outcome for repeated segments or simple cycles. Because exam questions are usually designed to produce very clean patterns, the correct option typically yields a string that can be neatly divided into identical blocks or symmetric halves. Step-by-Step Solution: Step 1: Substitute option (b) “NMON” into the blanks. The resulting string is: MNNOMNNOMNNO. Step 2: Try to group this string into equal parts. Write it as: MNNO | MNNO | MNNO. Step 3: Recognize the repetition. Each block is MNNO, repeated three times in a row. A repeated block pattern like this is exactly the kind of regular structure expected in such questions. Step 4: Quickly check other options and notice that they do not produce a simple exact repetition of a block of letters. Verification / Alternative check: Check that all blocks are identical: M N N O | M N N O | M N N O. There are no extra or missing letters. This high degree of regularity is a strong signal that the candidate is correct. By contrast, other options produce strings where letters do not group into equal, identical blocks, leading to uneven or irregular patterns. Why Other Options Are Wrong: • NMMN: Substituting this sequence does not produce simple blocks that repeat in a clean cycle. • MNOO: This option introduces a double O structure that disrupts any neat repetition of MNNO or similar blocks. • NMMM: This leads to clusters of M that are not mirrored or regularly repeated, making the overall pattern messy. Common Pitfalls: A common error is to accept a partial pattern, such as noticing MN or NO appearing several times, without confirming that the entire string breaks into identical segments. Another pitfall is failing to actually write or imagine the completed string, which can cause small irregularities to go unnoticed. Systematically testing each option avoids these issues. Final Answer: The correct set of letters to complete the series is NMON.

Question 17

A series of three letter groups is given with one term missing. Select the alternative that completes the pattern: WFB, TGD, QHG, ?

Accepted Answer

Introduction / Context: Here we have a sequence of three letter clusters that change in a structured way. You are asked to identify the next cluster that continues the pattern. Solving this problem requires tracking how each individual letter moves across the series and confirming that a single logical rule fits all three positions. Given Data / Assumptions: • Given groups: WFB, TGD, QHG, ? • Alphabet positions: A = 1, ..., Z = 26. • The first letters form one sequence, the second letters another, and the third letters a third sequence. • The rule should be arithmetic in nature and applied consistently. Concept / Approach: We treat each letter position as a separate numeric sequence. By converting letters to numbers, we can see whether the changes are constant additions, constant subtractions, or gradually changing steps. When the first, second, and third letter sequences all fit the same type of pattern, the next term can be determined reliably. Step-by-Step Solution: Step 1: Analyze the first letters: W, T, Q. Positions: W = 23, T = 20, Q = 17. Differences: 23 → 20 is −3, 20 → 17 is −3, so we subtract 3 each time. Next first letter: 17 − 3 = 14, which is N. Step 2: Analyze the second letters: F, G, H. Positions: F = 6, G = 7, H = 8. Differences: 6 → 7 is +1, 7 → 8 is +1, so we add 1 each time. Next second letter: 8 + 1 = 9, which is I. Step 3: Analyze the third letters: B, D, G. Positions: B = 2, D = 4, G = 7. Differences: 2 → 4 is +2, 4 → 7 is +3. The increment is increasing by 1. Next increment: +4, so 7 + 4 = 11, which is K. Step 4: Combine the letters to obtain the next term: NIK. Verification / Alternative check: Confirming the pattern: first letters follow −3 steps (23, 20, 17, 14), second letters follow +1 steps (6, 7, 8, 9), and third letters follow +2, +3, +4 (2, 4, 7, 11). The letter K is position 11, which fits this pattern. No other option satisfies all three sequences simultaneously. Why Other Options Are Wrong: • NIL: The third letter L is 12, which does not match the +4 step from 7. The second letter I is correct, but the third letter is too large by one position. • NLK: The second and third letters L and K do not result from the +1 and growing increment pattern observed in the series. • NJL: Here both J and L break the carefully established numeric differences in the second and third letter sequences. Common Pitfalls: One pitfall is to look for a single constant step affecting all three positions, which is not the case here. Another is to focus on only two positions and ignore the third. Alphabet pattern questions often use slightly different rules across positions, so it is crucial to verify each letter column. Final Answer: The correct group that completes the series is NIK.

Question 18

A series of letter pairs is given with one pair missing. Select the pair that correctly continues the pattern: AZ, BY, CX, ?

Accepted Answer

Introduction / Context: This is a classic alphabet series problem based on symmetric movement from the two ends of the alphabet. The first letters move forward from A, while the second letters move backward from Z. Your task is to find the next pair that preserves this symmetry. Given Data / Assumptions: • Given pairs: AZ, BY, CX, ? • The first letter of each pair progresses through the alphabet. • The second letter of each pair regresses through the alphabet. • Standard positions A = 1, Z = 26 are used. Concept / Approach: We observe that in each pair, the first letter starts near the beginning of the alphabet and moves forward, while the second letter starts near the end and moves backward. This is a common mirror style pattern in letter pair questions. Once we identify the next first letter and the next second letter, the pair is determined uniquely. Step-by-Step Solution: Step 1: List first letters in order. First letters: A, B, C, ? They increase by one position: A → B → C → D. So the next first letter must be D. Step 2: List second letters in order. Second letters: Z, Y, X, ? They decrease by one position: Z → Y → X → W. So the next second letter must be W. Step 3: Combine the letters to get the pair DW. Verification / Alternative check: Check the symmetry: A with Z are at the extremes of the alphabet, B with Y are next inwards, C with X are further inwards, and D with W continues this inward motion. No other option maintains this exact forward and backward single step progression from both ends simultaneously. Why Other Options Are Wrong: • WD: This reverses the correct order. The pattern clearly uses the ascending letter first and descending letter second. • DE: This pair has both letters advancing from the beginning side, breaking the mirror structure. • DX: The first letter D is correct but the second letter X does not continue the backward sequence from X to W. Common Pitfalls: Many candidates may choose WD because it uses the correct letters but in reversed order. Another pitfall is ignoring that the second letter is moving backward, not forward. Always track each position separately to avoid such traps. Final Answer: The pair that correctly completes the pattern is DW.

Question 19

In the following series of letter pairs, one pair is missing. Choose the pair that best continues the pattern: DM, EN, FO, ?

Accepted Answer

Introduction / Context: This is a straightforward alphabet series involving pairs of letters that both advance through the alphabet at the same rate. The question checks your comfort with letter positions and your ability to extend a simple pattern of increments. Given Data / Assumptions: • Given pairs: DM, EN, FO, ? • English alphabet positions are used: A = 1 to Z = 26. • Both letters within each pair change regularly from one term to the next. • The same increment is applied between corresponding letters of consecutive pairs. Concept / Approach: The simplest way to handle such a pattern is to examine each position separately. We look at the first letters D, E, F, then at the second letters M, N, O, and see how they move. If both sequences add one position each time, then the next pair is formed by adding one step to each letter. Step-by-Step Solution: Step 1: Convert first letters to numeric positions. D = 4, E = 5, F = 6. We add 1 at each step: 4 → 5 → 6, so the next first letter is 6 + 1 = 7, which is G. Step 2: Convert second letters to numeric positions. M = 13, N = 14, O = 15. Again, we add 1 each time: 13 → 14 → 15, so the next second letter is 15 + 1 = 16, which is P. Step 3: Combine the letters G and P to obtain the pair GP. Verification / Alternative check: Rewriting the sequence: DM, EN, FO, GP, both positions show consistent +1 steps. First letters are D, E, F, G; second letters are M, N, O, P. This smooth progression confirms that GP is correct. None of the other options uses a first letter directly after F and a second letter directly after O at the same time. Why Other Options Are Wrong: • FG: This does not preserve the pairing style, and the second letter G is far earlier in the alphabet than expected after O. • HI: Both letters H and I are ahead of what the pattern requires and do not align with the immediate next positions after D and M. • HP: H is too far ahead in the first letter sequence, even though P is correct for the second letter. Common Pitfalls: A typical mistake is to recognize the pattern in only one letter of the pair and then choose an option that fits this half pattern but breaks the other half. Always verify that both letters in the pair align with the expected progressions. Final Answer: The pair that correctly continues the sequence is GP.

Question 20

Fill in the blanks in the letter series “s_r_t_s_r” by choosing the set of letters that restores a structured repeating pattern.

Accepted Answer

Introduction / Context: This problem provides a partially hidden letter sequence with several blanks. Your task is to select the option that, when inserted, creates a clear pattern using the letters s, t, and r. Many such questions are built around repeating or mirrored permutations of a small set of letters. Given Data / Assumptions: • Base pattern: s_r_t_s_r • Options: trts, rtst, trst, tsss. • Letters from each option are placed into the blanks from left to right. • The completed string should show a neat, structured pattern, often in equal sized blocks. Concept / Approach: Instead of guessing, we fill the blanks with each option and then inspect the full sequence. We look for repeated subpatterns, especially of length three, since there are three distinct letters involved. A strong candidate creates a sequence that can be split into equal sized repeated segments or symmetric permutations of the same letters. Step-by-Step Solution: Step 1: Substitute option (c) “trst”. Filling the blanks yields: strrtsstr. Step 2: Divide the completed series into groups of three letters. We get: str | rts | str. Step 3: Recognize the pattern. The first group “str” contains the letters s, t, r in natural ascending order by position in the alphabet. The second group “rts” is a permutation of the same letters, providing a rotated middle segment. The third group repeats the original “str”, giving a symmetric structure: str, rts, str. Step 4: This forward middle forward configuration is a clean and deliberate pattern typical of exam questions. Verification / Alternative check: Try replacing the blanks with other options. They create sequences such as strrttssr or srrttsstr which do not divide naturally into symmetric or repeated three letter blocks. Option (c) alone provides a visually and logically satisfying sequence that starts and ends with the same triplet and uses a permutation in the center. Why Other Options Are Wrong: • “trts”: Produces a string where the middle and end portions do not reflect a clear repetition of any one triplet. • “rtst”: Leads to an arrangement that cannot be split into three neat groups containing all three letters s, t, and r in a structured way. • “tsss”: Generates large clusters of s that break the balanced use of all three letters and do not hint at any intended symmetry. Common Pitfalls: Learners often look only at local adjacency, trying to avoid repeated letters, and miss broader structural patterns. Another mistake is to stop at the first option that seems somewhat regular without checking if it gives a strongly symmetric or repeated structure. Exam designers tend to embed elegant patterns that become obvious once the correct option is applied. Final Answer: The letter set that correctly completes the series is trst.

Alphabet Test Questions