Syllogism — Premises: A) All girls are proud. B) All proud will be humiliated one day. Inferences: I) All girls will be humiliated one day. II) Some girls will be humiliated one day.

Difficulty: Easy

Correct Answer: Both I & II follow

Explanation:


Introduction / Context:
Two chained universal premises are given. We assess whether the universal and existential versions of the resulting consequence follow.


Given Data / Assumptions:

  • A: Girls ⊆ Proud.
  • B: Proud ⊆ HumiliatedOneDay.


Concept / Approach:
By transitivity, Girls ⊆ HumiliatedOneDay. From a universal inclusion, an existential statement 'Some girls ...' is also valid provided at least one girl exists; typical reasoning tests assume non-empty everyday categories.


Step-by-Step Solution:

Step 1: Combine A and B to get Girls ⊆ HumiliatedOneDay.Step 2: Conclusion I (universal) follows directly: all girls will be humiliated one day.Step 3: Conclusion II (existential) follows under the standard assumption that the class of girls is non-empty.


Verification / Alternative check:
Venn interpretation shows the Girls circle entirely inside Proud, which lies inside HumiliatedOneDay, making both I and II true in ordinary contexts.


Why Other Options Are Wrong:

  • Only I follows: ignores the routine existential inference.
  • Only II follows: the universal also follows by subset transitivity.
  • Neither: contradicted by the clear chain of subsets.


Common Pitfalls:
Forgetting that universal subset chains justify corresponding existential conclusions when the category is assumed non-empty.


Final Answer:
Both I & II follow.

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