Syllogism — Premises: (a) All frogs are tortoises. (b) No tortoise is a crocodile. Conclusions: I) No crocodile is a frog. II) No frog is a crocodile.

Difficulty: Easy

Correct Answer: Both I and II follow

Explanation:


Introduction / Context:
We combine a universal inclusion with a universal exclusion and test equivalent ways to state the same separation.


Given Data / Assumptions:

  • Frogs ⊆ Tortoises.
  • Tortoises ∩ Crocodiles = ∅.


Concept / Approach:
If all frogs are tortoises and no tortoise is a crocodile, then frogs share the same exclusion from crocodiles. Statements I and II are equivalent rephrasings of that separation.


Step-by-Step Solution:

Step 1: Substitute Frogs within Tortoises: any frog is a tortoise.Step 2: From (b), that tortoise cannot be a crocodile.Step 3: Therefore no frog is a crocodile, and equivalently no crocodile is a frog.


Verification / Alternative check:
Venn diagram: Frogs inside Tortoises; Tortoises disjoint from Crocodiles; hence Frogs disjoint from Crocodiles.


Why Other Options Are Wrong:
Any option denying either I or II conflicts with the chain of inclusion and exclusion.


Common Pitfalls:
Missing that I and II are logically equivalent statements of disjointness.


Final Answer:
Both I and II follow.

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