Syllogism — Premises: (a) All frogs are tortoises. (b) No tortoise is a crocodile. Conclusions: I) No crocodile is a frog. II) No frog is a crocodile.

Difficulty: Easy

Correct Answer: Both I and II follow

Explanation:

Introduction / Context:We combine a universal inclusion with a universal exclusion and test equivalent ways to state the same separation.

Given Data / Assumptions:

  • Frogs ⊆ Tortoises.
  • Tortoises ∩ Crocodiles = ∅.

Concept / Approach:If all frogs are tortoises and no tortoise is a crocodile, then frogs share the same exclusion from crocodiles. Statements I and II are equivalent rephrasings of that separation.

Step-by-Step Solution:

Step 1: Substitute Frogs within Tortoises: any frog is a tortoise.Step 2: From (b), that tortoise cannot be a crocodile.Step 3: Therefore no frog is a crocodile, and equivalently no crocodile is a frog.

Verification / Alternative check:Venn diagram: Frogs inside Tortoises; Tortoises disjoint from Crocodiles; hence Frogs disjoint from Crocodiles.

Why Other Options Are Wrong:Any option denying either I or II conflicts with the chain of inclusion and exclusion.

Common Pitfalls:Missing that I and II are logically equivalent statements of disjointness.

Final Answer:Both I and II follow.

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