Syllogism — Premises: All Americans are English-speaking. No Eskimos are English-speaking. Conclusions: I) No Eskimos are Americans. II) No English-speakers are Eskimos.

Introduction / Context:This is a classic combination of a universal inclusion and a universal exclusion. We test whether each conclusion is forced.

Given Data / Assumptions:

• Americans ⊆ EnglishSpeaking.
• Eskimos ∩ EnglishSpeaking = ∅ (equivalently, Eskimos ⊆ Not-EnglishSpeaking).

Concept / Approach:If Eskimos share no members with English-speaking, and Americans are entirely within English-speaking, then Eskimos cannot be Americans. Also, 'No Eskimos are English-speaking' is equivalent to 'No English-speakers are Eskimos' in set-theoretic negation.

Step-by-Step Solution:

Verification / Alternative check:Venn diagrams show disjoint sets Eskimos and EnglishSpeaking, with Americans inside EnglishSpeaking; thus both conclusions hold.

Why Other Options Are Wrong:Any option denying either I or II contradicts the disjointness and inclusion facts.

Common Pitfalls:Forgetting that 'No A are B' is bidirectional in effect for membership claims (mutual exclusivity).

Final Answer:Both I and II follow.