Gate behavior check: a multi-input NOR gate produces a logic HIGH at its output only for which specific input pattern?

Difficulty: Easy

Correct Answer: All inputs are 0s

Explanation:


Introduction / Context:
NOR is a fundamental logic gate defined as the logical complement of OR. Understanding its truth condition is crucial for designing active-low control signals, reset lines, and simple condition detectors. The question asks which input pattern yields a HIGH (1) at the output of a NOR gate.


Given Data / Assumptions:

  • NOR output = NOT(OR of all inputs).
  • Inputs are standard binary values (0 or 1).
  • We consider a NOR with two or more inputs; the property generalizes.


Concept / Approach:
By definition, OR outputs 1 if any input is 1. Therefore, NOR outputs 1 only when OR would output 0, which happens exclusively when every input is 0. Thus, NOR is an “all-zero detect” gate in its simplest interpretation.


Step-by-Step Solution:

Write relation: Y = NOR(A, B, …) = NOT(A + B + …). OR is 0 only when A = B = … = 0. Therefore Y = 1 exactly when all inputs are 0.


Verification / Alternative check:
Truth table inspection for 2-input NOR shows Y=1 only for A=0, B=0. Extending to more inputs preserves the condition: any single 1 forces OR to 1, making NOR 0.


Why Other Options Are Wrong:

Mix of 0s and 1s: OR becomes 1, so NOR becomes 0. All 1s: OR is 1, so NOR is 0. “Any inputs…”: ignores the defining complement relation to OR. None: incorrect because the all-zero condition is correct and present.


Common Pitfalls:
Confusing NOR with NAND; NAND outputs 0 only when all inputs are 1, whereas NOR outputs 1 only when all inputs are 0.


Final Answer:
All inputs are 0s

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